Add dateTime and dayTimeDuration












0















I cannot figure out how to add dateTime and dayTimeDuration with this very basic example:



<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="2.0" xmlns:xsd="http://www.w3.org/2001/XMLSchema" >
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:template match="/BroadcastData">
<tv>
<xsl:value-of select="xsd:dateTime('2008-10-08T05:00:00')+xsd:dayTimeDuration('PT1H')"/>
</tv>
</xsl:template>
</xsl:stylesheet>









share|improve this question

























  • Your code sample does seem to work. See xsltfiddle.liberty-development.net/pPqsHUu. Reasons why it might not work may be if you don't actually have a "BroadcastData" element in your XML, or if you are not actually using an XSLT 2.0 processor. How are you actually performing the transform, and what processor are you using? Thanks!

    – Tim C
    Nov 23 '18 at 17:14
















0















I cannot figure out how to add dateTime and dayTimeDuration with this very basic example:



<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="2.0" xmlns:xsd="http://www.w3.org/2001/XMLSchema" >
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:template match="/BroadcastData">
<tv>
<xsl:value-of select="xsd:dateTime('2008-10-08T05:00:00')+xsd:dayTimeDuration('PT1H')"/>
</tv>
</xsl:template>
</xsl:stylesheet>









share|improve this question

























  • Your code sample does seem to work. See xsltfiddle.liberty-development.net/pPqsHUu. Reasons why it might not work may be if you don't actually have a "BroadcastData" element in your XML, or if you are not actually using an XSLT 2.0 processor. How are you actually performing the transform, and what processor are you using? Thanks!

    – Tim C
    Nov 23 '18 at 17:14














0












0








0








I cannot figure out how to add dateTime and dayTimeDuration with this very basic example:



<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="2.0" xmlns:xsd="http://www.w3.org/2001/XMLSchema" >
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:template match="/BroadcastData">
<tv>
<xsl:value-of select="xsd:dateTime('2008-10-08T05:00:00')+xsd:dayTimeDuration('PT1H')"/>
</tv>
</xsl:template>
</xsl:stylesheet>









share|improve this question
















I cannot figure out how to add dateTime and dayTimeDuration with this very basic example:



<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="2.0" xmlns:xsd="http://www.w3.org/2001/XMLSchema" >
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:template match="/BroadcastData">
<tv>
<xsl:value-of select="xsd:dateTime('2008-10-08T05:00:00')+xsd:dayTimeDuration('PT1H')"/>
</tv>
</xsl:template>
</xsl:stylesheet>






xslt-2.0






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 24 '18 at 13:34









Micha Wiedenmann

10.4k1364104




10.4k1364104










asked Nov 23 '18 at 17:03









agsamorphagsamorph

1




1













  • Your code sample does seem to work. See xsltfiddle.liberty-development.net/pPqsHUu. Reasons why it might not work may be if you don't actually have a "BroadcastData" element in your XML, or if you are not actually using an XSLT 2.0 processor. How are you actually performing the transform, and what processor are you using? Thanks!

    – Tim C
    Nov 23 '18 at 17:14



















  • Your code sample does seem to work. See xsltfiddle.liberty-development.net/pPqsHUu. Reasons why it might not work may be if you don't actually have a "BroadcastData" element in your XML, or if you are not actually using an XSLT 2.0 processor. How are you actually performing the transform, and what processor are you using? Thanks!

    – Tim C
    Nov 23 '18 at 17:14

















Your code sample does seem to work. See xsltfiddle.liberty-development.net/pPqsHUu. Reasons why it might not work may be if you don't actually have a "BroadcastData" element in your XML, or if you are not actually using an XSLT 2.0 processor. How are you actually performing the transform, and what processor are you using? Thanks!

– Tim C
Nov 23 '18 at 17:14





Your code sample does seem to work. See xsltfiddle.liberty-development.net/pPqsHUu. Reasons why it might not work may be if you don't actually have a "BroadcastData" element in your XML, or if you are not actually using an XSLT 2.0 processor. How are you actually performing the transform, and what processor are you using? Thanks!

– Tim C
Nov 23 '18 at 17:14












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