Netsed dictionary in Python
-1
Trying to type a nested dictionary, but the results show the nested value with last entry. I guess this is because I'm trying to add the nested key with is the same for all:
for i in range(15, 19, 1):
left_index = counters[i].find(']')
right_index = counters[i].rfind(': ')
key = counters[i][left_index + 1:right_index]
value = counters[i][right_index + 1:].replace('[(','').replace(')]','').replace(') - (',' ').strip().split(' ')
d1['value'] = value[0]
d1['minimum'] = value[1]
d1['maximum'] = value[-1]
print 'key: ',key, 'value: ', d1
d[key] = d1
encoder.FLOAT_REPR = lambda x: format(x, '.5f')
print json.dumps(d, indent=5, sort_keys=True)
And the result is:
key: Socket/Modem 1/Bytes sent value: {'minimum': '0', 'maximum': '2482262614', 'value': '2482262614'}
key: Socket/Modem 1/recv value: {'minimum': '0', 'maximum': '19646', 'value': '19646'}
key: Socket/Modem 1/send value: {'minimum': '0', 'maximum': '2078818', 'value': '2078818'}
key: StreamerEngine/Bonding/Priority queue/Packets of '' priority dequeued value: {'minimum': '0', 'maximum': '0', 'value': '0'}
{
" Socket/Modem 1/Bytes sent": {
"maximum": "0",
"minimum": "0",
"value": "0"
},
" Socket/Modem 1/recv": {
"maximum": "0",
"minimum": "0",
"value": "0"
},
" Socket/Modem 1/send": {
"maximum": "0",
"minimum": "0",
"value": "0"
},
" StreamerEngine/Bonding/Priority queue/Packets of '' priority dequeued": {
"maximum": "0",
"minimum": "0",
"value": "0"
}
}
So you can see that the d1 dictionary is typed well but the accumulated dictionary d is not.
python dictionary
edited Nov 21 '18 at 15:00
John Kugelman
240k51398453
asked Nov 21 '18 at 13:40
Itaybz
133
add a comment |
-1
Trying to type a nested dictionary, but the results show the nested value with last entry. I guess this is because I'm trying to add the nested key with is the same for all:
for i in range(15, 19, 1):
left_index = counters[i].find(']')
right_index = counters[i].rfind(': ')
key = counters[i][left_index + 1:right_index]
value = counters[i][right_index + 1:].replace('[(','').replace(')]','').replace(') - (',' ').strip().split(' ')
d1['value'] = value[0]
d1['minimum'] = value[1]
d1['maximum'] = value[-1]
print 'key: ',key, 'value: ', d1
d[key] = d1
encoder.FLOAT_REPR = lambda x: format(x, '.5f')
print json.dumps(d, indent=5, sort_keys=True)
And the result is:
key: Socket/Modem 1/Bytes sent value: {'minimum': '0', 'maximum': '2482262614', 'value': '2482262614'}
key: Socket/Modem 1/recv value: {'minimum': '0', 'maximum': '19646', 'value': '19646'}
key: Socket/Modem 1/send value: {'minimum': '0', 'maximum': '2078818', 'value': '2078818'}
key: StreamerEngine/Bonding/Priority queue/Packets of '' priority dequeued value: {'minimum': '0', 'maximum': '0', 'value': '0'}
{
" Socket/Modem 1/Bytes sent": {
"maximum": "0",
"minimum": "0",
"value": "0"
},
" Socket/Modem 1/recv": {
"maximum": "0",
"minimum": "0",
"value": "0"
},
" Socket/Modem 1/send": {
"maximum": "0",
"minimum": "0",
"value": "0"
},
" StreamerEngine/Bonding/Priority queue/Packets of '' priority dequeued": {
"maximum": "0",
"minimum": "0",
"value": "0"
}
}
So you can see that the d1 dictionary is typed well but the accumulated dictionary d is not.
python dictionary
edited Nov 21 '18 at 15:00
John Kugelman
240k51398453
asked Nov 21 '18 at 13:40
Itaybz
133
Possible duplicate of Defining a nested dictionary in python
– Isma
Nov 21 '18 at 13:43
add a comment |
-1
-1
-1
Trying to type a nested dictionary, but the results show the nested value with last entry. I guess this is because I'm trying to add the nested key with is the same for all:
for i in range(15, 19, 1):
left_index = counters[i].find(']')
right_index = counters[i].rfind(': ')
key = counters[i][left_index + 1:right_index]
value = counters[i][right_index + 1:].replace('[(','').replace(')]','').replace(') - (',' ').strip().split(' ')
d1['value'] = value[0]
d1['minimum'] = value[1]
d1['maximum'] = value[-1]
print 'key: ',key, 'value: ', d1
d[key] = d1
encoder.FLOAT_REPR = lambda x: format(x, '.5f')
print json.dumps(d, indent=5, sort_keys=True)
And the result is:
key: Socket/Modem 1/Bytes sent value: {'minimum': '0', 'maximum': '2482262614', 'value': '2482262614'}
key: Socket/Modem 1/recv value: {'minimum': '0', 'maximum': '19646', 'value': '19646'}
key: Socket/Modem 1/send value: {'minimum': '0', 'maximum': '2078818', 'value': '2078818'}
key: StreamerEngine/Bonding/Priority queue/Packets of '' priority dequeued value: {'minimum': '0', 'maximum': '0', 'value': '0'}
{
" Socket/Modem 1/Bytes sent": {
"maximum": "0",
"minimum": "0",
"value": "0"
},
" Socket/Modem 1/recv": {
"maximum": "0",
"minimum": "0",
"value": "0"
},
" Socket/Modem 1/send": {
"maximum": "0",
"minimum": "0",
"value": "0"
},
" StreamerEngine/Bonding/Priority queue/Packets of '' priority dequeued": {
"maximum": "0",
"minimum": "0",
"value": "0"
}
}
So you can see that the d1 dictionary is typed well but the accumulated dictionary d is not.
python dictionary
edited Nov 21 '18 at 15:00
John Kugelman
240k51398453
asked Nov 21 '18 at 13:40
Itaybz
133
Trying to type a nested dictionary, but the results show the nested value with last entry. I guess this is because I'm trying to add the nested key with is the same for all:
for i in range(15, 19, 1):
left_index = counters[i].find(']')
right_index = counters[i].rfind(': ')
key = counters[i][left_index + 1:right_index]
value = counters[i][right_index + 1:].replace('[(','').replace(')]','').replace(') - (',' ').strip().split(' ')
d1['value'] = value[0]
d1['minimum'] = value[1]
d1['maximum'] = value[-1]
print 'key: ',key, 'value: ', d1
d[key] = d1
encoder.FLOAT_REPR = lambda x: format(x, '.5f')
print json.dumps(d, indent=5, sort_keys=True)
And the result is:
key: Socket/Modem 1/Bytes sent value: {'minimum': '0', 'maximum': '2482262614', 'value': '2482262614'}
key: Socket/Modem 1/recv value: {'minimum': '0', 'maximum': '19646', 'value': '19646'}
key: Socket/Modem 1/send value: {'minimum': '0', 'maximum': '2078818', 'value': '2078818'}
key: StreamerEngine/Bonding/Priority queue/Packets of '' priority dequeued value: {'minimum': '0', 'maximum': '0', 'value': '0'}
{
" Socket/Modem 1/Bytes sent": {
"maximum": "0",
"minimum": "0",
"value": "0"
},
" Socket/Modem 1/recv": {
"maximum": "0",
"minimum": "0",
"value": "0"
},
" Socket/Modem 1/send": {
"maximum": "0",
"minimum": "0",
"value": "0"
},
" StreamerEngine/Bonding/Priority queue/Packets of '' priority dequeued": {
"maximum": "0",
"minimum": "0",
"value": "0"
}
}
So you can see that the d1 dictionary is typed well but the accumulated dictionary d is not.
python dictionary
python dictionary
edited Nov 21 '18 at 15:00
John Kugelman
240k51398453
asked Nov 21 '18 at 13:40
Itaybz
133
edited Nov 21 '18 at 15:00
John Kugelman
240k51398453
asked Nov 21 '18 at 13:40
Itaybz
133
edited Nov 21 '18 at 15:00
John Kugelman
240k51398453
edited Nov 21 '18 at 15:00
John Kugelman
240k51398453
edited Nov 21 '18 at 15:00
John Kugelman
240k51398453
240k51398453
asked Nov 21 '18 at 13:40
Itaybz
133
asked Nov 21 '18 at 13:40
Itaybz
133
asked Nov 21 '18 at 13:40
Itaybz
133
133
Possible duplicate of Defining a nested dictionary in python
– Isma
Nov 21 '18 at 13:43
add a comment |
Possible duplicate of Defining a nested dictionary in python
– Isma
Nov 21 '18 at 13:43
Possible duplicate of Defining a nested dictionary in python
– Isma
Nov 21 '18 at 13:43
Possible duplicate of Defining a nested dictionary in python
– Isma
Nov 21 '18 at 13:43
add a comment |
1 Answer
1
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0
d1 is (probably) declared outside of your loop, so you are using the same object again and again, that's why the last assigned values are used in all other dicts.
Instead define d1 inside your loop:
for i in range(15, 19, 1):
left_index = counters[i].find(']')
right_index = counters[i].rfind(': ')
key = counters[i][left_index + 1:right_index]
value = counters[i][right_index + 1:].replace('[(','').replace(')]','').replace(') - (',' ').strip().split(' ')
d1 = {} # <- new dict!
d1['value'] = value[0]
d1['minimum'] = value[1]
d1['maximum'] = value[-1]
print 'key: ',key, 'value: ', d1
d[key] = d1
answered Nov 21 '18 at 13:45
Mike Scotty
5,53751933
add a comment |
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1 Answer
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1 Answer
1
active
oldest
votes
active
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votes
active
oldest
votes
0
d1 is (probably) declared outside of your loop, so you are using the same object again and again, that's why the last assigned values are used in all other dicts.
Instead define d1 inside your loop:
for i in range(15, 19, 1):
left_index = counters[i].find(']')
right_index = counters[i].rfind(': ')
key = counters[i][left_index + 1:right_index]
value = counters[i][right_index + 1:].replace('[(','').replace(')]','').replace(') - (',' ').strip().split(' ')
d1 = {} # <- new dict!
d1['value'] = value[0]
d1['minimum'] = value[1]
d1['maximum'] = value[-1]
print 'key: ',key, 'value: ', d1
d[key] = d1
answered Nov 21 '18 at 13:45
Mike Scotty
5,53751933
add a comment |
0
d1 is (probably) declared outside of your loop, so you are using the same object again and again, that's why the last assigned values are used in all other dicts.
Instead define d1 inside your loop:
for i in range(15, 19, 1):
left_index = counters[i].find(']')
right_index = counters[i].rfind(': ')
key = counters[i][left_index + 1:right_index]
value = counters[i][right_index + 1:].replace('[(','').replace(')]','').replace(') - (',' ').strip().split(' ')
d1 = {} # <- new dict!
d1['value'] = value[0]
d1['minimum'] = value[1]
d1['maximum'] = value[-1]
print 'key: ',key, 'value: ', d1
d[key] = d1
answered Nov 21 '18 at 13:45
Mike Scotty
5,53751933
add a comment |
0
0
0
d1 is (probably) declared outside of your loop, so you are using the same object again and again, that's why the last assigned values are used in all other dicts.
Instead define d1 inside your loop:
for i in range(15, 19, 1):
left_index = counters[i].find(']')
right_index = counters[i].rfind(': ')
key = counters[i][left_index + 1:right_index]
value = counters[i][right_index + 1:].replace('[(','').replace(')]','').replace(') - (',' ').strip().split(' ')
d1 = {} # <- new dict!
d1['value'] = value[0]
d1['minimum'] = value[1]
d1['maximum'] = value[-1]
print 'key: ',key, 'value: ', d1
d[key] = d1
answered Nov 21 '18 at 13:45
Mike Scotty
5,53751933
d1 is (probably) declared outside of your loop, so you are using the same object again and again, that's why the last assigned values are used in all other dicts.
Instead define d1 inside your loop:
for i in range(15, 19, 1):
left_index = counters[i].find(']')
right_index = counters[i].rfind(': ')
key = counters[i][left_index + 1:right_index]
value = counters[i][right_index + 1:].replace('[(','').replace(')]','').replace(') - (',' ').strip().split(' ')
d1 = {} # <- new dict!
d1['value'] = value[0]
d1['minimum'] = value[1]
d1['maximum'] = value[-1]
print 'key: ',key, 'value: ', d1
d[key] = d1
answered Nov 21 '18 at 13:45
Mike Scotty
5,53751933
answered Nov 21 '18 at 13:45
Mike Scotty
5,53751933
answered Nov 21 '18 at 13:45
Mike Scotty
5,53751933
answered Nov 21 '18 at 13:45
Mike Scotty
5,53751933
5,53751933
add a comment |
add a comment |
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Possible duplicate of Defining a nested dictionary in python
– Isma
Nov 21 '18 at 13:43