Curl To Pycurl Translation
I have been working with curl request (from bash)
/usr/bin/curl -L -k -u admin:admin -X GET 'https://localhost/test/123/123'
How can I translate this request to the pycurl code, and implement it through python, options are important as it is REST API.
The options that I used in curl are
-k for insecure(ssl bypass)
-L redirect
-X request GET
Thanks,
pycurl
asked Nov 21 at 5:08
Tiz
11
add a comment |
I have been working with curl request (from bash)
/usr/bin/curl -L -k -u admin:admin -X GET 'https://localhost/test/123/123'
How can I translate this request to the pycurl code, and implement it through python, options are important as it is REST API.
The options that I used in curl are
-k for insecure(ssl bypass)
-L redirect
-X request GET
Thanks,
pycurl
asked Nov 21 at 5:08
Tiz
11
add a comment |
I have been working with curl request (from bash)
/usr/bin/curl -L -k -u admin:admin -X GET 'https://localhost/test/123/123'
How can I translate this request to the pycurl code, and implement it through python, options are important as it is REST API.
The options that I used in curl are
-k for insecure(ssl bypass)
-L redirect
-X request GET
Thanks,
pycurl
asked Nov 21 at 5:08
Tiz
11
I have been working with curl request (from bash)
/usr/bin/curl -L -k -u admin:admin -X GET 'https://localhost/test/123/123'
How can I translate this request to the pycurl code, and implement it through python, options are important as it is REST API.
The options that I used in curl are
-k for insecure(ssl bypass)
-L redirect
-X request GET
Thanks,
pycurl
pycurl
asked Nov 21 at 5:08
Tiz
11
asked Nov 21 at 5:08
Tiz
11
asked Nov 21 at 5:08
Tiz
11
asked Nov 21 at 5:08
Tiz
11
asked Nov 21 at 5:08
Tiz
11
11
add a comment |
add a comment |
1 Answer
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There is documentation that you can read for information. It references CURL's setopt options. If you read the documentation you'd figure out what you want to know, but I assume you're asking here because you want someone else to read it for you.
import pycurl
c = pycurl.Curl()
c.setopt(c.URL, "https://localhost/test/123/123")
c.setopt(c.SSL_VERIFYPEER, False) # -k
c.setopt(c.FOLLOWLOCATION, True) # -L
c.setopt(c.HTTPGET, True) # -X
c.perform()
answered Nov 21 at 5:32
Conner
23.1k84568
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
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active
oldest
votes
There is documentation that you can read for information. It references CURL's setopt options. If you read the documentation you'd figure out what you want to know, but I assume you're asking here because you want someone else to read it for you.
import pycurl
c = pycurl.Curl()
c.setopt(c.URL, "https://localhost/test/123/123")
c.setopt(c.SSL_VERIFYPEER, False) # -k
c.setopt(c.FOLLOWLOCATION, True) # -L
c.setopt(c.HTTPGET, True) # -X
c.perform()
answered Nov 21 at 5:32
Conner
23.1k84568
add a comment |
There is documentation that you can read for information. It references CURL's setopt options. If you read the documentation you'd figure out what you want to know, but I assume you're asking here because you want someone else to read it for you.
import pycurl
c = pycurl.Curl()
c.setopt(c.URL, "https://localhost/test/123/123")
c.setopt(c.SSL_VERIFYPEER, False) # -k
c.setopt(c.FOLLOWLOCATION, True) # -L
c.setopt(c.HTTPGET, True) # -X
c.perform()
answered Nov 21 at 5:32
Conner
23.1k84568
add a comment |
There is documentation that you can read for information. It references CURL's setopt options. If you read the documentation you'd figure out what you want to know, but I assume you're asking here because you want someone else to read it for you.
import pycurl
c = pycurl.Curl()
c.setopt(c.URL, "https://localhost/test/123/123")
c.setopt(c.SSL_VERIFYPEER, False) # -k
c.setopt(c.FOLLOWLOCATION, True) # -L
c.setopt(c.HTTPGET, True) # -X
c.perform()
answered Nov 21 at 5:32
Conner
23.1k84568
There is documentation that you can read for information. It references CURL's setopt options. If you read the documentation you'd figure out what you want to know, but I assume you're asking here because you want someone else to read it for you.
import pycurl
c = pycurl.Curl()
c.setopt(c.URL, "https://localhost/test/123/123")
c.setopt(c.SSL_VERIFYPEER, False) # -k
c.setopt(c.FOLLOWLOCATION, True) # -L
c.setopt(c.HTTPGET, True) # -X
c.perform()
answered Nov 21 at 5:32
Conner
23.1k84568
answered Nov 21 at 5:32
Conner
23.1k84568
answered Nov 21 at 5:32
Conner
23.1k84568
answered Nov 21 at 5:32
Conner
23.1k84568
23.1k84568
add a comment |
add a comment |
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