Draw functions on Plot3D
2
$begingroup$
I have a 2D function $f(x,z)$ which I render with Plot3D. In the plot, on top of the surface, I want to plot 1D functions at $f(0, z)$, $f(100, z)$ and $f(200, z)$.
So far I only have this:
um = 1;
Potential[V0_, k_, w_, x_, z_] := V0*(Sin[k z]^2)*Exp[(-2 x^2)/w^2]
mfx =
Function[{x, y, z}, Evaluate[D[Potential[1, (2 π)/(0.725 um ), 200 um, x, z], x]]];
Plot3D[Potential[1, (2 π)/(0.725 um ), 200 um, x, z],
{x, -500 um, 500 um}, {z, -1.1 um, 1.1 um},
PlotRange -> Full,
AxesLabel -> {x, z},
PlotPoints -> 50,
MeshFunctions -> {mfx},
Mesh -> {{0}},
MeshStyle -> {{Red}},
Boxed -> False,
Axes -> {True, False, False},
PlotStyle -> Cyan]
And I get this:
This only works for the $x = 0$ bit though.. how can I also add lines at $x = 100, 200$?
plotting
edited 3 hours ago
m_goldberg
85k872196
asked 4 hours ago
SuperCiociaSuperCiocia
575312
$endgroup$
add a comment |
2
$begingroup$
I have a 2D function $f(x,z)$ which I render with Plot3D. In the plot, on top of the surface, I want to plot 1D functions at $f(0, z)$, $f(100, z)$ and $f(200, z)$.
So far I only have this:
um = 1;
Potential[V0_, k_, w_, x_, z_] := V0*(Sin[k z]^2)*Exp[(-2 x^2)/w^2]
mfx =
Function[{x, y, z}, Evaluate[D[Potential[1, (2 π)/(0.725 um ), 200 um, x, z], x]]];
Plot3D[Potential[1, (2 π)/(0.725 um ), 200 um, x, z],
{x, -500 um, 500 um}, {z, -1.1 um, 1.1 um},
PlotRange -> Full,
AxesLabel -> {x, z},
PlotPoints -> 50,
MeshFunctions -> {mfx},
Mesh -> {{0}},
MeshStyle -> {{Red}},
Boxed -> False,
Axes -> {True, False, False},
PlotStyle -> Cyan]
And I get this:
This only works for the $x = 0$ bit though.. how can I also add lines at $x = 100, 200$?
plotting
edited 3 hours ago
m_goldberg
85k872196
asked 4 hours ago
SuperCiociaSuperCiocia
575312
$endgroup$
add a comment |
2
2
2
$begingroup$
I have a 2D function $f(x,z)$ which I render with Plot3D. In the plot, on top of the surface, I want to plot 1D functions at $f(0, z)$, $f(100, z)$ and $f(200, z)$.
So far I only have this:
um = 1;
Potential[V0_, k_, w_, x_, z_] := V0*(Sin[k z]^2)*Exp[(-2 x^2)/w^2]
mfx =
Function[{x, y, z}, Evaluate[D[Potential[1, (2 π)/(0.725 um ), 200 um, x, z], x]]];
Plot3D[Potential[1, (2 π)/(0.725 um ), 200 um, x, z],
{x, -500 um, 500 um}, {z, -1.1 um, 1.1 um},
PlotRange -> Full,
AxesLabel -> {x, z},
PlotPoints -> 50,
MeshFunctions -> {mfx},
Mesh -> {{0}},
MeshStyle -> {{Red}},
Boxed -> False,
Axes -> {True, False, False},
PlotStyle -> Cyan]
And I get this:
This only works for the $x = 0$ bit though.. how can I also add lines at $x = 100, 200$?
plotting
edited 3 hours ago
m_goldberg
85k872196
asked 4 hours ago
SuperCiociaSuperCiocia
575312
$endgroup$
I have a 2D function $f(x,z)$ which I render with Plot3D. In the plot, on top of the surface, I want to plot 1D functions at $f(0, z)$, $f(100, z)$ and $f(200, z)$.
So far I only have this:
um = 1;
Potential[V0_, k_, w_, x_, z_] := V0*(Sin[k z]^2)*Exp[(-2 x^2)/w^2]
mfx =
Function[{x, y, z}, Evaluate[D[Potential[1, (2 π)/(0.725 um ), 200 um, x, z], x]]];
Plot3D[Potential[1, (2 π)/(0.725 um ), 200 um, x, z],
{x, -500 um, 500 um}, {z, -1.1 um, 1.1 um},
PlotRange -> Full,
AxesLabel -> {x, z},
PlotPoints -> 50,
MeshFunctions -> {mfx},
Mesh -> {{0}},
MeshStyle -> {{Red}},
Boxed -> False,
Axes -> {True, False, False},
PlotStyle -> Cyan]
And I get this:
This only works for the $x = 0$ bit though.. how can I also add lines at $x = 100, 200$?
plotting
plotting
edited 3 hours ago
m_goldberg
85k872196
asked 4 hours ago
SuperCiociaSuperCiocia
575312
edited 3 hours ago
m_goldberg
85k872196
asked 4 hours ago
SuperCiociaSuperCiocia
575312
edited 3 hours ago
m_goldberg
85k872196
edited 3 hours ago
m_goldberg
85k872196
edited 3 hours ago
m_goldberg
85k872196
85k872196
asked 4 hours ago
SuperCiociaSuperCiocia
575312
asked 4 hours ago
SuperCiociaSuperCiocia
575312
asked 4 hours ago
SuperCiociaSuperCiocia
575312
575312
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
3
$begingroup$
You have to indicate the Mesh as a List
um = 1;
Potential[V0_, k_, w_, x_, z_] := V0*(Sin[k z]^2)*Exp[(-2 x^2)/w^2]
Plot3D[Potential[1, (2 π)/(0.725 um), 200 um, x, z],
{x, -500 um, 500 um}, {z, -1.1 um, 1.1 um},
PlotRange -> Full,
AxesLabel -> {x, z}, PlotPoints -> 50,
Mesh -> {{0, 100, 200}, {30}, {30}}, MeshStyle -> {{Red}},
Boxed -> False, Axes -> {True, False, False}, PlotStyle -> Cyan]
edited 3 hours ago
m_goldberg
85k872196
answered 4 hours ago
M. VerueteM. Veruete
713
$endgroup$
$begingroup$
I have removed the definition ofmfxsince it is not relevant to your solution.
$endgroup$
– m_goldberg
3 hours ago
$begingroup$
I suggestMeshStyle -> {Directive[Red, AbsoluteThickness[4]]}. I think it make for a better looking plot.
$endgroup$
– m_goldberg
3 hours ago
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
3
$begingroup$
You have to indicate the Mesh as a List
um = 1;
Potential[V0_, k_, w_, x_, z_] := V0*(Sin[k z]^2)*Exp[(-2 x^2)/w^2]
Plot3D[Potential[1, (2 π)/(0.725 um), 200 um, x, z],
{x, -500 um, 500 um}, {z, -1.1 um, 1.1 um},
PlotRange -> Full,
AxesLabel -> {x, z}, PlotPoints -> 50,
Mesh -> {{0, 100, 200}, {30}, {30}}, MeshStyle -> {{Red}},
Boxed -> False, Axes -> {True, False, False}, PlotStyle -> Cyan]
edited 3 hours ago
m_goldberg
85k872196
answered 4 hours ago
M. VerueteM. Veruete
713
$endgroup$
$begingroup$
I have removed the definition ofmfxsince it is not relevant to your solution.
$endgroup$
– m_goldberg
3 hours ago
$begingroup$
I suggestMeshStyle -> {Directive[Red, AbsoluteThickness[4]]}. I think it make for a better looking plot.
$endgroup$
– m_goldberg
3 hours ago
add a comment |
3
$begingroup$
You have to indicate the Mesh as a List
um = 1;
Potential[V0_, k_, w_, x_, z_] := V0*(Sin[k z]^2)*Exp[(-2 x^2)/w^2]
Plot3D[Potential[1, (2 π)/(0.725 um), 200 um, x, z],
{x, -500 um, 500 um}, {z, -1.1 um, 1.1 um},
PlotRange -> Full,
AxesLabel -> {x, z}, PlotPoints -> 50,
Mesh -> {{0, 100, 200}, {30}, {30}}, MeshStyle -> {{Red}},
Boxed -> False, Axes -> {True, False, False}, PlotStyle -> Cyan]
edited 3 hours ago
m_goldberg
85k872196
answered 4 hours ago
M. VerueteM. Veruete
713
$endgroup$
$begingroup$
I have removed the definition ofmfxsince it is not relevant to your solution.
$endgroup$
– m_goldberg
3 hours ago
$begingroup$
I suggestMeshStyle -> {Directive[Red, AbsoluteThickness[4]]}. I think it make for a better looking plot.
$endgroup$
– m_goldberg
3 hours ago
add a comment |
3
3
3
$begingroup$
You have to indicate the Mesh as a List
um = 1;
Potential[V0_, k_, w_, x_, z_] := V0*(Sin[k z]^2)*Exp[(-2 x^2)/w^2]
Plot3D[Potential[1, (2 π)/(0.725 um), 200 um, x, z],
{x, -500 um, 500 um}, {z, -1.1 um, 1.1 um},
PlotRange -> Full,
AxesLabel -> {x, z}, PlotPoints -> 50,
Mesh -> {{0, 100, 200}, {30}, {30}}, MeshStyle -> {{Red}},
Boxed -> False, Axes -> {True, False, False}, PlotStyle -> Cyan]
edited 3 hours ago
m_goldberg
85k872196
answered 4 hours ago
M. VerueteM. Veruete
713
$endgroup$
You have to indicate the Mesh as a List
um = 1;
Potential[V0_, k_, w_, x_, z_] := V0*(Sin[k z]^2)*Exp[(-2 x^2)/w^2]
Plot3D[Potential[1, (2 π)/(0.725 um), 200 um, x, z],
{x, -500 um, 500 um}, {z, -1.1 um, 1.1 um},
PlotRange -> Full,
AxesLabel -> {x, z}, PlotPoints -> 50,
Mesh -> {{0, 100, 200}, {30}, {30}}, MeshStyle -> {{Red}},
Boxed -> False, Axes -> {True, False, False}, PlotStyle -> Cyan]
edited 3 hours ago
m_goldberg
85k872196
answered 4 hours ago
M. VerueteM. Veruete
713
edited 3 hours ago
m_goldberg
85k872196
edited 3 hours ago
m_goldberg
85k872196
edited 3 hours ago
m_goldberg
85k872196
85k872196
answered 4 hours ago
M. VerueteM. Veruete
713
answered 4 hours ago
M. VerueteM. Veruete
713
answered 4 hours ago
M. VerueteM. Veruete
713
713
$begingroup$
I have removed the definition ofmfxsince it is not relevant to your solution.
$endgroup$
– m_goldberg
3 hours ago
$begingroup$
I suggestMeshStyle -> {Directive[Red, AbsoluteThickness[4]]}. I think it make for a better looking plot.
$endgroup$
– m_goldberg
3 hours ago
add a comment |
$begingroup$
I have removed the definition ofmfxsince it is not relevant to your solution.
$endgroup$
– m_goldberg
3 hours ago
$begingroup$
I suggestMeshStyle -> {Directive[Red, AbsoluteThickness[4]]}. I think it make for a better looking plot.
$endgroup$
– m_goldberg
3 hours ago
$begingroup$
I have removed the definition of
mfxsince it is not relevant to your solution.$endgroup$
– m_goldberg
3 hours ago
$begingroup$
I have removed the definition of
mfxsince it is not relevant to your solution.$endgroup$
– m_goldberg
3 hours ago
$begingroup$
I suggest
MeshStyle -> {Directive[Red, AbsoluteThickness[4]]}. I think it make for a better looking plot.$endgroup$
– m_goldberg
3 hours ago
$begingroup$
I suggest
MeshStyle -> {Directive[Red, AbsoluteThickness[4]]}. I think it make for a better looking plot.$endgroup$
– m_goldberg
3 hours ago
add a comment |
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