Print Spreadsheet Cells Id in Scala
Problem
Spreadsheet cells are referenced by column and row identifiers. Columns are labeled with alphabetical characters, starting with "A", "B", "C", ...; rows are numbered from 1 in ascending order. Write a function that takes in a string identifying a range of cells in a spreadsheet and returns an ordered list of cells which compose that range.
Example:
"A3:D5" -> ["A3", "A4", "A5", "B3", "B4", "B5", "C3", "C4", "C5", "D3", "D4", "D5"]
"A3:D4" -> ["A3", "A4", "B3", "B4", "B5", "C3", "C4", "C5", "D3", "D4"]
Here is scala implementation of the same ,
import scala.language.postfixOps
object PrintSpreadSheet extends App {
val validAlphabets = ('A' to 'Z').toSeq
def cells(range: String): Seq[String] = {
val corners = (range split ":") flatMap { corner =>
Seq(corner.head, corner.last)
}
val rows = (corners filter (r => validAlphabets.contains(r))) sorted
val cols = (corners filter (c => !validAlphabets.contains(c))) sorted
(rows.head to rows.last) flatMap { r =>
(cols.head to cols.last) map { c =>
r.toString + ":" + c.toString
}
}
}
cells("A1:D5") foreach println
}
array interview-questions functional-programming matrix scala
asked 20 mins ago
vikrant
787
add a comment |
Problem
Spreadsheet cells are referenced by column and row identifiers. Columns are labeled with alphabetical characters, starting with "A", "B", "C", ...; rows are numbered from 1 in ascending order. Write a function that takes in a string identifying a range of cells in a spreadsheet and returns an ordered list of cells which compose that range.
Example:
"A3:D5" -> ["A3", "A4", "A5", "B3", "B4", "B5", "C3", "C4", "C5", "D3", "D4", "D5"]
"A3:D4" -> ["A3", "A4", "B3", "B4", "B5", "C3", "C4", "C5", "D3", "D4"]
Here is scala implementation of the same ,
import scala.language.postfixOps
object PrintSpreadSheet extends App {
val validAlphabets = ('A' to 'Z').toSeq
def cells(range: String): Seq[String] = {
val corners = (range split ":") flatMap { corner =>
Seq(corner.head, corner.last)
}
val rows = (corners filter (r => validAlphabets.contains(r))) sorted
val cols = (corners filter (c => !validAlphabets.contains(c))) sorted
(rows.head to rows.last) flatMap { r =>
(cols.head to cols.last) map { c =>
r.toString + ":" + c.toString
}
}
}
cells("A1:D5") foreach println
}
array interview-questions functional-programming matrix scala
asked 20 mins ago
vikrant
787
add a comment |
Problem
Spreadsheet cells are referenced by column and row identifiers. Columns are labeled with alphabetical characters, starting with "A", "B", "C", ...; rows are numbered from 1 in ascending order. Write a function that takes in a string identifying a range of cells in a spreadsheet and returns an ordered list of cells which compose that range.
Example:
"A3:D5" -> ["A3", "A4", "A5", "B3", "B4", "B5", "C3", "C4", "C5", "D3", "D4", "D5"]
"A3:D4" -> ["A3", "A4", "B3", "B4", "B5", "C3", "C4", "C5", "D3", "D4"]
Here is scala implementation of the same ,
import scala.language.postfixOps
object PrintSpreadSheet extends App {
val validAlphabets = ('A' to 'Z').toSeq
def cells(range: String): Seq[String] = {
val corners = (range split ":") flatMap { corner =>
Seq(corner.head, corner.last)
}
val rows = (corners filter (r => validAlphabets.contains(r))) sorted
val cols = (corners filter (c => !validAlphabets.contains(c))) sorted
(rows.head to rows.last) flatMap { r =>
(cols.head to cols.last) map { c =>
r.toString + ":" + c.toString
}
}
}
cells("A1:D5") foreach println
}
array interview-questions functional-programming matrix scala
asked 20 mins ago
vikrant
787
Problem
Spreadsheet cells are referenced by column and row identifiers. Columns are labeled with alphabetical characters, starting with "A", "B", "C", ...; rows are numbered from 1 in ascending order. Write a function that takes in a string identifying a range of cells in a spreadsheet and returns an ordered list of cells which compose that range.
Example:
"A3:D5" -> ["A3", "A4", "A5", "B3", "B4", "B5", "C3", "C4", "C5", "D3", "D4", "D5"]
"A3:D4" -> ["A3", "A4", "B3", "B4", "B5", "C3", "C4", "C5", "D3", "D4"]
Here is scala implementation of the same ,
import scala.language.postfixOps
object PrintSpreadSheet extends App {
val validAlphabets = ('A' to 'Z').toSeq
def cells(range: String): Seq[String] = {
val corners = (range split ":") flatMap { corner =>
Seq(corner.head, corner.last)
}
val rows = (corners filter (r => validAlphabets.contains(r))) sorted
val cols = (corners filter (c => !validAlphabets.contains(c))) sorted
(rows.head to rows.last) flatMap { r =>
(cols.head to cols.last) map { c =>
r.toString + ":" + c.toString
}
}
}
cells("A1:D5") foreach println
}
array interview-questions functional-programming matrix scala
array interview-questions functional-programming matrix scala
asked 20 mins ago
vikrant
787
asked 20 mins ago
vikrant
787
asked 20 mins ago
vikrant
787
asked 20 mins ago
vikrant
787
asked 20 mins ago
vikrant
787
787
add a comment |
add a comment |
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