SQL Column Value Within string











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I Have a string below



100Pipers22WoodfieldRoadBlackpoolFY16AX


I also have an address table on where i want to cross reference the postcode column to see if the value exists in the above string. Column value would be FY16AX which is visible in the string.



I cant seem to get a match.










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  • 2




    Tag your question with the database you are using. Also, provide the code you have.
    – Gordon Linoff
    Nov 20 at 12:08















up vote
0
down vote

favorite












I Have a string below



100Pipers22WoodfieldRoadBlackpoolFY16AX


I also have an address table on where i want to cross reference the postcode column to see if the value exists in the above string. Column value would be FY16AX which is visible in the string.



I cant seem to get a match.










share|improve this question


















  • 2




    Tag your question with the database you are using. Also, provide the code you have.
    – Gordon Linoff
    Nov 20 at 12:08













up vote
0
down vote

favorite









up vote
0
down vote

favorite











I Have a string below



100Pipers22WoodfieldRoadBlackpoolFY16AX


I also have an address table on where i want to cross reference the postcode column to see if the value exists in the above string. Column value would be FY16AX which is visible in the string.



I cant seem to get a match.










share|improve this question













I Have a string below



100Pipers22WoodfieldRoadBlackpoolFY16AX


I also have an address table on where i want to cross reference the postcode column to see if the value exists in the above string. Column value would be FY16AX which is visible in the string.



I cant seem to get a match.







sql function matching






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share|improve this question










asked Nov 20 at 12:08









Sam Parky

156




156








  • 2




    Tag your question with the database you are using. Also, provide the code you have.
    – Gordon Linoff
    Nov 20 at 12:08














  • 2




    Tag your question with the database you are using. Also, provide the code you have.
    – Gordon Linoff
    Nov 20 at 12:08








2




2




Tag your question with the database you are using. Also, provide the code you have.
– Gordon Linoff
Nov 20 at 12:08




Tag your question with the database you are using. Also, provide the code you have.
– Gordon Linoff
Nov 20 at 12:08












2 Answers
2






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1
down vote













If I understand correctly, you can use like. In standard SQL, this would look like:



where string like '%' || postcode


The || is the string concatenation operator. Some databases have their own operators or functions for this functionality.






share|improve this answer





















  • Might want to consider case too - e.g. UPPER or LOWER on both your string and search-term (in this case postcode)
    – doublesidedstickytape
    Nov 20 at 12:15






  • 1




    @doublesidedstickytape, better to use a case insensitive collation.
    – jarlh
    Nov 20 at 13:25




















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0
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Declare @vString nvarchar(50)
Set @vString = '100Pipers22WoodfieldRoadBlackpoolFY16AX'

Select Count(*) From tbl_Address Where Zip = right(@vString,6)


If the select statement returns a value greater than zero, you have a match.






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    2 Answers
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    up vote
    1
    down vote













    If I understand correctly, you can use like. In standard SQL, this would look like:



    where string like '%' || postcode


    The || is the string concatenation operator. Some databases have their own operators or functions for this functionality.






    share|improve this answer





















    • Might want to consider case too - e.g. UPPER or LOWER on both your string and search-term (in this case postcode)
      – doublesidedstickytape
      Nov 20 at 12:15






    • 1




      @doublesidedstickytape, better to use a case insensitive collation.
      – jarlh
      Nov 20 at 13:25

















    up vote
    1
    down vote













    If I understand correctly, you can use like. In standard SQL, this would look like:



    where string like '%' || postcode


    The || is the string concatenation operator. Some databases have their own operators or functions for this functionality.






    share|improve this answer





















    • Might want to consider case too - e.g. UPPER or LOWER on both your string and search-term (in this case postcode)
      – doublesidedstickytape
      Nov 20 at 12:15






    • 1




      @doublesidedstickytape, better to use a case insensitive collation.
      – jarlh
      Nov 20 at 13:25















    up vote
    1
    down vote










    up vote
    1
    down vote









    If I understand correctly, you can use like. In standard SQL, this would look like:



    where string like '%' || postcode


    The || is the string concatenation operator. Some databases have their own operators or functions for this functionality.






    share|improve this answer












    If I understand correctly, you can use like. In standard SQL, this would look like:



    where string like '%' || postcode


    The || is the string concatenation operator. Some databases have their own operators or functions for this functionality.







    share|improve this answer












    share|improve this answer



    share|improve this answer










    answered Nov 20 at 12:09









    Gordon Linoff

    754k35287395




    754k35287395












    • Might want to consider case too - e.g. UPPER or LOWER on both your string and search-term (in this case postcode)
      – doublesidedstickytape
      Nov 20 at 12:15






    • 1




      @doublesidedstickytape, better to use a case insensitive collation.
      – jarlh
      Nov 20 at 13:25




















    • Might want to consider case too - e.g. UPPER or LOWER on both your string and search-term (in this case postcode)
      – doublesidedstickytape
      Nov 20 at 12:15






    • 1




      @doublesidedstickytape, better to use a case insensitive collation.
      – jarlh
      Nov 20 at 13:25


















    Might want to consider case too - e.g. UPPER or LOWER on both your string and search-term (in this case postcode)
    – doublesidedstickytape
    Nov 20 at 12:15




    Might want to consider case too - e.g. UPPER or LOWER on both your string and search-term (in this case postcode)
    – doublesidedstickytape
    Nov 20 at 12:15




    1




    1




    @doublesidedstickytape, better to use a case insensitive collation.
    – jarlh
    Nov 20 at 13:25






    @doublesidedstickytape, better to use a case insensitive collation.
    – jarlh
    Nov 20 at 13:25














    up vote
    0
    down vote













    Declare @vString nvarchar(50)
    Set @vString = '100Pipers22WoodfieldRoadBlackpoolFY16AX'

    Select Count(*) From tbl_Address Where Zip = right(@vString,6)


    If the select statement returns a value greater than zero, you have a match.






    share|improve this answer

























      up vote
      0
      down vote













      Declare @vString nvarchar(50)
      Set @vString = '100Pipers22WoodfieldRoadBlackpoolFY16AX'

      Select Count(*) From tbl_Address Where Zip = right(@vString,6)


      If the select statement returns a value greater than zero, you have a match.






      share|improve this answer























        up vote
        0
        down vote










        up vote
        0
        down vote









        Declare @vString nvarchar(50)
        Set @vString = '100Pipers22WoodfieldRoadBlackpoolFY16AX'

        Select Count(*) From tbl_Address Where Zip = right(@vString,6)


        If the select statement returns a value greater than zero, you have a match.






        share|improve this answer












        Declare @vString nvarchar(50)
        Set @vString = '100Pipers22WoodfieldRoadBlackpoolFY16AX'

        Select Count(*) From tbl_Address Where Zip = right(@vString,6)


        If the select statement returns a value greater than zero, you have a match.







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 20 at 15:35









        level3looper

        1745




        1745






























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