How to remove vertices from a graph?
I have 2 lists: list 1 is a list of vertices of a graph, says, {1,2,3,4,5} and list 2 keeps track of edges (i.e which vertex connects to which) such as {{1,2}, {2,3},{3,4},{4,1},{2,5}}. Now I want to remove some vertices in list 1 and I want that any edges in list 2 that have an end same as one of the removed vertices will also be removed. What would be the best way to do this in Mathematica? (I can do this easily in other languages like vb.net, but I still am trying to get my head on Mathematica)
list-manipulation graphs-and-networks
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I have 2 lists: list 1 is a list of vertices of a graph, says, {1,2,3,4,5} and list 2 keeps track of edges (i.e which vertex connects to which) such as {{1,2}, {2,3},{3,4},{4,1},{2,5}}. Now I want to remove some vertices in list 1 and I want that any edges in list 2 that have an end same as one of the removed vertices will also be removed. What would be the best way to do this in Mathematica? (I can do this easily in other languages like vb.net, but I still am trying to get my head on Mathematica)
list-manipulation graphs-and-networks
add a comment |
I have 2 lists: list 1 is a list of vertices of a graph, says, {1,2,3,4,5} and list 2 keeps track of edges (i.e which vertex connects to which) such as {{1,2}, {2,3},{3,4},{4,1},{2,5}}. Now I want to remove some vertices in list 1 and I want that any edges in list 2 that have an end same as one of the removed vertices will also be removed. What would be the best way to do this in Mathematica? (I can do this easily in other languages like vb.net, but I still am trying to get my head on Mathematica)
list-manipulation graphs-and-networks
I have 2 lists: list 1 is a list of vertices of a graph, says, {1,2,3,4,5} and list 2 keeps track of edges (i.e which vertex connects to which) such as {{1,2}, {2,3},{3,4},{4,1},{2,5}}. Now I want to remove some vertices in list 1 and I want that any edges in list 2 that have an end same as one of the removed vertices will also be removed. What would be the best way to do this in Mathematica? (I can do this easily in other languages like vb.net, but I still am trying to get my head on Mathematica)
list-manipulation graphs-and-networks
list-manipulation graphs-and-networks
edited 50 mins ago
Henrik Schumacher
48.8k467139
48.8k467139
asked 2 hours ago
N.T.C
28517
28517
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add a comment |
4 Answers
4
active
oldest
votes
These are done easily with graph functions:
g = Graph[Range[5], {1 <-> 2, 2 <-> 3, 3 <-> 4, 4 <-> 1, 2 <-> 5}];
g2 = VertexDelete[g, 1];
EdgeList[g2]
(*
{2 <-> 3, 3 <-> 4, 2 <-> 5}
*)
Of course this works as well if you want to delete more than one vertex, e.g., vertices 1 and 5:
g2 = VertexDelete[g, {1, 5}];
add a comment |
edges = {{1, 2}, {2, 3}, {3, 4}, {4, 1}, {2, 5}};
A few more alternatives:
Select[edges, FreeQ[1]]
Pick[edges, FreeQ[1] /@ edges]
DeleteCases[edges, {_, 1} | {1, _}]
List @@@ EdgeList[VertexDelete[edges, 1]]
all give
{{2, 3}, {3, 4}, {2, 5}}
Your first three suggestions only work for removing a single vertex.
– geordie
1 hour ago
1
@geordie, if you want to remove a list of vertices, say{1,2}
, you can use1|2
instead of1
.
– kglr
1 hour ago
add a comment |
The following works for removing several vertices and corresponding edges:
verts = {1, 2, 3, 4, 5};
edges = {{1, 2}, {2, 3}, {3, 4}, {4, 1}, {2, 5}};
vertdel = {1, 4}
verts2 = Complement[verts, vertdel]
edges2 = Complement[edges, Flatten[Select[edges, MemberQ[#]] & /@ vertdel, 1]]
{1, 4}
{2, 3, 5}
{{2, 3}, {2, 5}}
add a comment |
Tiny keyboard alert.
A = SparseArray[edges -> 1, {1 ,1} Max[edges]];
a = DiagonalMatrix[SparseArray[vertdel -> 0, {Length[A]}, 1]];
(a.A.a)["NonzeroPositions"]
add a comment |
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4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
These are done easily with graph functions:
g = Graph[Range[5], {1 <-> 2, 2 <-> 3, 3 <-> 4, 4 <-> 1, 2 <-> 5}];
g2 = VertexDelete[g, 1];
EdgeList[g2]
(*
{2 <-> 3, 3 <-> 4, 2 <-> 5}
*)
Of course this works as well if you want to delete more than one vertex, e.g., vertices 1 and 5:
g2 = VertexDelete[g, {1, 5}];
add a comment |
These are done easily with graph functions:
g = Graph[Range[5], {1 <-> 2, 2 <-> 3, 3 <-> 4, 4 <-> 1, 2 <-> 5}];
g2 = VertexDelete[g, 1];
EdgeList[g2]
(*
{2 <-> 3, 3 <-> 4, 2 <-> 5}
*)
Of course this works as well if you want to delete more than one vertex, e.g., vertices 1 and 5:
g2 = VertexDelete[g, {1, 5}];
add a comment |
These are done easily with graph functions:
g = Graph[Range[5], {1 <-> 2, 2 <-> 3, 3 <-> 4, 4 <-> 1, 2 <-> 5}];
g2 = VertexDelete[g, 1];
EdgeList[g2]
(*
{2 <-> 3, 3 <-> 4, 2 <-> 5}
*)
Of course this works as well if you want to delete more than one vertex, e.g., vertices 1 and 5:
g2 = VertexDelete[g, {1, 5}];
These are done easily with graph functions:
g = Graph[Range[5], {1 <-> 2, 2 <-> 3, 3 <-> 4, 4 <-> 1, 2 <-> 5}];
g2 = VertexDelete[g, 1];
EdgeList[g2]
(*
{2 <-> 3, 3 <-> 4, 2 <-> 5}
*)
Of course this works as well if you want to delete more than one vertex, e.g., vertices 1 and 5:
g2 = VertexDelete[g, {1, 5}];
edited 1 hour ago
answered 1 hour ago
David G. Stork
23.1k22051
23.1k22051
add a comment |
add a comment |
edges = {{1, 2}, {2, 3}, {3, 4}, {4, 1}, {2, 5}};
A few more alternatives:
Select[edges, FreeQ[1]]
Pick[edges, FreeQ[1] /@ edges]
DeleteCases[edges, {_, 1} | {1, _}]
List @@@ EdgeList[VertexDelete[edges, 1]]
all give
{{2, 3}, {3, 4}, {2, 5}}
Your first three suggestions only work for removing a single vertex.
– geordie
1 hour ago
1
@geordie, if you want to remove a list of vertices, say{1,2}
, you can use1|2
instead of1
.
– kglr
1 hour ago
add a comment |
edges = {{1, 2}, {2, 3}, {3, 4}, {4, 1}, {2, 5}};
A few more alternatives:
Select[edges, FreeQ[1]]
Pick[edges, FreeQ[1] /@ edges]
DeleteCases[edges, {_, 1} | {1, _}]
List @@@ EdgeList[VertexDelete[edges, 1]]
all give
{{2, 3}, {3, 4}, {2, 5}}
Your first three suggestions only work for removing a single vertex.
– geordie
1 hour ago
1
@geordie, if you want to remove a list of vertices, say{1,2}
, you can use1|2
instead of1
.
– kglr
1 hour ago
add a comment |
edges = {{1, 2}, {2, 3}, {3, 4}, {4, 1}, {2, 5}};
A few more alternatives:
Select[edges, FreeQ[1]]
Pick[edges, FreeQ[1] /@ edges]
DeleteCases[edges, {_, 1} | {1, _}]
List @@@ EdgeList[VertexDelete[edges, 1]]
all give
{{2, 3}, {3, 4}, {2, 5}}
edges = {{1, 2}, {2, 3}, {3, 4}, {4, 1}, {2, 5}};
A few more alternatives:
Select[edges, FreeQ[1]]
Pick[edges, FreeQ[1] /@ edges]
DeleteCases[edges, {_, 1} | {1, _}]
List @@@ EdgeList[VertexDelete[edges, 1]]
all give
{{2, 3}, {3, 4}, {2, 5}}
answered 1 hour ago
kglr
176k9198404
176k9198404
Your first three suggestions only work for removing a single vertex.
– geordie
1 hour ago
1
@geordie, if you want to remove a list of vertices, say{1,2}
, you can use1|2
instead of1
.
– kglr
1 hour ago
add a comment |
Your first three suggestions only work for removing a single vertex.
– geordie
1 hour ago
1
@geordie, if you want to remove a list of vertices, say{1,2}
, you can use1|2
instead of1
.
– kglr
1 hour ago
Your first three suggestions only work for removing a single vertex.
– geordie
1 hour ago
Your first three suggestions only work for removing a single vertex.
– geordie
1 hour ago
1
1
@geordie, if you want to remove a list of vertices, say
{1,2}
, you can use 1|2
instead of 1
.– kglr
1 hour ago
@geordie, if you want to remove a list of vertices, say
{1,2}
, you can use 1|2
instead of 1
.– kglr
1 hour ago
add a comment |
The following works for removing several vertices and corresponding edges:
verts = {1, 2, 3, 4, 5};
edges = {{1, 2}, {2, 3}, {3, 4}, {4, 1}, {2, 5}};
vertdel = {1, 4}
verts2 = Complement[verts, vertdel]
edges2 = Complement[edges, Flatten[Select[edges, MemberQ[#]] & /@ vertdel, 1]]
{1, 4}
{2, 3, 5}
{{2, 3}, {2, 5}}
add a comment |
The following works for removing several vertices and corresponding edges:
verts = {1, 2, 3, 4, 5};
edges = {{1, 2}, {2, 3}, {3, 4}, {4, 1}, {2, 5}};
vertdel = {1, 4}
verts2 = Complement[verts, vertdel]
edges2 = Complement[edges, Flatten[Select[edges, MemberQ[#]] & /@ vertdel, 1]]
{1, 4}
{2, 3, 5}
{{2, 3}, {2, 5}}
add a comment |
The following works for removing several vertices and corresponding edges:
verts = {1, 2, 3, 4, 5};
edges = {{1, 2}, {2, 3}, {3, 4}, {4, 1}, {2, 5}};
vertdel = {1, 4}
verts2 = Complement[verts, vertdel]
edges2 = Complement[edges, Flatten[Select[edges, MemberQ[#]] & /@ vertdel, 1]]
{1, 4}
{2, 3, 5}
{{2, 3}, {2, 5}}
The following works for removing several vertices and corresponding edges:
verts = {1, 2, 3, 4, 5};
edges = {{1, 2}, {2, 3}, {3, 4}, {4, 1}, {2, 5}};
vertdel = {1, 4}
verts2 = Complement[verts, vertdel]
edges2 = Complement[edges, Flatten[Select[edges, MemberQ[#]] & /@ vertdel, 1]]
{1, 4}
{2, 3, 5}
{{2, 3}, {2, 5}}
answered 1 hour ago
geordie
1,9781530
1,9781530
add a comment |
add a comment |
Tiny keyboard alert.
A = SparseArray[edges -> 1, {1 ,1} Max[edges]];
a = DiagonalMatrix[SparseArray[vertdel -> 0, {Length[A]}, 1]];
(a.A.a)["NonzeroPositions"]
add a comment |
Tiny keyboard alert.
A = SparseArray[edges -> 1, {1 ,1} Max[edges]];
a = DiagonalMatrix[SparseArray[vertdel -> 0, {Length[A]}, 1]];
(a.A.a)["NonzeroPositions"]
add a comment |
Tiny keyboard alert.
A = SparseArray[edges -> 1, {1 ,1} Max[edges]];
a = DiagonalMatrix[SparseArray[vertdel -> 0, {Length[A]}, 1]];
(a.A.a)["NonzeroPositions"]
Tiny keyboard alert.
A = SparseArray[edges -> 1, {1 ,1} Max[edges]];
a = DiagonalMatrix[SparseArray[vertdel -> 0, {Length[A]}, 1]];
(a.A.a)["NonzeroPositions"]
edited 28 mins ago
answered 43 mins ago
Henrik Schumacher
48.8k467139
48.8k467139
add a comment |
add a comment |
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