Using 5 V adapter to power 12 V cordless phone












2














I am trying to power a 12 V 8 W cordless phone using a 5 V 1 A wall adapter.
I am using a step up DC/DC boost converter MT3608 for boosting output from 5 V to 12 V.



Theoretically it works - when I connect adapter to boost convertor input and setting potentiometer to 12 V by measuring output through multimeter - it shows 12 V.



But as soon as I connect the cordless the voltage drops to 2-3 V and cordless does not power on. So its not working on load.



I also have a 7.4 V li-ion cells which powers on the cordless fine - using the boost convertor.



My question is the DC coming from adapter different than DC coming from battery?



Also I noticed that the adapter indicator light is constant when charging a basic (non smartphone) phone battery but it pulsates when connected to step up convertor and cordless powered on. This made me more confused.



Please help me understand this behavior of adapter and what's wrong in what I am trying to do?










share|improve this question









New contributor




Raool is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
















  • 3




    I don't think $5 V × 1 A> 8 W$.
    – Harry Svensson
    4 hours ago








  • 1




    A 5V 1A wall adapter cannot provide the 8 W that the phone requires, regardless of any boost converter that you are using. As a result, the adapter is limiting its output current and the voltage sags through. Please try a 2 A or higher adapter instead.
    – Andrey Akhmetov
    4 hours ago








  • 2




    Just get a 12V 1A wall wart. Readily available. Cheap. Problem solved. The only wrinkle may be matching the connector plug.
    – Phil Freedenberg
    4 hours ago
















2














I am trying to power a 12 V 8 W cordless phone using a 5 V 1 A wall adapter.
I am using a step up DC/DC boost converter MT3608 for boosting output from 5 V to 12 V.



Theoretically it works - when I connect adapter to boost convertor input and setting potentiometer to 12 V by measuring output through multimeter - it shows 12 V.



But as soon as I connect the cordless the voltage drops to 2-3 V and cordless does not power on. So its not working on load.



I also have a 7.4 V li-ion cells which powers on the cordless fine - using the boost convertor.



My question is the DC coming from adapter different than DC coming from battery?



Also I noticed that the adapter indicator light is constant when charging a basic (non smartphone) phone battery but it pulsates when connected to step up convertor and cordless powered on. This made me more confused.



Please help me understand this behavior of adapter and what's wrong in what I am trying to do?










share|improve this question









New contributor




Raool is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
















  • 3




    I don't think $5 V × 1 A> 8 W$.
    – Harry Svensson
    4 hours ago








  • 1




    A 5V 1A wall adapter cannot provide the 8 W that the phone requires, regardless of any boost converter that you are using. As a result, the adapter is limiting its output current and the voltage sags through. Please try a 2 A or higher adapter instead.
    – Andrey Akhmetov
    4 hours ago








  • 2




    Just get a 12V 1A wall wart. Readily available. Cheap. Problem solved. The only wrinkle may be matching the connector plug.
    – Phil Freedenberg
    4 hours ago














2












2








2







I am trying to power a 12 V 8 W cordless phone using a 5 V 1 A wall adapter.
I am using a step up DC/DC boost converter MT3608 for boosting output from 5 V to 12 V.



Theoretically it works - when I connect adapter to boost convertor input and setting potentiometer to 12 V by measuring output through multimeter - it shows 12 V.



But as soon as I connect the cordless the voltage drops to 2-3 V and cordless does not power on. So its not working on load.



I also have a 7.4 V li-ion cells which powers on the cordless fine - using the boost convertor.



My question is the DC coming from adapter different than DC coming from battery?



Also I noticed that the adapter indicator light is constant when charging a basic (non smartphone) phone battery but it pulsates when connected to step up convertor and cordless powered on. This made me more confused.



Please help me understand this behavior of adapter and what's wrong in what I am trying to do?










share|improve this question









New contributor




Raool is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











I am trying to power a 12 V 8 W cordless phone using a 5 V 1 A wall adapter.
I am using a step up DC/DC boost converter MT3608 for boosting output from 5 V to 12 V.



Theoretically it works - when I connect adapter to boost convertor input and setting potentiometer to 12 V by measuring output through multimeter - it shows 12 V.



But as soon as I connect the cordless the voltage drops to 2-3 V and cordless does not power on. So its not working on load.



I also have a 7.4 V li-ion cells which powers on the cordless fine - using the boost convertor.



My question is the DC coming from adapter different than DC coming from battery?



Also I noticed that the adapter indicator light is constant when charging a basic (non smartphone) phone battery but it pulsates when connected to step up convertor and cordless powered on. This made me more confused.



Please help me understand this behavior of adapter and what's wrong in what I am trying to do?







batteries boost






share|improve this question









New contributor




Raool is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|improve this question









New contributor




Raool is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|improve this question




share|improve this question








edited 4 hours ago









Jakub Rakus

2,10131121




2,10131121






New contributor




Raool is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









asked 4 hours ago









Raool

111




111




New contributor




Raool is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





Raool is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






Raool is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.








  • 3




    I don't think $5 V × 1 A> 8 W$.
    – Harry Svensson
    4 hours ago








  • 1




    A 5V 1A wall adapter cannot provide the 8 W that the phone requires, regardless of any boost converter that you are using. As a result, the adapter is limiting its output current and the voltage sags through. Please try a 2 A or higher adapter instead.
    – Andrey Akhmetov
    4 hours ago








  • 2




    Just get a 12V 1A wall wart. Readily available. Cheap. Problem solved. The only wrinkle may be matching the connector plug.
    – Phil Freedenberg
    4 hours ago














  • 3




    I don't think $5 V × 1 A> 8 W$.
    – Harry Svensson
    4 hours ago








  • 1




    A 5V 1A wall adapter cannot provide the 8 W that the phone requires, regardless of any boost converter that you are using. As a result, the adapter is limiting its output current and the voltage sags through. Please try a 2 A or higher adapter instead.
    – Andrey Akhmetov
    4 hours ago








  • 2




    Just get a 12V 1A wall wart. Readily available. Cheap. Problem solved. The only wrinkle may be matching the connector plug.
    – Phil Freedenberg
    4 hours ago








3




3




I don't think $5 V × 1 A> 8 W$.
– Harry Svensson
4 hours ago






I don't think $5 V × 1 A> 8 W$.
– Harry Svensson
4 hours ago






1




1




A 5V 1A wall adapter cannot provide the 8 W that the phone requires, regardless of any boost converter that you are using. As a result, the adapter is limiting its output current and the voltage sags through. Please try a 2 A or higher adapter instead.
– Andrey Akhmetov
4 hours ago






A 5V 1A wall adapter cannot provide the 8 W that the phone requires, regardless of any boost converter that you are using. As a result, the adapter is limiting its output current and the voltage sags through. Please try a 2 A or higher adapter instead.
– Andrey Akhmetov
4 hours ago






2




2




Just get a 12V 1A wall wart. Readily available. Cheap. Problem solved. The only wrinkle may be matching the connector plug.
– Phil Freedenberg
4 hours ago




Just get a 12V 1A wall wart. Readily available. Cheap. Problem solved. The only wrinkle may be matching the connector plug.
– Phil Freedenberg
4 hours ago










2 Answers
2






active

oldest

votes


















8















Theoretically it works -




No it doesn't. In theory 5 V x 1 A = 5 W maximum from your PSU. Your phone needs 8 W and you'll lose another 1 or 2 W in the voltage booster. It doesn't work in theory and, as you've found, it doesn't work in practice.




... when I connect adapter to boost convertor input and setting potentiometer to 12 V by measuring output through multimeter - it shows 12 V.




That's the open-circuit or unloaded voltage.




My question is the DC coming from adapter different than DC coming from battery?




Yes. The battery has a much higher current limit.




Also I noticed that the adapter indicator light is constant when charging a basic (non smartphone) phone battery but it pulsates when connected to step up convertor and cordless powered on. This made me more confused.




Why the confusion? Check the manual for the adaptor and you'll probably find that it's indicating over-current fault.






share|improve this answer





















  • Hi, Thanks so much for clarifying it. It now makes complete sense to me. Also, can i ask whether this arrangement- (5v 1a adaptor and a dc booster)- can be used to charge a 6v 4.5ah lead acid battery- if i increase voltage to 7v for charging battery -- (Its printed- 7v for cyclic use on battery)
    – Raool
    2 hours ago












  • It possibly could but you need to ensure that it doesn't get overcharged. Read up on lead-acid battery charging to gain more understanding first.
    – Transistor
    1 hour ago



















4














1. Theoretically it works:



Theoretically it is not correct, the power of adapter is not equal to the load power.



2.when I connect adapter to boost convertor input and setting potentiometer to 12 V by measuring output through multimeter



No load condition.



3. But as soon as I connect the cordless the voltage drops to 2-3 V and cordless does not power on. So its not working on load.



Obviously it will not, since the adapter is unable to provide the power required by the load.



4. I also have a 7.4 V li-ion cells which powers on the cordless fine - using the boost convertor.



The battery what you are using is having an high current delivery. that is required by the load.



5.Also I noticed that the adapter indicator light is constant when charging a basic (non smartphone) phone battery but it pulsates when connected to step up convertor and cordless powered on. This made me more confused.



Yeh, most of the Boost converters works on PWM technique.. which is going to use a switch and an inductor and capacitive network to change and discharge continuously to boost voltage... in this case the converter is going to draw current from the adapter in pulses (non-continuous).



Try the following...



Go with an readily available 12V, 1A adapter



or



Try an higher current rated adapter at 5V like 5V, 2A ... which is 10 Watts... since no boost converters are 100% efficient.






share|improve this answer





















  • Hi, Thanks so much for clarifying it. It now makes complete sense to me. I just have a doubt-- the pwm technique iis it harmful for adapter - i mean will it short circuit, or are the adaters designed for such behaviour. Also, can i ask whether this arrangement- (5v 1a adaptor and a dc booster)- can be used to charge a 6v 4.5ah lead acid battery- if i increase voltage to 7v for charging battery -- (Its printed- 7v for cyclic use on battery)
    – Raool
    1 hour ago










  • Yeh you can ... need to design an auto cut-off circuit. and the charge current should be less than 20% of AH. so in your case < 1A
    – Satish Singupuram
    27 mins ago













Your Answer





StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["\$", "\$"]]);
});
});
}, "mathjax-editing");

StackExchange.ifUsing("editor", function () {
return StackExchange.using("schematics", function () {
StackExchange.schematics.init();
});
}, "cicuitlab");

StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "135"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});


}
});






Raool is a new contributor. Be nice, and check out our Code of Conduct.










draft saved

draft discarded


















StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2felectronics.stackexchange.com%2fquestions%2f413773%2fusing-5-v-adapter-to-power-12-v-cordless-phone%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown

























2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes









8















Theoretically it works -




No it doesn't. In theory 5 V x 1 A = 5 W maximum from your PSU. Your phone needs 8 W and you'll lose another 1 or 2 W in the voltage booster. It doesn't work in theory and, as you've found, it doesn't work in practice.




... when I connect adapter to boost convertor input and setting potentiometer to 12 V by measuring output through multimeter - it shows 12 V.




That's the open-circuit or unloaded voltage.




My question is the DC coming from adapter different than DC coming from battery?




Yes. The battery has a much higher current limit.




Also I noticed that the adapter indicator light is constant when charging a basic (non smartphone) phone battery but it pulsates when connected to step up convertor and cordless powered on. This made me more confused.




Why the confusion? Check the manual for the adaptor and you'll probably find that it's indicating over-current fault.






share|improve this answer





















  • Hi, Thanks so much for clarifying it. It now makes complete sense to me. Also, can i ask whether this arrangement- (5v 1a adaptor and a dc booster)- can be used to charge a 6v 4.5ah lead acid battery- if i increase voltage to 7v for charging battery -- (Its printed- 7v for cyclic use on battery)
    – Raool
    2 hours ago












  • It possibly could but you need to ensure that it doesn't get overcharged. Read up on lead-acid battery charging to gain more understanding first.
    – Transistor
    1 hour ago
















8















Theoretically it works -




No it doesn't. In theory 5 V x 1 A = 5 W maximum from your PSU. Your phone needs 8 W and you'll lose another 1 or 2 W in the voltage booster. It doesn't work in theory and, as you've found, it doesn't work in practice.




... when I connect adapter to boost convertor input and setting potentiometer to 12 V by measuring output through multimeter - it shows 12 V.




That's the open-circuit or unloaded voltage.




My question is the DC coming from adapter different than DC coming from battery?




Yes. The battery has a much higher current limit.




Also I noticed that the adapter indicator light is constant when charging a basic (non smartphone) phone battery but it pulsates when connected to step up convertor and cordless powered on. This made me more confused.




Why the confusion? Check the manual for the adaptor and you'll probably find that it's indicating over-current fault.






share|improve this answer





















  • Hi, Thanks so much for clarifying it. It now makes complete sense to me. Also, can i ask whether this arrangement- (5v 1a adaptor and a dc booster)- can be used to charge a 6v 4.5ah lead acid battery- if i increase voltage to 7v for charging battery -- (Its printed- 7v for cyclic use on battery)
    – Raool
    2 hours ago












  • It possibly could but you need to ensure that it doesn't get overcharged. Read up on lead-acid battery charging to gain more understanding first.
    – Transistor
    1 hour ago














8












8








8







Theoretically it works -




No it doesn't. In theory 5 V x 1 A = 5 W maximum from your PSU. Your phone needs 8 W and you'll lose another 1 or 2 W in the voltage booster. It doesn't work in theory and, as you've found, it doesn't work in practice.




... when I connect adapter to boost convertor input and setting potentiometer to 12 V by measuring output through multimeter - it shows 12 V.




That's the open-circuit or unloaded voltage.




My question is the DC coming from adapter different than DC coming from battery?




Yes. The battery has a much higher current limit.




Also I noticed that the adapter indicator light is constant when charging a basic (non smartphone) phone battery but it pulsates when connected to step up convertor and cordless powered on. This made me more confused.




Why the confusion? Check the manual for the adaptor and you'll probably find that it's indicating over-current fault.






share|improve this answer













Theoretically it works -




No it doesn't. In theory 5 V x 1 A = 5 W maximum from your PSU. Your phone needs 8 W and you'll lose another 1 or 2 W in the voltage booster. It doesn't work in theory and, as you've found, it doesn't work in practice.




... when I connect adapter to boost convertor input and setting potentiometer to 12 V by measuring output through multimeter - it shows 12 V.




That's the open-circuit or unloaded voltage.




My question is the DC coming from adapter different than DC coming from battery?




Yes. The battery has a much higher current limit.




Also I noticed that the adapter indicator light is constant when charging a basic (non smartphone) phone battery but it pulsates when connected to step up convertor and cordless powered on. This made me more confused.




Why the confusion? Check the manual for the adaptor and you'll probably find that it's indicating over-current fault.







share|improve this answer












share|improve this answer



share|improve this answer










answered 3 hours ago









Transistor

79.9k778172




79.9k778172












  • Hi, Thanks so much for clarifying it. It now makes complete sense to me. Also, can i ask whether this arrangement- (5v 1a adaptor and a dc booster)- can be used to charge a 6v 4.5ah lead acid battery- if i increase voltage to 7v for charging battery -- (Its printed- 7v for cyclic use on battery)
    – Raool
    2 hours ago












  • It possibly could but you need to ensure that it doesn't get overcharged. Read up on lead-acid battery charging to gain more understanding first.
    – Transistor
    1 hour ago


















  • Hi, Thanks so much for clarifying it. It now makes complete sense to me. Also, can i ask whether this arrangement- (5v 1a adaptor and a dc booster)- can be used to charge a 6v 4.5ah lead acid battery- if i increase voltage to 7v for charging battery -- (Its printed- 7v for cyclic use on battery)
    – Raool
    2 hours ago












  • It possibly could but you need to ensure that it doesn't get overcharged. Read up on lead-acid battery charging to gain more understanding first.
    – Transistor
    1 hour ago
















Hi, Thanks so much for clarifying it. It now makes complete sense to me. Also, can i ask whether this arrangement- (5v 1a adaptor and a dc booster)- can be used to charge a 6v 4.5ah lead acid battery- if i increase voltage to 7v for charging battery -- (Its printed- 7v for cyclic use on battery)
– Raool
2 hours ago






Hi, Thanks so much for clarifying it. It now makes complete sense to me. Also, can i ask whether this arrangement- (5v 1a adaptor and a dc booster)- can be used to charge a 6v 4.5ah lead acid battery- if i increase voltage to 7v for charging battery -- (Its printed- 7v for cyclic use on battery)
– Raool
2 hours ago














It possibly could but you need to ensure that it doesn't get overcharged. Read up on lead-acid battery charging to gain more understanding first.
– Transistor
1 hour ago




It possibly could but you need to ensure that it doesn't get overcharged. Read up on lead-acid battery charging to gain more understanding first.
– Transistor
1 hour ago













4














1. Theoretically it works:



Theoretically it is not correct, the power of adapter is not equal to the load power.



2.when I connect adapter to boost convertor input and setting potentiometer to 12 V by measuring output through multimeter



No load condition.



3. But as soon as I connect the cordless the voltage drops to 2-3 V and cordless does not power on. So its not working on load.



Obviously it will not, since the adapter is unable to provide the power required by the load.



4. I also have a 7.4 V li-ion cells which powers on the cordless fine - using the boost convertor.



The battery what you are using is having an high current delivery. that is required by the load.



5.Also I noticed that the adapter indicator light is constant when charging a basic (non smartphone) phone battery but it pulsates when connected to step up convertor and cordless powered on. This made me more confused.



Yeh, most of the Boost converters works on PWM technique.. which is going to use a switch and an inductor and capacitive network to change and discharge continuously to boost voltage... in this case the converter is going to draw current from the adapter in pulses (non-continuous).



Try the following...



Go with an readily available 12V, 1A adapter



or



Try an higher current rated adapter at 5V like 5V, 2A ... which is 10 Watts... since no boost converters are 100% efficient.






share|improve this answer





















  • Hi, Thanks so much for clarifying it. It now makes complete sense to me. I just have a doubt-- the pwm technique iis it harmful for adapter - i mean will it short circuit, or are the adaters designed for such behaviour. Also, can i ask whether this arrangement- (5v 1a adaptor and a dc booster)- can be used to charge a 6v 4.5ah lead acid battery- if i increase voltage to 7v for charging battery -- (Its printed- 7v for cyclic use on battery)
    – Raool
    1 hour ago










  • Yeh you can ... need to design an auto cut-off circuit. and the charge current should be less than 20% of AH. so in your case < 1A
    – Satish Singupuram
    27 mins ago


















4














1. Theoretically it works:



Theoretically it is not correct, the power of adapter is not equal to the load power.



2.when I connect adapter to boost convertor input and setting potentiometer to 12 V by measuring output through multimeter



No load condition.



3. But as soon as I connect the cordless the voltage drops to 2-3 V and cordless does not power on. So its not working on load.



Obviously it will not, since the adapter is unable to provide the power required by the load.



4. I also have a 7.4 V li-ion cells which powers on the cordless fine - using the boost convertor.



The battery what you are using is having an high current delivery. that is required by the load.



5.Also I noticed that the adapter indicator light is constant when charging a basic (non smartphone) phone battery but it pulsates when connected to step up convertor and cordless powered on. This made me more confused.



Yeh, most of the Boost converters works on PWM technique.. which is going to use a switch and an inductor and capacitive network to change and discharge continuously to boost voltage... in this case the converter is going to draw current from the adapter in pulses (non-continuous).



Try the following...



Go with an readily available 12V, 1A adapter



or



Try an higher current rated adapter at 5V like 5V, 2A ... which is 10 Watts... since no boost converters are 100% efficient.






share|improve this answer





















  • Hi, Thanks so much for clarifying it. It now makes complete sense to me. I just have a doubt-- the pwm technique iis it harmful for adapter - i mean will it short circuit, or are the adaters designed for such behaviour. Also, can i ask whether this arrangement- (5v 1a adaptor and a dc booster)- can be used to charge a 6v 4.5ah lead acid battery- if i increase voltage to 7v for charging battery -- (Its printed- 7v for cyclic use on battery)
    – Raool
    1 hour ago










  • Yeh you can ... need to design an auto cut-off circuit. and the charge current should be less than 20% of AH. so in your case < 1A
    – Satish Singupuram
    27 mins ago
















4












4








4






1. Theoretically it works:



Theoretically it is not correct, the power of adapter is not equal to the load power.



2.when I connect adapter to boost convertor input and setting potentiometer to 12 V by measuring output through multimeter



No load condition.



3. But as soon as I connect the cordless the voltage drops to 2-3 V and cordless does not power on. So its not working on load.



Obviously it will not, since the adapter is unable to provide the power required by the load.



4. I also have a 7.4 V li-ion cells which powers on the cordless fine - using the boost convertor.



The battery what you are using is having an high current delivery. that is required by the load.



5.Also I noticed that the adapter indicator light is constant when charging a basic (non smartphone) phone battery but it pulsates when connected to step up convertor and cordless powered on. This made me more confused.



Yeh, most of the Boost converters works on PWM technique.. which is going to use a switch and an inductor and capacitive network to change and discharge continuously to boost voltage... in this case the converter is going to draw current from the adapter in pulses (non-continuous).



Try the following...



Go with an readily available 12V, 1A adapter



or



Try an higher current rated adapter at 5V like 5V, 2A ... which is 10 Watts... since no boost converters are 100% efficient.






share|improve this answer












1. Theoretically it works:



Theoretically it is not correct, the power of adapter is not equal to the load power.



2.when I connect adapter to boost convertor input and setting potentiometer to 12 V by measuring output through multimeter



No load condition.



3. But as soon as I connect the cordless the voltage drops to 2-3 V and cordless does not power on. So its not working on load.



Obviously it will not, since the adapter is unable to provide the power required by the load.



4. I also have a 7.4 V li-ion cells which powers on the cordless fine - using the boost convertor.



The battery what you are using is having an high current delivery. that is required by the load.



5.Also I noticed that the adapter indicator light is constant when charging a basic (non smartphone) phone battery but it pulsates when connected to step up convertor and cordless powered on. This made me more confused.



Yeh, most of the Boost converters works on PWM technique.. which is going to use a switch and an inductor and capacitive network to change and discharge continuously to boost voltage... in this case the converter is going to draw current from the adapter in pulses (non-continuous).



Try the following...



Go with an readily available 12V, 1A adapter



or



Try an higher current rated adapter at 5V like 5V, 2A ... which is 10 Watts... since no boost converters are 100% efficient.







share|improve this answer












share|improve this answer



share|improve this answer










answered 2 hours ago









Satish Singupuram

4989




4989












  • Hi, Thanks so much for clarifying it. It now makes complete sense to me. I just have a doubt-- the pwm technique iis it harmful for adapter - i mean will it short circuit, or are the adaters designed for such behaviour. Also, can i ask whether this arrangement- (5v 1a adaptor and a dc booster)- can be used to charge a 6v 4.5ah lead acid battery- if i increase voltage to 7v for charging battery -- (Its printed- 7v for cyclic use on battery)
    – Raool
    1 hour ago










  • Yeh you can ... need to design an auto cut-off circuit. and the charge current should be less than 20% of AH. so in your case < 1A
    – Satish Singupuram
    27 mins ago




















  • Hi, Thanks so much for clarifying it. It now makes complete sense to me. I just have a doubt-- the pwm technique iis it harmful for adapter - i mean will it short circuit, or are the adaters designed for such behaviour. Also, can i ask whether this arrangement- (5v 1a adaptor and a dc booster)- can be used to charge a 6v 4.5ah lead acid battery- if i increase voltage to 7v for charging battery -- (Its printed- 7v for cyclic use on battery)
    – Raool
    1 hour ago










  • Yeh you can ... need to design an auto cut-off circuit. and the charge current should be less than 20% of AH. so in your case < 1A
    – Satish Singupuram
    27 mins ago


















Hi, Thanks so much for clarifying it. It now makes complete sense to me. I just have a doubt-- the pwm technique iis it harmful for adapter - i mean will it short circuit, or are the adaters designed for such behaviour. Also, can i ask whether this arrangement- (5v 1a adaptor and a dc booster)- can be used to charge a 6v 4.5ah lead acid battery- if i increase voltage to 7v for charging battery -- (Its printed- 7v for cyclic use on battery)
– Raool
1 hour ago




Hi, Thanks so much for clarifying it. It now makes complete sense to me. I just have a doubt-- the pwm technique iis it harmful for adapter - i mean will it short circuit, or are the adaters designed for such behaviour. Also, can i ask whether this arrangement- (5v 1a adaptor and a dc booster)- can be used to charge a 6v 4.5ah lead acid battery- if i increase voltage to 7v for charging battery -- (Its printed- 7v for cyclic use on battery)
– Raool
1 hour ago












Yeh you can ... need to design an auto cut-off circuit. and the charge current should be less than 20% of AH. so in your case < 1A
– Satish Singupuram
27 mins ago






Yeh you can ... need to design an auto cut-off circuit. and the charge current should be less than 20% of AH. so in your case < 1A
– Satish Singupuram
27 mins ago












Raool is a new contributor. Be nice, and check out our Code of Conduct.










draft saved

draft discarded


















Raool is a new contributor. Be nice, and check out our Code of Conduct.













Raool is a new contributor. Be nice, and check out our Code of Conduct.












Raool is a new contributor. Be nice, and check out our Code of Conduct.
















Thanks for contributing an answer to Electrical Engineering Stack Exchange!


  • Please be sure to answer the question. Provide details and share your research!

But avoid



  • Asking for help, clarification, or responding to other answers.

  • Making statements based on opinion; back them up with references or personal experience.


Use MathJax to format equations. MathJax reference.


To learn more, see our tips on writing great answers.





Some of your past answers have not been well-received, and you're in danger of being blocked from answering.


Please pay close attention to the following guidance:


  • Please be sure to answer the question. Provide details and share your research!

But avoid



  • Asking for help, clarification, or responding to other answers.

  • Making statements based on opinion; back them up with references or personal experience.


To learn more, see our tips on writing great answers.




draft saved


draft discarded














StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2felectronics.stackexchange.com%2fquestions%2f413773%2fusing-5-v-adapter-to-power-12-v-cordless-phone%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown





















































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown

































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown







Popular posts from this blog

404 Error Contact Form 7 ajax form submitting

How to know if a Active Directory user can login interactively

Refactoring coordinates for Minecraft Pi buildings written in Python