how to deserialize the serialize json data in android
how to deserialize from the following data.i used Gson lib to parase the data using Serializable. response to parse the data using replace command to remove the ''and parse it.
"[{"ALERT_IND":null,"ACTION_TY_NM":"Face to
Face","A_IND":2.0,"Act_Cat":"R
","ACT_SUB":"Meeting","Status":1.0,"SAG_NM":null,"PRI_TXT":"Medium ","DISPLAY_BACK_CLR":"#000080","OG_SHRT_NM":"Delhi
","OG_NM":"New
Delhi","EMP_NM":"Mannil","CONT_NM":"Kamakhya
Delhi","TO_DT":"29/09/2018","TIME":"08:47","MAST_DATA_TXT":null,"OG_ID":11.0,"C_DT":null,"CONT_ID":1129.0,"LeadOppoId":null,"CITY_NM":"","MOBILE":""}}]"
but some times its not working when using replace command to parse.Any specific lib is available in android. can u help me how to parse the data?
Can u share some code?
java
android arrays json api asked Nov 25 '18 at 6:58
kumarkumar
154
add a comment |
how to deserialize from the following data.i used Gson lib to parase the data using Serializable. response to parse the data using replace command to remove the ''and parse it.
"[{"ALERT_IND":null,"ACTION_TY_NM":"Face to
Face","A_IND":2.0,"Act_Cat":"R
","ACT_SUB":"Meeting","Status":1.0,"SAG_NM":null,"PRI_TXT":"Medium ","DISPLAY_BACK_CLR":"#000080","OG_SHRT_NM":"Delhi
","OG_NM":"New
Delhi","EMP_NM":"Mannil","CONT_NM":"Kamakhya
Delhi","TO_DT":"29/09/2018","TIME":"08:47","MAST_DATA_TXT":null,"OG_ID":11.0,"C_DT":null,"CONT_ID":1129.0,"LeadOppoId":null,"CITY_NM":"","MOBILE":""}}]"
but some times its not working when using replace command to parse.Any specific lib is available in android. can u help me how to parse the data?
Can u share some code?
java
android arrays json api asked Nov 25 '18 at 6:58
kumarkumar
154
add a comment |
how to deserialize from the following data.i used Gson lib to parase the data using Serializable. response to parse the data using replace command to remove the ''and parse it.
"[{"ALERT_IND":null,"ACTION_TY_NM":"Face to
Face","A_IND":2.0,"Act_Cat":"R
","ACT_SUB":"Meeting","Status":1.0,"SAG_NM":null,"PRI_TXT":"Medium ","DISPLAY_BACK_CLR":"#000080","OG_SHRT_NM":"Delhi
","OG_NM":"New
Delhi","EMP_NM":"Mannil","CONT_NM":"Kamakhya
Delhi","TO_DT":"29/09/2018","TIME":"08:47","MAST_DATA_TXT":null,"OG_ID":11.0,"C_DT":null,"CONT_ID":1129.0,"LeadOppoId":null,"CITY_NM":"","MOBILE":""}}]"
but some times its not working when using replace command to parse.Any specific lib is available in android. can u help me how to parse the data?
Can u share some code?
java
android arrays json api asked Nov 25 '18 at 6:58
kumarkumar
154
how to deserialize from the following data.i used Gson lib to parase the data using Serializable. response to parse the data using replace command to remove the ''and parse it.
"[{"ALERT_IND":null,"ACTION_TY_NM":"Face to
Face","A_IND":2.0,"Act_Cat":"R
","ACT_SUB":"Meeting","Status":1.0,"SAG_NM":null,"PRI_TXT":"Medium ","DISPLAY_BACK_CLR":"#000080","OG_SHRT_NM":"Delhi
","OG_NM":"New
Delhi","EMP_NM":"Mannil","CONT_NM":"Kamakhya
Delhi","TO_DT":"29/09/2018","TIME":"08:47","MAST_DATA_TXT":null,"OG_ID":11.0,"C_DT":null,"CONT_ID":1129.0,"LeadOppoId":null,"CITY_NM":"","MOBILE":""}}]"
but some times its not working when using replace command to parse.Any specific lib is available in android. can u help me how to parse the data?
Can u share some code?
java
android arrays json api java
android arrays json api asked Nov 25 '18 at 6:58
kumarkumar
154
asked Nov 25 '18 at 6:58
kumarkumar
154
asked Nov 25 '18 at 6:58
kumarkumar
154
asked Nov 25 '18 at 6:58
kumarkumar
154
asked Nov 25 '18 at 6:58
kumarkumar
154
154
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
You can use the Gson library for that.
Serialization is as simple as calling
new Gson().toJson(obj)
And for deserialization,
new Gson().fromJson(jsonStr, MyClass.class);
answered Nov 25 '18 at 7:05
Gourango SutradharGourango Sutradhar
24418
after i get response use replace command to remove the and than parse the string to gson . i already implemented this logic .my question is a any lib available in android.
– kumar
Nov 26 '18 at 4:25
add a comment |
First of all your json string is not a valid json. Because it is ending with an extra closing "}" curly bracket, remove it and then just replace in your json string "" with empty string "".
jsonString.replace("\", "");
And then you can parse it using Gson using a model class with serialized keys on fields.
public class Sample{
@SerializedName("ALERT_IND")
private String mAlertInd;
public void setAlertInd(String alertInd){
mAlertInd = alertInd;
}
public String getAlertInd(){
return mAlertInd;
}
}
answered Nov 25 '18 at 7:32
Muhammad NoorMuhammad Noor
11
i done like this only. my doubt any lib available in android to replace (\ ) and return valid json
– kumar
Nov 26 '18 at 4:17
add a comment |
you can use JSONObject and JSONArray that it creates a JSON object and you can get elements by key or index
new JSONObject(jsonString)
you can use GSON or LoganSquare tools that it parses JSON to a Model that you can get elements by fields name (pay attention to add dependencies before use it)
new Gson().fromJson(jsonString, Model.class)
LoganSquare.parse(jsonString, Model.class)
if you are encoded JSON string that means your string has a backslash before each quotation you can decode to raw string
String rawJson = str.replaceAll("\\", "");
answered Nov 25 '18 at 7:32
saeedatasaeedata
44126
with out removing the new Gson().fromJson(jsonString, Model.class) not working
– kumar
Nov 26 '18 at 4:19
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
You can use the Gson library for that.
Serialization is as simple as calling
new Gson().toJson(obj)
And for deserialization,
new Gson().fromJson(jsonStr, MyClass.class);
answered Nov 25 '18 at 7:05
Gourango SutradharGourango Sutradhar
24418
after i get response use replace command to remove the and than parse the string to gson . i already implemented this logic .my question is a any lib available in android.
– kumar
Nov 26 '18 at 4:25
add a comment |
You can use the Gson library for that.
Serialization is as simple as calling
new Gson().toJson(obj)
And for deserialization,
new Gson().fromJson(jsonStr, MyClass.class);
answered Nov 25 '18 at 7:05
Gourango SutradharGourango Sutradhar
24418
after i get response use replace command to remove the and than parse the string to gson . i already implemented this logic .my question is a any lib available in android.
– kumar
Nov 26 '18 at 4:25
add a comment |
You can use the Gson library for that.
Serialization is as simple as calling
new Gson().toJson(obj)
And for deserialization,
new Gson().fromJson(jsonStr, MyClass.class);
answered Nov 25 '18 at 7:05
Gourango SutradharGourango Sutradhar
24418
You can use the Gson library for that.
Serialization is as simple as calling
new Gson().toJson(obj)
And for deserialization,
new Gson().fromJson(jsonStr, MyClass.class);
answered Nov 25 '18 at 7:05
Gourango SutradharGourango Sutradhar
24418
answered Nov 25 '18 at 7:05
Gourango SutradharGourango Sutradhar
24418
answered Nov 25 '18 at 7:05
Gourango SutradharGourango Sutradhar
24418
answered Nov 25 '18 at 7:05
Gourango SutradharGourango Sutradhar
24418
24418
after i get response use replace command to remove the and than parse the string to gson . i already implemented this logic .my question is a any lib available in android.
– kumar
Nov 26 '18 at 4:25
add a comment |
after i get response use replace command to remove the and than parse the string to gson . i already implemented this logic .my question is a any lib available in android.
– kumar
Nov 26 '18 at 4:25
after i get response use replace command to remove the and than parse the string to gson . i already implemented this logic .my question is a any lib available in android.
– kumar
Nov 26 '18 at 4:25
after i get response use replace command to remove the and than parse the string to gson . i already implemented this logic .my question is a any lib available in android.
– kumar
Nov 26 '18 at 4:25
add a comment |
First of all your json string is not a valid json. Because it is ending with an extra closing "}" curly bracket, remove it and then just replace in your json string "" with empty string "".
jsonString.replace("\", "");
And then you can parse it using Gson using a model class with serialized keys on fields.
public class Sample{
@SerializedName("ALERT_IND")
private String mAlertInd;
public void setAlertInd(String alertInd){
mAlertInd = alertInd;
}
public String getAlertInd(){
return mAlertInd;
}
}
answered Nov 25 '18 at 7:32
Muhammad NoorMuhammad Noor
11
i done like this only. my doubt any lib available in android to replace (\ ) and return valid json
– kumar
Nov 26 '18 at 4:17
add a comment |
First of all your json string is not a valid json. Because it is ending with an extra closing "}" curly bracket, remove it and then just replace in your json string "" with empty string "".
jsonString.replace("\", "");
And then you can parse it using Gson using a model class with serialized keys on fields.
public class Sample{
@SerializedName("ALERT_IND")
private String mAlertInd;
public void setAlertInd(String alertInd){
mAlertInd = alertInd;
}
public String getAlertInd(){
return mAlertInd;
}
}
answered Nov 25 '18 at 7:32
Muhammad NoorMuhammad Noor
11
i done like this only. my doubt any lib available in android to replace (\ ) and return valid json
– kumar
Nov 26 '18 at 4:17
add a comment |
First of all your json string is not a valid json. Because it is ending with an extra closing "}" curly bracket, remove it and then just replace in your json string "" with empty string "".
jsonString.replace("\", "");
And then you can parse it using Gson using a model class with serialized keys on fields.
public class Sample{
@SerializedName("ALERT_IND")
private String mAlertInd;
public void setAlertInd(String alertInd){
mAlertInd = alertInd;
}
public String getAlertInd(){
return mAlertInd;
}
}
answered Nov 25 '18 at 7:32
Muhammad NoorMuhammad Noor
11
First of all your json string is not a valid json. Because it is ending with an extra closing "}" curly bracket, remove it and then just replace in your json string "" with empty string "".
jsonString.replace("\", "");
And then you can parse it using Gson using a model class with serialized keys on fields.
public class Sample{
@SerializedName("ALERT_IND")
private String mAlertInd;
public void setAlertInd(String alertInd){
mAlertInd = alertInd;
}
public String getAlertInd(){
return mAlertInd;
}
}
answered Nov 25 '18 at 7:32
Muhammad NoorMuhammad Noor
11
answered Nov 25 '18 at 7:32
Muhammad NoorMuhammad Noor
11
answered Nov 25 '18 at 7:32
Muhammad NoorMuhammad Noor
11
answered Nov 25 '18 at 7:32
Muhammad NoorMuhammad Noor
11
11
i done like this only. my doubt any lib available in android to replace (\ ) and return valid json
– kumar
Nov 26 '18 at 4:17
add a comment |
i done like this only. my doubt any lib available in android to replace (\ ) and return valid json
– kumar
Nov 26 '18 at 4:17
i done like this only. my doubt any lib available in android to replace (\ ) and return valid json
– kumar
Nov 26 '18 at 4:17
i done like this only. my doubt any lib available in android to replace (\ ) and return valid json
– kumar
Nov 26 '18 at 4:17
add a comment |
you can use JSONObject and JSONArray that it creates a JSON object and you can get elements by key or index
new JSONObject(jsonString)
you can use GSON or LoganSquare tools that it parses JSON to a Model that you can get elements by fields name (pay attention to add dependencies before use it)
new Gson().fromJson(jsonString, Model.class)
LoganSquare.parse(jsonString, Model.class)
if you are encoded JSON string that means your string has a backslash before each quotation you can decode to raw string
String rawJson = str.replaceAll("\\", "");
answered Nov 25 '18 at 7:32
saeedatasaeedata
44126
with out removing the new Gson().fromJson(jsonString, Model.class) not working
– kumar
Nov 26 '18 at 4:19
add a comment |
you can use JSONObject and JSONArray that it creates a JSON object and you can get elements by key or index
new JSONObject(jsonString)
you can use GSON or LoganSquare tools that it parses JSON to a Model that you can get elements by fields name (pay attention to add dependencies before use it)
new Gson().fromJson(jsonString, Model.class)
LoganSquare.parse(jsonString, Model.class)
if you are encoded JSON string that means your string has a backslash before each quotation you can decode to raw string
String rawJson = str.replaceAll("\\", "");
answered Nov 25 '18 at 7:32
saeedatasaeedata
44126
with out removing the new Gson().fromJson(jsonString, Model.class) not working
– kumar
Nov 26 '18 at 4:19
add a comment |
you can use JSONObject and JSONArray that it creates a JSON object and you can get elements by key or index
new JSONObject(jsonString)
you can use GSON or LoganSquare tools that it parses JSON to a Model that you can get elements by fields name (pay attention to add dependencies before use it)
new Gson().fromJson(jsonString, Model.class)
LoganSquare.parse(jsonString, Model.class)
if you are encoded JSON string that means your string has a backslash before each quotation you can decode to raw string
String rawJson = str.replaceAll("\\", "");
answered Nov 25 '18 at 7:32
saeedatasaeedata
44126
you can use JSONObject and JSONArray that it creates a JSON object and you can get elements by key or index
new JSONObject(jsonString)
you can use GSON or LoganSquare tools that it parses JSON to a Model that you can get elements by fields name (pay attention to add dependencies before use it)
new Gson().fromJson(jsonString, Model.class)
LoganSquare.parse(jsonString, Model.class)
if you are encoded JSON string that means your string has a backslash before each quotation you can decode to raw string
String rawJson = str.replaceAll("\\", "");
answered Nov 25 '18 at 7:32
saeedatasaeedata
44126
edited Nov 26 '18 at 7:16
answered Nov 25 '18 at 7:32
saeedatasaeedata
44126
answered Nov 25 '18 at 7:32
saeedatasaeedata
44126
answered Nov 25 '18 at 7:32
saeedatasaeedata
44126
44126
with out removing the new Gson().fromJson(jsonString, Model.class) not working
– kumar
Nov 26 '18 at 4:19
add a comment |
with out removing the new Gson().fromJson(jsonString, Model.class) not working
– kumar
Nov 26 '18 at 4:19
with out removing the new Gson().fromJson(jsonString, Model.class) not working
– kumar
Nov 26 '18 at 4:19
with out removing the new Gson().fromJson(jsonString, Model.class) not working
– kumar
Nov 26 '18 at 4:19
add a comment |
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