Polish notation interpreter/calculator












6














Just for the heck of it, I wrote a simple little interpreter that takes in inputs in the form of Polish Notation.



The user will input something like




+ 5 6




And it will then output




11




Here's another sample input:




+ 5 * 2 3




And the output:




11




Users can even define their own variables, like this:




def myVar 10




and like this:




def anotherVar + 5 6




And then of course reuse those variables. So let's say you type




myVar




it will ouput




10




or




anotherVar




which outputs




11




Furthermore, you type in




+ myVar anotherVar




you would then get




21






I'm a total newbie to well-formatted and readable code. What would be a good way to refactor this?



#include <iostream>
#include <vector>
#include <string>
#include <sstream>

using namespace std;

class Variable
{
public:
Variable(const string& name, double val)
{
this->name = name;
this->val = val;
}

inline const string& get_name() const { return name; }
inline double get_val() const { return val; }
private:
string name;
double val;
};

//----------------------------------

double operate(const string& op, istringstream& iss, vector<Variable>& v);
double perform_addition(istringstream& iss, vector<Variable>& v);
double perform_subtraction(istringstream& iss, vector<Variable>& v);
double perform_division(istringstream& iss, vector<Variable>& v);
double perform_multiplication(istringstream& iss, vector<Variable>& v);
void define_new_var(vector<Variable>& v, istringstream& iss);

bool is_number(const string& op)
{
int char_to_int = op[0];
if (char_to_int >= 48 && char_to_int <= 57)
return true;

return false;
}

void print_var_list(vector<Variable>& v)
{
int size = v.size();
for (int i = 0; i < size; i++)
{
cout << v[i].get_name() << ", " << v[i].get_val() << endl;
}
cout << endl;
}

int main()
{
cout << endl << "LeRPN Programming Language" << endl;

vector<Variable> v;

string temp;
while (cin)
{
cout << endl << "> ";

getline(cin, temp);

istringstream iss(temp);
string op;
iss >> op;

if (op == "quit")
break;
else if (op == "def")
define_new_var(v, iss);
else if (op == "show_vars")
print_var_list(v);
else
cout << endl << operate(op, iss, v) << endl;
}
}

double perform_addition(istringstream& iss, vector<Variable>& v)
{
string left;
iss >> left;

string right;
iss >> right;

return operate(left, iss, v) + operate(right, iss, v);
}

double perform_subtraction(istringstream& iss, vector<Variable>& v)
{
string left;
iss >> left;

string right;
iss >> right;

return operate(left, iss, v) - operate(right, iss, v);
}

double perform_division(istringstream& iss, vector<Variable>& v)
{
string left;
iss >> left;

string right;
iss >> right;

return operate(left, iss, v) / operate(right, iss, v);
}

double perform_multiplication(istringstream& iss, vector<Variable>& v)
{
string left;
iss >> left;

string right;
iss >> right;

return operate(left, iss, v) * operate(right, iss, v);
}

double get_variable(const string& op, vector<Variable>& v)
{
int size = v.size();
for (int i = 0; i < size; i++)
{
if (op == v[i].get_name())
return v[i].get_val();
}
}

double operate(const string& op, istringstream& iss, vector<Variable>& v)
{
double value;
if (op == "+")
value = perform_addition(iss, v);
else if (op == "-")
value = perform_subtraction(iss, v);
else if (op == "/")
value = perform_division(iss, v);
else if(op == "*")
value = perform_multiplication(iss, v);
else if (is_number(op))
value = atof(op.c_str());
else
value = get_variable(op, v);

return value;
}

void define_new_var(vector<Variable>& v, istringstream& iss)
{
string name;
iss >> name;

string temp;
iss >> temp;

double value = operate(temp, iss, v);

v.push_back(Variable(name, value));
}









share|improve this question
























  • You've described Polish notation, not Reverse Polish notation.
    – 200_success
    Jan 26 '14 at 20:50
















6














Just for the heck of it, I wrote a simple little interpreter that takes in inputs in the form of Polish Notation.



The user will input something like




+ 5 6




And it will then output




11




Here's another sample input:




+ 5 * 2 3




And the output:




11




Users can even define their own variables, like this:




def myVar 10




and like this:




def anotherVar + 5 6




And then of course reuse those variables. So let's say you type




myVar




it will ouput




10




or




anotherVar




which outputs




11




Furthermore, you type in




+ myVar anotherVar




you would then get




21






I'm a total newbie to well-formatted and readable code. What would be a good way to refactor this?



#include <iostream>
#include <vector>
#include <string>
#include <sstream>

using namespace std;

class Variable
{
public:
Variable(const string& name, double val)
{
this->name = name;
this->val = val;
}

inline const string& get_name() const { return name; }
inline double get_val() const { return val; }
private:
string name;
double val;
};

//----------------------------------

double operate(const string& op, istringstream& iss, vector<Variable>& v);
double perform_addition(istringstream& iss, vector<Variable>& v);
double perform_subtraction(istringstream& iss, vector<Variable>& v);
double perform_division(istringstream& iss, vector<Variable>& v);
double perform_multiplication(istringstream& iss, vector<Variable>& v);
void define_new_var(vector<Variable>& v, istringstream& iss);

bool is_number(const string& op)
{
int char_to_int = op[0];
if (char_to_int >= 48 && char_to_int <= 57)
return true;

return false;
}

void print_var_list(vector<Variable>& v)
{
int size = v.size();
for (int i = 0; i < size; i++)
{
cout << v[i].get_name() << ", " << v[i].get_val() << endl;
}
cout << endl;
}

int main()
{
cout << endl << "LeRPN Programming Language" << endl;

vector<Variable> v;

string temp;
while (cin)
{
cout << endl << "> ";

getline(cin, temp);

istringstream iss(temp);
string op;
iss >> op;

if (op == "quit")
break;
else if (op == "def")
define_new_var(v, iss);
else if (op == "show_vars")
print_var_list(v);
else
cout << endl << operate(op, iss, v) << endl;
}
}

double perform_addition(istringstream& iss, vector<Variable>& v)
{
string left;
iss >> left;

string right;
iss >> right;

return operate(left, iss, v) + operate(right, iss, v);
}

double perform_subtraction(istringstream& iss, vector<Variable>& v)
{
string left;
iss >> left;

string right;
iss >> right;

return operate(left, iss, v) - operate(right, iss, v);
}

double perform_division(istringstream& iss, vector<Variable>& v)
{
string left;
iss >> left;

string right;
iss >> right;

return operate(left, iss, v) / operate(right, iss, v);
}

double perform_multiplication(istringstream& iss, vector<Variable>& v)
{
string left;
iss >> left;

string right;
iss >> right;

return operate(left, iss, v) * operate(right, iss, v);
}

double get_variable(const string& op, vector<Variable>& v)
{
int size = v.size();
for (int i = 0; i < size; i++)
{
if (op == v[i].get_name())
return v[i].get_val();
}
}

double operate(const string& op, istringstream& iss, vector<Variable>& v)
{
double value;
if (op == "+")
value = perform_addition(iss, v);
else if (op == "-")
value = perform_subtraction(iss, v);
else if (op == "/")
value = perform_division(iss, v);
else if(op == "*")
value = perform_multiplication(iss, v);
else if (is_number(op))
value = atof(op.c_str());
else
value = get_variable(op, v);

return value;
}

void define_new_var(vector<Variable>& v, istringstream& iss)
{
string name;
iss >> name;

string temp;
iss >> temp;

double value = operate(temp, iss, v);

v.push_back(Variable(name, value));
}









share|improve this question
























  • You've described Polish notation, not Reverse Polish notation.
    – 200_success
    Jan 26 '14 at 20:50














6












6








6







Just for the heck of it, I wrote a simple little interpreter that takes in inputs in the form of Polish Notation.



The user will input something like




+ 5 6




And it will then output




11




Here's another sample input:




+ 5 * 2 3




And the output:




11




Users can even define their own variables, like this:




def myVar 10




and like this:




def anotherVar + 5 6




And then of course reuse those variables. So let's say you type




myVar




it will ouput




10




or




anotherVar




which outputs




11




Furthermore, you type in




+ myVar anotherVar




you would then get




21






I'm a total newbie to well-formatted and readable code. What would be a good way to refactor this?



#include <iostream>
#include <vector>
#include <string>
#include <sstream>

using namespace std;

class Variable
{
public:
Variable(const string& name, double val)
{
this->name = name;
this->val = val;
}

inline const string& get_name() const { return name; }
inline double get_val() const { return val; }
private:
string name;
double val;
};

//----------------------------------

double operate(const string& op, istringstream& iss, vector<Variable>& v);
double perform_addition(istringstream& iss, vector<Variable>& v);
double perform_subtraction(istringstream& iss, vector<Variable>& v);
double perform_division(istringstream& iss, vector<Variable>& v);
double perform_multiplication(istringstream& iss, vector<Variable>& v);
void define_new_var(vector<Variable>& v, istringstream& iss);

bool is_number(const string& op)
{
int char_to_int = op[0];
if (char_to_int >= 48 && char_to_int <= 57)
return true;

return false;
}

void print_var_list(vector<Variable>& v)
{
int size = v.size();
for (int i = 0; i < size; i++)
{
cout << v[i].get_name() << ", " << v[i].get_val() << endl;
}
cout << endl;
}

int main()
{
cout << endl << "LeRPN Programming Language" << endl;

vector<Variable> v;

string temp;
while (cin)
{
cout << endl << "> ";

getline(cin, temp);

istringstream iss(temp);
string op;
iss >> op;

if (op == "quit")
break;
else if (op == "def")
define_new_var(v, iss);
else if (op == "show_vars")
print_var_list(v);
else
cout << endl << operate(op, iss, v) << endl;
}
}

double perform_addition(istringstream& iss, vector<Variable>& v)
{
string left;
iss >> left;

string right;
iss >> right;

return operate(left, iss, v) + operate(right, iss, v);
}

double perform_subtraction(istringstream& iss, vector<Variable>& v)
{
string left;
iss >> left;

string right;
iss >> right;

return operate(left, iss, v) - operate(right, iss, v);
}

double perform_division(istringstream& iss, vector<Variable>& v)
{
string left;
iss >> left;

string right;
iss >> right;

return operate(left, iss, v) / operate(right, iss, v);
}

double perform_multiplication(istringstream& iss, vector<Variable>& v)
{
string left;
iss >> left;

string right;
iss >> right;

return operate(left, iss, v) * operate(right, iss, v);
}

double get_variable(const string& op, vector<Variable>& v)
{
int size = v.size();
for (int i = 0; i < size; i++)
{
if (op == v[i].get_name())
return v[i].get_val();
}
}

double operate(const string& op, istringstream& iss, vector<Variable>& v)
{
double value;
if (op == "+")
value = perform_addition(iss, v);
else if (op == "-")
value = perform_subtraction(iss, v);
else if (op == "/")
value = perform_division(iss, v);
else if(op == "*")
value = perform_multiplication(iss, v);
else if (is_number(op))
value = atof(op.c_str());
else
value = get_variable(op, v);

return value;
}

void define_new_var(vector<Variable>& v, istringstream& iss)
{
string name;
iss >> name;

string temp;
iss >> temp;

double value = operate(temp, iss, v);

v.push_back(Variable(name, value));
}









share|improve this question















Just for the heck of it, I wrote a simple little interpreter that takes in inputs in the form of Polish Notation.



The user will input something like




+ 5 6




And it will then output




11




Here's another sample input:




+ 5 * 2 3




And the output:




11




Users can even define their own variables, like this:




def myVar 10




and like this:




def anotherVar + 5 6




And then of course reuse those variables. So let's say you type




myVar




it will ouput




10




or




anotherVar




which outputs




11




Furthermore, you type in




+ myVar anotherVar




you would then get




21






I'm a total newbie to well-formatted and readable code. What would be a good way to refactor this?



#include <iostream>
#include <vector>
#include <string>
#include <sstream>

using namespace std;

class Variable
{
public:
Variable(const string& name, double val)
{
this->name = name;
this->val = val;
}

inline const string& get_name() const { return name; }
inline double get_val() const { return val; }
private:
string name;
double val;
};

//----------------------------------

double operate(const string& op, istringstream& iss, vector<Variable>& v);
double perform_addition(istringstream& iss, vector<Variable>& v);
double perform_subtraction(istringstream& iss, vector<Variable>& v);
double perform_division(istringstream& iss, vector<Variable>& v);
double perform_multiplication(istringstream& iss, vector<Variable>& v);
void define_new_var(vector<Variable>& v, istringstream& iss);

bool is_number(const string& op)
{
int char_to_int = op[0];
if (char_to_int >= 48 && char_to_int <= 57)
return true;

return false;
}

void print_var_list(vector<Variable>& v)
{
int size = v.size();
for (int i = 0; i < size; i++)
{
cout << v[i].get_name() << ", " << v[i].get_val() << endl;
}
cout << endl;
}

int main()
{
cout << endl << "LeRPN Programming Language" << endl;

vector<Variable> v;

string temp;
while (cin)
{
cout << endl << "> ";

getline(cin, temp);

istringstream iss(temp);
string op;
iss >> op;

if (op == "quit")
break;
else if (op == "def")
define_new_var(v, iss);
else if (op == "show_vars")
print_var_list(v);
else
cout << endl << operate(op, iss, v) << endl;
}
}

double perform_addition(istringstream& iss, vector<Variable>& v)
{
string left;
iss >> left;

string right;
iss >> right;

return operate(left, iss, v) + operate(right, iss, v);
}

double perform_subtraction(istringstream& iss, vector<Variable>& v)
{
string left;
iss >> left;

string right;
iss >> right;

return operate(left, iss, v) - operate(right, iss, v);
}

double perform_division(istringstream& iss, vector<Variable>& v)
{
string left;
iss >> left;

string right;
iss >> right;

return operate(left, iss, v) / operate(right, iss, v);
}

double perform_multiplication(istringstream& iss, vector<Variable>& v)
{
string left;
iss >> left;

string right;
iss >> right;

return operate(left, iss, v) * operate(right, iss, v);
}

double get_variable(const string& op, vector<Variable>& v)
{
int size = v.size();
for (int i = 0; i < size; i++)
{
if (op == v[i].get_name())
return v[i].get_val();
}
}

double operate(const string& op, istringstream& iss, vector<Variable>& v)
{
double value;
if (op == "+")
value = perform_addition(iss, v);
else if (op == "-")
value = perform_subtraction(iss, v);
else if (op == "/")
value = perform_division(iss, v);
else if(op == "*")
value = perform_multiplication(iss, v);
else if (is_number(op))
value = atof(op.c_str());
else
value = get_variable(op, v);

return value;
}

void define_new_var(vector<Variable>& v, istringstream& iss)
{
string name;
iss >> name;

string temp;
iss >> temp;

double value = operate(temp, iss, v);

v.push_back(Variable(name, value));
}






c++ calculator math-expression-eval






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share|improve this question








edited Aug 6 '15 at 0:08









Ethan Bierlein

12.8k242136




12.8k242136










asked May 3 '11 at 17:30









skizeey

339129




339129












  • You've described Polish notation, not Reverse Polish notation.
    – 200_success
    Jan 26 '14 at 20:50


















  • You've described Polish notation, not Reverse Polish notation.
    – 200_success
    Jan 26 '14 at 20:50
















You've described Polish notation, not Reverse Polish notation.
– 200_success
Jan 26 '14 at 20:50




You've described Polish notation, not Reverse Polish notation.
– 200_success
Jan 26 '14 at 20:50










5 Answers
5






active

oldest

votes


















5














#include <iostream>
#include <vector>
#include <string>
#include <sstream>
#include <cstdlib> // mmocny: I needed to add this to use atof
#include <functional>

using namespace std;

//----------------------------------

class Variable
{
public:
Variable(const string& name, double val)
: name_(name), val_(val) // mmocny: Use initializer lists
{
}

// mmocny: get_* syntax is less common in C++ than in java etc.
const string& name() const { return name_; } // mmocny: Don't mark as inline (they already are, and its premature optimization)
double val() const { return val_; } // mmocny: Again, don't mark as inline
private:
string name_; // mmocny: suggest renaming name_ or _name: Easier to spot member variables in method code, and no naming conflicts with methods
double val_;
};

//----------------------------------

// mmocny: Replace print_* methods with operator<< so that other (non cout) streams can be used.
// mmocny: Alternatively, define to_string()/str() methods which can also be piped out to different streams
std::ostream & operator<<(std::ostream & out, Variable const & v)
{
return out << v.name() << ", " << v.val() << endl;
}

std::ostream & operator<<(std::ostream & out, vector<Variable> const & v)
{
for (vector<Variable>::const_iterator it = v.begin(), end = v.end(); it != end; ++it ) // mmocny: Use iterators rather than index access
{
out << *it << endl;
}
return out;
}

//----------------------------------

double get_variable(const string& op, vector<Variable>& v)
{
// mmocny: instead of using a vector<Variable> you should be using a map/unordered_map<string,double> and doing a key lookup here
int size = v.size();
for (int i = 0; i < size; i++)
{
if (op == v[i].name())
return v[i].val();
}
// mmocny: what do you do if you don't find the variable?
throw std::exception(); // mmocny: You should do something better than throw a generic exception()
}

//----------------------------------

bool is_number(const string& op)
{
// mmocny: someone else already mentioned: what if op is empty?
int char_to_int = op[0];
// mmocny: couple notes here:
// 1) chars are actually numbers you can reference directly, and not need "magic" constants
// 2) functions in the form "if (...) return true; else return false;" should just be reduced to "return (...);"
// 3) is_number functionality already exists in libc as isdigit()
// 4) long term, you are probably going to want to improve this function.. what about negative numbers? numbers in the form .02? etc..
//return (char_to_int >= '0' && char_to_int <= '9');
return isdigit(char_to_int);
}

//----------------------------------

// mmocny: replace istringstream with istream
// mmocny: you only need to predeclare this one function
double operate(const string& op, istream& in, vector<Variable>& v);

//----------------------------------
/*
* mmocny: All of your perform_* functions have identical code other than the operator being used.
* You can turn all of these functions into a single function template where you pass the operator to be used.
* Luckily, <functional> already has plus minus multiplies divides function objects (functors)
*/

template< class Operator >
double perform_action(istream& in, vector<Variable>& v, Operator op)
{
string left;
in >> left;

double result = operate(left, in, v); // mmocny: This is a big one: for correctness, you must calculate result of left BEFORE you read right

string right;
in >> right;

return op(result, operate(right, in, v));
}

//----------------------------------

double operate(const string& op, istream& in, vector<Variable>& v)
{
double value;
if (op == "+")
value = perform_action(in, v, plus<double>());
else if (op == "-")
value = perform_action(in, v, minus<double>());
else if(op == "*")
value = perform_action(in, v, multiplies<double>());
else if (op == "/")
value = perform_action(in, v, divides<double>());
else if (is_number(op))
value = atof(op.c_str()); // mmocny: consider using boost::lexical_cast<>, or strtod (maybe)
else
value = get_variable(op, v);

return value;
}

//----------------------------------

void define_new_var(vector<Variable>& v, istream& in)
{
string name;
in >> name;

string temp;
in >> temp;

double value = operate(temp, in, v);

v.push_back(Variable(name, value));
}

//----------------------------------

int main()
{
cout << endl << "LeRPN Programming Language" << endl;

vector<Variable> v;

string temp;
while (cin)
{
cout << endl << "> ";

getline(cin, temp);

if (temp.empty()) // mmocny: This also handles the case of CTRL+D
continue;

istringstream iss(temp);
string op;
iss >> op;

if (op == "quit")
break;
else if (op == "def")
define_new_var(v, iss);
else if (op == "show_vars")
std::cout << v << std::endl;
else
cout << endl << operate(op, iss, v) << endl;
}
}


Those are my changes, with comments inline. I would make more changes, but thats enough for now :)



Notice one BIG change: you have a serious correctness bug in your perform_* functions. Not that I've tested my modified code above for all edge cases, but the original code was flat out always wrong for any nested calculations.






share|improve this answer































    3














    As a minor aside, I've renamed it to PN instead of RPN. The form you've give (with operators preceding the operands) is Polish Notation as Jan Łukasiewicz invented it. RPN is when you reverse that, and have the operands first, followed by the applicable operator.



    As to why they decided to call that RPN: because English speakers had a hard enough time figuring out that his last name was pronounced roughly like "Wookashayvitch", not to mention trying to figure out how to say that backwards.



    In any case, I think I'd write the code more like this:



    #include <iostream>
    #include <vector>
    #include <string>
    #include <sstream>
    #include <map>
    #include <iterator>

    using namespace std; // really would *not* normally do this, but...

    void define_var(map<string, int> &v, istringstream& iss) {
    std::string name;
    int value;
    iss >> name >> value;
    v[name] = value;
    }

    int do_op(char op, int val1, int val2) {
    switch (op) {
    case '+': return val1 + val2;
    case '-': return val1 - val2;
    case '*': return val1 * val2;
    case '/': return val1 / val2;
    default:
    string error("Unknown operator: ");
    error += op;
    throw runtime_error(error);
    }
    }

    bool isoperator(char ch) {
    return ch == '+' || ch == '-' || ch == '*' || ch == '/';
    }

    char getop(istream &is) {
    char ch;
    while (isspace(ch = is.peek()))
    is.get(ch);
    ch = is.peek();
    return ch;
    }

    int eval(istream &is, map<string, int> const &v) {
    // evaluate an expression. It consists of:
    // an operator followed by operands, or
    // a number, or
    // a variable.
    //

    char ch = getop(is);

    if (isoperator(ch)) {
    is.get(ch);
    int val1 = eval(is, v);
    int val2 = eval(is, v);
    return do_op(ch, val1, val2);
    }
    if (isdigit(ch)) {
    int val;
    is >> val;
    return val;
    }

    string var_name;
    is >> var_name;
    map<string, int>::const_iterator p = v.find(var_name);
    if (p==v.end()) {
    string problem("Unknown variable: ");
    problem +=var_name;
    throw runtime_error(problem.c_str());
    }
    return p->second;
    }

    // used only for dumping out the variables.
    namespace std {
    ostream &operator<<(ostream &os, pair<string, int> const &v) {
    return os << v.first << ": " << v.second;
    }
    }

    int main() {
    cout << endl << "LePN Programming Language" << endl;

    map<string, int> v;

    string temp;
    cout << endl << "> ";
    while (getline(cin, temp)) {
    istringstream iss(temp);

    string op;
    iss >> op;

    if (op == "quit")
    break;
    else if (op == "def")
    define_var(v, iss);
    else if (op == "show_vars")
    std::copy(v.begin(), v.end(), ostream_iterator<pair<string, int> >(cout, "n"));
    else {
    // Technically, this isn't right -- it only ungets one
    // character, not the whole string.
    // For example, this would interpret "this+ 2 3" as "+ 2 3"
    // and give 5 instead of an error message. Shouldn't affect
    // correct input though.
    //
    iss.unget();
    cout << endl << eval(iss, v) << endl;
    }
    cout << endl << "> ";
    }
    }





    share|improve this answer



















    • 1




      You throw a string in do_op instead of std::runtime_error(), though i imagine that was just overlooked as you do the right thing later... I believe that the ch = is.peek() is not needed in getop() after the loop... i like that you wrote a getop() function that doesn't require op to precede whitespace...
      – mmocny
      May 4 '11 at 2:38










    • @mmocny: Oops, thanks for pointing out the silly mistake in do_op. Perhaps a first: a time that an exception specification might have actually been useful! I think you're right and the ch=is.peek() is technically unnecessary, but at least to me it seemed clearer this way.
      – Jerry Coffin
      May 4 '11 at 2:45








    • 1




      Totally unrelated: depends on your notion of "reverse": a phonemic reversal such as Cziveisakuł would be [tʂiveisakuw], but a phonetic reversal would be [ʂtivejɕakuw], roughly Sztiveiśakuł.
      – Jon Purdy
      May 4 '11 at 23:17










    • Adding an overload to namespace std? :'( Edit: woah.. this is old.. didn't see that
      – dyp
      Jun 15 '14 at 23:27





















    2















    1. double get_variable(const string& op, vector<Variable>& v) -
      must return default value (0.0), for example if op is empty. Alternatively, you can show an error message.



    2. double operate(const string& op, istringstream& iss, vector<Variable>& v) -
      Always initialize variables, like this:



      double value(0.0); OR
      double value = 0.0;


      and you must check this op in vector, if it doesn't exist - show error.



    3. void define_new_var(vector<Variable>& v, istringstream& iss) -
      if variable already exists, set new value or show error.



    4. bool is_number(const string& op)



      int char_to_int = op[0];


      if op is empty.




    5. For this functions:



      double perform_addition(istringstream& iss, vector<Variable>& v);
      double perform_subtraction(istringstream& iss, vector<Variable>& v);
      double perform_division(istringstream& iss, vector<Variable>& v);
      double perform_multiplication(istringstream& iss, vector<Variable>& v);


      Define common function who get left and right.



      I think you can define some enums and functions, like this:



      double perform_operator(istringstream& iss, vector<Variable>& v, OperatorType type)
      {
      std::string lhs, rhs;
      GetValues(iss, lhs, rhs); // fill them
      switch(type)
      {
      case Minus
      {
      return operate(left, iss, v) - operate(right, iss, v);
      }
      break;
      }
      }







    share|improve this answer































      1














      If you look at the similarity of your various perform_xxx functions, it suggests there is duplication that could be removed. One way to do this would be to extract Operator classes, one for each operation, where the common behavior of extracting left and right values from the stream was expressed in the superclass and the individual operations of multiplication, addition, etc. was left to the subclasses.






      share|improve this answer





























        0














        I would not use the writing of expression as you did :



        Exp : + 5 * 2 3 = 11 .... (5 + 2 * 3)



        I would write :



        Exp : 5 2 3 * + = 11 .... (5 + 2 * 3)



        Another example of my writing :



        10 2 * 15 3 * 5 - + .... (10 * 2 + (15 * 3 - 5)) = 20 + (45 - 5) = 20 + 40 = 60



        You have to write the same way you enter in the RPN calculator , such as HP 12C





        share








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          5














          #include <iostream>
          #include <vector>
          #include <string>
          #include <sstream>
          #include <cstdlib> // mmocny: I needed to add this to use atof
          #include <functional>

          using namespace std;

          //----------------------------------

          class Variable
          {
          public:
          Variable(const string& name, double val)
          : name_(name), val_(val) // mmocny: Use initializer lists
          {
          }

          // mmocny: get_* syntax is less common in C++ than in java etc.
          const string& name() const { return name_; } // mmocny: Don't mark as inline (they already are, and its premature optimization)
          double val() const { return val_; } // mmocny: Again, don't mark as inline
          private:
          string name_; // mmocny: suggest renaming name_ or _name: Easier to spot member variables in method code, and no naming conflicts with methods
          double val_;
          };

          //----------------------------------

          // mmocny: Replace print_* methods with operator<< so that other (non cout) streams can be used.
          // mmocny: Alternatively, define to_string()/str() methods which can also be piped out to different streams
          std::ostream & operator<<(std::ostream & out, Variable const & v)
          {
          return out << v.name() << ", " << v.val() << endl;
          }

          std::ostream & operator<<(std::ostream & out, vector<Variable> const & v)
          {
          for (vector<Variable>::const_iterator it = v.begin(), end = v.end(); it != end; ++it ) // mmocny: Use iterators rather than index access
          {
          out << *it << endl;
          }
          return out;
          }

          //----------------------------------

          double get_variable(const string& op, vector<Variable>& v)
          {
          // mmocny: instead of using a vector<Variable> you should be using a map/unordered_map<string,double> and doing a key lookup here
          int size = v.size();
          for (int i = 0; i < size; i++)
          {
          if (op == v[i].name())
          return v[i].val();
          }
          // mmocny: what do you do if you don't find the variable?
          throw std::exception(); // mmocny: You should do something better than throw a generic exception()
          }

          //----------------------------------

          bool is_number(const string& op)
          {
          // mmocny: someone else already mentioned: what if op is empty?
          int char_to_int = op[0];
          // mmocny: couple notes here:
          // 1) chars are actually numbers you can reference directly, and not need "magic" constants
          // 2) functions in the form "if (...) return true; else return false;" should just be reduced to "return (...);"
          // 3) is_number functionality already exists in libc as isdigit()
          // 4) long term, you are probably going to want to improve this function.. what about negative numbers? numbers in the form .02? etc..
          //return (char_to_int >= '0' && char_to_int <= '9');
          return isdigit(char_to_int);
          }

          //----------------------------------

          // mmocny: replace istringstream with istream
          // mmocny: you only need to predeclare this one function
          double operate(const string& op, istream& in, vector<Variable>& v);

          //----------------------------------
          /*
          * mmocny: All of your perform_* functions have identical code other than the operator being used.
          * You can turn all of these functions into a single function template where you pass the operator to be used.
          * Luckily, <functional> already has plus minus multiplies divides function objects (functors)
          */

          template< class Operator >
          double perform_action(istream& in, vector<Variable>& v, Operator op)
          {
          string left;
          in >> left;

          double result = operate(left, in, v); // mmocny: This is a big one: for correctness, you must calculate result of left BEFORE you read right

          string right;
          in >> right;

          return op(result, operate(right, in, v));
          }

          //----------------------------------

          double operate(const string& op, istream& in, vector<Variable>& v)
          {
          double value;
          if (op == "+")
          value = perform_action(in, v, plus<double>());
          else if (op == "-")
          value = perform_action(in, v, minus<double>());
          else if(op == "*")
          value = perform_action(in, v, multiplies<double>());
          else if (op == "/")
          value = perform_action(in, v, divides<double>());
          else if (is_number(op))
          value = atof(op.c_str()); // mmocny: consider using boost::lexical_cast<>, or strtod (maybe)
          else
          value = get_variable(op, v);

          return value;
          }

          //----------------------------------

          void define_new_var(vector<Variable>& v, istream& in)
          {
          string name;
          in >> name;

          string temp;
          in >> temp;

          double value = operate(temp, in, v);

          v.push_back(Variable(name, value));
          }

          //----------------------------------

          int main()
          {
          cout << endl << "LeRPN Programming Language" << endl;

          vector<Variable> v;

          string temp;
          while (cin)
          {
          cout << endl << "> ";

          getline(cin, temp);

          if (temp.empty()) // mmocny: This also handles the case of CTRL+D
          continue;

          istringstream iss(temp);
          string op;
          iss >> op;

          if (op == "quit")
          break;
          else if (op == "def")
          define_new_var(v, iss);
          else if (op == "show_vars")
          std::cout << v << std::endl;
          else
          cout << endl << operate(op, iss, v) << endl;
          }
          }


          Those are my changes, with comments inline. I would make more changes, but thats enough for now :)



          Notice one BIG change: you have a serious correctness bug in your perform_* functions. Not that I've tested my modified code above for all edge cases, but the original code was flat out always wrong for any nested calculations.






          share|improve this answer




























            5














            #include <iostream>
            #include <vector>
            #include <string>
            #include <sstream>
            #include <cstdlib> // mmocny: I needed to add this to use atof
            #include <functional>

            using namespace std;

            //----------------------------------

            class Variable
            {
            public:
            Variable(const string& name, double val)
            : name_(name), val_(val) // mmocny: Use initializer lists
            {
            }

            // mmocny: get_* syntax is less common in C++ than in java etc.
            const string& name() const { return name_; } // mmocny: Don't mark as inline (they already are, and its premature optimization)
            double val() const { return val_; } // mmocny: Again, don't mark as inline
            private:
            string name_; // mmocny: suggest renaming name_ or _name: Easier to spot member variables in method code, and no naming conflicts with methods
            double val_;
            };

            //----------------------------------

            // mmocny: Replace print_* methods with operator<< so that other (non cout) streams can be used.
            // mmocny: Alternatively, define to_string()/str() methods which can also be piped out to different streams
            std::ostream & operator<<(std::ostream & out, Variable const & v)
            {
            return out << v.name() << ", " << v.val() << endl;
            }

            std::ostream & operator<<(std::ostream & out, vector<Variable> const & v)
            {
            for (vector<Variable>::const_iterator it = v.begin(), end = v.end(); it != end; ++it ) // mmocny: Use iterators rather than index access
            {
            out << *it << endl;
            }
            return out;
            }

            //----------------------------------

            double get_variable(const string& op, vector<Variable>& v)
            {
            // mmocny: instead of using a vector<Variable> you should be using a map/unordered_map<string,double> and doing a key lookup here
            int size = v.size();
            for (int i = 0; i < size; i++)
            {
            if (op == v[i].name())
            return v[i].val();
            }
            // mmocny: what do you do if you don't find the variable?
            throw std::exception(); // mmocny: You should do something better than throw a generic exception()
            }

            //----------------------------------

            bool is_number(const string& op)
            {
            // mmocny: someone else already mentioned: what if op is empty?
            int char_to_int = op[0];
            // mmocny: couple notes here:
            // 1) chars are actually numbers you can reference directly, and not need "magic" constants
            // 2) functions in the form "if (...) return true; else return false;" should just be reduced to "return (...);"
            // 3) is_number functionality already exists in libc as isdigit()
            // 4) long term, you are probably going to want to improve this function.. what about negative numbers? numbers in the form .02? etc..
            //return (char_to_int >= '0' && char_to_int <= '9');
            return isdigit(char_to_int);
            }

            //----------------------------------

            // mmocny: replace istringstream with istream
            // mmocny: you only need to predeclare this one function
            double operate(const string& op, istream& in, vector<Variable>& v);

            //----------------------------------
            /*
            * mmocny: All of your perform_* functions have identical code other than the operator being used.
            * You can turn all of these functions into a single function template where you pass the operator to be used.
            * Luckily, <functional> already has plus minus multiplies divides function objects (functors)
            */

            template< class Operator >
            double perform_action(istream& in, vector<Variable>& v, Operator op)
            {
            string left;
            in >> left;

            double result = operate(left, in, v); // mmocny: This is a big one: for correctness, you must calculate result of left BEFORE you read right

            string right;
            in >> right;

            return op(result, operate(right, in, v));
            }

            //----------------------------------

            double operate(const string& op, istream& in, vector<Variable>& v)
            {
            double value;
            if (op == "+")
            value = perform_action(in, v, plus<double>());
            else if (op == "-")
            value = perform_action(in, v, minus<double>());
            else if(op == "*")
            value = perform_action(in, v, multiplies<double>());
            else if (op == "/")
            value = perform_action(in, v, divides<double>());
            else if (is_number(op))
            value = atof(op.c_str()); // mmocny: consider using boost::lexical_cast<>, or strtod (maybe)
            else
            value = get_variable(op, v);

            return value;
            }

            //----------------------------------

            void define_new_var(vector<Variable>& v, istream& in)
            {
            string name;
            in >> name;

            string temp;
            in >> temp;

            double value = operate(temp, in, v);

            v.push_back(Variable(name, value));
            }

            //----------------------------------

            int main()
            {
            cout << endl << "LeRPN Programming Language" << endl;

            vector<Variable> v;

            string temp;
            while (cin)
            {
            cout << endl << "> ";

            getline(cin, temp);

            if (temp.empty()) // mmocny: This also handles the case of CTRL+D
            continue;

            istringstream iss(temp);
            string op;
            iss >> op;

            if (op == "quit")
            break;
            else if (op == "def")
            define_new_var(v, iss);
            else if (op == "show_vars")
            std::cout << v << std::endl;
            else
            cout << endl << operate(op, iss, v) << endl;
            }
            }


            Those are my changes, with comments inline. I would make more changes, but thats enough for now :)



            Notice one BIG change: you have a serious correctness bug in your perform_* functions. Not that I've tested my modified code above for all edge cases, but the original code was flat out always wrong for any nested calculations.






            share|improve this answer


























              5












              5








              5






              #include <iostream>
              #include <vector>
              #include <string>
              #include <sstream>
              #include <cstdlib> // mmocny: I needed to add this to use atof
              #include <functional>

              using namespace std;

              //----------------------------------

              class Variable
              {
              public:
              Variable(const string& name, double val)
              : name_(name), val_(val) // mmocny: Use initializer lists
              {
              }

              // mmocny: get_* syntax is less common in C++ than in java etc.
              const string& name() const { return name_; } // mmocny: Don't mark as inline (they already are, and its premature optimization)
              double val() const { return val_; } // mmocny: Again, don't mark as inline
              private:
              string name_; // mmocny: suggest renaming name_ or _name: Easier to spot member variables in method code, and no naming conflicts with methods
              double val_;
              };

              //----------------------------------

              // mmocny: Replace print_* methods with operator<< so that other (non cout) streams can be used.
              // mmocny: Alternatively, define to_string()/str() methods which can also be piped out to different streams
              std::ostream & operator<<(std::ostream & out, Variable const & v)
              {
              return out << v.name() << ", " << v.val() << endl;
              }

              std::ostream & operator<<(std::ostream & out, vector<Variable> const & v)
              {
              for (vector<Variable>::const_iterator it = v.begin(), end = v.end(); it != end; ++it ) // mmocny: Use iterators rather than index access
              {
              out << *it << endl;
              }
              return out;
              }

              //----------------------------------

              double get_variable(const string& op, vector<Variable>& v)
              {
              // mmocny: instead of using a vector<Variable> you should be using a map/unordered_map<string,double> and doing a key lookup here
              int size = v.size();
              for (int i = 0; i < size; i++)
              {
              if (op == v[i].name())
              return v[i].val();
              }
              // mmocny: what do you do if you don't find the variable?
              throw std::exception(); // mmocny: You should do something better than throw a generic exception()
              }

              //----------------------------------

              bool is_number(const string& op)
              {
              // mmocny: someone else already mentioned: what if op is empty?
              int char_to_int = op[0];
              // mmocny: couple notes here:
              // 1) chars are actually numbers you can reference directly, and not need "magic" constants
              // 2) functions in the form "if (...) return true; else return false;" should just be reduced to "return (...);"
              // 3) is_number functionality already exists in libc as isdigit()
              // 4) long term, you are probably going to want to improve this function.. what about negative numbers? numbers in the form .02? etc..
              //return (char_to_int >= '0' && char_to_int <= '9');
              return isdigit(char_to_int);
              }

              //----------------------------------

              // mmocny: replace istringstream with istream
              // mmocny: you only need to predeclare this one function
              double operate(const string& op, istream& in, vector<Variable>& v);

              //----------------------------------
              /*
              * mmocny: All of your perform_* functions have identical code other than the operator being used.
              * You can turn all of these functions into a single function template where you pass the operator to be used.
              * Luckily, <functional> already has plus minus multiplies divides function objects (functors)
              */

              template< class Operator >
              double perform_action(istream& in, vector<Variable>& v, Operator op)
              {
              string left;
              in >> left;

              double result = operate(left, in, v); // mmocny: This is a big one: for correctness, you must calculate result of left BEFORE you read right

              string right;
              in >> right;

              return op(result, operate(right, in, v));
              }

              //----------------------------------

              double operate(const string& op, istream& in, vector<Variable>& v)
              {
              double value;
              if (op == "+")
              value = perform_action(in, v, plus<double>());
              else if (op == "-")
              value = perform_action(in, v, minus<double>());
              else if(op == "*")
              value = perform_action(in, v, multiplies<double>());
              else if (op == "/")
              value = perform_action(in, v, divides<double>());
              else if (is_number(op))
              value = atof(op.c_str()); // mmocny: consider using boost::lexical_cast<>, or strtod (maybe)
              else
              value = get_variable(op, v);

              return value;
              }

              //----------------------------------

              void define_new_var(vector<Variable>& v, istream& in)
              {
              string name;
              in >> name;

              string temp;
              in >> temp;

              double value = operate(temp, in, v);

              v.push_back(Variable(name, value));
              }

              //----------------------------------

              int main()
              {
              cout << endl << "LeRPN Programming Language" << endl;

              vector<Variable> v;

              string temp;
              while (cin)
              {
              cout << endl << "> ";

              getline(cin, temp);

              if (temp.empty()) // mmocny: This also handles the case of CTRL+D
              continue;

              istringstream iss(temp);
              string op;
              iss >> op;

              if (op == "quit")
              break;
              else if (op == "def")
              define_new_var(v, iss);
              else if (op == "show_vars")
              std::cout << v << std::endl;
              else
              cout << endl << operate(op, iss, v) << endl;
              }
              }


              Those are my changes, with comments inline. I would make more changes, but thats enough for now :)



              Notice one BIG change: you have a serious correctness bug in your perform_* functions. Not that I've tested my modified code above for all edge cases, but the original code was flat out always wrong for any nested calculations.






              share|improve this answer














              #include <iostream>
              #include <vector>
              #include <string>
              #include <sstream>
              #include <cstdlib> // mmocny: I needed to add this to use atof
              #include <functional>

              using namespace std;

              //----------------------------------

              class Variable
              {
              public:
              Variable(const string& name, double val)
              : name_(name), val_(val) // mmocny: Use initializer lists
              {
              }

              // mmocny: get_* syntax is less common in C++ than in java etc.
              const string& name() const { return name_; } // mmocny: Don't mark as inline (they already are, and its premature optimization)
              double val() const { return val_; } // mmocny: Again, don't mark as inline
              private:
              string name_; // mmocny: suggest renaming name_ or _name: Easier to spot member variables in method code, and no naming conflicts with methods
              double val_;
              };

              //----------------------------------

              // mmocny: Replace print_* methods with operator<< so that other (non cout) streams can be used.
              // mmocny: Alternatively, define to_string()/str() methods which can also be piped out to different streams
              std::ostream & operator<<(std::ostream & out, Variable const & v)
              {
              return out << v.name() << ", " << v.val() << endl;
              }

              std::ostream & operator<<(std::ostream & out, vector<Variable> const & v)
              {
              for (vector<Variable>::const_iterator it = v.begin(), end = v.end(); it != end; ++it ) // mmocny: Use iterators rather than index access
              {
              out << *it << endl;
              }
              return out;
              }

              //----------------------------------

              double get_variable(const string& op, vector<Variable>& v)
              {
              // mmocny: instead of using a vector<Variable> you should be using a map/unordered_map<string,double> and doing a key lookup here
              int size = v.size();
              for (int i = 0; i < size; i++)
              {
              if (op == v[i].name())
              return v[i].val();
              }
              // mmocny: what do you do if you don't find the variable?
              throw std::exception(); // mmocny: You should do something better than throw a generic exception()
              }

              //----------------------------------

              bool is_number(const string& op)
              {
              // mmocny: someone else already mentioned: what if op is empty?
              int char_to_int = op[0];
              // mmocny: couple notes here:
              // 1) chars are actually numbers you can reference directly, and not need "magic" constants
              // 2) functions in the form "if (...) return true; else return false;" should just be reduced to "return (...);"
              // 3) is_number functionality already exists in libc as isdigit()
              // 4) long term, you are probably going to want to improve this function.. what about negative numbers? numbers in the form .02? etc..
              //return (char_to_int >= '0' && char_to_int <= '9');
              return isdigit(char_to_int);
              }

              //----------------------------------

              // mmocny: replace istringstream with istream
              // mmocny: you only need to predeclare this one function
              double operate(const string& op, istream& in, vector<Variable>& v);

              //----------------------------------
              /*
              * mmocny: All of your perform_* functions have identical code other than the operator being used.
              * You can turn all of these functions into a single function template where you pass the operator to be used.
              * Luckily, <functional> already has plus minus multiplies divides function objects (functors)
              */

              template< class Operator >
              double perform_action(istream& in, vector<Variable>& v, Operator op)
              {
              string left;
              in >> left;

              double result = operate(left, in, v); // mmocny: This is a big one: for correctness, you must calculate result of left BEFORE you read right

              string right;
              in >> right;

              return op(result, operate(right, in, v));
              }

              //----------------------------------

              double operate(const string& op, istream& in, vector<Variable>& v)
              {
              double value;
              if (op == "+")
              value = perform_action(in, v, plus<double>());
              else if (op == "-")
              value = perform_action(in, v, minus<double>());
              else if(op == "*")
              value = perform_action(in, v, multiplies<double>());
              else if (op == "/")
              value = perform_action(in, v, divides<double>());
              else if (is_number(op))
              value = atof(op.c_str()); // mmocny: consider using boost::lexical_cast<>, or strtod (maybe)
              else
              value = get_variable(op, v);

              return value;
              }

              //----------------------------------

              void define_new_var(vector<Variable>& v, istream& in)
              {
              string name;
              in >> name;

              string temp;
              in >> temp;

              double value = operate(temp, in, v);

              v.push_back(Variable(name, value));
              }

              //----------------------------------

              int main()
              {
              cout << endl << "LeRPN Programming Language" << endl;

              vector<Variable> v;

              string temp;
              while (cin)
              {
              cout << endl << "> ";

              getline(cin, temp);

              if (temp.empty()) // mmocny: This also handles the case of CTRL+D
              continue;

              istringstream iss(temp);
              string op;
              iss >> op;

              if (op == "quit")
              break;
              else if (op == "def")
              define_new_var(v, iss);
              else if (op == "show_vars")
              std::cout << v << std::endl;
              else
              cout << endl << operate(op, iss, v) << endl;
              }
              }


              Those are my changes, with comments inline. I would make more changes, but thats enough for now :)



              Notice one BIG change: you have a serious correctness bug in your perform_* functions. Not that I've tested my modified code above for all edge cases, but the original code was flat out always wrong for any nested calculations.







              share|improve this answer














              share|improve this answer



              share|improve this answer








              edited May 3 '11 at 19:46

























              answered May 3 '11 at 19:39









              mmocny

              1827




              1827

























                  3














                  As a minor aside, I've renamed it to PN instead of RPN. The form you've give (with operators preceding the operands) is Polish Notation as Jan Łukasiewicz invented it. RPN is when you reverse that, and have the operands first, followed by the applicable operator.



                  As to why they decided to call that RPN: because English speakers had a hard enough time figuring out that his last name was pronounced roughly like "Wookashayvitch", not to mention trying to figure out how to say that backwards.



                  In any case, I think I'd write the code more like this:



                  #include <iostream>
                  #include <vector>
                  #include <string>
                  #include <sstream>
                  #include <map>
                  #include <iterator>

                  using namespace std; // really would *not* normally do this, but...

                  void define_var(map<string, int> &v, istringstream& iss) {
                  std::string name;
                  int value;
                  iss >> name >> value;
                  v[name] = value;
                  }

                  int do_op(char op, int val1, int val2) {
                  switch (op) {
                  case '+': return val1 + val2;
                  case '-': return val1 - val2;
                  case '*': return val1 * val2;
                  case '/': return val1 / val2;
                  default:
                  string error("Unknown operator: ");
                  error += op;
                  throw runtime_error(error);
                  }
                  }

                  bool isoperator(char ch) {
                  return ch == '+' || ch == '-' || ch == '*' || ch == '/';
                  }

                  char getop(istream &is) {
                  char ch;
                  while (isspace(ch = is.peek()))
                  is.get(ch);
                  ch = is.peek();
                  return ch;
                  }

                  int eval(istream &is, map<string, int> const &v) {
                  // evaluate an expression. It consists of:
                  // an operator followed by operands, or
                  // a number, or
                  // a variable.
                  //

                  char ch = getop(is);

                  if (isoperator(ch)) {
                  is.get(ch);
                  int val1 = eval(is, v);
                  int val2 = eval(is, v);
                  return do_op(ch, val1, val2);
                  }
                  if (isdigit(ch)) {
                  int val;
                  is >> val;
                  return val;
                  }

                  string var_name;
                  is >> var_name;
                  map<string, int>::const_iterator p = v.find(var_name);
                  if (p==v.end()) {
                  string problem("Unknown variable: ");
                  problem +=var_name;
                  throw runtime_error(problem.c_str());
                  }
                  return p->second;
                  }

                  // used only for dumping out the variables.
                  namespace std {
                  ostream &operator<<(ostream &os, pair<string, int> const &v) {
                  return os << v.first << ": " << v.second;
                  }
                  }

                  int main() {
                  cout << endl << "LePN Programming Language" << endl;

                  map<string, int> v;

                  string temp;
                  cout << endl << "> ";
                  while (getline(cin, temp)) {
                  istringstream iss(temp);

                  string op;
                  iss >> op;

                  if (op == "quit")
                  break;
                  else if (op == "def")
                  define_var(v, iss);
                  else if (op == "show_vars")
                  std::copy(v.begin(), v.end(), ostream_iterator<pair<string, int> >(cout, "n"));
                  else {
                  // Technically, this isn't right -- it only ungets one
                  // character, not the whole string.
                  // For example, this would interpret "this+ 2 3" as "+ 2 3"
                  // and give 5 instead of an error message. Shouldn't affect
                  // correct input though.
                  //
                  iss.unget();
                  cout << endl << eval(iss, v) << endl;
                  }
                  cout << endl << "> ";
                  }
                  }





                  share|improve this answer



















                  • 1




                    You throw a string in do_op instead of std::runtime_error(), though i imagine that was just overlooked as you do the right thing later... I believe that the ch = is.peek() is not needed in getop() after the loop... i like that you wrote a getop() function that doesn't require op to precede whitespace...
                    – mmocny
                    May 4 '11 at 2:38










                  • @mmocny: Oops, thanks for pointing out the silly mistake in do_op. Perhaps a first: a time that an exception specification might have actually been useful! I think you're right and the ch=is.peek() is technically unnecessary, but at least to me it seemed clearer this way.
                    – Jerry Coffin
                    May 4 '11 at 2:45








                  • 1




                    Totally unrelated: depends on your notion of "reverse": a phonemic reversal such as Cziveisakuł would be [tʂiveisakuw], but a phonetic reversal would be [ʂtivejɕakuw], roughly Sztiveiśakuł.
                    – Jon Purdy
                    May 4 '11 at 23:17










                  • Adding an overload to namespace std? :'( Edit: woah.. this is old.. didn't see that
                    – dyp
                    Jun 15 '14 at 23:27


















                  3














                  As a minor aside, I've renamed it to PN instead of RPN. The form you've give (with operators preceding the operands) is Polish Notation as Jan Łukasiewicz invented it. RPN is when you reverse that, and have the operands first, followed by the applicable operator.



                  As to why they decided to call that RPN: because English speakers had a hard enough time figuring out that his last name was pronounced roughly like "Wookashayvitch", not to mention trying to figure out how to say that backwards.



                  In any case, I think I'd write the code more like this:



                  #include <iostream>
                  #include <vector>
                  #include <string>
                  #include <sstream>
                  #include <map>
                  #include <iterator>

                  using namespace std; // really would *not* normally do this, but...

                  void define_var(map<string, int> &v, istringstream& iss) {
                  std::string name;
                  int value;
                  iss >> name >> value;
                  v[name] = value;
                  }

                  int do_op(char op, int val1, int val2) {
                  switch (op) {
                  case '+': return val1 + val2;
                  case '-': return val1 - val2;
                  case '*': return val1 * val2;
                  case '/': return val1 / val2;
                  default:
                  string error("Unknown operator: ");
                  error += op;
                  throw runtime_error(error);
                  }
                  }

                  bool isoperator(char ch) {
                  return ch == '+' || ch == '-' || ch == '*' || ch == '/';
                  }

                  char getop(istream &is) {
                  char ch;
                  while (isspace(ch = is.peek()))
                  is.get(ch);
                  ch = is.peek();
                  return ch;
                  }

                  int eval(istream &is, map<string, int> const &v) {
                  // evaluate an expression. It consists of:
                  // an operator followed by operands, or
                  // a number, or
                  // a variable.
                  //

                  char ch = getop(is);

                  if (isoperator(ch)) {
                  is.get(ch);
                  int val1 = eval(is, v);
                  int val2 = eval(is, v);
                  return do_op(ch, val1, val2);
                  }
                  if (isdigit(ch)) {
                  int val;
                  is >> val;
                  return val;
                  }

                  string var_name;
                  is >> var_name;
                  map<string, int>::const_iterator p = v.find(var_name);
                  if (p==v.end()) {
                  string problem("Unknown variable: ");
                  problem +=var_name;
                  throw runtime_error(problem.c_str());
                  }
                  return p->second;
                  }

                  // used only for dumping out the variables.
                  namespace std {
                  ostream &operator<<(ostream &os, pair<string, int> const &v) {
                  return os << v.first << ": " << v.second;
                  }
                  }

                  int main() {
                  cout << endl << "LePN Programming Language" << endl;

                  map<string, int> v;

                  string temp;
                  cout << endl << "> ";
                  while (getline(cin, temp)) {
                  istringstream iss(temp);

                  string op;
                  iss >> op;

                  if (op == "quit")
                  break;
                  else if (op == "def")
                  define_var(v, iss);
                  else if (op == "show_vars")
                  std::copy(v.begin(), v.end(), ostream_iterator<pair<string, int> >(cout, "n"));
                  else {
                  // Technically, this isn't right -- it only ungets one
                  // character, not the whole string.
                  // For example, this would interpret "this+ 2 3" as "+ 2 3"
                  // and give 5 instead of an error message. Shouldn't affect
                  // correct input though.
                  //
                  iss.unget();
                  cout << endl << eval(iss, v) << endl;
                  }
                  cout << endl << "> ";
                  }
                  }





                  share|improve this answer



















                  • 1




                    You throw a string in do_op instead of std::runtime_error(), though i imagine that was just overlooked as you do the right thing later... I believe that the ch = is.peek() is not needed in getop() after the loop... i like that you wrote a getop() function that doesn't require op to precede whitespace...
                    – mmocny
                    May 4 '11 at 2:38










                  • @mmocny: Oops, thanks for pointing out the silly mistake in do_op. Perhaps a first: a time that an exception specification might have actually been useful! I think you're right and the ch=is.peek() is technically unnecessary, but at least to me it seemed clearer this way.
                    – Jerry Coffin
                    May 4 '11 at 2:45








                  • 1




                    Totally unrelated: depends on your notion of "reverse": a phonemic reversal such as Cziveisakuł would be [tʂiveisakuw], but a phonetic reversal would be [ʂtivejɕakuw], roughly Sztiveiśakuł.
                    – Jon Purdy
                    May 4 '11 at 23:17










                  • Adding an overload to namespace std? :'( Edit: woah.. this is old.. didn't see that
                    – dyp
                    Jun 15 '14 at 23:27
















                  3












                  3








                  3






                  As a minor aside, I've renamed it to PN instead of RPN. The form you've give (with operators preceding the operands) is Polish Notation as Jan Łukasiewicz invented it. RPN is when you reverse that, and have the operands first, followed by the applicable operator.



                  As to why they decided to call that RPN: because English speakers had a hard enough time figuring out that his last name was pronounced roughly like "Wookashayvitch", not to mention trying to figure out how to say that backwards.



                  In any case, I think I'd write the code more like this:



                  #include <iostream>
                  #include <vector>
                  #include <string>
                  #include <sstream>
                  #include <map>
                  #include <iterator>

                  using namespace std; // really would *not* normally do this, but...

                  void define_var(map<string, int> &v, istringstream& iss) {
                  std::string name;
                  int value;
                  iss >> name >> value;
                  v[name] = value;
                  }

                  int do_op(char op, int val1, int val2) {
                  switch (op) {
                  case '+': return val1 + val2;
                  case '-': return val1 - val2;
                  case '*': return val1 * val2;
                  case '/': return val1 / val2;
                  default:
                  string error("Unknown operator: ");
                  error += op;
                  throw runtime_error(error);
                  }
                  }

                  bool isoperator(char ch) {
                  return ch == '+' || ch == '-' || ch == '*' || ch == '/';
                  }

                  char getop(istream &is) {
                  char ch;
                  while (isspace(ch = is.peek()))
                  is.get(ch);
                  ch = is.peek();
                  return ch;
                  }

                  int eval(istream &is, map<string, int> const &v) {
                  // evaluate an expression. It consists of:
                  // an operator followed by operands, or
                  // a number, or
                  // a variable.
                  //

                  char ch = getop(is);

                  if (isoperator(ch)) {
                  is.get(ch);
                  int val1 = eval(is, v);
                  int val2 = eval(is, v);
                  return do_op(ch, val1, val2);
                  }
                  if (isdigit(ch)) {
                  int val;
                  is >> val;
                  return val;
                  }

                  string var_name;
                  is >> var_name;
                  map<string, int>::const_iterator p = v.find(var_name);
                  if (p==v.end()) {
                  string problem("Unknown variable: ");
                  problem +=var_name;
                  throw runtime_error(problem.c_str());
                  }
                  return p->second;
                  }

                  // used only for dumping out the variables.
                  namespace std {
                  ostream &operator<<(ostream &os, pair<string, int> const &v) {
                  return os << v.first << ": " << v.second;
                  }
                  }

                  int main() {
                  cout << endl << "LePN Programming Language" << endl;

                  map<string, int> v;

                  string temp;
                  cout << endl << "> ";
                  while (getline(cin, temp)) {
                  istringstream iss(temp);

                  string op;
                  iss >> op;

                  if (op == "quit")
                  break;
                  else if (op == "def")
                  define_var(v, iss);
                  else if (op == "show_vars")
                  std::copy(v.begin(), v.end(), ostream_iterator<pair<string, int> >(cout, "n"));
                  else {
                  // Technically, this isn't right -- it only ungets one
                  // character, not the whole string.
                  // For example, this would interpret "this+ 2 3" as "+ 2 3"
                  // and give 5 instead of an error message. Shouldn't affect
                  // correct input though.
                  //
                  iss.unget();
                  cout << endl << eval(iss, v) << endl;
                  }
                  cout << endl << "> ";
                  }
                  }





                  share|improve this answer














                  As a minor aside, I've renamed it to PN instead of RPN. The form you've give (with operators preceding the operands) is Polish Notation as Jan Łukasiewicz invented it. RPN is when you reverse that, and have the operands first, followed by the applicable operator.



                  As to why they decided to call that RPN: because English speakers had a hard enough time figuring out that his last name was pronounced roughly like "Wookashayvitch", not to mention trying to figure out how to say that backwards.



                  In any case, I think I'd write the code more like this:



                  #include <iostream>
                  #include <vector>
                  #include <string>
                  #include <sstream>
                  #include <map>
                  #include <iterator>

                  using namespace std; // really would *not* normally do this, but...

                  void define_var(map<string, int> &v, istringstream& iss) {
                  std::string name;
                  int value;
                  iss >> name >> value;
                  v[name] = value;
                  }

                  int do_op(char op, int val1, int val2) {
                  switch (op) {
                  case '+': return val1 + val2;
                  case '-': return val1 - val2;
                  case '*': return val1 * val2;
                  case '/': return val1 / val2;
                  default:
                  string error("Unknown operator: ");
                  error += op;
                  throw runtime_error(error);
                  }
                  }

                  bool isoperator(char ch) {
                  return ch == '+' || ch == '-' || ch == '*' || ch == '/';
                  }

                  char getop(istream &is) {
                  char ch;
                  while (isspace(ch = is.peek()))
                  is.get(ch);
                  ch = is.peek();
                  return ch;
                  }

                  int eval(istream &is, map<string, int> const &v) {
                  // evaluate an expression. It consists of:
                  // an operator followed by operands, or
                  // a number, or
                  // a variable.
                  //

                  char ch = getop(is);

                  if (isoperator(ch)) {
                  is.get(ch);
                  int val1 = eval(is, v);
                  int val2 = eval(is, v);
                  return do_op(ch, val1, val2);
                  }
                  if (isdigit(ch)) {
                  int val;
                  is >> val;
                  return val;
                  }

                  string var_name;
                  is >> var_name;
                  map<string, int>::const_iterator p = v.find(var_name);
                  if (p==v.end()) {
                  string problem("Unknown variable: ");
                  problem +=var_name;
                  throw runtime_error(problem.c_str());
                  }
                  return p->second;
                  }

                  // used only for dumping out the variables.
                  namespace std {
                  ostream &operator<<(ostream &os, pair<string, int> const &v) {
                  return os << v.first << ": " << v.second;
                  }
                  }

                  int main() {
                  cout << endl << "LePN Programming Language" << endl;

                  map<string, int> v;

                  string temp;
                  cout << endl << "> ";
                  while (getline(cin, temp)) {
                  istringstream iss(temp);

                  string op;
                  iss >> op;

                  if (op == "quit")
                  break;
                  else if (op == "def")
                  define_var(v, iss);
                  else if (op == "show_vars")
                  std::copy(v.begin(), v.end(), ostream_iterator<pair<string, int> >(cout, "n"));
                  else {
                  // Technically, this isn't right -- it only ungets one
                  // character, not the whole string.
                  // For example, this would interpret "this+ 2 3" as "+ 2 3"
                  // and give 5 instead of an error message. Shouldn't affect
                  // correct input though.
                  //
                  iss.unget();
                  cout << endl << eval(iss, v) << endl;
                  }
                  cout << endl << "> ";
                  }
                  }






                  share|improve this answer














                  share|improve this answer



                  share|improve this answer








                  edited May 4 '11 at 2:43

























                  answered May 3 '11 at 23:49









                  Jerry Coffin

                  27.8k460125




                  27.8k460125








                  • 1




                    You throw a string in do_op instead of std::runtime_error(), though i imagine that was just overlooked as you do the right thing later... I believe that the ch = is.peek() is not needed in getop() after the loop... i like that you wrote a getop() function that doesn't require op to precede whitespace...
                    – mmocny
                    May 4 '11 at 2:38










                  • @mmocny: Oops, thanks for pointing out the silly mistake in do_op. Perhaps a first: a time that an exception specification might have actually been useful! I think you're right and the ch=is.peek() is technically unnecessary, but at least to me it seemed clearer this way.
                    – Jerry Coffin
                    May 4 '11 at 2:45








                  • 1




                    Totally unrelated: depends on your notion of "reverse": a phonemic reversal such as Cziveisakuł would be [tʂiveisakuw], but a phonetic reversal would be [ʂtivejɕakuw], roughly Sztiveiśakuł.
                    – Jon Purdy
                    May 4 '11 at 23:17










                  • Adding an overload to namespace std? :'( Edit: woah.. this is old.. didn't see that
                    – dyp
                    Jun 15 '14 at 23:27
















                  • 1




                    You throw a string in do_op instead of std::runtime_error(), though i imagine that was just overlooked as you do the right thing later... I believe that the ch = is.peek() is not needed in getop() after the loop... i like that you wrote a getop() function that doesn't require op to precede whitespace...
                    – mmocny
                    May 4 '11 at 2:38










                  • @mmocny: Oops, thanks for pointing out the silly mistake in do_op. Perhaps a first: a time that an exception specification might have actually been useful! I think you're right and the ch=is.peek() is technically unnecessary, but at least to me it seemed clearer this way.
                    – Jerry Coffin
                    May 4 '11 at 2:45








                  • 1




                    Totally unrelated: depends on your notion of "reverse": a phonemic reversal such as Cziveisakuł would be [tʂiveisakuw], but a phonetic reversal would be [ʂtivejɕakuw], roughly Sztiveiśakuł.
                    – Jon Purdy
                    May 4 '11 at 23:17










                  • Adding an overload to namespace std? :'( Edit: woah.. this is old.. didn't see that
                    – dyp
                    Jun 15 '14 at 23:27










                  1




                  1




                  You throw a string in do_op instead of std::runtime_error(), though i imagine that was just overlooked as you do the right thing later... I believe that the ch = is.peek() is not needed in getop() after the loop... i like that you wrote a getop() function that doesn't require op to precede whitespace...
                  – mmocny
                  May 4 '11 at 2:38




                  You throw a string in do_op instead of std::runtime_error(), though i imagine that was just overlooked as you do the right thing later... I believe that the ch = is.peek() is not needed in getop() after the loop... i like that you wrote a getop() function that doesn't require op to precede whitespace...
                  – mmocny
                  May 4 '11 at 2:38












                  @mmocny: Oops, thanks for pointing out the silly mistake in do_op. Perhaps a first: a time that an exception specification might have actually been useful! I think you're right and the ch=is.peek() is technically unnecessary, but at least to me it seemed clearer this way.
                  – Jerry Coffin
                  May 4 '11 at 2:45






                  @mmocny: Oops, thanks for pointing out the silly mistake in do_op. Perhaps a first: a time that an exception specification might have actually been useful! I think you're right and the ch=is.peek() is technically unnecessary, but at least to me it seemed clearer this way.
                  – Jerry Coffin
                  May 4 '11 at 2:45






                  1




                  1




                  Totally unrelated: depends on your notion of "reverse": a phonemic reversal such as Cziveisakuł would be [tʂiveisakuw], but a phonetic reversal would be [ʂtivejɕakuw], roughly Sztiveiśakuł.
                  – Jon Purdy
                  May 4 '11 at 23:17




                  Totally unrelated: depends on your notion of "reverse": a phonemic reversal such as Cziveisakuł would be [tʂiveisakuw], but a phonetic reversal would be [ʂtivejɕakuw], roughly Sztiveiśakuł.
                  – Jon Purdy
                  May 4 '11 at 23:17












                  Adding an overload to namespace std? :'( Edit: woah.. this is old.. didn't see that
                  – dyp
                  Jun 15 '14 at 23:27






                  Adding an overload to namespace std? :'( Edit: woah.. this is old.. didn't see that
                  – dyp
                  Jun 15 '14 at 23:27













                  2















                  1. double get_variable(const string& op, vector<Variable>& v) -
                    must return default value (0.0), for example if op is empty. Alternatively, you can show an error message.



                  2. double operate(const string& op, istringstream& iss, vector<Variable>& v) -
                    Always initialize variables, like this:



                    double value(0.0); OR
                    double value = 0.0;


                    and you must check this op in vector, if it doesn't exist - show error.



                  3. void define_new_var(vector<Variable>& v, istringstream& iss) -
                    if variable already exists, set new value or show error.



                  4. bool is_number(const string& op)



                    int char_to_int = op[0];


                    if op is empty.




                  5. For this functions:



                    double perform_addition(istringstream& iss, vector<Variable>& v);
                    double perform_subtraction(istringstream& iss, vector<Variable>& v);
                    double perform_division(istringstream& iss, vector<Variable>& v);
                    double perform_multiplication(istringstream& iss, vector<Variable>& v);


                    Define common function who get left and right.



                    I think you can define some enums and functions, like this:



                    double perform_operator(istringstream& iss, vector<Variable>& v, OperatorType type)
                    {
                    std::string lhs, rhs;
                    GetValues(iss, lhs, rhs); // fill them
                    switch(type)
                    {
                    case Minus
                    {
                    return operate(left, iss, v) - operate(right, iss, v);
                    }
                    break;
                    }
                    }







                  share|improve this answer




























                    2















                    1. double get_variable(const string& op, vector<Variable>& v) -
                      must return default value (0.0), for example if op is empty. Alternatively, you can show an error message.



                    2. double operate(const string& op, istringstream& iss, vector<Variable>& v) -
                      Always initialize variables, like this:



                      double value(0.0); OR
                      double value = 0.0;


                      and you must check this op in vector, if it doesn't exist - show error.



                    3. void define_new_var(vector<Variable>& v, istringstream& iss) -
                      if variable already exists, set new value or show error.



                    4. bool is_number(const string& op)



                      int char_to_int = op[0];


                      if op is empty.




                    5. For this functions:



                      double perform_addition(istringstream& iss, vector<Variable>& v);
                      double perform_subtraction(istringstream& iss, vector<Variable>& v);
                      double perform_division(istringstream& iss, vector<Variable>& v);
                      double perform_multiplication(istringstream& iss, vector<Variable>& v);


                      Define common function who get left and right.



                      I think you can define some enums and functions, like this:



                      double perform_operator(istringstream& iss, vector<Variable>& v, OperatorType type)
                      {
                      std::string lhs, rhs;
                      GetValues(iss, lhs, rhs); // fill them
                      switch(type)
                      {
                      case Minus
                      {
                      return operate(left, iss, v) - operate(right, iss, v);
                      }
                      break;
                      }
                      }







                    share|improve this answer


























                      2












                      2








                      2







                      1. double get_variable(const string& op, vector<Variable>& v) -
                        must return default value (0.0), for example if op is empty. Alternatively, you can show an error message.



                      2. double operate(const string& op, istringstream& iss, vector<Variable>& v) -
                        Always initialize variables, like this:



                        double value(0.0); OR
                        double value = 0.0;


                        and you must check this op in vector, if it doesn't exist - show error.



                      3. void define_new_var(vector<Variable>& v, istringstream& iss) -
                        if variable already exists, set new value or show error.



                      4. bool is_number(const string& op)



                        int char_to_int = op[0];


                        if op is empty.




                      5. For this functions:



                        double perform_addition(istringstream& iss, vector<Variable>& v);
                        double perform_subtraction(istringstream& iss, vector<Variable>& v);
                        double perform_division(istringstream& iss, vector<Variable>& v);
                        double perform_multiplication(istringstream& iss, vector<Variable>& v);


                        Define common function who get left and right.



                        I think you can define some enums and functions, like this:



                        double perform_operator(istringstream& iss, vector<Variable>& v, OperatorType type)
                        {
                        std::string lhs, rhs;
                        GetValues(iss, lhs, rhs); // fill them
                        switch(type)
                        {
                        case Minus
                        {
                        return operate(left, iss, v) - operate(right, iss, v);
                        }
                        break;
                        }
                        }







                      share|improve this answer















                      1. double get_variable(const string& op, vector<Variable>& v) -
                        must return default value (0.0), for example if op is empty. Alternatively, you can show an error message.



                      2. double operate(const string& op, istringstream& iss, vector<Variable>& v) -
                        Always initialize variables, like this:



                        double value(0.0); OR
                        double value = 0.0;


                        and you must check this op in vector, if it doesn't exist - show error.



                      3. void define_new_var(vector<Variable>& v, istringstream& iss) -
                        if variable already exists, set new value or show error.



                      4. bool is_number(const string& op)



                        int char_to_int = op[0];


                        if op is empty.




                      5. For this functions:



                        double perform_addition(istringstream& iss, vector<Variable>& v);
                        double perform_subtraction(istringstream& iss, vector<Variable>& v);
                        double perform_division(istringstream& iss, vector<Variable>& v);
                        double perform_multiplication(istringstream& iss, vector<Variable>& v);


                        Define common function who get left and right.



                        I think you can define some enums and functions, like this:



                        double perform_operator(istringstream& iss, vector<Variable>& v, OperatorType type)
                        {
                        std::string lhs, rhs;
                        GetValues(iss, lhs, rhs); // fill them
                        switch(type)
                        {
                        case Minus
                        {
                        return operate(left, iss, v) - operate(right, iss, v);
                        }
                        break;
                        }
                        }








                      share|improve this answer














                      share|improve this answer



                      share|improve this answer








                      edited Jun 15 '14 at 6:07









                      Jamal

                      30.2k11116226




                      30.2k11116226










                      answered May 3 '11 at 19:00









                      siquell

                      23214




                      23214























                          1














                          If you look at the similarity of your various perform_xxx functions, it suggests there is duplication that could be removed. One way to do this would be to extract Operator classes, one for each operation, where the common behavior of extracting left and right values from the stream was expressed in the superclass and the individual operations of multiplication, addition, etc. was left to the subclasses.






                          share|improve this answer


























                            1














                            If you look at the similarity of your various perform_xxx functions, it suggests there is duplication that could be removed. One way to do this would be to extract Operator classes, one for each operation, where the common behavior of extracting left and right values from the stream was expressed in the superclass and the individual operations of multiplication, addition, etc. was left to the subclasses.






                            share|improve this answer
























                              1












                              1








                              1






                              If you look at the similarity of your various perform_xxx functions, it suggests there is duplication that could be removed. One way to do this would be to extract Operator classes, one for each operation, where the common behavior of extracting left and right values from the stream was expressed in the superclass and the individual operations of multiplication, addition, etc. was left to the subclasses.






                              share|improve this answer












                              If you look at the similarity of your various perform_xxx functions, it suggests there is duplication that could be removed. One way to do this would be to extract Operator classes, one for each operation, where the common behavior of extracting left and right values from the stream was expressed in the superclass and the individual operations of multiplication, addition, etc. was left to the subclasses.







                              share|improve this answer












                              share|improve this answer



                              share|improve this answer










                              answered May 3 '11 at 18:43









                              Carl Manaster

                              1,239812




                              1,239812























                                  0














                                  I would not use the writing of expression as you did :



                                  Exp : + 5 * 2 3 = 11 .... (5 + 2 * 3)



                                  I would write :



                                  Exp : 5 2 3 * + = 11 .... (5 + 2 * 3)



                                  Another example of my writing :



                                  10 2 * 15 3 * 5 - + .... (10 * 2 + (15 * 3 - 5)) = 20 + (45 - 5) = 20 + 40 = 60



                                  You have to write the same way you enter in the RPN calculator , such as HP 12C





                                  share








                                  New contributor




                                  Marcio Vale is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                  Check out our Code of Conduct.























                                    0














                                    I would not use the writing of expression as you did :



                                    Exp : + 5 * 2 3 = 11 .... (5 + 2 * 3)



                                    I would write :



                                    Exp : 5 2 3 * + = 11 .... (5 + 2 * 3)



                                    Another example of my writing :



                                    10 2 * 15 3 * 5 - + .... (10 * 2 + (15 * 3 - 5)) = 20 + (45 - 5) = 20 + 40 = 60



                                    You have to write the same way you enter in the RPN calculator , such as HP 12C





                                    share








                                    New contributor




                                    Marcio Vale is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                    Check out our Code of Conduct.





















                                      0












                                      0








                                      0






                                      I would not use the writing of expression as you did :



                                      Exp : + 5 * 2 3 = 11 .... (5 + 2 * 3)



                                      I would write :



                                      Exp : 5 2 3 * + = 11 .... (5 + 2 * 3)



                                      Another example of my writing :



                                      10 2 * 15 3 * 5 - + .... (10 * 2 + (15 * 3 - 5)) = 20 + (45 - 5) = 20 + 40 = 60



                                      You have to write the same way you enter in the RPN calculator , such as HP 12C





                                      share








                                      New contributor




                                      Marcio Vale is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                      Check out our Code of Conduct.









                                      I would not use the writing of expression as you did :



                                      Exp : + 5 * 2 3 = 11 .... (5 + 2 * 3)



                                      I would write :



                                      Exp : 5 2 3 * + = 11 .... (5 + 2 * 3)



                                      Another example of my writing :



                                      10 2 * 15 3 * 5 - + .... (10 * 2 + (15 * 3 - 5)) = 20 + (45 - 5) = 20 + 40 = 60



                                      You have to write the same way you enter in the RPN calculator , such as HP 12C






                                      share








                                      New contributor




                                      Marcio Vale is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                      Check out our Code of Conduct.








                                      share


                                      share






                                      New contributor




                                      Marcio Vale is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                      Check out our Code of Conduct.









                                      answered 3 mins ago









                                      Marcio Vale

                                      1




                                      1




                                      New contributor




                                      Marcio Vale is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                      Check out our Code of Conduct.





                                      New contributor





                                      Marcio Vale is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                      Check out our Code of Conduct.






                                      Marcio Vale is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                      Check out our Code of Conduct.






























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