Delete particular objects from array in javascript

I have a object of array stored in local-storage as shown below

  var todos = [

    {"id":0,"text":"Make lunch","completed":true},

    {"id":1,"text":"Do laundry","completed":false},

    {"id":2,"text":"Complete Project","completed":true}

  ]

How can i delete all objects that are completed?
Please tell me how to delete it with splice method as i cant replace array i want to just remove it from array!(as my project requirements)
Thanks for any help

edited Nov 24 '18 at 11:06

asked Nov 24 '18 at 10:34

Darshit

3017

1

The posted question does not appear to include any attempt at all to solve the problem. StackOverflow expects you to try to solve your own problem first, as your attempts help us to better understand what you want. Please edit the question to show what you've tried, so as to illustrate a specific roadblock you're running into a Minimal, Complete, and Verifiable example. For more information, please see How to Ask and take the tour.

– CertainPerformance
Nov 24 '18 at 10:35

I tried todos.splice(todos.findIndex((todo) => todo.completed), 1); but it wont worked.

– Darshit
Nov 24 '18 at 10:37

@Darshit use this Underscore library filter function underscorejs.org/#filter

– Pranesh Janarthanan
Nov 24 '18 at 10:47

Please tell me how to delete it with splice method as i cant replace array i want to just remove it from array!

– Darshit
Nov 24 '18 at 11:05

That is unfair - you asked a question, which @Fawzi answered correctly, and you accepted. Then you changed the question, and unselected Fawzi's answer. That is disrespectful of people's efforts that they've put into helping you, and it will make people far less inclined to help you now or in the future.

– CJK
Nov 24 '18 at 11:08

|
show 1 more comment

I have a object of array stored in local-storage as shown below

  var todos = [

    {"id":0,"text":"Make lunch","completed":true},

    {"id":1,"text":"Do laundry","completed":false},

    {"id":2,"text":"Complete Project","completed":true}

  ]

edited Nov 24 '18 at 11:06

asked Nov 24 '18 at 10:34

Darshit

3017

1

The posted question does not appear to include any attempt at all to solve the problem. StackOverflow expects you to try to solve your own problem first, as your attempts help us to better understand what you want. Please edit the question to show what you've tried, so as to illustrate a specific roadblock you're running into a Minimal, Complete, and Verifiable example. For more information, please see How to Ask and take the tour.

– CertainPerformance
Nov 24 '18 at 10:35

I tried todos.splice(todos.findIndex((todo) => todo.completed), 1); but it wont worked.

– Darshit
Nov 24 '18 at 10:37

@Darshit use this Underscore library filter function underscorejs.org/#filter

– Pranesh Janarthanan
Nov 24 '18 at 10:47

Please tell me how to delete it with splice method as i cant replace array i want to just remove it from array!

– Darshit
Nov 24 '18 at 11:05

That is unfair - you asked a question, which @Fawzi answered correctly, and you accepted. Then you changed the question, and unselected Fawzi's answer. That is disrespectful of people's efforts that they've put into helping you, and it will make people far less inclined to help you now or in the future.

– CJK
Nov 24 '18 at 11:08

|
show 1 more comment

I have a object of array stored in local-storage as shown below

  var todos = [

    {"id":0,"text":"Make lunch","completed":true},

    {"id":1,"text":"Do laundry","completed":false},

    {"id":2,"text":"Complete Project","completed":true}

  ]

edited Nov 24 '18 at 11:06

asked Nov 24 '18 at 10:34

Darshit

3017

I have a object of array stored in local-storage as shown below

  var todos = [

    {"id":0,"text":"Make lunch","completed":true},

    {"id":1,"text":"Do laundry","completed":false},

    {"id":2,"text":"Complete Project","completed":true}

  ]

javascript arrays

edited Nov 24 '18 at 11:06

asked Nov 24 '18 at 10:34

Darshit

3017

edited Nov 24 '18 at 11:06

asked Nov 24 '18 at 10:34

Darshit

3017

edited Nov 24 '18 at 11:06

asked Nov 24 '18 at 10:34

Darshit

3017

asked Nov 24 '18 at 10:34

Darshit

3017

asked Nov 24 '18 at 10:34

Darshit

3017

1

The posted question does not appear to include any attempt at all to solve the problem. StackOverflow expects you to try to solve your own problem first, as your attempts help us to better understand what you want. Please edit the question to show what you've tried, so as to illustrate a specific roadblock you're running into a Minimal, Complete, and Verifiable example. For more information, please see How to Ask and take the tour.

– CertainPerformance
Nov 24 '18 at 10:35

I tried todos.splice(todos.findIndex((todo) => todo.completed), 1); but it wont worked.

– Darshit
Nov 24 '18 at 10:37

@Darshit use this Underscore library filter function underscorejs.org/#filter

– Pranesh Janarthanan
Nov 24 '18 at 10:47

Please tell me how to delete it with splice method as i cant replace array i want to just remove it from array!

– Darshit
Nov 24 '18 at 11:05

That is unfair - you asked a question, which @Fawzi answered correctly, and you accepted. Then you changed the question, and unselected Fawzi's answer. That is disrespectful of people's efforts that they've put into helping you, and it will make people far less inclined to help you now or in the future.

– CJK
Nov 24 '18 at 11:08

|
show 1 more comment

1

The posted question does not appear to include any attempt at all to solve the problem. StackOverflow expects you to try to solve your own problem first, as your attempts help us to better understand what you want. Please edit the question to show what you've tried, so as to illustrate a specific roadblock you're running into a Minimal, Complete, and Verifiable example. For more information, please see How to Ask and take the tour.

– CertainPerformance
Nov 24 '18 at 10:35

I tried todos.splice(todos.findIndex((todo) => todo.completed), 1); but it wont worked.

– Darshit
Nov 24 '18 at 10:37

@Darshit use this Underscore library filter function underscorejs.org/#filter

– Pranesh Janarthanan
Nov 24 '18 at 10:47

Please tell me how to delete it with splice method as i cant replace array i want to just remove it from array!

– Darshit
Nov 24 '18 at 11:05

That is unfair - you asked a question, which @Fawzi answered correctly, and you accepted. Then you changed the question, and unselected Fawzi's answer. That is disrespectful of people's efforts that they've put into helping you, and it will make people far less inclined to help you now or in the future.

– CJK
Nov 24 '18 at 11:08

The posted question does not appear to include any attempt at all to solve the problem. StackOverflow expects you to try to solve your own problem first, as your attempts help us to better understand what you want. Please edit the question to show what you've tried, so as to illustrate a specific roadblock you're running into a Minimal, Complete, and Verifiable example. For more information, please see How to Ask and take the tour.

– CertainPerformance
Nov 24 '18 at 10:35

I tried todos.splice(todos.findIndex((todo) => todo.completed), 1); but it wont worked.

– Darshit
Nov 24 '18 at 10:37

@Darshit use this Underscore library filter function underscorejs.org/#filter

– Pranesh Janarthanan
Nov 24 '18 at 10:47

Please tell me how to delete it with splice method as i cant replace array i want to just remove it from array!

– Darshit
Nov 24 '18 at 11:05

That is unfair - you asked a question, which @Fawzi answered correctly, and you accepted. Then you changed the question, and unselected Fawzi's answer. That is disrespectful of people's efforts that they've put into helping you, and it will make people far less inclined to help you now or in the future.

– CJK
Nov 24 '18 at 11:08

|
show 1 more comment

4 Answers
4

active

oldest

votes

You can try using the javascript array.filter

todos=todos.filter(todo=>!todo.completed);

answered Nov 24 '18 at 10:38

Fawzi

267110

never used angular before, but check this out as you might be calling the updated outside Angular zone.

– Fawzi
Nov 24 '18 at 11:06

add a comment |

var todos = [

{"id":0,"text":"Make lunch","completed":true},

{"id":1,"text":"Do laundry","completed":false},

{"id":2,"text":"Complete Project","completed":true} ];



var inCompletes = todos.filter(item => !item.completed );

inCompletes will return an array of objects with completed is false.

Output

inCompletes = [{"id":1,"text":"Do laundry","completed":false}];

answered Nov 24 '18 at 11:21

Anand S

45718

add a comment |

Something like this would do the job

var filteredAry = todos.filter(function(e) { return e.competed !== 'true' })

answered Nov 24 '18 at 10:37

thepolishboy

246

1

This won't work because, firstly, "completed" is misspelled. But, secondly, you've put quotes around true.

– CJK
Nov 24 '18 at 10:42

add a comment |

You can filter uncompleted todos like:

const unCompletedTodos = todos.filter(todo => !todo.completed);

Also you don't have to use const you can use var but I recommend you to use const or let instead of var

answered Nov 24 '18 at 10:40

Burak Güneli

368

add a comment |

Your Answer

StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");

StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});

}
});

draft saved

draft discarded

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53457261%2fdelete-particular-objects-from-array-in-javascript%23new-answer', 'question_page');
}
);

Post as a guest

Name

Required, but never shown

4 Answers
4

active

oldest

votes

4 Answers
4

active

oldest

votes

You can try using the javascript array.filter

todos=todos.filter(todo=>!todo.completed);

answered Nov 24 '18 at 10:38

Fawzi

267110

never used angular before, but check this out as you might be calling the updated outside Angular zone.

– Fawzi
Nov 24 '18 at 11:06

add a comment |

You can try using the javascript array.filter

todos=todos.filter(todo=>!todo.completed);

answered Nov 24 '18 at 10:38

Fawzi

267110

never used angular before, but check this out as you might be calling the updated outside Angular zone.

– Fawzi
Nov 24 '18 at 11:06

add a comment |

You can try using the javascript array.filter

todos=todos.filter(todo=>!todo.completed);

answered Nov 24 '18 at 10:38

Fawzi

267110

You can try using the javascript array.filter

todos=todos.filter(todo=>!todo.completed);

answered Nov 24 '18 at 10:38

Fawzi

267110

answered Nov 24 '18 at 10:38

Fawzi

267110

answered Nov 24 '18 at 10:38

Fawzi

267110

answered Nov 24 '18 at 10:38

Fawzi

267110

never used angular before, but check this out as you might be calling the updated outside Angular zone.

– Fawzi
Nov 24 '18 at 11:06

add a comment |

never used angular before, but check this out as you might be calling the updated outside Angular zone.

– Fawzi
Nov 24 '18 at 11:06

never used angular before, but check this out as you might be calling the updated outside Angular zone.

– Fawzi
Nov 24 '18 at 11:06

add a comment |

var todos = [

{"id":0,"text":"Make lunch","completed":true},

{"id":1,"text":"Do laundry","completed":false},

{"id":2,"text":"Complete Project","completed":true} ];



var inCompletes = todos.filter(item => !item.completed );

inCompletes will return an array of objects with completed is false.

Output

inCompletes = [{"id":1,"text":"Do laundry","completed":false}];

answered Nov 24 '18 at 11:21

Anand S

45718

add a comment |

var todos = [

{"id":0,"text":"Make lunch","completed":true},

{"id":1,"text":"Do laundry","completed":false},

{"id":2,"text":"Complete Project","completed":true} ];



var inCompletes = todos.filter(item => !item.completed );

inCompletes will return an array of objects with completed is false.

Output

inCompletes = [{"id":1,"text":"Do laundry","completed":false}];

answered Nov 24 '18 at 11:21

Anand S

45718

add a comment |

var todos = [

{"id":0,"text":"Make lunch","completed":true},

{"id":1,"text":"Do laundry","completed":false},

{"id":2,"text":"Complete Project","completed":true} ];



var inCompletes = todos.filter(item => !item.completed );

inCompletes will return an array of objects with completed is false.

Output

inCompletes = [{"id":1,"text":"Do laundry","completed":false}];

answered Nov 24 '18 at 11:21

Anand S

45718

var todos = [

{"id":0,"text":"Make lunch","completed":true},

{"id":1,"text":"Do laundry","completed":false},

{"id":2,"text":"Complete Project","completed":true} ];



var inCompletes = todos.filter(item => !item.completed );

inCompletes will return an array of objects with completed is false.

Output

inCompletes = [{"id":1,"text":"Do laundry","completed":false}];

answered Nov 24 '18 at 11:21

Anand S

45718

answered Nov 24 '18 at 11:21

Anand S

45718

answered Nov 24 '18 at 11:21

Anand S

45718

answered Nov 24 '18 at 11:21

Anand S

45718

add a comment |

Something like this would do the job

var filteredAry = todos.filter(function(e) { return e.competed !== 'true' })

answered Nov 24 '18 at 10:37

thepolishboy

246

1

This won't work because, firstly, "completed" is misspelled. But, secondly, you've put quotes around true.

– CJK
Nov 24 '18 at 10:42

add a comment |

Something like this would do the job

var filteredAry = todos.filter(function(e) { return e.competed !== 'true' })

answered Nov 24 '18 at 10:37

thepolishboy

246

1

This won't work because, firstly, "completed" is misspelled. But, secondly, you've put quotes around true.

– CJK
Nov 24 '18 at 10:42

add a comment |

Something like this would do the job

var filteredAry = todos.filter(function(e) { return e.competed !== 'true' })

answered Nov 24 '18 at 10:37

thepolishboy

246

Something like this would do the job

var filteredAry = todos.filter(function(e) { return e.competed !== 'true' })

answered Nov 24 '18 at 10:37

thepolishboy

246

answered Nov 24 '18 at 10:37

thepolishboy

246

answered Nov 24 '18 at 10:37

thepolishboy

246

answered Nov 24 '18 at 10:37

thepolishboy

246

1

This won't work because, firstly, "completed" is misspelled. But, secondly, you've put quotes around true.

– CJK
Nov 24 '18 at 10:42

add a comment |

1

This won't work because, firstly, "completed" is misspelled. But, secondly, you've put quotes around true.

– CJK
Nov 24 '18 at 10:42

This won't work because, firstly, "completed" is misspelled. But, secondly, you've put quotes around true.

– CJK
Nov 24 '18 at 10:42

add a comment |

You can filter uncompleted todos like:

const unCompletedTodos = todos.filter(todo => !todo.completed);

Also you don't have to use const you can use var but I recommend you to use const or let instead of var

answered Nov 24 '18 at 10:40

Burak Güneli

368

add a comment |

You can filter uncompleted todos like:

const unCompletedTodos = todos.filter(todo => !todo.completed);

Also you don't have to use const you can use var but I recommend you to use const or let instead of var

answered Nov 24 '18 at 10:40

Burak Güneli

368

add a comment |

You can filter uncompleted todos like:

const unCompletedTodos = todos.filter(todo => !todo.completed);

Also you don't have to use const you can use var but I recommend you to use const or let instead of var

answered Nov 24 '18 at 10:40

Burak Güneli

368

You can filter uncompleted todos like:

const unCompletedTodos = todos.filter(todo => !todo.completed);

Also you don't have to use const you can use var but I recommend you to use const or let instead of var

answered Nov 24 '18 at 10:40

Burak Güneli

368

answered Nov 24 '18 at 10:40

Burak Güneli

368

answered Nov 24 '18 at 10:40

Burak Güneli

368

answered Nov 24 '18 at 10:40

Burak Güneli

368

add a comment |

draft saved

draft discarded

Thanks for contributing an answer to Stack Overflow!

Please be sure to answer the question. Provide details and share your research!

But avoid …

Asking for help, clarification, or responding to other answers.

Making statements based on opinion; back them up with references or personal experience.

To learn more, see our tips on writing great answers.

draft saved

draft discarded

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

Post as a guest

Name

Required, but never shown

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

Name

Required, but never shown

Name

Required, but never shown

This page is only for reference, If you need detailed information, please check here

搜尋此網誌

Tukukkk