Replace a word every N lines with sed between a specific line interval
I have an input file:
Line 1 a
Line 2 b
Line 3 c
Line 4 d
Line 5 e
Line 6 f
Line 7 g
Line 8 h
Line 9 i
Line 10 j
Line 11 k
Line 12 l
Line 13 m
Line 14 n
Line 15 o
Line 16 p
Line 17 q
.
.
.
I want to insert with sed in a specific line interval, say between line 3 and line 17 of the file, a word that replaces the last word of each line every 4 lines.
In this case, let's say I want to put a Z in line 3 of the file, then line 7 of the file (i.e., 3+4), then line 11 of the file (i.e., 7+4), then line 15 of the file (i.e., 11+4).
Is there a way to do this with sed but just opening only once the file that I want to change?
The expected output would be:
Line 1 a
Line 2 b
Line 3 Z
Line 4 d
Line 5 e
Line 6 f
Line 7 Z
Line 8 h
Line 9 i
Line 10 j
Line 11 Z
Line 12 l
Line 13 m
Line 14 n
Line 15 Z
Line 16 p
Line 17 q
.
.
.
sed
edited Nov 21 '18 at 15:12
Benjamin W.
20.3k134655
asked Nov 21 '18 at 14:47
Ivan
53
add a comment |
I have an input file:
Line 1 a
Line 2 b
Line 3 c
Line 4 d
Line 5 e
Line 6 f
Line 7 g
Line 8 h
Line 9 i
Line 10 j
Line 11 k
Line 12 l
Line 13 m
Line 14 n
Line 15 o
Line 16 p
Line 17 q
.
.
.
I want to insert with sed in a specific line interval, say between line 3 and line 17 of the file, a word that replaces the last word of each line every 4 lines.
In this case, let's say I want to put a Z in line 3 of the file, then line 7 of the file (i.e., 3+4), then line 11 of the file (i.e., 7+4), then line 15 of the file (i.e., 11+4).
Is there a way to do this with sed but just opening only once the file that I want to change?
The expected output would be:
Line 1 a
Line 2 b
Line 3 Z
Line 4 d
Line 5 e
Line 6 f
Line 7 Z
Line 8 h
Line 9 i
Line 10 j
Line 11 Z
Line 12 l
Line 13 m
Line 14 n
Line 15 Z
Line 16 p
Line 17 q
.
.
.
sed
edited Nov 21 '18 at 15:12
Benjamin W.
20.3k134655
asked Nov 21 '18 at 14:47
Ivan
53
Generate the desired lines outside of sed: egseq 46 44 180. Use that to generate the sed commands.
– William Pursell
Nov 21 '18 at 14:53
add a comment |
I have an input file:
Line 1 a
Line 2 b
Line 3 c
Line 4 d
Line 5 e
Line 6 f
Line 7 g
Line 8 h
Line 9 i
Line 10 j
Line 11 k
Line 12 l
Line 13 m
Line 14 n
Line 15 o
Line 16 p
Line 17 q
.
.
.
I want to insert with sed in a specific line interval, say between line 3 and line 17 of the file, a word that replaces the last word of each line every 4 lines.
In this case, let's say I want to put a Z in line 3 of the file, then line 7 of the file (i.e., 3+4), then line 11 of the file (i.e., 7+4), then line 15 of the file (i.e., 11+4).
Is there a way to do this with sed but just opening only once the file that I want to change?
The expected output would be:
Line 1 a
Line 2 b
Line 3 Z
Line 4 d
Line 5 e
Line 6 f
Line 7 Z
Line 8 h
Line 9 i
Line 10 j
Line 11 Z
Line 12 l
Line 13 m
Line 14 n
Line 15 Z
Line 16 p
Line 17 q
.
.
.
sed
edited Nov 21 '18 at 15:12
Benjamin W.
20.3k134655
asked Nov 21 '18 at 14:47
Ivan
53
I have an input file:
Line 1 a
Line 2 b
Line 3 c
Line 4 d
Line 5 e
Line 6 f
Line 7 g
Line 8 h
Line 9 i
Line 10 j
Line 11 k
Line 12 l
Line 13 m
Line 14 n
Line 15 o
Line 16 p
Line 17 q
.
.
.
I want to insert with sed in a specific line interval, say between line 3 and line 17 of the file, a word that replaces the last word of each line every 4 lines.
In this case, let's say I want to put a Z in line 3 of the file, then line 7 of the file (i.e., 3+4), then line 11 of the file (i.e., 7+4), then line 15 of the file (i.e., 11+4).
Is there a way to do this with sed but just opening only once the file that I want to change?
The expected output would be:
Line 1 a
Line 2 b
Line 3 Z
Line 4 d
Line 5 e
Line 6 f
Line 7 Z
Line 8 h
Line 9 i
Line 10 j
Line 11 Z
Line 12 l
Line 13 m
Line 14 n
Line 15 Z
Line 16 p
Line 17 q
.
.
.
sed
sed
edited Nov 21 '18 at 15:12
Benjamin W.
20.3k134655
asked Nov 21 '18 at 14:47
Ivan
53
edited Nov 21 '18 at 15:12
Benjamin W.
20.3k134655
asked Nov 21 '18 at 14:47
Ivan
53
edited Nov 21 '18 at 15:12
Benjamin W.
20.3k134655
edited Nov 21 '18 at 15:12
Benjamin W.
20.3k134655
edited Nov 21 '18 at 15:12
Benjamin W.
20.3k134655
20.3k134655
asked Nov 21 '18 at 14:47
Ivan
53
asked Nov 21 '18 at 14:47
Ivan
53
asked Nov 21 '18 at 14:47
Ivan
53
53
Generate the desired lines outside of sed: egseq 46 44 180. Use that to generate the sed commands.
– William Pursell
Nov 21 '18 at 14:53
add a comment |
Generate the desired lines outside of sed: egseq 46 44 180. Use that to generate the sed commands.
– William Pursell
Nov 21 '18 at 14:53
Generate the desired lines outside of sed: eg
seq 46 44 180. Use that to generate the sed commands.– William Pursell
Nov 21 '18 at 14:53
Generate the desired lines outside of sed: eg
seq 46 44 180. Use that to generate the sed commands.– William Pursell
Nov 21 '18 at 14:53
add a comment |
2 Answers
2
active
oldest
votes
If you have GNU sed, you can use the first~step line addressing form:
sed '3,17{3~4s/S*$/Z/}' infile
First, we limit all actions to an address range with 3,17{...}.
Then, within the curly braces, we run this:
3~4s/S*$/Z/
"On line 3 and every 4th line after, replace the last word of the line (S*$ – longest sequence of non-space characters) with Z".
answered Nov 21 '18 at 15:07
Benjamin W.
20.3k134655
add a comment |
Using POSIX sed, you can do:
sed '3,17{s/[^ ]*$/Z/;n;n;n;}'
An alternative could be awk which can be made a bit more flexible:
awk 'NR==3,NR==17{if (c++%4==0) { $NF="Z" }}1'
answered Nov 21 '18 at 18:40
kvantour
7,93831129
add a comment |
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2 Answers
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active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
If you have GNU sed, you can use the first~step line addressing form:
sed '3,17{3~4s/S*$/Z/}' infile
First, we limit all actions to an address range with 3,17{...}.
Then, within the curly braces, we run this:
3~4s/S*$/Z/
"On line 3 and every 4th line after, replace the last word of the line (S*$ – longest sequence of non-space characters) with Z".
answered Nov 21 '18 at 15:07
Benjamin W.
20.3k134655
add a comment |
If you have GNU sed, you can use the first~step line addressing form:
sed '3,17{3~4s/S*$/Z/}' infile
First, we limit all actions to an address range with 3,17{...}.
Then, within the curly braces, we run this:
3~4s/S*$/Z/
"On line 3 and every 4th line after, replace the last word of the line (S*$ – longest sequence of non-space characters) with Z".
answered Nov 21 '18 at 15:07
Benjamin W.
20.3k134655
add a comment |
If you have GNU sed, you can use the first~step line addressing form:
sed '3,17{3~4s/S*$/Z/}' infile
First, we limit all actions to an address range with 3,17{...}.
Then, within the curly braces, we run this:
3~4s/S*$/Z/
"On line 3 and every 4th line after, replace the last word of the line (S*$ – longest sequence of non-space characters) with Z".
answered Nov 21 '18 at 15:07
Benjamin W.
20.3k134655
If you have GNU sed, you can use the first~step line addressing form:
sed '3,17{3~4s/S*$/Z/}' infile
First, we limit all actions to an address range with 3,17{...}.
Then, within the curly braces, we run this:
3~4s/S*$/Z/
"On line 3 and every 4th line after, replace the last word of the line (S*$ – longest sequence of non-space characters) with Z".
answered Nov 21 '18 at 15:07
Benjamin W.
20.3k134655
answered Nov 21 '18 at 15:07
Benjamin W.
20.3k134655
answered Nov 21 '18 at 15:07
Benjamin W.
20.3k134655
answered Nov 21 '18 at 15:07
Benjamin W.
20.3k134655
20.3k134655
add a comment |
add a comment |
Using POSIX sed, you can do:
sed '3,17{s/[^ ]*$/Z/;n;n;n;}'
An alternative could be awk which can be made a bit more flexible:
awk 'NR==3,NR==17{if (c++%4==0) { $NF="Z" }}1'
answered Nov 21 '18 at 18:40
kvantour
7,93831129
add a comment |
Using POSIX sed, you can do:
sed '3,17{s/[^ ]*$/Z/;n;n;n;}'
An alternative could be awk which can be made a bit more flexible:
awk 'NR==3,NR==17{if (c++%4==0) { $NF="Z" }}1'
answered Nov 21 '18 at 18:40
kvantour
7,93831129
add a comment |
Using POSIX sed, you can do:
sed '3,17{s/[^ ]*$/Z/;n;n;n;}'
An alternative could be awk which can be made a bit more flexible:
awk 'NR==3,NR==17{if (c++%4==0) { $NF="Z" }}1'
answered Nov 21 '18 at 18:40
kvantour
7,93831129
Using POSIX sed, you can do:
sed '3,17{s/[^ ]*$/Z/;n;n;n;}'
An alternative could be awk which can be made a bit more flexible:
awk 'NR==3,NR==17{if (c++%4==0) { $NF="Z" }}1'
answered Nov 21 '18 at 18:40
kvantour
7,93831129
edited Nov 21 '18 at 18:51
answered Nov 21 '18 at 18:40
kvantour
7,93831129
answered Nov 21 '18 at 18:40
kvantour
7,93831129
answered Nov 21 '18 at 18:40
kvantour
7,93831129
7,93831129
add a comment |
add a comment |
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Generate the desired lines outside of sed: eg
seq 46 44 180. Use that to generate the sed commands.– William Pursell
Nov 21 '18 at 14:53