Binary search for students
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I'm putting together an example for students where I would like to show how we can optimize even such basic algorithm like a binary search with respect to hardware. I do not consider threads. I wrote it in C++ and the whole example can be found here. I'm trying to show some examples of the prefetching. The basic algorithm is the following:
using Type = int64_t;
int binarySearch_basic(size_t item_count, const Type arr, int search)
{
int l = 0;
int r = item_count - 1;
while (l <= r) {
int m = l + ((r - l) >> 1);
if (arr[m] == search) return m;
if (arr[m] < search) l = m + 1;
else r = m - 1;
}
return -1;
}
The first optimization simply try to prefetch possible memory in advance
int binarySearch_basic(size_t item_count, const Type arr, int search)
{
int l = 0;
int r = item_count - 1;
while (l <= r) {
int m1 = arr[l + ((r - l) >> 2)]; // new code
int m2 = arr[r - ((r - l) >> 2)]; // new code
int m = l + ((r - l) >> 1);
if (arr[m] == search) return m;
if (arr[m] < search) l = m + 1;
else r = m - 1;
}
return -1;
}
The second optimization is a little bit more sophisticated. It accesses more than one item per iteration which allows read more relevant data per CPU L2 cache miss wait.
int binarySearch_duo(size_t item_count, const Type arr, int search)
{
int l = 0;
int r = item_count - 1;
while (r - l > 7) {
int delta = (r - l) / 3;
int m1 = l + delta;
int m2 = r - delta;
if (arr[m1] == search) return m1;
if (arr[m2] == search) return m2;
if (arr[m1] < search) {
if (arr[m2] < search) {
l = m2 + 1;
}
else {
r = m2 - 1;
l = m1 + 1;
}
}
else {
r = m1 - 1;
}
}
for (int i = l; i <= r; i++)
{
if (arr[i] == search) return i;
}
return -1;
}
Of course, this approach can be done with more accesses per iteration (I'm testing three as well in my demo). I have several questions:
- Are there any other possible significant optimizations that could help the algorithm?
- Is my explanation of the improvement of the last algorithm correct? (is it really due to the fact that the CPU read in parallel two data items; therefore, he waits for it just once not twice like in the first algorithm).
- Are there any other comments about my code?
c++ performance binary-search
New contributor
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add a comment |
$begingroup$
I'm putting together an example for students where I would like to show how we can optimize even such basic algorithm like a binary search with respect to hardware. I do not consider threads. I wrote it in C++ and the whole example can be found here. I'm trying to show some examples of the prefetching. The basic algorithm is the following:
using Type = int64_t;
int binarySearch_basic(size_t item_count, const Type arr, int search)
{
int l = 0;
int r = item_count - 1;
while (l <= r) {
int m = l + ((r - l) >> 1);
if (arr[m] == search) return m;
if (arr[m] < search) l = m + 1;
else r = m - 1;
}
return -1;
}
The first optimization simply try to prefetch possible memory in advance
int binarySearch_basic(size_t item_count, const Type arr, int search)
{
int l = 0;
int r = item_count - 1;
while (l <= r) {
int m1 = arr[l + ((r - l) >> 2)]; // new code
int m2 = arr[r - ((r - l) >> 2)]; // new code
int m = l + ((r - l) >> 1);
if (arr[m] == search) return m;
if (arr[m] < search) l = m + 1;
else r = m - 1;
}
return -1;
}
The second optimization is a little bit more sophisticated. It accesses more than one item per iteration which allows read more relevant data per CPU L2 cache miss wait.
int binarySearch_duo(size_t item_count, const Type arr, int search)
{
int l = 0;
int r = item_count - 1;
while (r - l > 7) {
int delta = (r - l) / 3;
int m1 = l + delta;
int m2 = r - delta;
if (arr[m1] == search) return m1;
if (arr[m2] == search) return m2;
if (arr[m1] < search) {
if (arr[m2] < search) {
l = m2 + 1;
}
else {
r = m2 - 1;
l = m1 + 1;
}
}
else {
r = m1 - 1;
}
}
for (int i = l; i <= r; i++)
{
if (arr[i] == search) return i;
}
return -1;
}
Of course, this approach can be done with more accesses per iteration (I'm testing three as well in my demo). I have several questions:
- Are there any other possible significant optimizations that could help the algorithm?
- Is my explanation of the improvement of the last algorithm correct? (is it really due to the fact that the CPU read in parallel two data items; therefore, he waits for it just once not twice like in the first algorithm).
- Are there any other comments about my code?
c++ performance binary-search
New contributor
$endgroup$
add a comment |
$begingroup$
I'm putting together an example for students where I would like to show how we can optimize even such basic algorithm like a binary search with respect to hardware. I do not consider threads. I wrote it in C++ and the whole example can be found here. I'm trying to show some examples of the prefetching. The basic algorithm is the following:
using Type = int64_t;
int binarySearch_basic(size_t item_count, const Type arr, int search)
{
int l = 0;
int r = item_count - 1;
while (l <= r) {
int m = l + ((r - l) >> 1);
if (arr[m] == search) return m;
if (arr[m] < search) l = m + 1;
else r = m - 1;
}
return -1;
}
The first optimization simply try to prefetch possible memory in advance
int binarySearch_basic(size_t item_count, const Type arr, int search)
{
int l = 0;
int r = item_count - 1;
while (l <= r) {
int m1 = arr[l + ((r - l) >> 2)]; // new code
int m2 = arr[r - ((r - l) >> 2)]; // new code
int m = l + ((r - l) >> 1);
if (arr[m] == search) return m;
if (arr[m] < search) l = m + 1;
else r = m - 1;
}
return -1;
}
The second optimization is a little bit more sophisticated. It accesses more than one item per iteration which allows read more relevant data per CPU L2 cache miss wait.
int binarySearch_duo(size_t item_count, const Type arr, int search)
{
int l = 0;
int r = item_count - 1;
while (r - l > 7) {
int delta = (r - l) / 3;
int m1 = l + delta;
int m2 = r - delta;
if (arr[m1] == search) return m1;
if (arr[m2] == search) return m2;
if (arr[m1] < search) {
if (arr[m2] < search) {
l = m2 + 1;
}
else {
r = m2 - 1;
l = m1 + 1;
}
}
else {
r = m1 - 1;
}
}
for (int i = l; i <= r; i++)
{
if (arr[i] == search) return i;
}
return -1;
}
Of course, this approach can be done with more accesses per iteration (I'm testing three as well in my demo). I have several questions:
- Are there any other possible significant optimizations that could help the algorithm?
- Is my explanation of the improvement of the last algorithm correct? (is it really due to the fact that the CPU read in parallel two data items; therefore, he waits for it just once not twice like in the first algorithm).
- Are there any other comments about my code?
c++ performance binary-search
New contributor
$endgroup$
I'm putting together an example for students where I would like to show how we can optimize even such basic algorithm like a binary search with respect to hardware. I do not consider threads. I wrote it in C++ and the whole example can be found here. I'm trying to show some examples of the prefetching. The basic algorithm is the following:
using Type = int64_t;
int binarySearch_basic(size_t item_count, const Type arr, int search)
{
int l = 0;
int r = item_count - 1;
while (l <= r) {
int m = l + ((r - l) >> 1);
if (arr[m] == search) return m;
if (arr[m] < search) l = m + 1;
else r = m - 1;
}
return -1;
}
The first optimization simply try to prefetch possible memory in advance
int binarySearch_basic(size_t item_count, const Type arr, int search)
{
int l = 0;
int r = item_count - 1;
while (l <= r) {
int m1 = arr[l + ((r - l) >> 2)]; // new code
int m2 = arr[r - ((r - l) >> 2)]; // new code
int m = l + ((r - l) >> 1);
if (arr[m] == search) return m;
if (arr[m] < search) l = m + 1;
else r = m - 1;
}
return -1;
}
The second optimization is a little bit more sophisticated. It accesses more than one item per iteration which allows read more relevant data per CPU L2 cache miss wait.
int binarySearch_duo(size_t item_count, const Type arr, int search)
{
int l = 0;
int r = item_count - 1;
while (r - l > 7) {
int delta = (r - l) / 3;
int m1 = l + delta;
int m2 = r - delta;
if (arr[m1] == search) return m1;
if (arr[m2] == search) return m2;
if (arr[m1] < search) {
if (arr[m2] < search) {
l = m2 + 1;
}
else {
r = m2 - 1;
l = m1 + 1;
}
}
else {
r = m1 - 1;
}
}
for (int i = l; i <= r; i++)
{
if (arr[i] == search) return i;
}
return -1;
}
Of course, this approach can be done with more accesses per iteration (I'm testing three as well in my demo). I have several questions:
- Are there any other possible significant optimizations that could help the algorithm?
- Is my explanation of the improvement of the last algorithm correct? (is it really due to the fact that the CPU read in parallel two data items; therefore, he waits for it just once not twice like in the first algorithm).
- Are there any other comments about my code?
c++ performance binary-search
c++ performance binary-search
New contributor
New contributor
edited 15 mins ago
Toby Speight
23.9k739113
23.9k739113
New contributor
asked 45 mins ago
Radim BačaRadim Bača
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1062
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