SPARQL: Find all artist living in the same city












0















How do I select all artists (or all x) living in the same city (or y) if the city (y) is not specified?



I just tried to query it like (generic example):



    SELECT ?x1 ?x2 ?y1
WHERE {
?x1 :livesIn ?y1.
OPTIONAL {?x2 :livesIn ?y2.}
FILTER(?y1 = ?y2)
}









share|improve this question




















  • 1





    And what does not work? Why not using the same variable y for both x1 and x2. Moreover, you should omit same x_i: SELECT ?x1 ?x2 ?y1 WHERE { ?x1 :livesIn ?y1. ?x2 :livesIn ?y1. FILTER(?x1 != ?x2) - I don't know what you mean by "if the city is unknown" - in that case no comparison is possible, or not?

    – AKSW
    Nov 22 '18 at 17:35


















0















How do I select all artists (or all x) living in the same city (or y) if the city (y) is not specified?



I just tried to query it like (generic example):



    SELECT ?x1 ?x2 ?y1
WHERE {
?x1 :livesIn ?y1.
OPTIONAL {?x2 :livesIn ?y2.}
FILTER(?y1 = ?y2)
}









share|improve this question




















  • 1





    And what does not work? Why not using the same variable y for both x1 and x2. Moreover, you should omit same x_i: SELECT ?x1 ?x2 ?y1 WHERE { ?x1 :livesIn ?y1. ?x2 :livesIn ?y1. FILTER(?x1 != ?x2) - I don't know what you mean by "if the city is unknown" - in that case no comparison is possible, or not?

    – AKSW
    Nov 22 '18 at 17:35
















0












0








0








How do I select all artists (or all x) living in the same city (or y) if the city (y) is not specified?



I just tried to query it like (generic example):



    SELECT ?x1 ?x2 ?y1
WHERE {
?x1 :livesIn ?y1.
OPTIONAL {?x2 :livesIn ?y2.}
FILTER(?y1 = ?y2)
}









share|improve this question
















How do I select all artists (or all x) living in the same city (or y) if the city (y) is not specified?



I just tried to query it like (generic example):



    SELECT ?x1 ?x2 ?y1
WHERE {
?x1 :livesIn ?y1.
OPTIONAL {?x2 :livesIn ?y2.}
FILTER(?y1 = ?y2)
}






filter sparql






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 23 '18 at 4:41









Skynet

4,32452640




4,32452640










asked Nov 22 '18 at 14:40









ChrisiDChrisiD

183




183








  • 1





    And what does not work? Why not using the same variable y for both x1 and x2. Moreover, you should omit same x_i: SELECT ?x1 ?x2 ?y1 WHERE { ?x1 :livesIn ?y1. ?x2 :livesIn ?y1. FILTER(?x1 != ?x2) - I don't know what you mean by "if the city is unknown" - in that case no comparison is possible, or not?

    – AKSW
    Nov 22 '18 at 17:35
















  • 1





    And what does not work? Why not using the same variable y for both x1 and x2. Moreover, you should omit same x_i: SELECT ?x1 ?x2 ?y1 WHERE { ?x1 :livesIn ?y1. ?x2 :livesIn ?y1. FILTER(?x1 != ?x2) - I don't know what you mean by "if the city is unknown" - in that case no comparison is possible, or not?

    – AKSW
    Nov 22 '18 at 17:35










1




1





And what does not work? Why not using the same variable y for both x1 and x2. Moreover, you should omit same x_i: SELECT ?x1 ?x2 ?y1 WHERE { ?x1 :livesIn ?y1. ?x2 :livesIn ?y1. FILTER(?x1 != ?x2) - I don't know what you mean by "if the city is unknown" - in that case no comparison is possible, or not?

– AKSW
Nov 22 '18 at 17:35







And what does not work? Why not using the same variable y for both x1 and x2. Moreover, you should omit same x_i: SELECT ?x1 ?x2 ?y1 WHERE { ?x1 :livesIn ?y1. ?x2 :livesIn ?y1. FILTER(?x1 != ?x2) - I don't know what you mean by "if the city is unknown" - in that case no comparison is possible, or not?

– AKSW
Nov 22 '18 at 17:35














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