String split using regex with pattern present in text
I have many string that I need to split by commas. Example:
myString = r'test,Test,NEAR(this,that,DISTANCE=4),test again,"another test"'
myString = r'test,Test,FOLLOWEDBY(this,that,DISTANCE=4),test again,"another test"'
My desired output would be:
["test", "Test", "NEAR(this,that,DISTANCE=4)", "test again", """another test"""] #list length = 5
I can't figure out how to keep the commas between "this,that,DISTANCE" in one item. I tried this:
l = re.compile(r',').split(myString) # matches all commas
l = re.compile(r'(?<!(),(?=))').split(myString) # (negative lookback/lookforward) - no matches at all
Any ideas? Let's say the list of allowed "functions" is defined as:
f = ["NEAR","FOLLOWEDBY","AND","OR","MAX"]
python regex token
asked Nov 22 '18 at 14:17
michal111michal111
6910
add a comment |
I have many string that I need to split by commas. Example:
myString = r'test,Test,NEAR(this,that,DISTANCE=4),test again,"another test"'
myString = r'test,Test,FOLLOWEDBY(this,that,DISTANCE=4),test again,"another test"'
My desired output would be:
["test", "Test", "NEAR(this,that,DISTANCE=4)", "test again", """another test"""] #list length = 5
I can't figure out how to keep the commas between "this,that,DISTANCE" in one item. I tried this:
l = re.compile(r',').split(myString) # matches all commas
l = re.compile(r'(?<!(),(?=))').split(myString) # (negative lookback/lookforward) - no matches at all
Any ideas? Let's say the list of allowed "functions" is defined as:
f = ["NEAR","FOLLOWEDBY","AND","OR","MAX"]
python regex token
asked Nov 22 '18 at 14:17
michal111michal111
6910
1
Possible duplicate of How to split by commas that are not within parentheses?
– Austin
Nov 22 '18 at 14:20
add a comment |
I have many string that I need to split by commas. Example:
myString = r'test,Test,NEAR(this,that,DISTANCE=4),test again,"another test"'
myString = r'test,Test,FOLLOWEDBY(this,that,DISTANCE=4),test again,"another test"'
My desired output would be:
["test", "Test", "NEAR(this,that,DISTANCE=4)", "test again", """another test"""] #list length = 5
I can't figure out how to keep the commas between "this,that,DISTANCE" in one item. I tried this:
l = re.compile(r',').split(myString) # matches all commas
l = re.compile(r'(?<!(),(?=))').split(myString) # (negative lookback/lookforward) - no matches at all
Any ideas? Let's say the list of allowed "functions" is defined as:
f = ["NEAR","FOLLOWEDBY","AND","OR","MAX"]
python regex token
asked Nov 22 '18 at 14:17
michal111michal111
6910
I have many string that I need to split by commas. Example:
myString = r'test,Test,NEAR(this,that,DISTANCE=4),test again,"another test"'
myString = r'test,Test,FOLLOWEDBY(this,that,DISTANCE=4),test again,"another test"'
My desired output would be:
["test", "Test", "NEAR(this,that,DISTANCE=4)", "test again", """another test"""] #list length = 5
I can't figure out how to keep the commas between "this,that,DISTANCE" in one item. I tried this:
l = re.compile(r',').split(myString) # matches all commas
l = re.compile(r'(?<!(),(?=))').split(myString) # (negative lookback/lookforward) - no matches at all
Any ideas? Let's say the list of allowed "functions" is defined as:
f = ["NEAR","FOLLOWEDBY","AND","OR","MAX"]
python regex token
python regex token
asked Nov 22 '18 at 14:17
michal111michal111
6910
asked Nov 22 '18 at 14:17
michal111michal111
6910
asked Nov 22 '18 at 14:17
michal111michal111
6910
asked Nov 22 '18 at 14:17
michal111michal111
6910
asked Nov 22 '18 at 14:17
michal111michal111
6910
6910
1
Possible duplicate of How to split by commas that are not within parentheses?
– Austin
Nov 22 '18 at 14:20
add a comment |
1
Possible duplicate of How to split by commas that are not within parentheses?
– Austin
Nov 22 '18 at 14:20
1
1
Possible duplicate of How to split by commas that are not within parentheses?
– Austin
Nov 22 '18 at 14:20
Possible duplicate of How to split by commas that are not within parentheses?
– Austin
Nov 22 '18 at 14:20
add a comment |
2 Answers
2
active
oldest
votes
You may use
(?:([^()]*)|[^,])+
See the regex demo.
The (?:([^()]*)|[^,])+ pattern matches one or more occurrences of any substring between parentheses with no ( and ) in them or any char other than ,.
See the Python demo:
import re
rx = r"(?:([^()]*)|[^,])+"
s = 'test,Test,NEAR(this,that,DISTANCE=4),test again,"another test"'
print(re.findall(rx, s))
# => ['test', 'Test', 'NEAR(this,that,DISTANCE=4)', 'test again', '"another test"']
answered Nov 22 '18 at 14:20
Wiktor StribiżewWiktor Stribiżew
311k16132207
add a comment |
If explicitly want to specify which strings count as functions, you need to build the regex dynamically. Otherwise, go with Wiktor's solution.
>>> functions = ["NEAR","FOLLOWEDBY","AND","OR","MAX"]
>>> funcs = '|'.join('{}([^)]+)'.format(f) for f in functions)
>>> regex = '({})|,'.format(funcs)
>>>
>>> myString1 = 'test,Test,NEAR(this,that,DISTANCE=4),test again,"another test"'
>>> list(filter(None, re.split(regex, myString1)))
['test', 'Test', 'NEAR(this,that,DISTANCE=4)', 'test again', '"another test"']
>>> myString2 = 'test,Test,FOLLOWEDBY(this,that,DISTANCE=4),test again,"another test"'
>>> list(filter(None, re.split(regex, myString2)))
['test',
'Test',
'FOLLOWEDBY(this,that,DISTANCE=4)',
'test again',
'"another test"']
answered Nov 22 '18 at 14:26
timgebtimgeb
50.5k116392
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
You may use
(?:([^()]*)|[^,])+
See the regex demo.
The (?:([^()]*)|[^,])+ pattern matches one or more occurrences of any substring between parentheses with no ( and ) in them or any char other than ,.
See the Python demo:
import re
rx = r"(?:([^()]*)|[^,])+"
s = 'test,Test,NEAR(this,that,DISTANCE=4),test again,"another test"'
print(re.findall(rx, s))
# => ['test', 'Test', 'NEAR(this,that,DISTANCE=4)', 'test again', '"another test"']
answered Nov 22 '18 at 14:20
Wiktor StribiżewWiktor Stribiżew
311k16132207
add a comment |
You may use
(?:([^()]*)|[^,])+
See the regex demo.
The (?:([^()]*)|[^,])+ pattern matches one or more occurrences of any substring between parentheses with no ( and ) in them or any char other than ,.
See the Python demo:
import re
rx = r"(?:([^()]*)|[^,])+"
s = 'test,Test,NEAR(this,that,DISTANCE=4),test again,"another test"'
print(re.findall(rx, s))
# => ['test', 'Test', 'NEAR(this,that,DISTANCE=4)', 'test again', '"another test"']
answered Nov 22 '18 at 14:20
Wiktor StribiżewWiktor Stribiżew
311k16132207
add a comment |
You may use
(?:([^()]*)|[^,])+
See the regex demo.
The (?:([^()]*)|[^,])+ pattern matches one or more occurrences of any substring between parentheses with no ( and ) in them or any char other than ,.
See the Python demo:
import re
rx = r"(?:([^()]*)|[^,])+"
s = 'test,Test,NEAR(this,that,DISTANCE=4),test again,"another test"'
print(re.findall(rx, s))
# => ['test', 'Test', 'NEAR(this,that,DISTANCE=4)', 'test again', '"another test"']
answered Nov 22 '18 at 14:20
Wiktor StribiżewWiktor Stribiżew
311k16132207
You may use
(?:([^()]*)|[^,])+
See the regex demo.
The (?:([^()]*)|[^,])+ pattern matches one or more occurrences of any substring between parentheses with no ( and ) in them or any char other than ,.
See the Python demo:
import re
rx = r"(?:([^()]*)|[^,])+"
s = 'test,Test,NEAR(this,that,DISTANCE=4),test again,"another test"'
print(re.findall(rx, s))
# => ['test', 'Test', 'NEAR(this,that,DISTANCE=4)', 'test again', '"another test"']
answered Nov 22 '18 at 14:20
Wiktor StribiżewWiktor Stribiżew
311k16132207
answered Nov 22 '18 at 14:20
Wiktor StribiżewWiktor Stribiżew
311k16132207
answered Nov 22 '18 at 14:20
Wiktor StribiżewWiktor Stribiżew
311k16132207
answered Nov 22 '18 at 14:20
Wiktor StribiżewWiktor Stribiżew
311k16132207
311k16132207
add a comment |
add a comment |
If explicitly want to specify which strings count as functions, you need to build the regex dynamically. Otherwise, go with Wiktor's solution.
>>> functions = ["NEAR","FOLLOWEDBY","AND","OR","MAX"]
>>> funcs = '|'.join('{}([^)]+)'.format(f) for f in functions)
>>> regex = '({})|,'.format(funcs)
>>>
>>> myString1 = 'test,Test,NEAR(this,that,DISTANCE=4),test again,"another test"'
>>> list(filter(None, re.split(regex, myString1)))
['test', 'Test', 'NEAR(this,that,DISTANCE=4)', 'test again', '"another test"']
>>> myString2 = 'test,Test,FOLLOWEDBY(this,that,DISTANCE=4),test again,"another test"'
>>> list(filter(None, re.split(regex, myString2)))
['test',
'Test',
'FOLLOWEDBY(this,that,DISTANCE=4)',
'test again',
'"another test"']
answered Nov 22 '18 at 14:26
timgebtimgeb
50.5k116392
add a comment |
If explicitly want to specify which strings count as functions, you need to build the regex dynamically. Otherwise, go with Wiktor's solution.
>>> functions = ["NEAR","FOLLOWEDBY","AND","OR","MAX"]
>>> funcs = '|'.join('{}([^)]+)'.format(f) for f in functions)
>>> regex = '({})|,'.format(funcs)
>>>
>>> myString1 = 'test,Test,NEAR(this,that,DISTANCE=4),test again,"another test"'
>>> list(filter(None, re.split(regex, myString1)))
['test', 'Test', 'NEAR(this,that,DISTANCE=4)', 'test again', '"another test"']
>>> myString2 = 'test,Test,FOLLOWEDBY(this,that,DISTANCE=4),test again,"another test"'
>>> list(filter(None, re.split(regex, myString2)))
['test',
'Test',
'FOLLOWEDBY(this,that,DISTANCE=4)',
'test again',
'"another test"']
answered Nov 22 '18 at 14:26
timgebtimgeb
50.5k116392
add a comment |
If explicitly want to specify which strings count as functions, you need to build the regex dynamically. Otherwise, go with Wiktor's solution.
>>> functions = ["NEAR","FOLLOWEDBY","AND","OR","MAX"]
>>> funcs = '|'.join('{}([^)]+)'.format(f) for f in functions)
>>> regex = '({})|,'.format(funcs)
>>>
>>> myString1 = 'test,Test,NEAR(this,that,DISTANCE=4),test again,"another test"'
>>> list(filter(None, re.split(regex, myString1)))
['test', 'Test', 'NEAR(this,that,DISTANCE=4)', 'test again', '"another test"']
>>> myString2 = 'test,Test,FOLLOWEDBY(this,that,DISTANCE=4),test again,"another test"'
>>> list(filter(None, re.split(regex, myString2)))
['test',
'Test',
'FOLLOWEDBY(this,that,DISTANCE=4)',
'test again',
'"another test"']
answered Nov 22 '18 at 14:26
timgebtimgeb
50.5k116392
If explicitly want to specify which strings count as functions, you need to build the regex dynamically. Otherwise, go with Wiktor's solution.
>>> functions = ["NEAR","FOLLOWEDBY","AND","OR","MAX"]
>>> funcs = '|'.join('{}([^)]+)'.format(f) for f in functions)
>>> regex = '({})|,'.format(funcs)
>>>
>>> myString1 = 'test,Test,NEAR(this,that,DISTANCE=4),test again,"another test"'
>>> list(filter(None, re.split(regex, myString1)))
['test', 'Test', 'NEAR(this,that,DISTANCE=4)', 'test again', '"another test"']
>>> myString2 = 'test,Test,FOLLOWEDBY(this,that,DISTANCE=4),test again,"another test"'
>>> list(filter(None, re.split(regex, myString2)))
['test',
'Test',
'FOLLOWEDBY(this,that,DISTANCE=4)',
'test again',
'"another test"']
answered Nov 22 '18 at 14:26
timgebtimgeb
50.5k116392
answered Nov 22 '18 at 14:26
timgebtimgeb
50.5k116392
answered Nov 22 '18 at 14:26
timgebtimgeb
50.5k116392
answered Nov 22 '18 at 14:26
timgebtimgeb
50.5k116392
50.5k116392
add a comment |
add a comment |
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1
Possible duplicate of How to split by commas that are not within parentheses?
– Austin
Nov 22 '18 at 14:20