SQL Column Value Within string
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I Have a string below
100Pipers22WoodfieldRoadBlackpoolFY16AX
I also have an address table on where i want to cross reference the postcode column to see if the value exists in the above string. Column value would be FY16AX which is visible in the string.
I cant seem to get a match.
sql function matching
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up vote
0
down vote
favorite
I Have a string below
100Pipers22WoodfieldRoadBlackpoolFY16AX
I also have an address table on where i want to cross reference the postcode column to see if the value exists in the above string. Column value would be FY16AX which is visible in the string.
I cant seem to get a match.
sql function matching
2
Tag your question with the database you are using. Also, provide the code you have.
– Gordon Linoff
Nov 20 at 12:08
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I Have a string below
100Pipers22WoodfieldRoadBlackpoolFY16AX
I also have an address table on where i want to cross reference the postcode column to see if the value exists in the above string. Column value would be FY16AX which is visible in the string.
I cant seem to get a match.
sql function matching
I Have a string below
100Pipers22WoodfieldRoadBlackpoolFY16AX
I also have an address table on where i want to cross reference the postcode column to see if the value exists in the above string. Column value would be FY16AX which is visible in the string.
I cant seem to get a match.
sql function matching
sql function matching
asked Nov 20 at 12:08
Sam Parky
156
156
2
Tag your question with the database you are using. Also, provide the code you have.
– Gordon Linoff
Nov 20 at 12:08
add a comment |
2
Tag your question with the database you are using. Also, provide the code you have.
– Gordon Linoff
Nov 20 at 12:08
2
2
Tag your question with the database you are using. Also, provide the code you have.
– Gordon Linoff
Nov 20 at 12:08
Tag your question with the database you are using. Also, provide the code you have.
– Gordon Linoff
Nov 20 at 12:08
add a comment |
2 Answers
2
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1
down vote
If I understand correctly, you can use like. In standard SQL, this would look like:
where string like '%' || postcode
The || is the string concatenation operator. Some databases have their own operators or functions for this functionality.
Might want to consider case too - e.g.UPPERorLOWERon both your string and search-term (in this casepostcode)
– doublesidedstickytape
Nov 20 at 12:15
1
@doublesidedstickytape, better to use a case insensitive collation.
– jarlh
Nov 20 at 13:25
add a comment |
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Declare @vString nvarchar(50)
Set @vString = '100Pipers22WoodfieldRoadBlackpoolFY16AX'
Select Count(*) From tbl_Address Where Zip = right(@vString,6)
If the select statement returns a value greater than zero, you have a match.
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
If I understand correctly, you can use like. In standard SQL, this would look like:
where string like '%' || postcode
The || is the string concatenation operator. Some databases have their own operators or functions for this functionality.
Might want to consider case too - e.g.UPPERorLOWERon both your string and search-term (in this casepostcode)
– doublesidedstickytape
Nov 20 at 12:15
1
@doublesidedstickytape, better to use a case insensitive collation.
– jarlh
Nov 20 at 13:25
add a comment |
up vote
1
down vote
If I understand correctly, you can use like. In standard SQL, this would look like:
where string like '%' || postcode
The || is the string concatenation operator. Some databases have their own operators or functions for this functionality.
Might want to consider case too - e.g.UPPERorLOWERon both your string and search-term (in this casepostcode)
– doublesidedstickytape
Nov 20 at 12:15
1
@doublesidedstickytape, better to use a case insensitive collation.
– jarlh
Nov 20 at 13:25
add a comment |
up vote
1
down vote
up vote
1
down vote
If I understand correctly, you can use like. In standard SQL, this would look like:
where string like '%' || postcode
The || is the string concatenation operator. Some databases have their own operators or functions for this functionality.
If I understand correctly, you can use like. In standard SQL, this would look like:
where string like '%' || postcode
The || is the string concatenation operator. Some databases have their own operators or functions for this functionality.
answered Nov 20 at 12:09
Gordon Linoff
754k35287395
754k35287395
Might want to consider case too - e.g.UPPERorLOWERon both your string and search-term (in this casepostcode)
– doublesidedstickytape
Nov 20 at 12:15
1
@doublesidedstickytape, better to use a case insensitive collation.
– jarlh
Nov 20 at 13:25
add a comment |
Might want to consider case too - e.g.UPPERorLOWERon both your string and search-term (in this casepostcode)
– doublesidedstickytape
Nov 20 at 12:15
1
@doublesidedstickytape, better to use a case insensitive collation.
– jarlh
Nov 20 at 13:25
Might want to consider case too - e.g.
UPPER or LOWER on both your string and search-term (in this case postcode)– doublesidedstickytape
Nov 20 at 12:15
Might want to consider case too - e.g.
UPPER or LOWER on both your string and search-term (in this case postcode)– doublesidedstickytape
Nov 20 at 12:15
1
1
@doublesidedstickytape, better to use a case insensitive collation.
– jarlh
Nov 20 at 13:25
@doublesidedstickytape, better to use a case insensitive collation.
– jarlh
Nov 20 at 13:25
add a comment |
up vote
0
down vote
Declare @vString nvarchar(50)
Set @vString = '100Pipers22WoodfieldRoadBlackpoolFY16AX'
Select Count(*) From tbl_Address Where Zip = right(@vString,6)
If the select statement returns a value greater than zero, you have a match.
add a comment |
up vote
0
down vote
Declare @vString nvarchar(50)
Set @vString = '100Pipers22WoodfieldRoadBlackpoolFY16AX'
Select Count(*) From tbl_Address Where Zip = right(@vString,6)
If the select statement returns a value greater than zero, you have a match.
add a comment |
up vote
0
down vote
up vote
0
down vote
Declare @vString nvarchar(50)
Set @vString = '100Pipers22WoodfieldRoadBlackpoolFY16AX'
Select Count(*) From tbl_Address Where Zip = right(@vString,6)
If the select statement returns a value greater than zero, you have a match.
Declare @vString nvarchar(50)
Set @vString = '100Pipers22WoodfieldRoadBlackpoolFY16AX'
Select Count(*) From tbl_Address Where Zip = right(@vString,6)
If the select statement returns a value greater than zero, you have a match.
answered Nov 20 at 15:35
level3looper
1745
1745
add a comment |
add a comment |
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Tag your question with the database you are using. Also, provide the code you have.
– Gordon Linoff
Nov 20 at 12:08