Join one value from an array to each result row
0
I want to select data from a table and assign one value from an array to each result row.
e.g. given a table with the following product data
product
-------
car
bike
elephant
and an array like this
string_to_array('0.8, 0.6, 0.9', ',')
I want to get a table like this
product | value
---------------
bike 0.8
car 0.6
elephant 0.9
Any ideas how to easily solve this?
Something like this
WITH data_table AS (
SELECT
pr.id
, pr.name
FROM
products pr
ORDER BY pr.id
LIMIT 20
)
SELECT
data_table.name
, multipliers[row_number() over(order by data_table.id)]::numeric * data_table.id AS multiplied_value
FROM
data_table
, string_to_array('0.8, 0.6, 0.9, 0.65, 0.34, 0.67, 0.85, 0.12, 0.45, 0.76, 0.68, 0.98, 1.23, 0.69, 0.86, 1.11, 0.75, 1.02, 0.3, 0.79', ',') multipliers
ORDER BY multiplied_value DESC
LIMIT 20
postgresql
asked Nov 22 '18 at 20:07
Joseph TuraJoseph Tura
4,04653767
add a comment |
0
I want to select data from a table and assign one value from an array to each result row.
e.g. given a table with the following product data
product
-------
car
bike
elephant
and an array like this
string_to_array('0.8, 0.6, 0.9', ',')
I want to get a table like this
product | value
---------------
bike 0.8
car 0.6
elephant 0.9
Any ideas how to easily solve this?
Something like this
WITH data_table AS (
SELECT
pr.id
, pr.name
FROM
products pr
ORDER BY pr.id
LIMIT 20
)
SELECT
data_table.name
, multipliers[row_number() over(order by data_table.id)]::numeric * data_table.id AS multiplied_value
FROM
data_table
, string_to_array('0.8, 0.6, 0.9, 0.65, 0.34, 0.67, 0.85, 0.12, 0.45, 0.76, 0.68, 0.98, 1.23, 0.69, 0.86, 1.11, 0.75, 1.02, 0.3, 0.79', ',') multipliers
ORDER BY multiplied_value DESC
LIMIT 20
postgresql
asked Nov 22 '18 at 20:07
Joseph TuraJoseph Tura
4,04653767
Can you be more specific please?
– Kurohige
Nov 22 '18 at 20:12
What is the assign logic? You can update your table, or you have to solve with sql select. You can solve it out of postgre too.
– László Tóth
Nov 22 '18 at 20:25
add a comment |
0
0
0
I want to select data from a table and assign one value from an array to each result row.
e.g. given a table with the following product data
product
-------
car
bike
elephant
and an array like this
string_to_array('0.8, 0.6, 0.9', ',')
I want to get a table like this
product | value
---------------
bike 0.8
car 0.6
elephant 0.9
Any ideas how to easily solve this?
Something like this
WITH data_table AS (
SELECT
pr.id
, pr.name
FROM
products pr
ORDER BY pr.id
LIMIT 20
)
SELECT
data_table.name
, multipliers[row_number() over(order by data_table.id)]::numeric * data_table.id AS multiplied_value
FROM
data_table
, string_to_array('0.8, 0.6, 0.9, 0.65, 0.34, 0.67, 0.85, 0.12, 0.45, 0.76, 0.68, 0.98, 1.23, 0.69, 0.86, 1.11, 0.75, 1.02, 0.3, 0.79', ',') multipliers
ORDER BY multiplied_value DESC
LIMIT 20
postgresql
asked Nov 22 '18 at 20:07
Joseph TuraJoseph Tura
4,04653767
I want to select data from a table and assign one value from an array to each result row.
e.g. given a table with the following product data
product
-------
car
bike
elephant
and an array like this
string_to_array('0.8, 0.6, 0.9', ',')
I want to get a table like this
product | value
---------------
bike 0.8
car 0.6
elephant 0.9
Any ideas how to easily solve this?
Something like this
WITH data_table AS (
SELECT
pr.id
, pr.name
FROM
products pr
ORDER BY pr.id
LIMIT 20
)
SELECT
data_table.name
, multipliers[row_number() over(order by data_table.id)]::numeric * data_table.id AS multiplied_value
FROM
data_table
, string_to_array('0.8, 0.6, 0.9, 0.65, 0.34, 0.67, 0.85, 0.12, 0.45, 0.76, 0.68, 0.98, 1.23, 0.69, 0.86, 1.11, 0.75, 1.02, 0.3, 0.79', ',') multipliers
ORDER BY multiplied_value DESC
LIMIT 20
postgresql
postgresql
asked Nov 22 '18 at 20:07
Joseph TuraJoseph Tura
4,04653767
asked Nov 22 '18 at 20:07
Joseph TuraJoseph Tura
4,04653767
edited Nov 22 '18 at 20:28
Joseph Tura
asked Nov 22 '18 at 20:07
Joseph TuraJoseph Tura
4,04653767
asked Nov 22 '18 at 20:07
Joseph TuraJoseph Tura
4,04653767
asked Nov 22 '18 at 20:07
Joseph TuraJoseph Tura
4,04653767
4,04653767
Can you be more specific please?
– Kurohige
Nov 22 '18 at 20:12
What is the assign logic? You can update your table, or you have to solve with sql select. You can solve it out of postgre too.
– László Tóth
Nov 22 '18 at 20:25
add a comment |
Can you be more specific please?
– Kurohige
Nov 22 '18 at 20:12
What is the assign logic? You can update your table, or you have to solve with sql select. You can solve it out of postgre too.
– László Tóth
Nov 22 '18 at 20:25
Can you be more specific please?
– Kurohige
Nov 22 '18 at 20:12
Can you be more specific please?
– Kurohige
Nov 22 '18 at 20:12
What is the assign logic? You can update your table, or you have to solve with sql select. You can solve it out of postgre too.
– László Tóth
Nov 22 '18 at 20:25
What is the assign logic? You can update your table, or you have to solve with sql select. You can solve it out of postgre too.
– László Tóth
Nov 22 '18 at 20:25
add a comment |
1 Answer
1
active
oldest
votes
0
Assuming the order of the rows should be defined by sorting by name, you can use the following:
select name, n[rn] as value
from (
select name, row_number() over (order by name) as rn,
string_to_array('0.8, 0.6, 0.9', ',') as n
from the_table
) t
answered Nov 22 '18 at 20:27
a_horse_with_no_namea_horse_with_no_name
295k46451546
I think my problem is that I want to order the end result differently from the sort order for determining the row numbers. In the above extended example, I want to sort by the result of the multiplication of the array value with a value in the table.
– Joseph Tura
Nov 22 '18 at 20:38
Actually both your solution and my solution above seem to work fine. Just didn't see it after staring at the screen for too long.
– Joseph Tura
Nov 22 '18 at 20:44
@JosephTura: you can sort the result of my query by any column you like
– a_horse_with_no_name
Nov 22 '18 at 21:14
add a comment |
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1 Answer
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1 Answer
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active
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0
Assuming the order of the rows should be defined by sorting by name, you can use the following:
select name, n[rn] as value
from (
select name, row_number() over (order by name) as rn,
string_to_array('0.8, 0.6, 0.9', ',') as n
from the_table
) t
answered Nov 22 '18 at 20:27
a_horse_with_no_namea_horse_with_no_name
295k46451546
I think my problem is that I want to order the end result differently from the sort order for determining the row numbers. In the above extended example, I want to sort by the result of the multiplication of the array value with a value in the table.
– Joseph Tura
Nov 22 '18 at 20:38
Actually both your solution and my solution above seem to work fine. Just didn't see it after staring at the screen for too long.
– Joseph Tura
Nov 22 '18 at 20:44
@JosephTura: you can sort the result of my query by any column you like
– a_horse_with_no_name
Nov 22 '18 at 21:14
add a comment |
0
Assuming the order of the rows should be defined by sorting by name, you can use the following:
select name, n[rn] as value
from (
select name, row_number() over (order by name) as rn,
string_to_array('0.8, 0.6, 0.9', ',') as n
from the_table
) t
answered Nov 22 '18 at 20:27
a_horse_with_no_namea_horse_with_no_name
295k46451546
I think my problem is that I want to order the end result differently from the sort order for determining the row numbers. In the above extended example, I want to sort by the result of the multiplication of the array value with a value in the table.
– Joseph Tura
Nov 22 '18 at 20:38
Actually both your solution and my solution above seem to work fine. Just didn't see it after staring at the screen for too long.
– Joseph Tura
Nov 22 '18 at 20:44
@JosephTura: you can sort the result of my query by any column you like
– a_horse_with_no_name
Nov 22 '18 at 21:14
add a comment |
0
0
0
Assuming the order of the rows should be defined by sorting by name, you can use the following:
select name, n[rn] as value
from (
select name, row_number() over (order by name) as rn,
string_to_array('0.8, 0.6, 0.9', ',') as n
from the_table
) t
answered Nov 22 '18 at 20:27
a_horse_with_no_namea_horse_with_no_name
295k46451546
Assuming the order of the rows should be defined by sorting by name, you can use the following:
select name, n[rn] as value
from (
select name, row_number() over (order by name) as rn,
string_to_array('0.8, 0.6, 0.9', ',') as n
from the_table
) t
answered Nov 22 '18 at 20:27
a_horse_with_no_namea_horse_with_no_name
295k46451546
answered Nov 22 '18 at 20:27
a_horse_with_no_namea_horse_with_no_name
295k46451546
answered Nov 22 '18 at 20:27
a_horse_with_no_namea_horse_with_no_name
295k46451546
answered Nov 22 '18 at 20:27
a_horse_with_no_namea_horse_with_no_name
295k46451546
295k46451546
I think my problem is that I want to order the end result differently from the sort order for determining the row numbers. In the above extended example, I want to sort by the result of the multiplication of the array value with a value in the table.
– Joseph Tura
Nov 22 '18 at 20:38
Actually both your solution and my solution above seem to work fine. Just didn't see it after staring at the screen for too long.
– Joseph Tura
Nov 22 '18 at 20:44
@JosephTura: you can sort the result of my query by any column you like
– a_horse_with_no_name
Nov 22 '18 at 21:14
add a comment |
I think my problem is that I want to order the end result differently from the sort order for determining the row numbers. In the above extended example, I want to sort by the result of the multiplication of the array value with a value in the table.
– Joseph Tura
Nov 22 '18 at 20:38
Actually both your solution and my solution above seem to work fine. Just didn't see it after staring at the screen for too long.
– Joseph Tura
Nov 22 '18 at 20:44
@JosephTura: you can sort the result of my query by any column you like
– a_horse_with_no_name
Nov 22 '18 at 21:14
I think my problem is that I want to order the end result differently from the sort order for determining the row numbers. In the above extended example, I want to sort by the result of the multiplication of the array value with a value in the table.
– Joseph Tura
Nov 22 '18 at 20:38
I think my problem is that I want to order the end result differently from the sort order for determining the row numbers. In the above extended example, I want to sort by the result of the multiplication of the array value with a value in the table.
– Joseph Tura
Nov 22 '18 at 20:38
Actually both your solution and my solution above seem to work fine. Just didn't see it after staring at the screen for too long.
– Joseph Tura
Nov 22 '18 at 20:44
Actually both your solution and my solution above seem to work fine. Just didn't see it after staring at the screen for too long.
– Joseph Tura
Nov 22 '18 at 20:44
@JosephTura: you can sort the result of my query by any column you like
– a_horse_with_no_name
Nov 22 '18 at 21:14
@JosephTura: you can sort the result of my query by any column you like
– a_horse_with_no_name
Nov 22 '18 at 21:14
add a comment |
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Can you be more specific please?
– Kurohige
Nov 22 '18 at 20:12
What is the assign logic? You can update your table, or you have to solve with sql select. You can solve it out of postgre too.
– László Tóth
Nov 22 '18 at 20:25