How to pass form data using jquery Ajax to insert data in database?












1















I have 4 tables namely stud, country_master_academic,master_state and master_city.
The main problem is that my form consists of many different fields like textbox, radio buttons, dropdown and an image file, so i am getting really confused.
I can't insert data in database. Please help me. I tried many times but its not working. Thanks for the help in advance.
Modal in home.php page



 <div class="container">
<div class="modal fade" id="add_data_modal" role="dialog">
<div class="modal-dialog">
<div class="modal-content">
<div class="modal-heading" style="margin-top:30px;text-align:center">
<button class="close" data-dismiss="modal" style="margin-right:20px;font-weight:bold;">x</button>
<h4 class="modal-title"><span class="glyphicon glyphicon-user"></span> Add Student</h4>
</div>
<div class="modal-body">
<div class="form-group">
<form class="form-horizontal" name="form" id="form" method="post" action="<?php $_PHP_SELF?>" enctype="multipart/form-data">
<label for="name" id="name"><span class="glyphicon glyphicon-user"></span><b> Student Name: </b></label><label id="p1">*</label>
<input type="text" class="form-control" name="name" id="name" pattern="[a-zA-Z]{3,}" title="Name should only contain letters and atleast 3 letters" required />
</div>
<div class="form-group">
<label for="no"><span class="glyphicon glyphicon-phone"></span><b> Mobile No: </b></label><label id="p2">*</label>
<input type="text" class="form-control" name="mob_no" id="mob_no" pattern="[0-9]{10}" title="Mobile number should be of 10 digits" required />
</div>
<div class="form-group">
<label for="dob"><span class="glyphicon glyphicon-calendar"></span><b> Birth Date: </b></label><label id="p3">*</label>
<input type="date" class="form-control" name="dob" required />
</div>
<div class="form-group">
<label for="add"><span class="glyphicon glyphicon-map-marker"></span><b> Address: </b></label><label id="p4">*</label>
<textarea rows="4" cols="33" class="form-control" name="add" id="add" required></textarea>
</div>
<div class="form-group">
<label for="photo"><span class="glyphicon glyphicon-camera"></span><b> Photo: </b></label><label id="p5">*</label>
<input type="file" name="photo" id="photo" required />
</div>
<div class="form-group">
<label for="gen"><b> Gender: </b></label><label id="p6">*</label><br/>
<input type="radio" name="gender" id="gender" value="M" required="required">Male
<input type="radio" name="gender" id="gender" value="F" required="required">Female
</div>
<div class="form-group">
<label for="cntry"><span class="glyphicon glyphicon-map-marker"></span><b> Country: </b></label><label id="p7"> *</label>
<?php
$country="SELECT * from country_master_academic";
$res= $conn->query($country);
if($res->num_rows>0)
{
echo '<select name="country" id="country" class="form-control" required>';
echo '<option value="">Select</option>';
while($row=$res->fetch_assoc())
{
echo '<option value='.$row["country_code"].'>'.$row['country_name'].'</option>';
}
echo '</select>';
} else {
echo "0 result";
}
?>

</div>
<div class="form-group">
<label for="state"><span class="glyphicon glyphicon-map-marker"></span><b> State: </b></label><label id="p8">*</label>
<?php
$state = "SELECT * from master_state";
$res=$conn->query($state);
if($res->num_rows>0)
{
echo '<select name="state" id="state" class="form-control" required>';
echo '<option value="">Select</option>';
while($row=$res->fetch_assoc())
{
echo '<option value='.$row["state_code"].'>'.$row["state_name"].'</option>';
}
echo '</select>';
} else {
echo "0 result";
}
?>
</div>
<div class="form-group">
<label for="city"><span class="glyphicon glyphicon-map-marker"></span><b> City: </b></label><label id="p9">*</label>
<?php
$city="SELECT * from master_city";
$res=$conn->query($city);
if($res->num_rows>0)
{
echo '<select name="city" id="city" class="form-control" required>';
echo '<option value="">Select</option>';
while($row=$res->fetch_assoc())
{
echo '<option value='.$row["city_code"].'>'.$row["city_name"].'</option>';
}
echo '</select>';
} else {
echo "0 result";
}
?>
</div>

<div class="form-group">
<button type="submit" name="save" id="save" class="btn btn-info" onclick="validate()">Save</button>
</div>
</form>
</div>
<div class="modal-footer">
<button class="btn btn-danger" type="button" data-dismiss="modal">Close</button>
</div>
</div>
</div>
</div>


My jquery in home page



    $('.insert_data').click(function(){
var vname = $("#name").val();
var vmob = $("#mob_no").val();
var vdob = $("#dob").val();
var vadd = $("#add").val();
var vphoto = $("#photo").val();
var vgender = $("#gender").val();
var vcountry = $("#country").val();
var vstate = $("#state").val();
var vcity = $("#city").val();

$.ajax({
url:"insert.php",
method:"post",
data: {
name:vname,
mob_no:vmob,
dob:vdob,
add:vadd,
photo:vphoto,
gender:vgender,
country:vcountry,
state:vstate,
city:vcity
},
success: function(data){
$('#form')[0].reset();
$('#add_data_Modal').modal('hide');
$('#stud_insert').html(data);
}
});
});


my insert.php page



<?php
include("connection.php");
if(!empty($_POST))
{
$output = '';
$name = $_POST['name']);
$mob = $_POST['mob_no']);
$dob = $_POST['dob']);
$add = $_POST['add']);
$photo = $_FILES['photo']['name']);
$gender = $_POST['gender']);
$cn = $_POST['country']);
$st = $_POST['state']);
$ct = $_POST['city']);

$qrycn= mysqli_query($conn,"select country_code from country_master_academic where country_name=' ".$cn." ' ");
$row = mysqli_fetch_array($qrycn);
$country = $row['country_code'];

$qryst=mysqli_query($conn,"select state_code from master_state where state_name='".$st."'");
$row = mysqli_fetch_array($qryst);
$state = $row['state_code'];

$qryct= mysqli_query($conn,"select city_code from master_city where city_name='".$ct."'");
$row = mysqli_fetch_array($qryct);
$city = $row['city_code'];

$query = "INSERT INTO stud (stud_name, mobile, dob,address,photo,gender,country,state,city) VALUES('$name', '$mob', '$dob', '$add', '$photo', '$gender', '$country', '$state', '$city')";
if (mysqli_query($conn, $query)) {

$target_dir="images/";
$target_file=$target_dir.basename($_FILES["photo"]["name"]);
$imageFileType=pathinfo($target_file,PATHINFO_EXTENSION);
if(move_uploaded_file($_FILES["photo"]["tmp_name"],$target_file)){
echo '<script language="javascript">';
echo 'alert("Image and data Inserted Successfully")';
echo '</script>';
} else {
echo '<script language="javascript">';
echo 'alert("Cannot upload")';
echo '</script>';
}
}
else {
echo '<script language="javascript">';
echo 'alert("Cannot insert record")';
echo '</script>';
}
$output .= '<label class="text-success">Data Inserted</label>';
$output .= '
<table class="table table-bordered">
<tr>
<th>No</th>
<th>Name</th>
<th>Mobile</th>
<th>Birthdate</th>
<th>Address</th>
<th>Photo</th>
<th>Gender</th>
<th>Country</th>
<th>State</th>
<th>City</th>
</tr>

';
$result= mysqli_query($conn,"select * from stud s, country_master_academic c, master_state st, master_city ct where s.country=c.country_code and s.state=st.state_code and s.city=ct.city_code");
while($row = mysqli_fetch_array($result))
{
$output .= '
<tr>
<td><a href="update.php?no='.$row["stud_no"].'"><button name="edit" value="Edit" style="font-weight:bold;" class="btn btn-warning"><span class="glyphicon glyphicon-edit"></span> Edit</button></a></td>
<td><button type="submit" style="font-weight:bold;" name="delete" id='.$row["stud_no"].' class="btn btn-danger delete_data"><span class="glyphicon glyphicon-trash"></span> Delete</button></td>
<td><button type="submit" style="font-weight:bold;" name="view" id='.$row["stud_no"].' class="btn btn-success view_data" data-target="#modalDelete" data-toggle="modal"><span class="glyphicon glyphicon-user"></span> View</button></td>

</tr>
';
}
$output .= '</table>';
}
echo $output;
}


?>










share|improve this question

























  • So do you get any errors? What part doesn't work? At first glance your code seems like it should work.

    – Dirk Scholten
    Nov 22 '18 at 10:03











  • what you mean from 'not working'? Do you get any error in console? Script error or PHP error? no error?

    – Ali Sheikhpour
    Nov 22 '18 at 10:03













  • @DirkScholten no sir... It's not showing any errors..

    – Jaicy Joseph
    Nov 22 '18 at 10:07











  • @AliSheikhpour no errors... Just after i click on save , modal gets closed

    – Jaicy Joseph
    Nov 22 '18 at 10:08











  • Data is not getting inserted, I think problem with my jquery or i am not inserting properly

    – Jaicy Joseph
    Nov 22 '18 at 10:08


















1















I have 4 tables namely stud, country_master_academic,master_state and master_city.
The main problem is that my form consists of many different fields like textbox, radio buttons, dropdown and an image file, so i am getting really confused.
I can't insert data in database. Please help me. I tried many times but its not working. Thanks for the help in advance.
Modal in home.php page



 <div class="container">
<div class="modal fade" id="add_data_modal" role="dialog">
<div class="modal-dialog">
<div class="modal-content">
<div class="modal-heading" style="margin-top:30px;text-align:center">
<button class="close" data-dismiss="modal" style="margin-right:20px;font-weight:bold;">x</button>
<h4 class="modal-title"><span class="glyphicon glyphicon-user"></span> Add Student</h4>
</div>
<div class="modal-body">
<div class="form-group">
<form class="form-horizontal" name="form" id="form" method="post" action="<?php $_PHP_SELF?>" enctype="multipart/form-data">
<label for="name" id="name"><span class="glyphicon glyphicon-user"></span><b> Student Name: </b></label><label id="p1">*</label>
<input type="text" class="form-control" name="name" id="name" pattern="[a-zA-Z]{3,}" title="Name should only contain letters and atleast 3 letters" required />
</div>
<div class="form-group">
<label for="no"><span class="glyphicon glyphicon-phone"></span><b> Mobile No: </b></label><label id="p2">*</label>
<input type="text" class="form-control" name="mob_no" id="mob_no" pattern="[0-9]{10}" title="Mobile number should be of 10 digits" required />
</div>
<div class="form-group">
<label for="dob"><span class="glyphicon glyphicon-calendar"></span><b> Birth Date: </b></label><label id="p3">*</label>
<input type="date" class="form-control" name="dob" required />
</div>
<div class="form-group">
<label for="add"><span class="glyphicon glyphicon-map-marker"></span><b> Address: </b></label><label id="p4">*</label>
<textarea rows="4" cols="33" class="form-control" name="add" id="add" required></textarea>
</div>
<div class="form-group">
<label for="photo"><span class="glyphicon glyphicon-camera"></span><b> Photo: </b></label><label id="p5">*</label>
<input type="file" name="photo" id="photo" required />
</div>
<div class="form-group">
<label for="gen"><b> Gender: </b></label><label id="p6">*</label><br/>
<input type="radio" name="gender" id="gender" value="M" required="required">Male
<input type="radio" name="gender" id="gender" value="F" required="required">Female
</div>
<div class="form-group">
<label for="cntry"><span class="glyphicon glyphicon-map-marker"></span><b> Country: </b></label><label id="p7"> *</label>
<?php
$country="SELECT * from country_master_academic";
$res= $conn->query($country);
if($res->num_rows>0)
{
echo '<select name="country" id="country" class="form-control" required>';
echo '<option value="">Select</option>';
while($row=$res->fetch_assoc())
{
echo '<option value='.$row["country_code"].'>'.$row['country_name'].'</option>';
}
echo '</select>';
} else {
echo "0 result";
}
?>

</div>
<div class="form-group">
<label for="state"><span class="glyphicon glyphicon-map-marker"></span><b> State: </b></label><label id="p8">*</label>
<?php
$state = "SELECT * from master_state";
$res=$conn->query($state);
if($res->num_rows>0)
{
echo '<select name="state" id="state" class="form-control" required>';
echo '<option value="">Select</option>';
while($row=$res->fetch_assoc())
{
echo '<option value='.$row["state_code"].'>'.$row["state_name"].'</option>';
}
echo '</select>';
} else {
echo "0 result";
}
?>
</div>
<div class="form-group">
<label for="city"><span class="glyphicon glyphicon-map-marker"></span><b> City: </b></label><label id="p9">*</label>
<?php
$city="SELECT * from master_city";
$res=$conn->query($city);
if($res->num_rows>0)
{
echo '<select name="city" id="city" class="form-control" required>';
echo '<option value="">Select</option>';
while($row=$res->fetch_assoc())
{
echo '<option value='.$row["city_code"].'>'.$row["city_name"].'</option>';
}
echo '</select>';
} else {
echo "0 result";
}
?>
</div>

<div class="form-group">
<button type="submit" name="save" id="save" class="btn btn-info" onclick="validate()">Save</button>
</div>
</form>
</div>
<div class="modal-footer">
<button class="btn btn-danger" type="button" data-dismiss="modal">Close</button>
</div>
</div>
</div>
</div>


My jquery in home page



    $('.insert_data').click(function(){
var vname = $("#name").val();
var vmob = $("#mob_no").val();
var vdob = $("#dob").val();
var vadd = $("#add").val();
var vphoto = $("#photo").val();
var vgender = $("#gender").val();
var vcountry = $("#country").val();
var vstate = $("#state").val();
var vcity = $("#city").val();

$.ajax({
url:"insert.php",
method:"post",
data: {
name:vname,
mob_no:vmob,
dob:vdob,
add:vadd,
photo:vphoto,
gender:vgender,
country:vcountry,
state:vstate,
city:vcity
},
success: function(data){
$('#form')[0].reset();
$('#add_data_Modal').modal('hide');
$('#stud_insert').html(data);
}
});
});


my insert.php page



<?php
include("connection.php");
if(!empty($_POST))
{
$output = '';
$name = $_POST['name']);
$mob = $_POST['mob_no']);
$dob = $_POST['dob']);
$add = $_POST['add']);
$photo = $_FILES['photo']['name']);
$gender = $_POST['gender']);
$cn = $_POST['country']);
$st = $_POST['state']);
$ct = $_POST['city']);

$qrycn= mysqli_query($conn,"select country_code from country_master_academic where country_name=' ".$cn." ' ");
$row = mysqli_fetch_array($qrycn);
$country = $row['country_code'];

$qryst=mysqli_query($conn,"select state_code from master_state where state_name='".$st."'");
$row = mysqli_fetch_array($qryst);
$state = $row['state_code'];

$qryct= mysqli_query($conn,"select city_code from master_city where city_name='".$ct."'");
$row = mysqli_fetch_array($qryct);
$city = $row['city_code'];

$query = "INSERT INTO stud (stud_name, mobile, dob,address,photo,gender,country,state,city) VALUES('$name', '$mob', '$dob', '$add', '$photo', '$gender', '$country', '$state', '$city')";
if (mysqli_query($conn, $query)) {

$target_dir="images/";
$target_file=$target_dir.basename($_FILES["photo"]["name"]);
$imageFileType=pathinfo($target_file,PATHINFO_EXTENSION);
if(move_uploaded_file($_FILES["photo"]["tmp_name"],$target_file)){
echo '<script language="javascript">';
echo 'alert("Image and data Inserted Successfully")';
echo '</script>';
} else {
echo '<script language="javascript">';
echo 'alert("Cannot upload")';
echo '</script>';
}
}
else {
echo '<script language="javascript">';
echo 'alert("Cannot insert record")';
echo '</script>';
}
$output .= '<label class="text-success">Data Inserted</label>';
$output .= '
<table class="table table-bordered">
<tr>
<th>No</th>
<th>Name</th>
<th>Mobile</th>
<th>Birthdate</th>
<th>Address</th>
<th>Photo</th>
<th>Gender</th>
<th>Country</th>
<th>State</th>
<th>City</th>
</tr>

';
$result= mysqli_query($conn,"select * from stud s, country_master_academic c, master_state st, master_city ct where s.country=c.country_code and s.state=st.state_code and s.city=ct.city_code");
while($row = mysqli_fetch_array($result))
{
$output .= '
<tr>
<td><a href="update.php?no='.$row["stud_no"].'"><button name="edit" value="Edit" style="font-weight:bold;" class="btn btn-warning"><span class="glyphicon glyphicon-edit"></span> Edit</button></a></td>
<td><button type="submit" style="font-weight:bold;" name="delete" id='.$row["stud_no"].' class="btn btn-danger delete_data"><span class="glyphicon glyphicon-trash"></span> Delete</button></td>
<td><button type="submit" style="font-weight:bold;" name="view" id='.$row["stud_no"].' class="btn btn-success view_data" data-target="#modalDelete" data-toggle="modal"><span class="glyphicon glyphicon-user"></span> View</button></td>

</tr>
';
}
$output .= '</table>';
}
echo $output;
}


?>










share|improve this question

























  • So do you get any errors? What part doesn't work? At first glance your code seems like it should work.

    – Dirk Scholten
    Nov 22 '18 at 10:03











  • what you mean from 'not working'? Do you get any error in console? Script error or PHP error? no error?

    – Ali Sheikhpour
    Nov 22 '18 at 10:03













  • @DirkScholten no sir... It's not showing any errors..

    – Jaicy Joseph
    Nov 22 '18 at 10:07











  • @AliSheikhpour no errors... Just after i click on save , modal gets closed

    – Jaicy Joseph
    Nov 22 '18 at 10:08











  • Data is not getting inserted, I think problem with my jquery or i am not inserting properly

    – Jaicy Joseph
    Nov 22 '18 at 10:08
















1












1








1








I have 4 tables namely stud, country_master_academic,master_state and master_city.
The main problem is that my form consists of many different fields like textbox, radio buttons, dropdown and an image file, so i am getting really confused.
I can't insert data in database. Please help me. I tried many times but its not working. Thanks for the help in advance.
Modal in home.php page



 <div class="container">
<div class="modal fade" id="add_data_modal" role="dialog">
<div class="modal-dialog">
<div class="modal-content">
<div class="modal-heading" style="margin-top:30px;text-align:center">
<button class="close" data-dismiss="modal" style="margin-right:20px;font-weight:bold;">x</button>
<h4 class="modal-title"><span class="glyphicon glyphicon-user"></span> Add Student</h4>
</div>
<div class="modal-body">
<div class="form-group">
<form class="form-horizontal" name="form" id="form" method="post" action="<?php $_PHP_SELF?>" enctype="multipart/form-data">
<label for="name" id="name"><span class="glyphicon glyphicon-user"></span><b> Student Name: </b></label><label id="p1">*</label>
<input type="text" class="form-control" name="name" id="name" pattern="[a-zA-Z]{3,}" title="Name should only contain letters and atleast 3 letters" required />
</div>
<div class="form-group">
<label for="no"><span class="glyphicon glyphicon-phone"></span><b> Mobile No: </b></label><label id="p2">*</label>
<input type="text" class="form-control" name="mob_no" id="mob_no" pattern="[0-9]{10}" title="Mobile number should be of 10 digits" required />
</div>
<div class="form-group">
<label for="dob"><span class="glyphicon glyphicon-calendar"></span><b> Birth Date: </b></label><label id="p3">*</label>
<input type="date" class="form-control" name="dob" required />
</div>
<div class="form-group">
<label for="add"><span class="glyphicon glyphicon-map-marker"></span><b> Address: </b></label><label id="p4">*</label>
<textarea rows="4" cols="33" class="form-control" name="add" id="add" required></textarea>
</div>
<div class="form-group">
<label for="photo"><span class="glyphicon glyphicon-camera"></span><b> Photo: </b></label><label id="p5">*</label>
<input type="file" name="photo" id="photo" required />
</div>
<div class="form-group">
<label for="gen"><b> Gender: </b></label><label id="p6">*</label><br/>
<input type="radio" name="gender" id="gender" value="M" required="required">Male
<input type="radio" name="gender" id="gender" value="F" required="required">Female
</div>
<div class="form-group">
<label for="cntry"><span class="glyphicon glyphicon-map-marker"></span><b> Country: </b></label><label id="p7"> *</label>
<?php
$country="SELECT * from country_master_academic";
$res= $conn->query($country);
if($res->num_rows>0)
{
echo '<select name="country" id="country" class="form-control" required>';
echo '<option value="">Select</option>';
while($row=$res->fetch_assoc())
{
echo '<option value='.$row["country_code"].'>'.$row['country_name'].'</option>';
}
echo '</select>';
} else {
echo "0 result";
}
?>

</div>
<div class="form-group">
<label for="state"><span class="glyphicon glyphicon-map-marker"></span><b> State: </b></label><label id="p8">*</label>
<?php
$state = "SELECT * from master_state";
$res=$conn->query($state);
if($res->num_rows>0)
{
echo '<select name="state" id="state" class="form-control" required>';
echo '<option value="">Select</option>';
while($row=$res->fetch_assoc())
{
echo '<option value='.$row["state_code"].'>'.$row["state_name"].'</option>';
}
echo '</select>';
} else {
echo "0 result";
}
?>
</div>
<div class="form-group">
<label for="city"><span class="glyphicon glyphicon-map-marker"></span><b> City: </b></label><label id="p9">*</label>
<?php
$city="SELECT * from master_city";
$res=$conn->query($city);
if($res->num_rows>0)
{
echo '<select name="city" id="city" class="form-control" required>';
echo '<option value="">Select</option>';
while($row=$res->fetch_assoc())
{
echo '<option value='.$row["city_code"].'>'.$row["city_name"].'</option>';
}
echo '</select>';
} else {
echo "0 result";
}
?>
</div>

<div class="form-group">
<button type="submit" name="save" id="save" class="btn btn-info" onclick="validate()">Save</button>
</div>
</form>
</div>
<div class="modal-footer">
<button class="btn btn-danger" type="button" data-dismiss="modal">Close</button>
</div>
</div>
</div>
</div>


My jquery in home page



    $('.insert_data').click(function(){
var vname = $("#name").val();
var vmob = $("#mob_no").val();
var vdob = $("#dob").val();
var vadd = $("#add").val();
var vphoto = $("#photo").val();
var vgender = $("#gender").val();
var vcountry = $("#country").val();
var vstate = $("#state").val();
var vcity = $("#city").val();

$.ajax({
url:"insert.php",
method:"post",
data: {
name:vname,
mob_no:vmob,
dob:vdob,
add:vadd,
photo:vphoto,
gender:vgender,
country:vcountry,
state:vstate,
city:vcity
},
success: function(data){
$('#form')[0].reset();
$('#add_data_Modal').modal('hide');
$('#stud_insert').html(data);
}
});
});


my insert.php page



<?php
include("connection.php");
if(!empty($_POST))
{
$output = '';
$name = $_POST['name']);
$mob = $_POST['mob_no']);
$dob = $_POST['dob']);
$add = $_POST['add']);
$photo = $_FILES['photo']['name']);
$gender = $_POST['gender']);
$cn = $_POST['country']);
$st = $_POST['state']);
$ct = $_POST['city']);

$qrycn= mysqli_query($conn,"select country_code from country_master_academic where country_name=' ".$cn." ' ");
$row = mysqli_fetch_array($qrycn);
$country = $row['country_code'];

$qryst=mysqli_query($conn,"select state_code from master_state where state_name='".$st."'");
$row = mysqli_fetch_array($qryst);
$state = $row['state_code'];

$qryct= mysqli_query($conn,"select city_code from master_city where city_name='".$ct."'");
$row = mysqli_fetch_array($qryct);
$city = $row['city_code'];

$query = "INSERT INTO stud (stud_name, mobile, dob,address,photo,gender,country,state,city) VALUES('$name', '$mob', '$dob', '$add', '$photo', '$gender', '$country', '$state', '$city')";
if (mysqli_query($conn, $query)) {

$target_dir="images/";
$target_file=$target_dir.basename($_FILES["photo"]["name"]);
$imageFileType=pathinfo($target_file,PATHINFO_EXTENSION);
if(move_uploaded_file($_FILES["photo"]["tmp_name"],$target_file)){
echo '<script language="javascript">';
echo 'alert("Image and data Inserted Successfully")';
echo '</script>';
} else {
echo '<script language="javascript">';
echo 'alert("Cannot upload")';
echo '</script>';
}
}
else {
echo '<script language="javascript">';
echo 'alert("Cannot insert record")';
echo '</script>';
}
$output .= '<label class="text-success">Data Inserted</label>';
$output .= '
<table class="table table-bordered">
<tr>
<th>No</th>
<th>Name</th>
<th>Mobile</th>
<th>Birthdate</th>
<th>Address</th>
<th>Photo</th>
<th>Gender</th>
<th>Country</th>
<th>State</th>
<th>City</th>
</tr>

';
$result= mysqli_query($conn,"select * from stud s, country_master_academic c, master_state st, master_city ct where s.country=c.country_code and s.state=st.state_code and s.city=ct.city_code");
while($row = mysqli_fetch_array($result))
{
$output .= '
<tr>
<td><a href="update.php?no='.$row["stud_no"].'"><button name="edit" value="Edit" style="font-weight:bold;" class="btn btn-warning"><span class="glyphicon glyphicon-edit"></span> Edit</button></a></td>
<td><button type="submit" style="font-weight:bold;" name="delete" id='.$row["stud_no"].' class="btn btn-danger delete_data"><span class="glyphicon glyphicon-trash"></span> Delete</button></td>
<td><button type="submit" style="font-weight:bold;" name="view" id='.$row["stud_no"].' class="btn btn-success view_data" data-target="#modalDelete" data-toggle="modal"><span class="glyphicon glyphicon-user"></span> View</button></td>

</tr>
';
}
$output .= '</table>';
}
echo $output;
}


?>










share|improve this question
















I have 4 tables namely stud, country_master_academic,master_state and master_city.
The main problem is that my form consists of many different fields like textbox, radio buttons, dropdown and an image file, so i am getting really confused.
I can't insert data in database. Please help me. I tried many times but its not working. Thanks for the help in advance.
Modal in home.php page



 <div class="container">
<div class="modal fade" id="add_data_modal" role="dialog">
<div class="modal-dialog">
<div class="modal-content">
<div class="modal-heading" style="margin-top:30px;text-align:center">
<button class="close" data-dismiss="modal" style="margin-right:20px;font-weight:bold;">x</button>
<h4 class="modal-title"><span class="glyphicon glyphicon-user"></span> Add Student</h4>
</div>
<div class="modal-body">
<div class="form-group">
<form class="form-horizontal" name="form" id="form" method="post" action="<?php $_PHP_SELF?>" enctype="multipart/form-data">
<label for="name" id="name"><span class="glyphicon glyphicon-user"></span><b> Student Name: </b></label><label id="p1">*</label>
<input type="text" class="form-control" name="name" id="name" pattern="[a-zA-Z]{3,}" title="Name should only contain letters and atleast 3 letters" required />
</div>
<div class="form-group">
<label for="no"><span class="glyphicon glyphicon-phone"></span><b> Mobile No: </b></label><label id="p2">*</label>
<input type="text" class="form-control" name="mob_no" id="mob_no" pattern="[0-9]{10}" title="Mobile number should be of 10 digits" required />
</div>
<div class="form-group">
<label for="dob"><span class="glyphicon glyphicon-calendar"></span><b> Birth Date: </b></label><label id="p3">*</label>
<input type="date" class="form-control" name="dob" required />
</div>
<div class="form-group">
<label for="add"><span class="glyphicon glyphicon-map-marker"></span><b> Address: </b></label><label id="p4">*</label>
<textarea rows="4" cols="33" class="form-control" name="add" id="add" required></textarea>
</div>
<div class="form-group">
<label for="photo"><span class="glyphicon glyphicon-camera"></span><b> Photo: </b></label><label id="p5">*</label>
<input type="file" name="photo" id="photo" required />
</div>
<div class="form-group">
<label for="gen"><b> Gender: </b></label><label id="p6">*</label><br/>
<input type="radio" name="gender" id="gender" value="M" required="required">Male
<input type="radio" name="gender" id="gender" value="F" required="required">Female
</div>
<div class="form-group">
<label for="cntry"><span class="glyphicon glyphicon-map-marker"></span><b> Country: </b></label><label id="p7"> *</label>
<?php
$country="SELECT * from country_master_academic";
$res= $conn->query($country);
if($res->num_rows>0)
{
echo '<select name="country" id="country" class="form-control" required>';
echo '<option value="">Select</option>';
while($row=$res->fetch_assoc())
{
echo '<option value='.$row["country_code"].'>'.$row['country_name'].'</option>';
}
echo '</select>';
} else {
echo "0 result";
}
?>

</div>
<div class="form-group">
<label for="state"><span class="glyphicon glyphicon-map-marker"></span><b> State: </b></label><label id="p8">*</label>
<?php
$state = "SELECT * from master_state";
$res=$conn->query($state);
if($res->num_rows>0)
{
echo '<select name="state" id="state" class="form-control" required>';
echo '<option value="">Select</option>';
while($row=$res->fetch_assoc())
{
echo '<option value='.$row["state_code"].'>'.$row["state_name"].'</option>';
}
echo '</select>';
} else {
echo "0 result";
}
?>
</div>
<div class="form-group">
<label for="city"><span class="glyphicon glyphicon-map-marker"></span><b> City: </b></label><label id="p9">*</label>
<?php
$city="SELECT * from master_city";
$res=$conn->query($city);
if($res->num_rows>0)
{
echo '<select name="city" id="city" class="form-control" required>';
echo '<option value="">Select</option>';
while($row=$res->fetch_assoc())
{
echo '<option value='.$row["city_code"].'>'.$row["city_name"].'</option>';
}
echo '</select>';
} else {
echo "0 result";
}
?>
</div>

<div class="form-group">
<button type="submit" name="save" id="save" class="btn btn-info" onclick="validate()">Save</button>
</div>
</form>
</div>
<div class="modal-footer">
<button class="btn btn-danger" type="button" data-dismiss="modal">Close</button>
</div>
</div>
</div>
</div>


My jquery in home page



    $('.insert_data').click(function(){
var vname = $("#name").val();
var vmob = $("#mob_no").val();
var vdob = $("#dob").val();
var vadd = $("#add").val();
var vphoto = $("#photo").val();
var vgender = $("#gender").val();
var vcountry = $("#country").val();
var vstate = $("#state").val();
var vcity = $("#city").val();

$.ajax({
url:"insert.php",
method:"post",
data: {
name:vname,
mob_no:vmob,
dob:vdob,
add:vadd,
photo:vphoto,
gender:vgender,
country:vcountry,
state:vstate,
city:vcity
},
success: function(data){
$('#form')[0].reset();
$('#add_data_Modal').modal('hide');
$('#stud_insert').html(data);
}
});
});


my insert.php page



<?php
include("connection.php");
if(!empty($_POST))
{
$output = '';
$name = $_POST['name']);
$mob = $_POST['mob_no']);
$dob = $_POST['dob']);
$add = $_POST['add']);
$photo = $_FILES['photo']['name']);
$gender = $_POST['gender']);
$cn = $_POST['country']);
$st = $_POST['state']);
$ct = $_POST['city']);

$qrycn= mysqli_query($conn,"select country_code from country_master_academic where country_name=' ".$cn." ' ");
$row = mysqli_fetch_array($qrycn);
$country = $row['country_code'];

$qryst=mysqli_query($conn,"select state_code from master_state where state_name='".$st."'");
$row = mysqli_fetch_array($qryst);
$state = $row['state_code'];

$qryct= mysqli_query($conn,"select city_code from master_city where city_name='".$ct."'");
$row = mysqli_fetch_array($qryct);
$city = $row['city_code'];

$query = "INSERT INTO stud (stud_name, mobile, dob,address,photo,gender,country,state,city) VALUES('$name', '$mob', '$dob', '$add', '$photo', '$gender', '$country', '$state', '$city')";
if (mysqli_query($conn, $query)) {

$target_dir="images/";
$target_file=$target_dir.basename($_FILES["photo"]["name"]);
$imageFileType=pathinfo($target_file,PATHINFO_EXTENSION);
if(move_uploaded_file($_FILES["photo"]["tmp_name"],$target_file)){
echo '<script language="javascript">';
echo 'alert("Image and data Inserted Successfully")';
echo '</script>';
} else {
echo '<script language="javascript">';
echo 'alert("Cannot upload")';
echo '</script>';
}
}
else {
echo '<script language="javascript">';
echo 'alert("Cannot insert record")';
echo '</script>';
}
$output .= '<label class="text-success">Data Inserted</label>';
$output .= '
<table class="table table-bordered">
<tr>
<th>No</th>
<th>Name</th>
<th>Mobile</th>
<th>Birthdate</th>
<th>Address</th>
<th>Photo</th>
<th>Gender</th>
<th>Country</th>
<th>State</th>
<th>City</th>
</tr>

';
$result= mysqli_query($conn,"select * from stud s, country_master_academic c, master_state st, master_city ct where s.country=c.country_code and s.state=st.state_code and s.city=ct.city_code");
while($row = mysqli_fetch_array($result))
{
$output .= '
<tr>
<td><a href="update.php?no='.$row["stud_no"].'"><button name="edit" value="Edit" style="font-weight:bold;" class="btn btn-warning"><span class="glyphicon glyphicon-edit"></span> Edit</button></a></td>
<td><button type="submit" style="font-weight:bold;" name="delete" id='.$row["stud_no"].' class="btn btn-danger delete_data"><span class="glyphicon glyphicon-trash"></span> Delete</button></td>
<td><button type="submit" style="font-weight:bold;" name="view" id='.$row["stud_no"].' class="btn btn-success view_data" data-target="#modalDelete" data-toggle="modal"><span class="glyphicon glyphicon-user"></span> View</button></td>

</tr>
';
}
$output .= '</table>';
}
echo $output;
}


?>







php jquery ajax bootstrap-modal






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 22 '18 at 9:56







Jaicy Joseph

















asked Nov 22 '18 at 9:54









Jaicy JosephJaicy Joseph

207




207













  • So do you get any errors? What part doesn't work? At first glance your code seems like it should work.

    – Dirk Scholten
    Nov 22 '18 at 10:03











  • what you mean from 'not working'? Do you get any error in console? Script error or PHP error? no error?

    – Ali Sheikhpour
    Nov 22 '18 at 10:03













  • @DirkScholten no sir... It's not showing any errors..

    – Jaicy Joseph
    Nov 22 '18 at 10:07











  • @AliSheikhpour no errors... Just after i click on save , modal gets closed

    – Jaicy Joseph
    Nov 22 '18 at 10:08











  • Data is not getting inserted, I think problem with my jquery or i am not inserting properly

    – Jaicy Joseph
    Nov 22 '18 at 10:08





















  • So do you get any errors? What part doesn't work? At first glance your code seems like it should work.

    – Dirk Scholten
    Nov 22 '18 at 10:03











  • what you mean from 'not working'? Do you get any error in console? Script error or PHP error? no error?

    – Ali Sheikhpour
    Nov 22 '18 at 10:03













  • @DirkScholten no sir... It's not showing any errors..

    – Jaicy Joseph
    Nov 22 '18 at 10:07











  • @AliSheikhpour no errors... Just after i click on save , modal gets closed

    – Jaicy Joseph
    Nov 22 '18 at 10:08











  • Data is not getting inserted, I think problem with my jquery or i am not inserting properly

    – Jaicy Joseph
    Nov 22 '18 at 10:08



















So do you get any errors? What part doesn't work? At first glance your code seems like it should work.

– Dirk Scholten
Nov 22 '18 at 10:03





So do you get any errors? What part doesn't work? At first glance your code seems like it should work.

– Dirk Scholten
Nov 22 '18 at 10:03













what you mean from 'not working'? Do you get any error in console? Script error or PHP error? no error?

– Ali Sheikhpour
Nov 22 '18 at 10:03







what you mean from 'not working'? Do you get any error in console? Script error or PHP error? no error?

– Ali Sheikhpour
Nov 22 '18 at 10:03















@DirkScholten no sir... It's not showing any errors..

– Jaicy Joseph
Nov 22 '18 at 10:07





@DirkScholten no sir... It's not showing any errors..

– Jaicy Joseph
Nov 22 '18 at 10:07













@AliSheikhpour no errors... Just after i click on save , modal gets closed

– Jaicy Joseph
Nov 22 '18 at 10:08





@AliSheikhpour no errors... Just after i click on save , modal gets closed

– Jaicy Joseph
Nov 22 '18 at 10:08













Data is not getting inserted, I think problem with my jquery or i am not inserting properly

– Jaicy Joseph
Nov 22 '18 at 10:08







Data is not getting inserted, I think problem with my jquery or i am not inserting properly

– Jaicy Joseph
Nov 22 '18 at 10:08














3 Answers
3






active

oldest

votes


















3














Please use your form id submit and get you to form data and pass through ajax and debug with alert(data).



$(document).ready(function(){
$("#form").submit(function(event){
event.preventDefault();
var formData = new FormData(this);
$.ajax({
url: 'insert.php',
type: 'POST',
data: formData,
async: false,
success: function(data) {
alert(data);
},
cache: false,
contentType: false,
processData: false
});
});
});





share|improve this answer
























  • thank u so much, but I want to say one thing, in database i have stored country code, not country name, so while inserting i have to store country code and while displaying it should show country name. Rest all records are getting inserted. Only country,state and city not getting inserted

    – Jaicy Joseph
    Nov 22 '18 at 11:13













  • Please check with the database table stud datatype and length.

    – Subhash Patel
    Nov 22 '18 at 11:22



















2














ok let me list all errors in your html



<label for="name" id="name"><span class="glyphicon glyphicon-user"></span><b> Student Name: </b></label><label id="p1">*</label>


remove id like this



<label for="name"><span class="glyphicon glyphicon-user"></span><b> Student Name: </b></label><label id="p1">*</label>


and add id to this



<input type="date" class="form-control" name="dob" required />


add id



<input type="date" class="form-control" name="dob" id="dob" required />


in your php



$output = '';
$name = $_POST['name']);
$mob = $_POST['mob_no']);
$dob = $_POST['dob']);
$add = $_POST['add']);
$photo = $_FILES['photo']['name']);
$gender = $_POST['gender']);
$cn = $_POST['country']);
$st = $_POST['state']);
$ct = $_POST['city']);


change it to



$output = '';
$name = $_POST['name'];
$mob = $_POST['mob_no'];
$dob = $_POST['dob'];
$add = $_POST['add'];
$photo = $_FILES['photo']['name'];
$gender = $_POST['gender'];
$cn = $_POST['country'];
$st = $_POST['state'];
$ct = $_POST['city'];


then remove



$qrycn= mysqli_query($conn,"select country_code from country_master_academic where country_name=' ".$cn." ' ");
$row = mysqli_fetch_array($qrycn);
$country = $row['country_code'];

$qryst=mysqli_query($conn,"select state_code from master_state where state_name='".$st."'");
$row = mysqli_fetch_array($qryst);
$state = $row['state_code'];

$qryct= mysqli_query($conn,"select city_code from master_city where city_name='".$ct."'");
$row = mysqli_fetch_array($qryct);
$city = $row['city_code'];


and change insert to



$query = "INSERT INTO stud (stud_name, mobile, dob,address,photo,gender,country,state,city) VALUES('$name', '$mob', '$dob', '$add', '$photo', '$gender', '$cn', '$st', '$ct')";


in you js you should use FormData() like this



$('.insert_data').click(function(){
var vname = $("#name").val();
var vmob = $("#mob_no").val();
var vdob = $("#dob").val();
var vadd = $("#add").val();
var vphoto = $("#photo").val();
var vgender = $("#gender").val();
var vcountry = $("#country").val();
var vstate = $("#state").val();
var vcity = $("#city").val();
var fd=new FormData();
fd.append('name',vname);
fd.append('mob_no',vmob);
fd.append('dob',vdob);
fd.append('add',vadd);
fd.append('photo',vphoto);
fd.append('gender',vgender);
fd.append('country',vcountry);
fd.append('state',vstate);
fd.append('city',vcity);
$.ajax({
url:"insert.php",
method:"post",
data: fd,
success: function(data){
$('#form')[0].reset();
$('#add_data_Modal').modal('hide');
$('#stud_insert').html(data);
}
});
});





share|improve this answer


























  • in your insert.php you don't need to search data base for country code, state code or city code because you already pass them to php, so remove the 3 queries and in your insert statement use the post values and save them to database

    – abdulsattar-alkhalaf
    Nov 22 '18 at 11:36











  • $query = "INSERT INTO stud (stud_name, mobile, dob,address,photo,gender,country,state,city) VALUES('$name', '$mob', '$dob', '$add', '$photo', '$gender', '$cn', '$st', '$ct')";

    – abdulsattar-alkhalaf
    Nov 22 '18 at 11:37











  • see the edited post, its working and all data are stored in database

    – abdulsattar-alkhalaf
    Nov 22 '18 at 11:42



















0














New code for Insert:
Thank u every one for helping me.



<?php
include("connection.php");
if(!empty($_POST))
{
$output = '';
$name = $_POST['name'];
$mob = $_POST['mob_no'];
$dob = $_POST['dob'];
$add = $_POST['add'];
$photo = $_FILES['photo']['name'];
$gender = $_POST['gender'];
$cn = $_POST['country'];
$st = $_POST['state'];
$ct = $_POST['city'];

$query = "INSERT INTO stud(stud_name, mobile, dob,address,photo,gender,country,state,city)VALUES('$name', '$mob', '$dob', '$add', '$photo', '$gender', '$cn', '$st', '$ct ')";
if (mysqli_query($conn, $query)) {

$target_dir="images/";
$target_file=$target_dir.basename($_FILES["photo"]["name"]);
$imageFileType=pathinfo($target_file,PATHINFO_EXTENSION);
if(move_uploaded_file($_FILES["photo"]["tmp_name"],$target_file)){
echo '<script language="javascript">';
echo 'alert("Image Inserted Successfully")';
echo '</script>';
} else {
echo '<script language="javascript">';
echo 'alert("Cannot upload")';
echo '</script>';
}
echo '<script language="javascript">';
echo 'alert("Data Inserted Successfully")';
echo '</script>';
}
else {
echo '<script language="javascript">';
echo 'alert("Cannot insert record")';
echo '</script>';
}
}


?>






share|improve this answer

























    Your Answer






    StackExchange.ifUsing("editor", function () {
    StackExchange.using("externalEditor", function () {
    StackExchange.using("snippets", function () {
    StackExchange.snippets.init();
    });
    });
    }, "code-snippets");

    StackExchange.ready(function() {
    var channelOptions = {
    tags: "".split(" "),
    id: "1"
    };
    initTagRenderer("".split(" "), "".split(" "), channelOptions);

    StackExchange.using("externalEditor", function() {
    // Have to fire editor after snippets, if snippets enabled
    if (StackExchange.settings.snippets.snippetsEnabled) {
    StackExchange.using("snippets", function() {
    createEditor();
    });
    }
    else {
    createEditor();
    }
    });

    function createEditor() {
    StackExchange.prepareEditor({
    heartbeatType: 'answer',
    autoActivateHeartbeat: false,
    convertImagesToLinks: true,
    noModals: true,
    showLowRepImageUploadWarning: true,
    reputationToPostImages: 10,
    bindNavPrevention: true,
    postfix: "",
    imageUploader: {
    brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
    contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
    allowUrls: true
    },
    onDemand: true,
    discardSelector: ".discard-answer"
    ,immediatelyShowMarkdownHelp:true
    });


    }
    });














    draft saved

    draft discarded


















    StackExchange.ready(
    function () {
    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53428218%2fhow-to-pass-form-data-using-jquery-ajax-to-insert-data-in-database%23new-answer', 'question_page');
    }
    );

    Post as a guest















    Required, but never shown

























    3 Answers
    3






    active

    oldest

    votes








    3 Answers
    3






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    3














    Please use your form id submit and get you to form data and pass through ajax and debug with alert(data).



    $(document).ready(function(){
    $("#form").submit(function(event){
    event.preventDefault();
    var formData = new FormData(this);
    $.ajax({
    url: 'insert.php',
    type: 'POST',
    data: formData,
    async: false,
    success: function(data) {
    alert(data);
    },
    cache: false,
    contentType: false,
    processData: false
    });
    });
    });





    share|improve this answer
























    • thank u so much, but I want to say one thing, in database i have stored country code, not country name, so while inserting i have to store country code and while displaying it should show country name. Rest all records are getting inserted. Only country,state and city not getting inserted

      – Jaicy Joseph
      Nov 22 '18 at 11:13













    • Please check with the database table stud datatype and length.

      – Subhash Patel
      Nov 22 '18 at 11:22
















    3














    Please use your form id submit and get you to form data and pass through ajax and debug with alert(data).



    $(document).ready(function(){
    $("#form").submit(function(event){
    event.preventDefault();
    var formData = new FormData(this);
    $.ajax({
    url: 'insert.php',
    type: 'POST',
    data: formData,
    async: false,
    success: function(data) {
    alert(data);
    },
    cache: false,
    contentType: false,
    processData: false
    });
    });
    });





    share|improve this answer
























    • thank u so much, but I want to say one thing, in database i have stored country code, not country name, so while inserting i have to store country code and while displaying it should show country name. Rest all records are getting inserted. Only country,state and city not getting inserted

      – Jaicy Joseph
      Nov 22 '18 at 11:13













    • Please check with the database table stud datatype and length.

      – Subhash Patel
      Nov 22 '18 at 11:22














    3












    3








    3







    Please use your form id submit and get you to form data and pass through ajax and debug with alert(data).



    $(document).ready(function(){
    $("#form").submit(function(event){
    event.preventDefault();
    var formData = new FormData(this);
    $.ajax({
    url: 'insert.php',
    type: 'POST',
    data: formData,
    async: false,
    success: function(data) {
    alert(data);
    },
    cache: false,
    contentType: false,
    processData: false
    });
    });
    });





    share|improve this answer













    Please use your form id submit and get you to form data and pass through ajax and debug with alert(data).



    $(document).ready(function(){
    $("#form").submit(function(event){
    event.preventDefault();
    var formData = new FormData(this);
    $.ajax({
    url: 'insert.php',
    type: 'POST',
    data: formData,
    async: false,
    success: function(data) {
    alert(data);
    },
    cache: false,
    contentType: false,
    processData: false
    });
    });
    });






    share|improve this answer












    share|improve this answer



    share|improve this answer










    answered Nov 22 '18 at 10:54









    Subhash PatelSubhash Patel

    1567




    1567













    • thank u so much, but I want to say one thing, in database i have stored country code, not country name, so while inserting i have to store country code and while displaying it should show country name. Rest all records are getting inserted. Only country,state and city not getting inserted

      – Jaicy Joseph
      Nov 22 '18 at 11:13













    • Please check with the database table stud datatype and length.

      – Subhash Patel
      Nov 22 '18 at 11:22



















    • thank u so much, but I want to say one thing, in database i have stored country code, not country name, so while inserting i have to store country code and while displaying it should show country name. Rest all records are getting inserted. Only country,state and city not getting inserted

      – Jaicy Joseph
      Nov 22 '18 at 11:13













    • Please check with the database table stud datatype and length.

      – Subhash Patel
      Nov 22 '18 at 11:22

















    thank u so much, but I want to say one thing, in database i have stored country code, not country name, so while inserting i have to store country code and while displaying it should show country name. Rest all records are getting inserted. Only country,state and city not getting inserted

    – Jaicy Joseph
    Nov 22 '18 at 11:13







    thank u so much, but I want to say one thing, in database i have stored country code, not country name, so while inserting i have to store country code and while displaying it should show country name. Rest all records are getting inserted. Only country,state and city not getting inserted

    – Jaicy Joseph
    Nov 22 '18 at 11:13















    Please check with the database table stud datatype and length.

    – Subhash Patel
    Nov 22 '18 at 11:22





    Please check with the database table stud datatype and length.

    – Subhash Patel
    Nov 22 '18 at 11:22













    2














    ok let me list all errors in your html



    <label for="name" id="name"><span class="glyphicon glyphicon-user"></span><b> Student Name: </b></label><label id="p1">*</label>


    remove id like this



    <label for="name"><span class="glyphicon glyphicon-user"></span><b> Student Name: </b></label><label id="p1">*</label>


    and add id to this



    <input type="date" class="form-control" name="dob" required />


    add id



    <input type="date" class="form-control" name="dob" id="dob" required />


    in your php



    $output = '';
    $name = $_POST['name']);
    $mob = $_POST['mob_no']);
    $dob = $_POST['dob']);
    $add = $_POST['add']);
    $photo = $_FILES['photo']['name']);
    $gender = $_POST['gender']);
    $cn = $_POST['country']);
    $st = $_POST['state']);
    $ct = $_POST['city']);


    change it to



    $output = '';
    $name = $_POST['name'];
    $mob = $_POST['mob_no'];
    $dob = $_POST['dob'];
    $add = $_POST['add'];
    $photo = $_FILES['photo']['name'];
    $gender = $_POST['gender'];
    $cn = $_POST['country'];
    $st = $_POST['state'];
    $ct = $_POST['city'];


    then remove



    $qrycn= mysqli_query($conn,"select country_code from country_master_academic where country_name=' ".$cn." ' ");
    $row = mysqli_fetch_array($qrycn);
    $country = $row['country_code'];

    $qryst=mysqli_query($conn,"select state_code from master_state where state_name='".$st."'");
    $row = mysqli_fetch_array($qryst);
    $state = $row['state_code'];

    $qryct= mysqli_query($conn,"select city_code from master_city where city_name='".$ct."'");
    $row = mysqli_fetch_array($qryct);
    $city = $row['city_code'];


    and change insert to



    $query = "INSERT INTO stud (stud_name, mobile, dob,address,photo,gender,country,state,city) VALUES('$name', '$mob', '$dob', '$add', '$photo', '$gender', '$cn', '$st', '$ct')";


    in you js you should use FormData() like this



    $('.insert_data').click(function(){
    var vname = $("#name").val();
    var vmob = $("#mob_no").val();
    var vdob = $("#dob").val();
    var vadd = $("#add").val();
    var vphoto = $("#photo").val();
    var vgender = $("#gender").val();
    var vcountry = $("#country").val();
    var vstate = $("#state").val();
    var vcity = $("#city").val();
    var fd=new FormData();
    fd.append('name',vname);
    fd.append('mob_no',vmob);
    fd.append('dob',vdob);
    fd.append('add',vadd);
    fd.append('photo',vphoto);
    fd.append('gender',vgender);
    fd.append('country',vcountry);
    fd.append('state',vstate);
    fd.append('city',vcity);
    $.ajax({
    url:"insert.php",
    method:"post",
    data: fd,
    success: function(data){
    $('#form')[0].reset();
    $('#add_data_Modal').modal('hide');
    $('#stud_insert').html(data);
    }
    });
    });





    share|improve this answer


























    • in your insert.php you don't need to search data base for country code, state code or city code because you already pass them to php, so remove the 3 queries and in your insert statement use the post values and save them to database

      – abdulsattar-alkhalaf
      Nov 22 '18 at 11:36











    • $query = "INSERT INTO stud (stud_name, mobile, dob,address,photo,gender,country,state,city) VALUES('$name', '$mob', '$dob', '$add', '$photo', '$gender', '$cn', '$st', '$ct')";

      – abdulsattar-alkhalaf
      Nov 22 '18 at 11:37











    • see the edited post, its working and all data are stored in database

      – abdulsattar-alkhalaf
      Nov 22 '18 at 11:42
















    2














    ok let me list all errors in your html



    <label for="name" id="name"><span class="glyphicon glyphicon-user"></span><b> Student Name: </b></label><label id="p1">*</label>


    remove id like this



    <label for="name"><span class="glyphicon glyphicon-user"></span><b> Student Name: </b></label><label id="p1">*</label>


    and add id to this



    <input type="date" class="form-control" name="dob" required />


    add id



    <input type="date" class="form-control" name="dob" id="dob" required />


    in your php



    $output = '';
    $name = $_POST['name']);
    $mob = $_POST['mob_no']);
    $dob = $_POST['dob']);
    $add = $_POST['add']);
    $photo = $_FILES['photo']['name']);
    $gender = $_POST['gender']);
    $cn = $_POST['country']);
    $st = $_POST['state']);
    $ct = $_POST['city']);


    change it to



    $output = '';
    $name = $_POST['name'];
    $mob = $_POST['mob_no'];
    $dob = $_POST['dob'];
    $add = $_POST['add'];
    $photo = $_FILES['photo']['name'];
    $gender = $_POST['gender'];
    $cn = $_POST['country'];
    $st = $_POST['state'];
    $ct = $_POST['city'];


    then remove



    $qrycn= mysqli_query($conn,"select country_code from country_master_academic where country_name=' ".$cn." ' ");
    $row = mysqli_fetch_array($qrycn);
    $country = $row['country_code'];

    $qryst=mysqli_query($conn,"select state_code from master_state where state_name='".$st."'");
    $row = mysqli_fetch_array($qryst);
    $state = $row['state_code'];

    $qryct= mysqli_query($conn,"select city_code from master_city where city_name='".$ct."'");
    $row = mysqli_fetch_array($qryct);
    $city = $row['city_code'];


    and change insert to



    $query = "INSERT INTO stud (stud_name, mobile, dob,address,photo,gender,country,state,city) VALUES('$name', '$mob', '$dob', '$add', '$photo', '$gender', '$cn', '$st', '$ct')";


    in you js you should use FormData() like this



    $('.insert_data').click(function(){
    var vname = $("#name").val();
    var vmob = $("#mob_no").val();
    var vdob = $("#dob").val();
    var vadd = $("#add").val();
    var vphoto = $("#photo").val();
    var vgender = $("#gender").val();
    var vcountry = $("#country").val();
    var vstate = $("#state").val();
    var vcity = $("#city").val();
    var fd=new FormData();
    fd.append('name',vname);
    fd.append('mob_no',vmob);
    fd.append('dob',vdob);
    fd.append('add',vadd);
    fd.append('photo',vphoto);
    fd.append('gender',vgender);
    fd.append('country',vcountry);
    fd.append('state',vstate);
    fd.append('city',vcity);
    $.ajax({
    url:"insert.php",
    method:"post",
    data: fd,
    success: function(data){
    $('#form')[0].reset();
    $('#add_data_Modal').modal('hide');
    $('#stud_insert').html(data);
    }
    });
    });





    share|improve this answer


























    • in your insert.php you don't need to search data base for country code, state code or city code because you already pass them to php, so remove the 3 queries and in your insert statement use the post values and save them to database

      – abdulsattar-alkhalaf
      Nov 22 '18 at 11:36











    • $query = "INSERT INTO stud (stud_name, mobile, dob,address,photo,gender,country,state,city) VALUES('$name', '$mob', '$dob', '$add', '$photo', '$gender', '$cn', '$st', '$ct')";

      – abdulsattar-alkhalaf
      Nov 22 '18 at 11:37











    • see the edited post, its working and all data are stored in database

      – abdulsattar-alkhalaf
      Nov 22 '18 at 11:42














    2












    2








    2







    ok let me list all errors in your html



    <label for="name" id="name"><span class="glyphicon glyphicon-user"></span><b> Student Name: </b></label><label id="p1">*</label>


    remove id like this



    <label for="name"><span class="glyphicon glyphicon-user"></span><b> Student Name: </b></label><label id="p1">*</label>


    and add id to this



    <input type="date" class="form-control" name="dob" required />


    add id



    <input type="date" class="form-control" name="dob" id="dob" required />


    in your php



    $output = '';
    $name = $_POST['name']);
    $mob = $_POST['mob_no']);
    $dob = $_POST['dob']);
    $add = $_POST['add']);
    $photo = $_FILES['photo']['name']);
    $gender = $_POST['gender']);
    $cn = $_POST['country']);
    $st = $_POST['state']);
    $ct = $_POST['city']);


    change it to



    $output = '';
    $name = $_POST['name'];
    $mob = $_POST['mob_no'];
    $dob = $_POST['dob'];
    $add = $_POST['add'];
    $photo = $_FILES['photo']['name'];
    $gender = $_POST['gender'];
    $cn = $_POST['country'];
    $st = $_POST['state'];
    $ct = $_POST['city'];


    then remove



    $qrycn= mysqli_query($conn,"select country_code from country_master_academic where country_name=' ".$cn." ' ");
    $row = mysqli_fetch_array($qrycn);
    $country = $row['country_code'];

    $qryst=mysqli_query($conn,"select state_code from master_state where state_name='".$st."'");
    $row = mysqli_fetch_array($qryst);
    $state = $row['state_code'];

    $qryct= mysqli_query($conn,"select city_code from master_city where city_name='".$ct."'");
    $row = mysqli_fetch_array($qryct);
    $city = $row['city_code'];


    and change insert to



    $query = "INSERT INTO stud (stud_name, mobile, dob,address,photo,gender,country,state,city) VALUES('$name', '$mob', '$dob', '$add', '$photo', '$gender', '$cn', '$st', '$ct')";


    in you js you should use FormData() like this



    $('.insert_data').click(function(){
    var vname = $("#name").val();
    var vmob = $("#mob_no").val();
    var vdob = $("#dob").val();
    var vadd = $("#add").val();
    var vphoto = $("#photo").val();
    var vgender = $("#gender").val();
    var vcountry = $("#country").val();
    var vstate = $("#state").val();
    var vcity = $("#city").val();
    var fd=new FormData();
    fd.append('name',vname);
    fd.append('mob_no',vmob);
    fd.append('dob',vdob);
    fd.append('add',vadd);
    fd.append('photo',vphoto);
    fd.append('gender',vgender);
    fd.append('country',vcountry);
    fd.append('state',vstate);
    fd.append('city',vcity);
    $.ajax({
    url:"insert.php",
    method:"post",
    data: fd,
    success: function(data){
    $('#form')[0].reset();
    $('#add_data_Modal').modal('hide');
    $('#stud_insert').html(data);
    }
    });
    });





    share|improve this answer















    ok let me list all errors in your html



    <label for="name" id="name"><span class="glyphicon glyphicon-user"></span><b> Student Name: </b></label><label id="p1">*</label>


    remove id like this



    <label for="name"><span class="glyphicon glyphicon-user"></span><b> Student Name: </b></label><label id="p1">*</label>


    and add id to this



    <input type="date" class="form-control" name="dob" required />


    add id



    <input type="date" class="form-control" name="dob" id="dob" required />


    in your php



    $output = '';
    $name = $_POST['name']);
    $mob = $_POST['mob_no']);
    $dob = $_POST['dob']);
    $add = $_POST['add']);
    $photo = $_FILES['photo']['name']);
    $gender = $_POST['gender']);
    $cn = $_POST['country']);
    $st = $_POST['state']);
    $ct = $_POST['city']);


    change it to



    $output = '';
    $name = $_POST['name'];
    $mob = $_POST['mob_no'];
    $dob = $_POST['dob'];
    $add = $_POST['add'];
    $photo = $_FILES['photo']['name'];
    $gender = $_POST['gender'];
    $cn = $_POST['country'];
    $st = $_POST['state'];
    $ct = $_POST['city'];


    then remove



    $qrycn= mysqli_query($conn,"select country_code from country_master_academic where country_name=' ".$cn." ' ");
    $row = mysqli_fetch_array($qrycn);
    $country = $row['country_code'];

    $qryst=mysqli_query($conn,"select state_code from master_state where state_name='".$st."'");
    $row = mysqli_fetch_array($qryst);
    $state = $row['state_code'];

    $qryct= mysqli_query($conn,"select city_code from master_city where city_name='".$ct."'");
    $row = mysqli_fetch_array($qryct);
    $city = $row['city_code'];


    and change insert to



    $query = "INSERT INTO stud (stud_name, mobile, dob,address,photo,gender,country,state,city) VALUES('$name', '$mob', '$dob', '$add', '$photo', '$gender', '$cn', '$st', '$ct')";


    in you js you should use FormData() like this



    $('.insert_data').click(function(){
    var vname = $("#name").val();
    var vmob = $("#mob_no").val();
    var vdob = $("#dob").val();
    var vadd = $("#add").val();
    var vphoto = $("#photo").val();
    var vgender = $("#gender").val();
    var vcountry = $("#country").val();
    var vstate = $("#state").val();
    var vcity = $("#city").val();
    var fd=new FormData();
    fd.append('name',vname);
    fd.append('mob_no',vmob);
    fd.append('dob',vdob);
    fd.append('add',vadd);
    fd.append('photo',vphoto);
    fd.append('gender',vgender);
    fd.append('country',vcountry);
    fd.append('state',vstate);
    fd.append('city',vcity);
    $.ajax({
    url:"insert.php",
    method:"post",
    data: fd,
    success: function(data){
    $('#form')[0].reset();
    $('#add_data_Modal').modal('hide');
    $('#stud_insert').html(data);
    }
    });
    });






    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited Nov 22 '18 at 11:39

























    answered Nov 22 '18 at 11:02









    abdulsattar-alkhalafabdulsattar-alkhalaf

    31715




    31715













    • in your insert.php you don't need to search data base for country code, state code or city code because you already pass them to php, so remove the 3 queries and in your insert statement use the post values and save them to database

      – abdulsattar-alkhalaf
      Nov 22 '18 at 11:36











    • $query = "INSERT INTO stud (stud_name, mobile, dob,address,photo,gender,country,state,city) VALUES('$name', '$mob', '$dob', '$add', '$photo', '$gender', '$cn', '$st', '$ct')";

      – abdulsattar-alkhalaf
      Nov 22 '18 at 11:37











    • see the edited post, its working and all data are stored in database

      – abdulsattar-alkhalaf
      Nov 22 '18 at 11:42



















    • in your insert.php you don't need to search data base for country code, state code or city code because you already pass them to php, so remove the 3 queries and in your insert statement use the post values and save them to database

      – abdulsattar-alkhalaf
      Nov 22 '18 at 11:36











    • $query = "INSERT INTO stud (stud_name, mobile, dob,address,photo,gender,country,state,city) VALUES('$name', '$mob', '$dob', '$add', '$photo', '$gender', '$cn', '$st', '$ct')";

      – abdulsattar-alkhalaf
      Nov 22 '18 at 11:37











    • see the edited post, its working and all data are stored in database

      – abdulsattar-alkhalaf
      Nov 22 '18 at 11:42

















    in your insert.php you don't need to search data base for country code, state code or city code because you already pass them to php, so remove the 3 queries and in your insert statement use the post values and save them to database

    – abdulsattar-alkhalaf
    Nov 22 '18 at 11:36





    in your insert.php you don't need to search data base for country code, state code or city code because you already pass them to php, so remove the 3 queries and in your insert statement use the post values and save them to database

    – abdulsattar-alkhalaf
    Nov 22 '18 at 11:36













    $query = "INSERT INTO stud (stud_name, mobile, dob,address,photo,gender,country,state,city) VALUES('$name', '$mob', '$dob', '$add', '$photo', '$gender', '$cn', '$st', '$ct')";

    – abdulsattar-alkhalaf
    Nov 22 '18 at 11:37





    $query = "INSERT INTO stud (stud_name, mobile, dob,address,photo,gender,country,state,city) VALUES('$name', '$mob', '$dob', '$add', '$photo', '$gender', '$cn', '$st', '$ct')";

    – abdulsattar-alkhalaf
    Nov 22 '18 at 11:37













    see the edited post, its working and all data are stored in database

    – abdulsattar-alkhalaf
    Nov 22 '18 at 11:42





    see the edited post, its working and all data are stored in database

    – abdulsattar-alkhalaf
    Nov 22 '18 at 11:42











    0














    New code for Insert:
    Thank u every one for helping me.



    <?php
    include("connection.php");
    if(!empty($_POST))
    {
    $output = '';
    $name = $_POST['name'];
    $mob = $_POST['mob_no'];
    $dob = $_POST['dob'];
    $add = $_POST['add'];
    $photo = $_FILES['photo']['name'];
    $gender = $_POST['gender'];
    $cn = $_POST['country'];
    $st = $_POST['state'];
    $ct = $_POST['city'];

    $query = "INSERT INTO stud(stud_name, mobile, dob,address,photo,gender,country,state,city)VALUES('$name', '$mob', '$dob', '$add', '$photo', '$gender', '$cn', '$st', '$ct ')";
    if (mysqli_query($conn, $query)) {

    $target_dir="images/";
    $target_file=$target_dir.basename($_FILES["photo"]["name"]);
    $imageFileType=pathinfo($target_file,PATHINFO_EXTENSION);
    if(move_uploaded_file($_FILES["photo"]["tmp_name"],$target_file)){
    echo '<script language="javascript">';
    echo 'alert("Image Inserted Successfully")';
    echo '</script>';
    } else {
    echo '<script language="javascript">';
    echo 'alert("Cannot upload")';
    echo '</script>';
    }
    echo '<script language="javascript">';
    echo 'alert("Data Inserted Successfully")';
    echo '</script>';
    }
    else {
    echo '<script language="javascript">';
    echo 'alert("Cannot insert record")';
    echo '</script>';
    }
    }


    ?>






    share|improve this answer






























      0














      New code for Insert:
      Thank u every one for helping me.



      <?php
      include("connection.php");
      if(!empty($_POST))
      {
      $output = '';
      $name = $_POST['name'];
      $mob = $_POST['mob_no'];
      $dob = $_POST['dob'];
      $add = $_POST['add'];
      $photo = $_FILES['photo']['name'];
      $gender = $_POST['gender'];
      $cn = $_POST['country'];
      $st = $_POST['state'];
      $ct = $_POST['city'];

      $query = "INSERT INTO stud(stud_name, mobile, dob,address,photo,gender,country,state,city)VALUES('$name', '$mob', '$dob', '$add', '$photo', '$gender', '$cn', '$st', '$ct ')";
      if (mysqli_query($conn, $query)) {

      $target_dir="images/";
      $target_file=$target_dir.basename($_FILES["photo"]["name"]);
      $imageFileType=pathinfo($target_file,PATHINFO_EXTENSION);
      if(move_uploaded_file($_FILES["photo"]["tmp_name"],$target_file)){
      echo '<script language="javascript">';
      echo 'alert("Image Inserted Successfully")';
      echo '</script>';
      } else {
      echo '<script language="javascript">';
      echo 'alert("Cannot upload")';
      echo '</script>';
      }
      echo '<script language="javascript">';
      echo 'alert("Data Inserted Successfully")';
      echo '</script>';
      }
      else {
      echo '<script language="javascript">';
      echo 'alert("Cannot insert record")';
      echo '</script>';
      }
      }


      ?>






      share|improve this answer




























        0












        0








        0







        New code for Insert:
        Thank u every one for helping me.



        <?php
        include("connection.php");
        if(!empty($_POST))
        {
        $output = '';
        $name = $_POST['name'];
        $mob = $_POST['mob_no'];
        $dob = $_POST['dob'];
        $add = $_POST['add'];
        $photo = $_FILES['photo']['name'];
        $gender = $_POST['gender'];
        $cn = $_POST['country'];
        $st = $_POST['state'];
        $ct = $_POST['city'];

        $query = "INSERT INTO stud(stud_name, mobile, dob,address,photo,gender,country,state,city)VALUES('$name', '$mob', '$dob', '$add', '$photo', '$gender', '$cn', '$st', '$ct ')";
        if (mysqli_query($conn, $query)) {

        $target_dir="images/";
        $target_file=$target_dir.basename($_FILES["photo"]["name"]);
        $imageFileType=pathinfo($target_file,PATHINFO_EXTENSION);
        if(move_uploaded_file($_FILES["photo"]["tmp_name"],$target_file)){
        echo '<script language="javascript">';
        echo 'alert("Image Inserted Successfully")';
        echo '</script>';
        } else {
        echo '<script language="javascript">';
        echo 'alert("Cannot upload")';
        echo '</script>';
        }
        echo '<script language="javascript">';
        echo 'alert("Data Inserted Successfully")';
        echo '</script>';
        }
        else {
        echo '<script language="javascript">';
        echo 'alert("Cannot insert record")';
        echo '</script>';
        }
        }


        ?>






        share|improve this answer















        New code for Insert:
        Thank u every one for helping me.



        <?php
        include("connection.php");
        if(!empty($_POST))
        {
        $output = '';
        $name = $_POST['name'];
        $mob = $_POST['mob_no'];
        $dob = $_POST['dob'];
        $add = $_POST['add'];
        $photo = $_FILES['photo']['name'];
        $gender = $_POST['gender'];
        $cn = $_POST['country'];
        $st = $_POST['state'];
        $ct = $_POST['city'];

        $query = "INSERT INTO stud(stud_name, mobile, dob,address,photo,gender,country,state,city)VALUES('$name', '$mob', '$dob', '$add', '$photo', '$gender', '$cn', '$st', '$ct ')";
        if (mysqli_query($conn, $query)) {

        $target_dir="images/";
        $target_file=$target_dir.basename($_FILES["photo"]["name"]);
        $imageFileType=pathinfo($target_file,PATHINFO_EXTENSION);
        if(move_uploaded_file($_FILES["photo"]["tmp_name"],$target_file)){
        echo '<script language="javascript">';
        echo 'alert("Image Inserted Successfully")';
        echo '</script>';
        } else {
        echo '<script language="javascript">';
        echo 'alert("Cannot upload")';
        echo '</script>';
        }
        echo '<script language="javascript">';
        echo 'alert("Data Inserted Successfully")';
        echo '</script>';
        }
        else {
        echo '<script language="javascript">';
        echo 'alert("Cannot insert record")';
        echo '</script>';
        }
        }


        ?>







        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited Nov 22 '18 at 11:34

























        answered Nov 22 '18 at 10:31









        Jaicy JosephJaicy Joseph

        207




        207






























            draft saved

            draft discarded




















































            Thanks for contributing an answer to Stack Overflow!


            • Please be sure to answer the question. Provide details and share your research!

            But avoid



            • Asking for help, clarification, or responding to other answers.

            • Making statements based on opinion; back them up with references or personal experience.


            To learn more, see our tips on writing great answers.




            draft saved


            draft discarded














            StackExchange.ready(
            function () {
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53428218%2fhow-to-pass-form-data-using-jquery-ajax-to-insert-data-in-database%23new-answer', 'question_page');
            }
            );

            Post as a guest















            Required, but never shown





















































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown

































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown







            Popular posts from this blog

            404 Error Contact Form 7 ajax form submitting

            How to know if a Active Directory user can login interactively

            TypeError: fit_transform() missing 1 required positional argument: 'X'