How to pass form data using jquery Ajax to insert data in database?












1















I have 4 tables namely stud, country_master_academic,master_state and master_city.
The main problem is that my form consists of many different fields like textbox, radio buttons, dropdown and an image file, so i am getting really confused.
I can't insert data in database. Please help me. I tried many times but its not working. Thanks for the help in advance.
Modal in home.php page



 <div class="container">
<div class="modal fade" id="add_data_modal" role="dialog">
<div class="modal-dialog">
<div class="modal-content">
<div class="modal-heading" style="margin-top:30px;text-align:center">
<button class="close" data-dismiss="modal" style="margin-right:20px;font-weight:bold;">x</button>
<h4 class="modal-title"><span class="glyphicon glyphicon-user"></span> Add Student</h4>
</div>
<div class="modal-body">
<div class="form-group">
<form class="form-horizontal" name="form" id="form" method="post" action="<?php $_PHP_SELF?>" enctype="multipart/form-data">
<label for="name" id="name"><span class="glyphicon glyphicon-user"></span><b> Student Name: </b></label><label id="p1">*</label>
<input type="text" class="form-control" name="name" id="name" pattern="[a-zA-Z]{3,}" title="Name should only contain letters and atleast 3 letters" required />
</div>
<div class="form-group">
<label for="no"><span class="glyphicon glyphicon-phone"></span><b> Mobile No: </b></label><label id="p2">*</label>
<input type="text" class="form-control" name="mob_no" id="mob_no" pattern="[0-9]{10}" title="Mobile number should be of 10 digits" required />
</div>
<div class="form-group">
<label for="dob"><span class="glyphicon glyphicon-calendar"></span><b> Birth Date: </b></label><label id="p3">*</label>
<input type="date" class="form-control" name="dob" required />
</div>
<div class="form-group">
<label for="add"><span class="glyphicon glyphicon-map-marker"></span><b> Address: </b></label><label id="p4">*</label>
<textarea rows="4" cols="33" class="form-control" name="add" id="add" required></textarea>
</div>
<div class="form-group">
<label for="photo"><span class="glyphicon glyphicon-camera"></span><b> Photo: </b></label><label id="p5">*</label>
<input type="file" name="photo" id="photo" required />
</div>
<div class="form-group">
<label for="gen"><b> Gender: </b></label><label id="p6">*</label><br/>
<input type="radio" name="gender" id="gender" value="M" required="required">Male
<input type="radio" name="gender" id="gender" value="F" required="required">Female
</div>
<div class="form-group">
<label for="cntry"><span class="glyphicon glyphicon-map-marker"></span><b> Country: </b></label><label id="p7"> *</label>
<?php
$country="SELECT * from country_master_academic";
$res= $conn->query($country);
if($res->num_rows>0)
{
echo '<select name="country" id="country" class="form-control" required>';
echo '<option value="">Select</option>';
while($row=$res->fetch_assoc())
{
echo '<option value='.$row["country_code"].'>'.$row['country_name'].'</option>';
}
echo '</select>';
} else {
echo "0 result";
}
?>

</div>
<div class="form-group">
<label for="state"><span class="glyphicon glyphicon-map-marker"></span><b> State: </b></label><label id="p8">*</label>
<?php
$state = "SELECT * from master_state";
$res=$conn->query($state);
if($res->num_rows>0)
{
echo '<select name="state" id="state" class="form-control" required>';
echo '<option value="">Select</option>';
while($row=$res->fetch_assoc())
{
echo '<option value='.$row["state_code"].'>'.$row["state_name"].'</option>';
}
echo '</select>';
} else {
echo "0 result";
}
?>
</div>
<div class="form-group">
<label for="city"><span class="glyphicon glyphicon-map-marker"></span><b> City: </b></label><label id="p9">*</label>
<?php
$city="SELECT * from master_city";
$res=$conn->query($city);
if($res->num_rows>0)
{
echo '<select name="city" id="city" class="form-control" required>';
echo '<option value="">Select</option>';
while($row=$res->fetch_assoc())
{
echo '<option value='.$row["city_code"].'>'.$row["city_name"].'</option>';
}
echo '</select>';
} else {
echo "0 result";
}
?>
</div>

<div class="form-group">
<button type="submit" name="save" id="save" class="btn btn-info" onclick="validate()">Save</button>
</div>
</form>
</div>
<div class="modal-footer">
<button class="btn btn-danger" type="button" data-dismiss="modal">Close</button>
</div>
</div>
</div>
</div>


My jquery in home page



    $('.insert_data').click(function(){
var vname = $("#name").val();
var vmob = $("#mob_no").val();
var vdob = $("#dob").val();
var vadd = $("#add").val();
var vphoto = $("#photo").val();
var vgender = $("#gender").val();
var vcountry = $("#country").val();
var vstate = $("#state").val();
var vcity = $("#city").val();

$.ajax({
url:"insert.php",
method:"post",
data: {
name:vname,
mob_no:vmob,
dob:vdob,
add:vadd,
photo:vphoto,
gender:vgender,
country:vcountry,
state:vstate,
city:vcity
},
success: function(data){
$('#form')[0].reset();
$('#add_data_Modal').modal('hide');
$('#stud_insert').html(data);
}
});
});


my insert.php page



<?php
include("connection.php");
if(!empty($_POST))
{
$output = '';
$name = $_POST['name']);
$mob = $_POST['mob_no']);
$dob = $_POST['dob']);
$add = $_POST['add']);
$photo = $_FILES['photo']['name']);
$gender = $_POST['gender']);
$cn = $_POST['country']);
$st = $_POST['state']);
$ct = $_POST['city']);

$qrycn= mysqli_query($conn,"select country_code from country_master_academic where country_name=' ".$cn." ' ");
$row = mysqli_fetch_array($qrycn);
$country = $row['country_code'];

$qryst=mysqli_query($conn,"select state_code from master_state where state_name='".$st."'");
$row = mysqli_fetch_array($qryst);
$state = $row['state_code'];

$qryct= mysqli_query($conn,"select city_code from master_city where city_name='".$ct."'");
$row = mysqli_fetch_array($qryct);
$city = $row['city_code'];

$query = "INSERT INTO stud (stud_name, mobile, dob,address,photo,gender,country,state,city) VALUES('$name', '$mob', '$dob', '$add', '$photo', '$gender', '$country', '$state', '$city')";
if (mysqli_query($conn, $query)) {

$target_dir="images/";
$target_file=$target_dir.basename($_FILES["photo"]["name"]);
$imageFileType=pathinfo($target_file,PATHINFO_EXTENSION);
if(move_uploaded_file($_FILES["photo"]["tmp_name"],$target_file)){
echo '<script language="javascript">';
echo 'alert("Image and data Inserted Successfully")';
echo '</script>';
} else {
echo '<script language="javascript">';
echo 'alert("Cannot upload")';
echo '</script>';
}
}
else {
echo '<script language="javascript">';
echo 'alert("Cannot insert record")';
echo '</script>';
}
$output .= '<label class="text-success">Data Inserted</label>';
$output .= '
<table class="table table-bordered">
<tr>
<th>No</th>
<th>Name</th>
<th>Mobile</th>
<th>Birthdate</th>
<th>Address</th>
<th>Photo</th>
<th>Gender</th>
<th>Country</th>
<th>State</th>
<th>City</th>
</tr>

';
$result= mysqli_query($conn,"select * from stud s, country_master_academic c, master_state st, master_city ct where s.country=c.country_code and s.state=st.state_code and s.city=ct.city_code");
while($row = mysqli_fetch_array($result))
{
$output .= '
<tr>
<td><a href="update.php?no='.$row["stud_no"].'"><button name="edit" value="Edit" style="font-weight:bold;" class="btn btn-warning"><span class="glyphicon glyphicon-edit"></span> Edit</button></a></td>
<td><button type="submit" style="font-weight:bold;" name="delete" id='.$row["stud_no"].' class="btn btn-danger delete_data"><span class="glyphicon glyphicon-trash"></span> Delete</button></td>
<td><button type="submit" style="font-weight:bold;" name="view" id='.$row["stud_no"].' class="btn btn-success view_data" data-target="#modalDelete" data-toggle="modal"><span class="glyphicon glyphicon-user"></span> View</button></td>

</tr>
';
}
$output .= '</table>';
}
echo $output;
}


?>










share|improve this question

























  • So do you get any errors? What part doesn't work? At first glance your code seems like it should work.

    – Dirk Scholten
    Nov 22 '18 at 10:03











  • what you mean from 'not working'? Do you get any error in console? Script error or PHP error? no error?

    – Ali Sheikhpour
    Nov 22 '18 at 10:03













  • @DirkScholten no sir... It's not showing any errors..

    – Jaicy Joseph
    Nov 22 '18 at 10:07











  • @AliSheikhpour no errors... Just after i click on save , modal gets closed

    – Jaicy Joseph
    Nov 22 '18 at 10:08











  • Data is not getting inserted, I think problem with my jquery or i am not inserting properly

    – Jaicy Joseph
    Nov 22 '18 at 10:08


















1















I have 4 tables namely stud, country_master_academic,master_state and master_city.
The main problem is that my form consists of many different fields like textbox, radio buttons, dropdown and an image file, so i am getting really confused.
I can't insert data in database. Please help me. I tried many times but its not working. Thanks for the help in advance.
Modal in home.php page



 <div class="container">
<div class="modal fade" id="add_data_modal" role="dialog">
<div class="modal-dialog">
<div class="modal-content">
<div class="modal-heading" style="margin-top:30px;text-align:center">
<button class="close" data-dismiss="modal" style="margin-right:20px;font-weight:bold;">x</button>
<h4 class="modal-title"><span class="glyphicon glyphicon-user"></span> Add Student</h4>
</div>
<div class="modal-body">
<div class="form-group">
<form class="form-horizontal" name="form" id="form" method="post" action="<?php $_PHP_SELF?>" enctype="multipart/form-data">
<label for="name" id="name"><span class="glyphicon glyphicon-user"></span><b> Student Name: </b></label><label id="p1">*</label>
<input type="text" class="form-control" name="name" id="name" pattern="[a-zA-Z]{3,}" title="Name should only contain letters and atleast 3 letters" required />
</div>
<div class="form-group">
<label for="no"><span class="glyphicon glyphicon-phone"></span><b> Mobile No: </b></label><label id="p2">*</label>
<input type="text" class="form-control" name="mob_no" id="mob_no" pattern="[0-9]{10}" title="Mobile number should be of 10 digits" required />
</div>
<div class="form-group">
<label for="dob"><span class="glyphicon glyphicon-calendar"></span><b> Birth Date: </b></label><label id="p3">*</label>
<input type="date" class="form-control" name="dob" required />
</div>
<div class="form-group">
<label for="add"><span class="glyphicon glyphicon-map-marker"></span><b> Address: </b></label><label id="p4">*</label>
<textarea rows="4" cols="33" class="form-control" name="add" id="add" required></textarea>
</div>
<div class="form-group">
<label for="photo"><span class="glyphicon glyphicon-camera"></span><b> Photo: </b></label><label id="p5">*</label>
<input type="file" name="photo" id="photo" required />
</div>
<div class="form-group">
<label for="gen"><b> Gender: </b></label><label id="p6">*</label><br/>
<input type="radio" name="gender" id="gender" value="M" required="required">Male
<input type="radio" name="gender" id="gender" value="F" required="required">Female
</div>
<div class="form-group">
<label for="cntry"><span class="glyphicon glyphicon-map-marker"></span><b> Country: </b></label><label id="p7"> *</label>
<?php
$country="SELECT * from country_master_academic";
$res= $conn->query($country);
if($res->num_rows>0)
{
echo '<select name="country" id="country" class="form-control" required>';
echo '<option value="">Select</option>';
while($row=$res->fetch_assoc())
{
echo '<option value='.$row["country_code"].'>'.$row['country_name'].'</option>';
}
echo '</select>';
} else {
echo "0 result";
}
?>

</div>
<div class="form-group">
<label for="state"><span class="glyphicon glyphicon-map-marker"></span><b> State: </b></label><label id="p8">*</label>
<?php
$state = "SELECT * from master_state";
$res=$conn->query($state);
if($res->num_rows>0)
{
echo '<select name="state" id="state" class="form-control" required>';
echo '<option value="">Select</option>';
while($row=$res->fetch_assoc())
{
echo '<option value='.$row["state_code"].'>'.$row["state_name"].'</option>';
}
echo '</select>';
} else {
echo "0 result";
}
?>
</div>
<div class="form-group">
<label for="city"><span class="glyphicon glyphicon-map-marker"></span><b> City: </b></label><label id="p9">*</label>
<?php
$city="SELECT * from master_city";
$res=$conn->query($city);
if($res->num_rows>0)
{
echo '<select name="city" id="city" class="form-control" required>';
echo '<option value="">Select</option>';
while($row=$res->fetch_assoc())
{
echo '<option value='.$row["city_code"].'>'.$row["city_name"].'</option>';
}
echo '</select>';
} else {
echo "0 result";
}
?>
</div>

<div class="form-group">
<button type="submit" name="save" id="save" class="btn btn-info" onclick="validate()">Save</button>
</div>
</form>
</div>
<div class="modal-footer">
<button class="btn btn-danger" type="button" data-dismiss="modal">Close</button>
</div>
</div>
</div>
</div>


My jquery in home page



    $('.insert_data').click(function(){
var vname = $("#name").val();
var vmob = $("#mob_no").val();
var vdob = $("#dob").val();
var vadd = $("#add").val();
var vphoto = $("#photo").val();
var vgender = $("#gender").val();
var vcountry = $("#country").val();
var vstate = $("#state").val();
var vcity = $("#city").val();

$.ajax({
url:"insert.php",
method:"post",
data: {
name:vname,
mob_no:vmob,
dob:vdob,
add:vadd,
photo:vphoto,
gender:vgender,
country:vcountry,
state:vstate,
city:vcity
},
success: function(data){
$('#form')[0].reset();
$('#add_data_Modal').modal('hide');
$('#stud_insert').html(data);
}
});
});


my insert.php page



<?php
include("connection.php");
if(!empty($_POST))
{
$output = '';
$name = $_POST['name']);
$mob = $_POST['mob_no']);
$dob = $_POST['dob']);
$add = $_POST['add']);
$photo = $_FILES['photo']['name']);
$gender = $_POST['gender']);
$cn = $_POST['country']);
$st = $_POST['state']);
$ct = $_POST['city']);

$qrycn= mysqli_query($conn,"select country_code from country_master_academic where country_name=' ".$cn." ' ");
$row = mysqli_fetch_array($qrycn);
$country = $row['country_code'];

$qryst=mysqli_query($conn,"select state_code from master_state where state_name='".$st."'");
$row = mysqli_fetch_array($qryst);
$state = $row['state_code'];

$qryct= mysqli_query($conn,"select city_code from master_city where city_name='".$ct."'");
$row = mysqli_fetch_array($qryct);
$city = $row['city_code'];

$query = "INSERT INTO stud (stud_name, mobile, dob,address,photo,gender,country,state,city) VALUES('$name', '$mob', '$dob', '$add', '$photo', '$gender', '$country', '$state', '$city')";
if (mysqli_query($conn, $query)) {

$target_dir="images/";
$target_file=$target_dir.basename($_FILES["photo"]["name"]);
$imageFileType=pathinfo($target_file,PATHINFO_EXTENSION);
if(move_uploaded_file($_FILES["photo"]["tmp_name"],$target_file)){
echo '<script language="javascript">';
echo 'alert("Image and data Inserted Successfully")';
echo '</script>';
} else {
echo '<script language="javascript">';
echo 'alert("Cannot upload")';
echo '</script>';
}
}
else {
echo '<script language="javascript">';
echo 'alert("Cannot insert record")';
echo '</script>';
}
$output .= '<label class="text-success">Data Inserted</label>';
$output .= '
<table class="table table-bordered">
<tr>
<th>No</th>
<th>Name</th>
<th>Mobile</th>
<th>Birthdate</th>
<th>Address</th>
<th>Photo</th>
<th>Gender</th>
<th>Country</th>
<th>State</th>
<th>City</th>
</tr>

';
$result= mysqli_query($conn,"select * from stud s, country_master_academic c, master_state st, master_city ct where s.country=c.country_code and s.state=st.state_code and s.city=ct.city_code");
while($row = mysqli_fetch_array($result))
{
$output .= '
<tr>
<td><a href="update.php?no='.$row["stud_no"].'"><button name="edit" value="Edit" style="font-weight:bold;" class="btn btn-warning"><span class="glyphicon glyphicon-edit"></span> Edit</button></a></td>
<td><button type="submit" style="font-weight:bold;" name="delete" id='.$row["stud_no"].' class="btn btn-danger delete_data"><span class="glyphicon glyphicon-trash"></span> Delete</button></td>
<td><button type="submit" style="font-weight:bold;" name="view" id='.$row["stud_no"].' class="btn btn-success view_data" data-target="#modalDelete" data-toggle="modal"><span class="glyphicon glyphicon-user"></span> View</button></td>

</tr>
';
}
$output .= '</table>';
}
echo $output;
}


?>










share|improve this question

























  • So do you get any errors? What part doesn't work? At first glance your code seems like it should work.

    – Dirk Scholten
    Nov 22 '18 at 10:03











  • what you mean from 'not working'? Do you get any error in console? Script error or PHP error? no error?

    – Ali Sheikhpour
    Nov 22 '18 at 10:03













  • @DirkScholten no sir... It's not showing any errors..

    – Jaicy Joseph
    Nov 22 '18 at 10:07











  • @AliSheikhpour no errors... Just after i click on save , modal gets closed

    – Jaicy Joseph
    Nov 22 '18 at 10:08











  • Data is not getting inserted, I think problem with my jquery or i am not inserting properly

    – Jaicy Joseph
    Nov 22 '18 at 10:08
















1












1








1








I have 4 tables namely stud, country_master_academic,master_state and master_city.
The main problem is that my form consists of many different fields like textbox, radio buttons, dropdown and an image file, so i am getting really confused.
I can't insert data in database. Please help me. I tried many times but its not working. Thanks for the help in advance.
Modal in home.php page



 <div class="container">
<div class="modal fade" id="add_data_modal" role="dialog">
<div class="modal-dialog">
<div class="modal-content">
<div class="modal-heading" style="margin-top:30px;text-align:center">
<button class="close" data-dismiss="modal" style="margin-right:20px;font-weight:bold;">x</button>
<h4 class="modal-title"><span class="glyphicon glyphicon-user"></span> Add Student</h4>
</div>
<div class="modal-body">
<div class="form-group">
<form class="form-horizontal" name="form" id="form" method="post" action="<?php $_PHP_SELF?>" enctype="multipart/form-data">
<label for="name" id="name"><span class="glyphicon glyphicon-user"></span><b> Student Name: </b></label><label id="p1">*</label>
<input type="text" class="form-control" name="name" id="name" pattern="[a-zA-Z]{3,}" title="Name should only contain letters and atleast 3 letters" required />
</div>
<div class="form-group">
<label for="no"><span class="glyphicon glyphicon-phone"></span><b> Mobile No: </b></label><label id="p2">*</label>
<input type="text" class="form-control" name="mob_no" id="mob_no" pattern="[0-9]{10}" title="Mobile number should be of 10 digits" required />
</div>
<div class="form-group">
<label for="dob"><span class="glyphicon glyphicon-calendar"></span><b> Birth Date: </b></label><label id="p3">*</label>
<input type="date" class="form-control" name="dob" required />
</div>
<div class="form-group">
<label for="add"><span class="glyphicon glyphicon-map-marker"></span><b> Address: </b></label><label id="p4">*</label>
<textarea rows="4" cols="33" class="form-control" name="add" id="add" required></textarea>
</div>
<div class="form-group">
<label for="photo"><span class="glyphicon glyphicon-camera"></span><b> Photo: </b></label><label id="p5">*</label>
<input type="file" name="photo" id="photo" required />
</div>
<div class="form-group">
<label for="gen"><b> Gender: </b></label><label id="p6">*</label><br/>
<input type="radio" name="gender" id="gender" value="M" required="required">Male
<input type="radio" name="gender" id="gender" value="F" required="required">Female
</div>
<div class="form-group">
<label for="cntry"><span class="glyphicon glyphicon-map-marker"></span><b> Country: </b></label><label id="p7"> *</label>
<?php
$country="SELECT * from country_master_academic";
$res= $conn->query($country);
if($res->num_rows>0)
{
echo '<select name="country" id="country" class="form-control" required>';
echo '<option value="">Select</option>';
while($row=$res->fetch_assoc())
{
echo '<option value='.$row["country_code"].'>'.$row['country_name'].'</option>';
}
echo '</select>';
} else {
echo "0 result";
}
?>

</div>
<div class="form-group">
<label for="state"><span class="glyphicon glyphicon-map-marker"></span><b> State: </b></label><label id="p8">*</label>
<?php
$state = "SELECT * from master_state";
$res=$conn->query($state);
if($res->num_rows>0)
{
echo '<select name="state" id="state" class="form-control" required>';
echo '<option value="">Select</option>';
while($row=$res->fetch_assoc())
{
echo '<option value='.$row["state_code"].'>'.$row["state_name"].'</option>';
}
echo '</select>';
} else {
echo "0 result";
}
?>
</div>
<div class="form-group">
<label for="city"><span class="glyphicon glyphicon-map-marker"></span><b> City: </b></label><label id="p9">*</label>
<?php
$city="SELECT * from master_city";
$res=$conn->query($city);
if($res->num_rows>0)
{
echo '<select name="city" id="city" class="form-control" required>';
echo '<option value="">Select</option>';
while($row=$res->fetch_assoc())
{
echo '<option value='.$row["city_code"].'>'.$row["city_name"].'</option>';
}
echo '</select>';
} else {
echo "0 result";
}
?>
</div>

<div class="form-group">
<button type="submit" name="save" id="save" class="btn btn-info" onclick="validate()">Save</button>
</div>
</form>
</div>
<div class="modal-footer">
<button class="btn btn-danger" type="button" data-dismiss="modal">Close</button>
</div>
</div>
</div>
</div>


My jquery in home page



    $('.insert_data').click(function(){
var vname = $("#name").val();
var vmob = $("#mob_no").val();
var vdob = $("#dob").val();
var vadd = $("#add").val();
var vphoto = $("#photo").val();
var vgender = $("#gender").val();
var vcountry = $("#country").val();
var vstate = $("#state").val();
var vcity = $("#city").val();

$.ajax({
url:"insert.php",
method:"post",
data: {
name:vname,
mob_no:vmob,
dob:vdob,
add:vadd,
photo:vphoto,
gender:vgender,
country:vcountry,
state:vstate,
city:vcity
},
success: function(data){
$('#form')[0].reset();
$('#add_data_Modal').modal('hide');
$('#stud_insert').html(data);
}
});
});


my insert.php page



<?php
include("connection.php");
if(!empty($_POST))
{
$output = '';
$name = $_POST['name']);
$mob = $_POST['mob_no']);
$dob = $_POST['dob']);
$add = $_POST['add']);
$photo = $_FILES['photo']['name']);
$gender = $_POST['gender']);
$cn = $_POST['country']);
$st = $_POST['state']);
$ct = $_POST['city']);

$qrycn= mysqli_query($conn,"select country_code from country_master_academic where country_name=' ".$cn." ' ");
$row = mysqli_fetch_array($qrycn);
$country = $row['country_code'];

$qryst=mysqli_query($conn,"select state_code from master_state where state_name='".$st."'");
$row = mysqli_fetch_array($qryst);
$state = $row['state_code'];

$qryct= mysqli_query($conn,"select city_code from master_city where city_name='".$ct."'");
$row = mysqli_fetch_array($qryct);
$city = $row['city_code'];

$query = "INSERT INTO stud (stud_name, mobile, dob,address,photo,gender,country,state,city) VALUES('$name', '$mob', '$dob', '$add', '$photo', '$gender', '$country', '$state', '$city')";
if (mysqli_query($conn, $query)) {

$target_dir="images/";
$target_file=$target_dir.basename($_FILES["photo"]["name"]);
$imageFileType=pathinfo($target_file,PATHINFO_EXTENSION);
if(move_uploaded_file($_FILES["photo"]["tmp_name"],$target_file)){
echo '<script language="javascript">';
echo 'alert("Image and data Inserted Successfully")';
echo '</script>';
} else {
echo '<script language="javascript">';
echo 'alert("Cannot upload")';
echo '</script>';
}
}
else {
echo '<script language="javascript">';
echo 'alert("Cannot insert record")';
echo '</script>';
}
$output .= '<label class="text-success">Data Inserted</label>';
$output .= '
<table class="table table-bordered">
<tr>
<th>No</th>
<th>Name</th>
<th>Mobile</th>
<th>Birthdate</th>
<th>Address</th>
<th>Photo</th>
<th>Gender</th>
<th>Country</th>
<th>State</th>
<th>City</th>
</tr>

';
$result= mysqli_query($conn,"select * from stud s, country_master_academic c, master_state st, master_city ct where s.country=c.country_code and s.state=st.state_code and s.city=ct.city_code");
while($row = mysqli_fetch_array($result))
{
$output .= '
<tr>
<td><a href="update.php?no='.$row["stud_no"].'"><button name="edit" value="Edit" style="font-weight:bold;" class="btn btn-warning"><span class="glyphicon glyphicon-edit"></span> Edit</button></a></td>
<td><button type="submit" style="font-weight:bold;" name="delete" id='.$row["stud_no"].' class="btn btn-danger delete_data"><span class="glyphicon glyphicon-trash"></span> Delete</button></td>
<td><button type="submit" style="font-weight:bold;" name="view" id='.$row["stud_no"].' class="btn btn-success view_data" data-target="#modalDelete" data-toggle="modal"><span class="glyphicon glyphicon-user"></span> View</button></td>

</tr>
';
}
$output .= '</table>';
}
echo $output;
}


?>










share|improve this question
















I have 4 tables namely stud, country_master_academic,master_state and master_city.
The main problem is that my form consists of many different fields like textbox, radio buttons, dropdown and an image file, so i am getting really confused.
I can't insert data in database. Please help me. I tried many times but its not working. Thanks for the help in advance.
Modal in home.php page



 <div class="container">
<div class="modal fade" id="add_data_modal" role="dialog">
<div class="modal-dialog">
<div class="modal-content">
<div class="modal-heading" style="margin-top:30px;text-align:center">
<button class="close" data-dismiss="modal" style="margin-right:20px;font-weight:bold;">x</button>
<h4 class="modal-title"><span class="glyphicon glyphicon-user"></span> Add Student</h4>
</div>
<div class="modal-body">
<div class="form-group">
<form class="form-horizontal" name="form" id="form" method="post" action="<?php $_PHP_SELF?>" enctype="multipart/form-data">
<label for="name" id="name"><span class="glyphicon glyphicon-user"></span><b> Student Name: </b></label><label id="p1">*</label>
<input type="text" class="form-control" name="name" id="name" pattern="[a-zA-Z]{3,}" title="Name should only contain letters and atleast 3 letters" required />
</div>
<div class="form-group">
<label for="no"><span class="glyphicon glyphicon-phone"></span><b> Mobile No: </b></label><label id="p2">*</label>
<input type="text" class="form-control" name="mob_no" id="mob_no" pattern="[0-9]{10}" title="Mobile number should be of 10 digits" required />
</div>
<div class="form-group">
<label for="dob"><span class="glyphicon glyphicon-calendar"></span><b> Birth Date: </b></label><label id="p3">*</label>
<input type="date" class="form-control" name="dob" required />
</div>
<div class="form-group">
<label for="add"><span class="glyphicon glyphicon-map-marker"></span><b> Address: </b></label><label id="p4">*</label>
<textarea rows="4" cols="33" class="form-control" name="add" id="add" required></textarea>
</div>
<div class="form-group">
<label for="photo"><span class="glyphicon glyphicon-camera"></span><b> Photo: </b></label><label id="p5">*</label>
<input type="file" name="photo" id="photo" required />
</div>
<div class="form-group">
<label for="gen"><b> Gender: </b></label><label id="p6">*</label><br/>
<input type="radio" name="gender" id="gender" value="M" required="required">Male
<input type="radio" name="gender" id="gender" value="F" required="required">Female
</div>
<div class="form-group">
<label for="cntry"><span class="glyphicon glyphicon-map-marker"></span><b> Country: </b></label><label id="p7"> *</label>
<?php
$country="SELECT * from country_master_academic";
$res= $conn->query($country);
if($res->num_rows>0)
{
echo '<select name="country" id="country" class="form-control" required>';
echo '<option value="">Select</option>';
while($row=$res->fetch_assoc())
{
echo '<option value='.$row["country_code"].'>'.$row['country_name'].'</option>';
}
echo '</select>';
} else {
echo "0 result";
}
?>

</div>
<div class="form-group">
<label for="state"><span class="glyphicon glyphicon-map-marker"></span><b> State: </b></label><label id="p8">*</label>
<?php
$state = "SELECT * from master_state";
$res=$conn->query($state);
if($res->num_rows>0)
{
echo '<select name="state" id="state" class="form-control" required>';
echo '<option value="">Select</option>';
while($row=$res->fetch_assoc())
{
echo '<option value='.$row["state_code"].'>'.$row["state_name"].'</option>';
}
echo '</select>';
} else {
echo "0 result";
}
?>
</div>
<div class="form-group">
<label for="city"><span class="glyphicon glyphicon-map-marker"></span><b> City: </b></label><label id="p9">*</label>
<?php
$city="SELECT * from master_city";
$res=$conn->query($city);
if($res->num_rows>0)
{
echo '<select name="city" id="city" class="form-control" required>';
echo '<option value="">Select</option>';
while($row=$res->fetch_assoc())
{
echo '<option value='.$row["city_code"].'>'.$row["city_name"].'</option>';
}
echo '</select>';
} else {
echo "0 result";
}
?>
</div>

<div class="form-group">
<button type="submit" name="save" id="save" class="btn btn-info" onclick="validate()">Save</button>
</div>
</form>
</div>
<div class="modal-footer">
<button class="btn btn-danger" type="button" data-dismiss="modal">Close</button>
</div>
</div>
</div>
</div>


My jquery in home page



    $('.insert_data').click(function(){
var vname = $("#name").val();
var vmob = $("#mob_no").val();
var vdob = $("#dob").val();
var vadd = $("#add").val();
var vphoto = $("#photo").val();
var vgender = $("#gender").val();
var vcountry = $("#country").val();
var vstate = $("#state").val();
var vcity = $("#city").val();

$.ajax({
url:"insert.php",
method:"post",
data: {
name:vname,
mob_no:vmob,
dob:vdob,
add:vadd,
photo:vphoto,
gender:vgender,
country:vcountry,
state:vstate,
city:vcity
},
success: function(data){
$('#form')[0].reset();
$('#add_data_Modal').modal('hide');
$('#stud_insert').html(data);
}
});
});


my insert.php page



<?php
include("connection.php");
if(!empty($_POST))
{
$output = '';
$name = $_POST['name']);
$mob = $_POST['mob_no']);
$dob = $_POST['dob']);
$add = $_POST['add']);
$photo = $_FILES['photo']['name']);
$gender = $_POST['gender']);
$cn = $_POST['country']);
$st = $_POST['state']);
$ct = $_POST['city']);

$qrycn= mysqli_query($conn,"select country_code from country_master_academic where country_name=' ".$cn." ' ");
$row = mysqli_fetch_array($qrycn);
$country = $row['country_code'];

$qryst=mysqli_query($conn,"select state_code from master_state where state_name='".$st."'");
$row = mysqli_fetch_array($qryst);
$state = $row['state_code'];

$qryct= mysqli_query($conn,"select city_code from master_city where city_name='".$ct."'");
$row = mysqli_fetch_array($qryct);
$city = $row['city_code'];

$query = "INSERT INTO stud (stud_name, mobile, dob,address,photo,gender,country,state,city) VALUES('$name', '$mob', '$dob', '$add', '$photo', '$gender', '$country', '$state', '$city')";
if (mysqli_query($conn, $query)) {

$target_dir="images/";
$target_file=$target_dir.basename($_FILES["photo"]["name"]);
$imageFileType=pathinfo($target_file,PATHINFO_EXTENSION);
if(move_uploaded_file($_FILES["photo"]["tmp_name"],$target_file)){
echo '<script language="javascript">';
echo 'alert("Image and data Inserted Successfully")';
echo '</script>';
} else {
echo '<script language="javascript">';
echo 'alert("Cannot upload")';
echo '</script>';
}
}
else {
echo '<script language="javascript">';
echo 'alert("Cannot insert record")';
echo '</script>';
}
$output .= '<label class="text-success">Data Inserted</label>';
$output .= '
<table class="table table-bordered">
<tr>
<th>No</th>
<th>Name</th>
<th>Mobile</th>
<th>Birthdate</th>
<th>Address</th>
<th>Photo</th>
<th>Gender</th>
<th>Country</th>
<th>State</th>
<th>City</th>
</tr>

';
$result= mysqli_query($conn,"select * from stud s, country_master_academic c, master_state st, master_city ct where s.country=c.country_code and s.state=st.state_code and s.city=ct.city_code");
while($row = mysqli_fetch_array($result))
{
$output .= '
<tr>
<td><a href="update.php?no='.$row["stud_no"].'"><button name="edit" value="Edit" style="font-weight:bold;" class="btn btn-warning"><span class="glyphicon glyphicon-edit"></span> Edit</button></a></td>
<td><button type="submit" style="font-weight:bold;" name="delete" id='.$row["stud_no"].' class="btn btn-danger delete_data"><span class="glyphicon glyphicon-trash"></span> Delete</button></td>
<td><button type="submit" style="font-weight:bold;" name="view" id='.$row["stud_no"].' class="btn btn-success view_data" data-target="#modalDelete" data-toggle="modal"><span class="glyphicon glyphicon-user"></span> View</button></td>

</tr>
';
}
$output .= '</table>';
}
echo $output;
}


?>







php jquery ajax bootstrap-modal






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 22 '18 at 9:56







Jaicy Joseph

















asked Nov 22 '18 at 9:54









Jaicy JosephJaicy Joseph

207




207













  • So do you get any errors? What part doesn't work? At first glance your code seems like it should work.

    – Dirk Scholten
    Nov 22 '18 at 10:03











  • what you mean from 'not working'? Do you get any error in console? Script error or PHP error? no error?

    – Ali Sheikhpour
    Nov 22 '18 at 10:03













  • @DirkScholten no sir... It's not showing any errors..

    – Jaicy Joseph
    Nov 22 '18 at 10:07











  • @AliSheikhpour no errors... Just after i click on save , modal gets closed

    – Jaicy Joseph
    Nov 22 '18 at 10:08











  • Data is not getting inserted, I think problem with my jquery or i am not inserting properly

    – Jaicy Joseph
    Nov 22 '18 at 10:08





















  • So do you get any errors? What part doesn't work? At first glance your code seems like it should work.

    – Dirk Scholten
    Nov 22 '18 at 10:03











  • what you mean from 'not working'? Do you get any error in console? Script error or PHP error? no error?

    – Ali Sheikhpour
    Nov 22 '18 at 10:03













  • @DirkScholten no sir... It's not showing any errors..

    – Jaicy Joseph
    Nov 22 '18 at 10:07











  • @AliSheikhpour no errors... Just after i click on save , modal gets closed

    – Jaicy Joseph
    Nov 22 '18 at 10:08











  • Data is not getting inserted, I think problem with my jquery or i am not inserting properly

    – Jaicy Joseph
    Nov 22 '18 at 10:08



















So do you get any errors? What part doesn't work? At first glance your code seems like it should work.

– Dirk Scholten
Nov 22 '18 at 10:03





So do you get any errors? What part doesn't work? At first glance your code seems like it should work.

– Dirk Scholten
Nov 22 '18 at 10:03













what you mean from 'not working'? Do you get any error in console? Script error or PHP error? no error?

– Ali Sheikhpour
Nov 22 '18 at 10:03







what you mean from 'not working'? Do you get any error in console? Script error or PHP error? no error?

– Ali Sheikhpour
Nov 22 '18 at 10:03















@DirkScholten no sir... It's not showing any errors..

– Jaicy Joseph
Nov 22 '18 at 10:07





@DirkScholten no sir... It's not showing any errors..

– Jaicy Joseph
Nov 22 '18 at 10:07













@AliSheikhpour no errors... Just after i click on save , modal gets closed

– Jaicy Joseph
Nov 22 '18 at 10:08





@AliSheikhpour no errors... Just after i click on save , modal gets closed

– Jaicy Joseph
Nov 22 '18 at 10:08













Data is not getting inserted, I think problem with my jquery or i am not inserting properly

– Jaicy Joseph
Nov 22 '18 at 10:08







Data is not getting inserted, I think problem with my jquery or i am not inserting properly

– Jaicy Joseph
Nov 22 '18 at 10:08














3 Answers
3






active

oldest

votes


















3














Please use your form id submit and get you to form data and pass through ajax and debug with alert(data).



$(document).ready(function(){
$("#form").submit(function(event){
event.preventDefault();
var formData = new FormData(this);
$.ajax({
url: 'insert.php',
type: 'POST',
data: formData,
async: false,
success: function(data) {
alert(data);
},
cache: false,
contentType: false,
processData: false
});
});
});





share|improve this answer
























  • thank u so much, but I want to say one thing, in database i have stored country code, not country name, so while inserting i have to store country code and while displaying it should show country name. Rest all records are getting inserted. Only country,state and city not getting inserted

    – Jaicy Joseph
    Nov 22 '18 at 11:13













  • Please check with the database table stud datatype and length.

    – Subhash Patel
    Nov 22 '18 at 11:22



















2














ok let me list all errors in your html



<label for="name" id="name"><span class="glyphicon glyphicon-user"></span><b> Student Name: </b></label><label id="p1">*</label>


remove id like this



<label for="name"><span class="glyphicon glyphicon-user"></span><b> Student Name: </b></label><label id="p1">*</label>


and add id to this



<input type="date" class="form-control" name="dob" required />


add id



<input type="date" class="form-control" name="dob" id="dob" required />


in your php



$output = '';
$name = $_POST['name']);
$mob = $_POST['mob_no']);
$dob = $_POST['dob']);
$add = $_POST['add']);
$photo = $_FILES['photo']['name']);
$gender = $_POST['gender']);
$cn = $_POST['country']);
$st = $_POST['state']);
$ct = $_POST['city']);


change it to



$output = '';
$name = $_POST['name'];
$mob = $_POST['mob_no'];
$dob = $_POST['dob'];
$add = $_POST['add'];
$photo = $_FILES['photo']['name'];
$gender = $_POST['gender'];
$cn = $_POST['country'];
$st = $_POST['state'];
$ct = $_POST['city'];


then remove



$qrycn= mysqli_query($conn,"select country_code from country_master_academic where country_name=' ".$cn." ' ");
$row = mysqli_fetch_array($qrycn);
$country = $row['country_code'];

$qryst=mysqli_query($conn,"select state_code from master_state where state_name='".$st."'");
$row = mysqli_fetch_array($qryst);
$state = $row['state_code'];

$qryct= mysqli_query($conn,"select city_code from master_city where city_name='".$ct."'");
$row = mysqli_fetch_array($qryct);
$city = $row['city_code'];


and change insert to



$query = "INSERT INTO stud (stud_name, mobile, dob,address,photo,gender,country,state,city) VALUES('$name', '$mob', '$dob', '$add', '$photo', '$gender', '$cn', '$st', '$ct')";


in you js you should use FormData() like this



$('.insert_data').click(function(){
var vname = $("#name").val();
var vmob = $("#mob_no").val();
var vdob = $("#dob").val();
var vadd = $("#add").val();
var vphoto = $("#photo").val();
var vgender = $("#gender").val();
var vcountry = $("#country").val();
var vstate = $("#state").val();
var vcity = $("#city").val();
var fd=new FormData();
fd.append('name',vname);
fd.append('mob_no',vmob);
fd.append('dob',vdob);
fd.append('add',vadd);
fd.append('photo',vphoto);
fd.append('gender',vgender);
fd.append('country',vcountry);
fd.append('state',vstate);
fd.append('city',vcity);
$.ajax({
url:"insert.php",
method:"post",
data: fd,
success: function(data){
$('#form')[0].reset();
$('#add_data_Modal').modal('hide');
$('#stud_insert').html(data);
}
});
});





share|improve this answer


























  • in your insert.php you don't need to search data base for country code, state code or city code because you already pass them to php, so remove the 3 queries and in your insert statement use the post values and save them to database

    – abdulsattar-alkhalaf
    Nov 22 '18 at 11:36











  • $query = "INSERT INTO stud (stud_name, mobile, dob,address,photo,gender,country,state,city) VALUES('$name', '$mob', '$dob', '$add', '$photo', '$gender', '$cn', '$st', '$ct')";

    – abdulsattar-alkhalaf
    Nov 22 '18 at 11:37











  • see the edited post, its working and all data are stored in database

    – abdulsattar-alkhalaf
    Nov 22 '18 at 11:42



















0














New code for Insert:
Thank u every one for helping me.



<?php
include("connection.php");
if(!empty($_POST))
{
$output = '';
$name = $_POST['name'];
$mob = $_POST['mob_no'];
$dob = $_POST['dob'];
$add = $_POST['add'];
$photo = $_FILES['photo']['name'];
$gender = $_POST['gender'];
$cn = $_POST['country'];
$st = $_POST['state'];
$ct = $_POST['city'];

$query = "INSERT INTO stud(stud_name, mobile, dob,address,photo,gender,country,state,city)VALUES('$name', '$mob', '$dob', '$add', '$photo', '$gender', '$cn', '$st', '$ct ')";
if (mysqli_query($conn, $query)) {

$target_dir="images/";
$target_file=$target_dir.basename($_FILES["photo"]["name"]);
$imageFileType=pathinfo($target_file,PATHINFO_EXTENSION);
if(move_uploaded_file($_FILES["photo"]["tmp_name"],$target_file)){
echo '<script language="javascript">';
echo 'alert("Image Inserted Successfully")';
echo '</script>';
} else {
echo '<script language="javascript">';
echo 'alert("Cannot upload")';
echo '</script>';
}
echo '<script language="javascript">';
echo 'alert("Data Inserted Successfully")';
echo '</script>';
}
else {
echo '<script language="javascript">';
echo 'alert("Cannot insert record")';
echo '</script>';
}
}


?>






share|improve this answer

























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    3 Answers
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    3 Answers
    3






    active

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    active

    oldest

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    active

    oldest

    votes









    3














    Please use your form id submit and get you to form data and pass through ajax and debug with alert(data).



    $(document).ready(function(){
    $("#form").submit(function(event){
    event.preventDefault();
    var formData = new FormData(this);
    $.ajax({
    url: 'insert.php',
    type: 'POST',
    data: formData,
    async: false,
    success: function(data) {
    alert(data);
    },
    cache: false,
    contentType: false,
    processData: false
    });
    });
    });





    share|improve this answer
























    • thank u so much, but I want to say one thing, in database i have stored country code, not country name, so while inserting i have to store country code and while displaying it should show country name. Rest all records are getting inserted. Only country,state and city not getting inserted

      – Jaicy Joseph
      Nov 22 '18 at 11:13













    • Please check with the database table stud datatype and length.

      – Subhash Patel
      Nov 22 '18 at 11:22
















    3














    Please use your form id submit and get you to form data and pass through ajax and debug with alert(data).



    $(document).ready(function(){
    $("#form").submit(function(event){
    event.preventDefault();
    var formData = new FormData(this);
    $.ajax({
    url: 'insert.php',
    type: 'POST',
    data: formData,
    async: false,
    success: function(data) {
    alert(data);
    },
    cache: false,
    contentType: false,
    processData: false
    });
    });
    });





    share|improve this answer
























    • thank u so much, but I want to say one thing, in database i have stored country code, not country name, so while inserting i have to store country code and while displaying it should show country name. Rest all records are getting inserted. Only country,state and city not getting inserted

      – Jaicy Joseph
      Nov 22 '18 at 11:13













    • Please check with the database table stud datatype and length.

      – Subhash Patel
      Nov 22 '18 at 11:22














    3












    3








    3







    Please use your form id submit and get you to form data and pass through ajax and debug with alert(data).



    $(document).ready(function(){
    $("#form").submit(function(event){
    event.preventDefault();
    var formData = new FormData(this);
    $.ajax({
    url: 'insert.php',
    type: 'POST',
    data: formData,
    async: false,
    success: function(data) {
    alert(data);
    },
    cache: false,
    contentType: false,
    processData: false
    });
    });
    });





    share|improve this answer













    Please use your form id submit and get you to form data and pass through ajax and debug with alert(data).



    $(document).ready(function(){
    $("#form").submit(function(event){
    event.preventDefault();
    var formData = new FormData(this);
    $.ajax({
    url: 'insert.php',
    type: 'POST',
    data: formData,
    async: false,
    success: function(data) {
    alert(data);
    },
    cache: false,
    contentType: false,
    processData: false
    });
    });
    });






    share|improve this answer












    share|improve this answer



    share|improve this answer










    answered Nov 22 '18 at 10:54









    Subhash PatelSubhash Patel

    1567




    1567













    • thank u so much, but I want to say one thing, in database i have stored country code, not country name, so while inserting i have to store country code and while displaying it should show country name. Rest all records are getting inserted. Only country,state and city not getting inserted

      – Jaicy Joseph
      Nov 22 '18 at 11:13













    • Please check with the database table stud datatype and length.

      – Subhash Patel
      Nov 22 '18 at 11:22



















    • thank u so much, but I want to say one thing, in database i have stored country code, not country name, so while inserting i have to store country code and while displaying it should show country name. Rest all records are getting inserted. Only country,state and city not getting inserted

      – Jaicy Joseph
      Nov 22 '18 at 11:13













    • Please check with the database table stud datatype and length.

      – Subhash Patel
      Nov 22 '18 at 11:22

















    thank u so much, but I want to say one thing, in database i have stored country code, not country name, so while inserting i have to store country code and while displaying it should show country name. Rest all records are getting inserted. Only country,state and city not getting inserted

    – Jaicy Joseph
    Nov 22 '18 at 11:13







    thank u so much, but I want to say one thing, in database i have stored country code, not country name, so while inserting i have to store country code and while displaying it should show country name. Rest all records are getting inserted. Only country,state and city not getting inserted

    – Jaicy Joseph
    Nov 22 '18 at 11:13















    Please check with the database table stud datatype and length.

    – Subhash Patel
    Nov 22 '18 at 11:22





    Please check with the database table stud datatype and length.

    – Subhash Patel
    Nov 22 '18 at 11:22













    2














    ok let me list all errors in your html



    <label for="name" id="name"><span class="glyphicon glyphicon-user"></span><b> Student Name: </b></label><label id="p1">*</label>


    remove id like this



    <label for="name"><span class="glyphicon glyphicon-user"></span><b> Student Name: </b></label><label id="p1">*</label>


    and add id to this



    <input type="date" class="form-control" name="dob" required />


    add id



    <input type="date" class="form-control" name="dob" id="dob" required />


    in your php



    $output = '';
    $name = $_POST['name']);
    $mob = $_POST['mob_no']);
    $dob = $_POST['dob']);
    $add = $_POST['add']);
    $photo = $_FILES['photo']['name']);
    $gender = $_POST['gender']);
    $cn = $_POST['country']);
    $st = $_POST['state']);
    $ct = $_POST['city']);


    change it to



    $output = '';
    $name = $_POST['name'];
    $mob = $_POST['mob_no'];
    $dob = $_POST['dob'];
    $add = $_POST['add'];
    $photo = $_FILES['photo']['name'];
    $gender = $_POST['gender'];
    $cn = $_POST['country'];
    $st = $_POST['state'];
    $ct = $_POST['city'];


    then remove



    $qrycn= mysqli_query($conn,"select country_code from country_master_academic where country_name=' ".$cn." ' ");
    $row = mysqli_fetch_array($qrycn);
    $country = $row['country_code'];

    $qryst=mysqli_query($conn,"select state_code from master_state where state_name='".$st."'");
    $row = mysqli_fetch_array($qryst);
    $state = $row['state_code'];

    $qryct= mysqli_query($conn,"select city_code from master_city where city_name='".$ct."'");
    $row = mysqli_fetch_array($qryct);
    $city = $row['city_code'];


    and change insert to



    $query = "INSERT INTO stud (stud_name, mobile, dob,address,photo,gender,country,state,city) VALUES('$name', '$mob', '$dob', '$add', '$photo', '$gender', '$cn', '$st', '$ct')";


    in you js you should use FormData() like this



    $('.insert_data').click(function(){
    var vname = $("#name").val();
    var vmob = $("#mob_no").val();
    var vdob = $("#dob").val();
    var vadd = $("#add").val();
    var vphoto = $("#photo").val();
    var vgender = $("#gender").val();
    var vcountry = $("#country").val();
    var vstate = $("#state").val();
    var vcity = $("#city").val();
    var fd=new FormData();
    fd.append('name',vname);
    fd.append('mob_no',vmob);
    fd.append('dob',vdob);
    fd.append('add',vadd);
    fd.append('photo',vphoto);
    fd.append('gender',vgender);
    fd.append('country',vcountry);
    fd.append('state',vstate);
    fd.append('city',vcity);
    $.ajax({
    url:"insert.php",
    method:"post",
    data: fd,
    success: function(data){
    $('#form')[0].reset();
    $('#add_data_Modal').modal('hide');
    $('#stud_insert').html(data);
    }
    });
    });





    share|improve this answer


























    • in your insert.php you don't need to search data base for country code, state code or city code because you already pass them to php, so remove the 3 queries and in your insert statement use the post values and save them to database

      – abdulsattar-alkhalaf
      Nov 22 '18 at 11:36











    • $query = "INSERT INTO stud (stud_name, mobile, dob,address,photo,gender,country,state,city) VALUES('$name', '$mob', '$dob', '$add', '$photo', '$gender', '$cn', '$st', '$ct')";

      – abdulsattar-alkhalaf
      Nov 22 '18 at 11:37











    • see the edited post, its working and all data are stored in database

      – abdulsattar-alkhalaf
      Nov 22 '18 at 11:42
















    2














    ok let me list all errors in your html



    <label for="name" id="name"><span class="glyphicon glyphicon-user"></span><b> Student Name: </b></label><label id="p1">*</label>


    remove id like this



    <label for="name"><span class="glyphicon glyphicon-user"></span><b> Student Name: </b></label><label id="p1">*</label>


    and add id to this



    <input type="date" class="form-control" name="dob" required />


    add id



    <input type="date" class="form-control" name="dob" id="dob" required />


    in your php



    $output = '';
    $name = $_POST['name']);
    $mob = $_POST['mob_no']);
    $dob = $_POST['dob']);
    $add = $_POST['add']);
    $photo = $_FILES['photo']['name']);
    $gender = $_POST['gender']);
    $cn = $_POST['country']);
    $st = $_POST['state']);
    $ct = $_POST['city']);


    change it to



    $output = '';
    $name = $_POST['name'];
    $mob = $_POST['mob_no'];
    $dob = $_POST['dob'];
    $add = $_POST['add'];
    $photo = $_FILES['photo']['name'];
    $gender = $_POST['gender'];
    $cn = $_POST['country'];
    $st = $_POST['state'];
    $ct = $_POST['city'];


    then remove



    $qrycn= mysqli_query($conn,"select country_code from country_master_academic where country_name=' ".$cn." ' ");
    $row = mysqli_fetch_array($qrycn);
    $country = $row['country_code'];

    $qryst=mysqli_query($conn,"select state_code from master_state where state_name='".$st."'");
    $row = mysqli_fetch_array($qryst);
    $state = $row['state_code'];

    $qryct= mysqli_query($conn,"select city_code from master_city where city_name='".$ct."'");
    $row = mysqli_fetch_array($qryct);
    $city = $row['city_code'];


    and change insert to



    $query = "INSERT INTO stud (stud_name, mobile, dob,address,photo,gender,country,state,city) VALUES('$name', '$mob', '$dob', '$add', '$photo', '$gender', '$cn', '$st', '$ct')";


    in you js you should use FormData() like this



    $('.insert_data').click(function(){
    var vname = $("#name").val();
    var vmob = $("#mob_no").val();
    var vdob = $("#dob").val();
    var vadd = $("#add").val();
    var vphoto = $("#photo").val();
    var vgender = $("#gender").val();
    var vcountry = $("#country").val();
    var vstate = $("#state").val();
    var vcity = $("#city").val();
    var fd=new FormData();
    fd.append('name',vname);
    fd.append('mob_no',vmob);
    fd.append('dob',vdob);
    fd.append('add',vadd);
    fd.append('photo',vphoto);
    fd.append('gender',vgender);
    fd.append('country',vcountry);
    fd.append('state',vstate);
    fd.append('city',vcity);
    $.ajax({
    url:"insert.php",
    method:"post",
    data: fd,
    success: function(data){
    $('#form')[0].reset();
    $('#add_data_Modal').modal('hide');
    $('#stud_insert').html(data);
    }
    });
    });





    share|improve this answer


























    • in your insert.php you don't need to search data base for country code, state code or city code because you already pass them to php, so remove the 3 queries and in your insert statement use the post values and save them to database

      – abdulsattar-alkhalaf
      Nov 22 '18 at 11:36











    • $query = "INSERT INTO stud (stud_name, mobile, dob,address,photo,gender,country,state,city) VALUES('$name', '$mob', '$dob', '$add', '$photo', '$gender', '$cn', '$st', '$ct')";

      – abdulsattar-alkhalaf
      Nov 22 '18 at 11:37











    • see the edited post, its working and all data are stored in database

      – abdulsattar-alkhalaf
      Nov 22 '18 at 11:42














    2












    2








    2







    ok let me list all errors in your html



    <label for="name" id="name"><span class="glyphicon glyphicon-user"></span><b> Student Name: </b></label><label id="p1">*</label>


    remove id like this



    <label for="name"><span class="glyphicon glyphicon-user"></span><b> Student Name: </b></label><label id="p1">*</label>


    and add id to this



    <input type="date" class="form-control" name="dob" required />


    add id



    <input type="date" class="form-control" name="dob" id="dob" required />


    in your php



    $output = '';
    $name = $_POST['name']);
    $mob = $_POST['mob_no']);
    $dob = $_POST['dob']);
    $add = $_POST['add']);
    $photo = $_FILES['photo']['name']);
    $gender = $_POST['gender']);
    $cn = $_POST['country']);
    $st = $_POST['state']);
    $ct = $_POST['city']);


    change it to



    $output = '';
    $name = $_POST['name'];
    $mob = $_POST['mob_no'];
    $dob = $_POST['dob'];
    $add = $_POST['add'];
    $photo = $_FILES['photo']['name'];
    $gender = $_POST['gender'];
    $cn = $_POST['country'];
    $st = $_POST['state'];
    $ct = $_POST['city'];


    then remove



    $qrycn= mysqli_query($conn,"select country_code from country_master_academic where country_name=' ".$cn." ' ");
    $row = mysqli_fetch_array($qrycn);
    $country = $row['country_code'];

    $qryst=mysqli_query($conn,"select state_code from master_state where state_name='".$st."'");
    $row = mysqli_fetch_array($qryst);
    $state = $row['state_code'];

    $qryct= mysqli_query($conn,"select city_code from master_city where city_name='".$ct."'");
    $row = mysqli_fetch_array($qryct);
    $city = $row['city_code'];


    and change insert to



    $query = "INSERT INTO stud (stud_name, mobile, dob,address,photo,gender,country,state,city) VALUES('$name', '$mob', '$dob', '$add', '$photo', '$gender', '$cn', '$st', '$ct')";


    in you js you should use FormData() like this



    $('.insert_data').click(function(){
    var vname = $("#name").val();
    var vmob = $("#mob_no").val();
    var vdob = $("#dob").val();
    var vadd = $("#add").val();
    var vphoto = $("#photo").val();
    var vgender = $("#gender").val();
    var vcountry = $("#country").val();
    var vstate = $("#state").val();
    var vcity = $("#city").val();
    var fd=new FormData();
    fd.append('name',vname);
    fd.append('mob_no',vmob);
    fd.append('dob',vdob);
    fd.append('add',vadd);
    fd.append('photo',vphoto);
    fd.append('gender',vgender);
    fd.append('country',vcountry);
    fd.append('state',vstate);
    fd.append('city',vcity);
    $.ajax({
    url:"insert.php",
    method:"post",
    data: fd,
    success: function(data){
    $('#form')[0].reset();
    $('#add_data_Modal').modal('hide');
    $('#stud_insert').html(data);
    }
    });
    });





    share|improve this answer















    ok let me list all errors in your html



    <label for="name" id="name"><span class="glyphicon glyphicon-user"></span><b> Student Name: </b></label><label id="p1">*</label>


    remove id like this



    <label for="name"><span class="glyphicon glyphicon-user"></span><b> Student Name: </b></label><label id="p1">*</label>


    and add id to this



    <input type="date" class="form-control" name="dob" required />


    add id



    <input type="date" class="form-control" name="dob" id="dob" required />


    in your php



    $output = '';
    $name = $_POST['name']);
    $mob = $_POST['mob_no']);
    $dob = $_POST['dob']);
    $add = $_POST['add']);
    $photo = $_FILES['photo']['name']);
    $gender = $_POST['gender']);
    $cn = $_POST['country']);
    $st = $_POST['state']);
    $ct = $_POST['city']);


    change it to



    $output = '';
    $name = $_POST['name'];
    $mob = $_POST['mob_no'];
    $dob = $_POST['dob'];
    $add = $_POST['add'];
    $photo = $_FILES['photo']['name'];
    $gender = $_POST['gender'];
    $cn = $_POST['country'];
    $st = $_POST['state'];
    $ct = $_POST['city'];


    then remove



    $qrycn= mysqli_query($conn,"select country_code from country_master_academic where country_name=' ".$cn." ' ");
    $row = mysqli_fetch_array($qrycn);
    $country = $row['country_code'];

    $qryst=mysqli_query($conn,"select state_code from master_state where state_name='".$st."'");
    $row = mysqli_fetch_array($qryst);
    $state = $row['state_code'];

    $qryct= mysqli_query($conn,"select city_code from master_city where city_name='".$ct."'");
    $row = mysqli_fetch_array($qryct);
    $city = $row['city_code'];


    and change insert to



    $query = "INSERT INTO stud (stud_name, mobile, dob,address,photo,gender,country,state,city) VALUES('$name', '$mob', '$dob', '$add', '$photo', '$gender', '$cn', '$st', '$ct')";


    in you js you should use FormData() like this



    $('.insert_data').click(function(){
    var vname = $("#name").val();
    var vmob = $("#mob_no").val();
    var vdob = $("#dob").val();
    var vadd = $("#add").val();
    var vphoto = $("#photo").val();
    var vgender = $("#gender").val();
    var vcountry = $("#country").val();
    var vstate = $("#state").val();
    var vcity = $("#city").val();
    var fd=new FormData();
    fd.append('name',vname);
    fd.append('mob_no',vmob);
    fd.append('dob',vdob);
    fd.append('add',vadd);
    fd.append('photo',vphoto);
    fd.append('gender',vgender);
    fd.append('country',vcountry);
    fd.append('state',vstate);
    fd.append('city',vcity);
    $.ajax({
    url:"insert.php",
    method:"post",
    data: fd,
    success: function(data){
    $('#form')[0].reset();
    $('#add_data_Modal').modal('hide');
    $('#stud_insert').html(data);
    }
    });
    });






    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited Nov 22 '18 at 11:39

























    answered Nov 22 '18 at 11:02









    abdulsattar-alkhalafabdulsattar-alkhalaf

    31715




    31715













    • in your insert.php you don't need to search data base for country code, state code or city code because you already pass them to php, so remove the 3 queries and in your insert statement use the post values and save them to database

      – abdulsattar-alkhalaf
      Nov 22 '18 at 11:36











    • $query = "INSERT INTO stud (stud_name, mobile, dob,address,photo,gender,country,state,city) VALUES('$name', '$mob', '$dob', '$add', '$photo', '$gender', '$cn', '$st', '$ct')";

      – abdulsattar-alkhalaf
      Nov 22 '18 at 11:37











    • see the edited post, its working and all data are stored in database

      – abdulsattar-alkhalaf
      Nov 22 '18 at 11:42



















    • in your insert.php you don't need to search data base for country code, state code or city code because you already pass them to php, so remove the 3 queries and in your insert statement use the post values and save them to database

      – abdulsattar-alkhalaf
      Nov 22 '18 at 11:36











    • $query = "INSERT INTO stud (stud_name, mobile, dob,address,photo,gender,country,state,city) VALUES('$name', '$mob', '$dob', '$add', '$photo', '$gender', '$cn', '$st', '$ct')";

      – abdulsattar-alkhalaf
      Nov 22 '18 at 11:37











    • see the edited post, its working and all data are stored in database

      – abdulsattar-alkhalaf
      Nov 22 '18 at 11:42

















    in your insert.php you don't need to search data base for country code, state code or city code because you already pass them to php, so remove the 3 queries and in your insert statement use the post values and save them to database

    – abdulsattar-alkhalaf
    Nov 22 '18 at 11:36





    in your insert.php you don't need to search data base for country code, state code or city code because you already pass them to php, so remove the 3 queries and in your insert statement use the post values and save them to database

    – abdulsattar-alkhalaf
    Nov 22 '18 at 11:36













    $query = "INSERT INTO stud (stud_name, mobile, dob,address,photo,gender,country,state,city) VALUES('$name', '$mob', '$dob', '$add', '$photo', '$gender', '$cn', '$st', '$ct')";

    – abdulsattar-alkhalaf
    Nov 22 '18 at 11:37





    $query = "INSERT INTO stud (stud_name, mobile, dob,address,photo,gender,country,state,city) VALUES('$name', '$mob', '$dob', '$add', '$photo', '$gender', '$cn', '$st', '$ct')";

    – abdulsattar-alkhalaf
    Nov 22 '18 at 11:37













    see the edited post, its working and all data are stored in database

    – abdulsattar-alkhalaf
    Nov 22 '18 at 11:42





    see the edited post, its working and all data are stored in database

    – abdulsattar-alkhalaf
    Nov 22 '18 at 11:42











    0














    New code for Insert:
    Thank u every one for helping me.



    <?php
    include("connection.php");
    if(!empty($_POST))
    {
    $output = '';
    $name = $_POST['name'];
    $mob = $_POST['mob_no'];
    $dob = $_POST['dob'];
    $add = $_POST['add'];
    $photo = $_FILES['photo']['name'];
    $gender = $_POST['gender'];
    $cn = $_POST['country'];
    $st = $_POST['state'];
    $ct = $_POST['city'];

    $query = "INSERT INTO stud(stud_name, mobile, dob,address,photo,gender,country,state,city)VALUES('$name', '$mob', '$dob', '$add', '$photo', '$gender', '$cn', '$st', '$ct ')";
    if (mysqli_query($conn, $query)) {

    $target_dir="images/";
    $target_file=$target_dir.basename($_FILES["photo"]["name"]);
    $imageFileType=pathinfo($target_file,PATHINFO_EXTENSION);
    if(move_uploaded_file($_FILES["photo"]["tmp_name"],$target_file)){
    echo '<script language="javascript">';
    echo 'alert("Image Inserted Successfully")';
    echo '</script>';
    } else {
    echo '<script language="javascript">';
    echo 'alert("Cannot upload")';
    echo '</script>';
    }
    echo '<script language="javascript">';
    echo 'alert("Data Inserted Successfully")';
    echo '</script>';
    }
    else {
    echo '<script language="javascript">';
    echo 'alert("Cannot insert record")';
    echo '</script>';
    }
    }


    ?>






    share|improve this answer






























      0














      New code for Insert:
      Thank u every one for helping me.



      <?php
      include("connection.php");
      if(!empty($_POST))
      {
      $output = '';
      $name = $_POST['name'];
      $mob = $_POST['mob_no'];
      $dob = $_POST['dob'];
      $add = $_POST['add'];
      $photo = $_FILES['photo']['name'];
      $gender = $_POST['gender'];
      $cn = $_POST['country'];
      $st = $_POST['state'];
      $ct = $_POST['city'];

      $query = "INSERT INTO stud(stud_name, mobile, dob,address,photo,gender,country,state,city)VALUES('$name', '$mob', '$dob', '$add', '$photo', '$gender', '$cn', '$st', '$ct ')";
      if (mysqli_query($conn, $query)) {

      $target_dir="images/";
      $target_file=$target_dir.basename($_FILES["photo"]["name"]);
      $imageFileType=pathinfo($target_file,PATHINFO_EXTENSION);
      if(move_uploaded_file($_FILES["photo"]["tmp_name"],$target_file)){
      echo '<script language="javascript">';
      echo 'alert("Image Inserted Successfully")';
      echo '</script>';
      } else {
      echo '<script language="javascript">';
      echo 'alert("Cannot upload")';
      echo '</script>';
      }
      echo '<script language="javascript">';
      echo 'alert("Data Inserted Successfully")';
      echo '</script>';
      }
      else {
      echo '<script language="javascript">';
      echo 'alert("Cannot insert record")';
      echo '</script>';
      }
      }


      ?>






      share|improve this answer




























        0












        0








        0







        New code for Insert:
        Thank u every one for helping me.



        <?php
        include("connection.php");
        if(!empty($_POST))
        {
        $output = '';
        $name = $_POST['name'];
        $mob = $_POST['mob_no'];
        $dob = $_POST['dob'];
        $add = $_POST['add'];
        $photo = $_FILES['photo']['name'];
        $gender = $_POST['gender'];
        $cn = $_POST['country'];
        $st = $_POST['state'];
        $ct = $_POST['city'];

        $query = "INSERT INTO stud(stud_name, mobile, dob,address,photo,gender,country,state,city)VALUES('$name', '$mob', '$dob', '$add', '$photo', '$gender', '$cn', '$st', '$ct ')";
        if (mysqli_query($conn, $query)) {

        $target_dir="images/";
        $target_file=$target_dir.basename($_FILES["photo"]["name"]);
        $imageFileType=pathinfo($target_file,PATHINFO_EXTENSION);
        if(move_uploaded_file($_FILES["photo"]["tmp_name"],$target_file)){
        echo '<script language="javascript">';
        echo 'alert("Image Inserted Successfully")';
        echo '</script>';
        } else {
        echo '<script language="javascript">';
        echo 'alert("Cannot upload")';
        echo '</script>';
        }
        echo '<script language="javascript">';
        echo 'alert("Data Inserted Successfully")';
        echo '</script>';
        }
        else {
        echo '<script language="javascript">';
        echo 'alert("Cannot insert record")';
        echo '</script>';
        }
        }


        ?>






        share|improve this answer















        New code for Insert:
        Thank u every one for helping me.



        <?php
        include("connection.php");
        if(!empty($_POST))
        {
        $output = '';
        $name = $_POST['name'];
        $mob = $_POST['mob_no'];
        $dob = $_POST['dob'];
        $add = $_POST['add'];
        $photo = $_FILES['photo']['name'];
        $gender = $_POST['gender'];
        $cn = $_POST['country'];
        $st = $_POST['state'];
        $ct = $_POST['city'];

        $query = "INSERT INTO stud(stud_name, mobile, dob,address,photo,gender,country,state,city)VALUES('$name', '$mob', '$dob', '$add', '$photo', '$gender', '$cn', '$st', '$ct ')";
        if (mysqli_query($conn, $query)) {

        $target_dir="images/";
        $target_file=$target_dir.basename($_FILES["photo"]["name"]);
        $imageFileType=pathinfo($target_file,PATHINFO_EXTENSION);
        if(move_uploaded_file($_FILES["photo"]["tmp_name"],$target_file)){
        echo '<script language="javascript">';
        echo 'alert("Image Inserted Successfully")';
        echo '</script>';
        } else {
        echo '<script language="javascript">';
        echo 'alert("Cannot upload")';
        echo '</script>';
        }
        echo '<script language="javascript">';
        echo 'alert("Data Inserted Successfully")';
        echo '</script>';
        }
        else {
        echo '<script language="javascript">';
        echo 'alert("Cannot insert record")';
        echo '</script>';
        }
        }


        ?>







        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited Nov 22 '18 at 11:34

























        answered Nov 22 '18 at 10:31









        Jaicy JosephJaicy Joseph

        207




        207






























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