Why isn't my Jest spy showing as called when I can see that it is?
I am trying to determine why exactly my Jest spy isn't being called when I can see that the spy is properly "injected" into my component? Here's my very simple example:
TestComponent.js
export default class TestComponent extends Component {
constructor(props) {
super(props);
this.handleSubmit = this.handleSubmit.bind(this);
}
handleSubmit(event) {
event && event.preventDefault();
console.log("handleSubmit called!");
}
render() {
return (
<form onSubmit={this.handleSubmit}>
<button className="submit-button" type="submit">
Submit
</button>
</form>
);
}
}
TestComponent.test.js
describe("TestComponent tests", () => {
it("`handleSubmit` is called when form is submitted", () => {
const wrapper = shallow(<TestComponent />);
const spy = jest.spyOn(wrapper.instance(), "handleSubmit");
wrapper.find("form").simulate("submit");
expect(spy).toHaveBeenCalled();
});
});
If I do a console.log on the wrapper.instance().handleSubmit I can clearly see that the spy has been injected into the object's property, yet my test still fails stating that the spy was not called.
A CodeSandbox with a working example can be found here: https://codesandbox.io/s/3ymkp3w5x1
Thanks!
jestjs enzyme
edited Nov 20 at 21:19
skyboyer
3,25611128
asked Nov 20 at 20:21
slashp
1,69712139
add a comment |
I am trying to determine why exactly my Jest spy isn't being called when I can see that the spy is properly "injected" into my component? Here's my very simple example:
TestComponent.js
export default class TestComponent extends Component {
constructor(props) {
super(props);
this.handleSubmit = this.handleSubmit.bind(this);
}
handleSubmit(event) {
event && event.preventDefault();
console.log("handleSubmit called!");
}
render() {
return (
<form onSubmit={this.handleSubmit}>
<button className="submit-button" type="submit">
Submit
</button>
</form>
);
}
}
TestComponent.test.js
describe("TestComponent tests", () => {
it("`handleSubmit` is called when form is submitted", () => {
const wrapper = shallow(<TestComponent />);
const spy = jest.spyOn(wrapper.instance(), "handleSubmit");
wrapper.find("form").simulate("submit");
expect(spy).toHaveBeenCalled();
});
});
If I do a console.log on the wrapper.instance().handleSubmit I can clearly see that the spy has been injected into the object's property, yet my test still fails stating that the spy was not called.
A CodeSandbox with a working example can be found here: https://codesandbox.io/s/3ymkp3w5x1
Thanks!
jestjs enzyme
edited Nov 20 at 21:19
skyboyer
3,25611128
asked Nov 20 at 20:21
slashp
1,69712139
I'm guessing this is due to the fact that the onSubmit function is somehow getting called asynchronously -- going to do some more research in this area.
– slashp
Nov 20 at 21:54
add a comment |
I am trying to determine why exactly my Jest spy isn't being called when I can see that the spy is properly "injected" into my component? Here's my very simple example:
TestComponent.js
export default class TestComponent extends Component {
constructor(props) {
super(props);
this.handleSubmit = this.handleSubmit.bind(this);
}
handleSubmit(event) {
event && event.preventDefault();
console.log("handleSubmit called!");
}
render() {
return (
<form onSubmit={this.handleSubmit}>
<button className="submit-button" type="submit">
Submit
</button>
</form>
);
}
}
TestComponent.test.js
describe("TestComponent tests", () => {
it("`handleSubmit` is called when form is submitted", () => {
const wrapper = shallow(<TestComponent />);
const spy = jest.spyOn(wrapper.instance(), "handleSubmit");
wrapper.find("form").simulate("submit");
expect(spy).toHaveBeenCalled();
});
});
If I do a console.log on the wrapper.instance().handleSubmit I can clearly see that the spy has been injected into the object's property, yet my test still fails stating that the spy was not called.
A CodeSandbox with a working example can be found here: https://codesandbox.io/s/3ymkp3w5x1
Thanks!
jestjs enzyme
edited Nov 20 at 21:19
skyboyer
3,25611128
asked Nov 20 at 20:21
slashp
1,69712139
I am trying to determine why exactly my Jest spy isn't being called when I can see that the spy is properly "injected" into my component? Here's my very simple example:
TestComponent.js
export default class TestComponent extends Component {
constructor(props) {
super(props);
this.handleSubmit = this.handleSubmit.bind(this);
}
handleSubmit(event) {
event && event.preventDefault();
console.log("handleSubmit called!");
}
render() {
return (
<form onSubmit={this.handleSubmit}>
<button className="submit-button" type="submit">
Submit
</button>
</form>
);
}
}
TestComponent.test.js
describe("TestComponent tests", () => {
it("`handleSubmit` is called when form is submitted", () => {
const wrapper = shallow(<TestComponent />);
const spy = jest.spyOn(wrapper.instance(), "handleSubmit");
wrapper.find("form").simulate("submit");
expect(spy).toHaveBeenCalled();
});
});
If I do a console.log on the wrapper.instance().handleSubmit I can clearly see that the spy has been injected into the object's property, yet my test still fails stating that the spy was not called.
A CodeSandbox with a working example can be found here: https://codesandbox.io/s/3ymkp3w5x1
Thanks!
jestjs enzyme
jestjs enzyme
edited Nov 20 at 21:19
skyboyer
3,25611128
asked Nov 20 at 20:21
slashp
1,69712139
edited Nov 20 at 21:19
skyboyer
3,25611128
asked Nov 20 at 20:21
slashp
1,69712139
edited Nov 20 at 21:19
skyboyer
3,25611128
edited Nov 20 at 21:19
skyboyer
3,25611128
edited Nov 20 at 21:19
skyboyer
3,25611128
3,25611128
asked Nov 20 at 20:21
slashp
1,69712139
asked Nov 20 at 20:21
slashp
1,69712139
asked Nov 20 at 20:21
slashp
1,69712139
1,69712139
I'm guessing this is due to the fact that the onSubmit function is somehow getting called asynchronously -- going to do some more research in this area.
– slashp
Nov 20 at 21:54
add a comment |
I'm guessing this is due to the fact that the onSubmit function is somehow getting called asynchronously -- going to do some more research in this area.
– slashp
Nov 20 at 21:54
I'm guessing this is due to the fact that the onSubmit function is somehow getting called asynchronously -- going to do some more research in this area.
– slashp
Nov 20 at 21:54
I'm guessing this is due to the fact that the onSubmit function is somehow getting called asynchronously -- going to do some more research in this area.
– slashp
Nov 20 at 21:54
add a comment |
1 Answer
1
active
oldest
votes
Best practice is not to test that handleSubmit was called, but just to check for the results of calling handleSubmit. Having said that...
Issue
onSubmit is bound directly to the value of this.handleSubmit at the time the component renders.
Solution
Use a lambda function (note, this might cause performance issues) so that onSubmit calls the current value of this.handleSubmit when it is invoked:
<form onSubmit={() => this.handleSubmit()}>
answered Nov 22 at 3:33
brian-lives-outdoors
4,840322
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Best practice is not to test that handleSubmit was called, but just to check for the results of calling handleSubmit. Having said that...
Issue
onSubmit is bound directly to the value of this.handleSubmit at the time the component renders.
Solution
Use a lambda function (note, this might cause performance issues) so that onSubmit calls the current value of this.handleSubmit when it is invoked:
<form onSubmit={() => this.handleSubmit()}>
answered Nov 22 at 3:33
brian-lives-outdoors
4,840322
add a comment |
Best practice is not to test that handleSubmit was called, but just to check for the results of calling handleSubmit. Having said that...
Issue
onSubmit is bound directly to the value of this.handleSubmit at the time the component renders.
Solution
Use a lambda function (note, this might cause performance issues) so that onSubmit calls the current value of this.handleSubmit when it is invoked:
<form onSubmit={() => this.handleSubmit()}>
answered Nov 22 at 3:33
brian-lives-outdoors
4,840322
add a comment |
Best practice is not to test that handleSubmit was called, but just to check for the results of calling handleSubmit. Having said that...
Issue
onSubmit is bound directly to the value of this.handleSubmit at the time the component renders.
Solution
Use a lambda function (note, this might cause performance issues) so that onSubmit calls the current value of this.handleSubmit when it is invoked:
<form onSubmit={() => this.handleSubmit()}>
answered Nov 22 at 3:33
brian-lives-outdoors
4,840322
Best practice is not to test that handleSubmit was called, but just to check for the results of calling handleSubmit. Having said that...
Issue
onSubmit is bound directly to the value of this.handleSubmit at the time the component renders.
Solution
Use a lambda function (note, this might cause performance issues) so that onSubmit calls the current value of this.handleSubmit when it is invoked:
<form onSubmit={() => this.handleSubmit()}>
answered Nov 22 at 3:33
brian-lives-outdoors
4,840322
answered Nov 22 at 3:33
brian-lives-outdoors
4,840322
answered Nov 22 at 3:33
brian-lives-outdoors
4,840322
answered Nov 22 at 3:33
brian-lives-outdoors
4,840322
4,840322
add a comment |
add a comment |
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I'm guessing this is due to the fact that the onSubmit function is somehow getting called asynchronously -- going to do some more research in this area.
– slashp
Nov 20 at 21:54