Generate choose on custom data type with 2 options












0















I am trying to achieve something very simple.
I have this data type :



import Test.QuickCheck
import System.Random
data Letter = G | B deriving(Show, Eq, Bounded)

arbitraryLetter :: Gen Letter
arbitraryLetter = choose (G,B)


I am compiling and getting this error



    • No instance for (Random Letter) arising from a use of ‘choose’
• In the expression: choose (G, B)
In an equation for ‘arbitraryLetter’:
arbitraryLetter = choose (G, B)


Why isn't this working?
I want to be able to use QuickCheck on this data type.










share|improve this question



























    0















    I am trying to achieve something very simple.
    I have this data type :



    import Test.QuickCheck
    import System.Random
    data Letter = G | B deriving(Show, Eq, Bounded)

    arbitraryLetter :: Gen Letter
    arbitraryLetter = choose (G,B)


    I am compiling and getting this error



        • No instance for (Random Letter) arising from a use of ‘choose’
    • In the expression: choose (G, B)
    In an equation for ‘arbitraryLetter’:
    arbitraryLetter = choose (G, B)


    Why isn't this working?
    I want to be able to use QuickCheck on this data type.










    share|improve this question

























      0












      0








      0








      I am trying to achieve something very simple.
      I have this data type :



      import Test.QuickCheck
      import System.Random
      data Letter = G | B deriving(Show, Eq, Bounded)

      arbitraryLetter :: Gen Letter
      arbitraryLetter = choose (G,B)


      I am compiling and getting this error



          • No instance for (Random Letter) arising from a use of ‘choose’
      • In the expression: choose (G, B)
      In an equation for ‘arbitraryLetter’:
      arbitraryLetter = choose (G, B)


      Why isn't this working?
      I want to be able to use QuickCheck on this data type.










      share|improve this question














      I am trying to achieve something very simple.
      I have this data type :



      import Test.QuickCheck
      import System.Random
      data Letter = G | B deriving(Show, Eq, Bounded)

      arbitraryLetter :: Gen Letter
      arbitraryLetter = choose (G,B)


      I am compiling and getting this error



          • No instance for (Random Letter) arising from a use of ‘choose’
      • In the expression: choose (G, B)
      In an equation for ‘arbitraryLetter’:
      arbitraryLetter = choose (G, B)


      Why isn't this working?
      I want to be able to use QuickCheck on this data type.







      haskell quickcheck






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 24 '18 at 13:12









      EyzukyEyzuky

      7741024




      7741024
























          1 Answer
          1






          active

          oldest

          votes


















          1














          choose has type Random a => (a, a) -> Gen a, so choose (G, B) requires a Random instance for your Letter type. If you want to create a generator from a set of values you can use elements instead:



          arbitraryLetter :: Gen Letter
          arbitraryLetter = elements [G, B]





          share|improve this answer
























          • Thanks, How do I generate 1 and print to the console? I tried running arbitraryLetter and got an error : • No instance for (Show (Gen Letter)) arising from a use of ‘print’ • In a stmt of an interactive GHCi command: print it

            – Eyzuky
            Nov 24 '18 at 13:47






          • 1





            @Eyzuky - You can use sample in ghci: sample arbitraryLetter.

            – Lee
            Nov 24 '18 at 14:20











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          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          1














          choose has type Random a => (a, a) -> Gen a, so choose (G, B) requires a Random instance for your Letter type. If you want to create a generator from a set of values you can use elements instead:



          arbitraryLetter :: Gen Letter
          arbitraryLetter = elements [G, B]





          share|improve this answer
























          • Thanks, How do I generate 1 and print to the console? I tried running arbitraryLetter and got an error : • No instance for (Show (Gen Letter)) arising from a use of ‘print’ • In a stmt of an interactive GHCi command: print it

            – Eyzuky
            Nov 24 '18 at 13:47






          • 1





            @Eyzuky - You can use sample in ghci: sample arbitraryLetter.

            – Lee
            Nov 24 '18 at 14:20
















          1














          choose has type Random a => (a, a) -> Gen a, so choose (G, B) requires a Random instance for your Letter type. If you want to create a generator from a set of values you can use elements instead:



          arbitraryLetter :: Gen Letter
          arbitraryLetter = elements [G, B]





          share|improve this answer
























          • Thanks, How do I generate 1 and print to the console? I tried running arbitraryLetter and got an error : • No instance for (Show (Gen Letter)) arising from a use of ‘print’ • In a stmt of an interactive GHCi command: print it

            – Eyzuky
            Nov 24 '18 at 13:47






          • 1





            @Eyzuky - You can use sample in ghci: sample arbitraryLetter.

            – Lee
            Nov 24 '18 at 14:20














          1












          1








          1







          choose has type Random a => (a, a) -> Gen a, so choose (G, B) requires a Random instance for your Letter type. If you want to create a generator from a set of values you can use elements instead:



          arbitraryLetter :: Gen Letter
          arbitraryLetter = elements [G, B]





          share|improve this answer













          choose has type Random a => (a, a) -> Gen a, so choose (G, B) requires a Random instance for your Letter type. If you want to create a generator from a set of values you can use elements instead:



          arbitraryLetter :: Gen Letter
          arbitraryLetter = elements [G, B]






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 24 '18 at 13:26









          LeeLee

          119k14175245




          119k14175245













          • Thanks, How do I generate 1 and print to the console? I tried running arbitraryLetter and got an error : • No instance for (Show (Gen Letter)) arising from a use of ‘print’ • In a stmt of an interactive GHCi command: print it

            – Eyzuky
            Nov 24 '18 at 13:47






          • 1





            @Eyzuky - You can use sample in ghci: sample arbitraryLetter.

            – Lee
            Nov 24 '18 at 14:20



















          • Thanks, How do I generate 1 and print to the console? I tried running arbitraryLetter and got an error : • No instance for (Show (Gen Letter)) arising from a use of ‘print’ • In a stmt of an interactive GHCi command: print it

            – Eyzuky
            Nov 24 '18 at 13:47






          • 1





            @Eyzuky - You can use sample in ghci: sample arbitraryLetter.

            – Lee
            Nov 24 '18 at 14:20

















          Thanks, How do I generate 1 and print to the console? I tried running arbitraryLetter and got an error : • No instance for (Show (Gen Letter)) arising from a use of ‘print’ • In a stmt of an interactive GHCi command: print it

          – Eyzuky
          Nov 24 '18 at 13:47





          Thanks, How do I generate 1 and print to the console? I tried running arbitraryLetter and got an error : • No instance for (Show (Gen Letter)) arising from a use of ‘print’ • In a stmt of an interactive GHCi command: print it

          – Eyzuky
          Nov 24 '18 at 13:47




          1




          1





          @Eyzuky - You can use sample in ghci: sample arbitraryLetter.

          – Lee
          Nov 24 '18 at 14:20





          @Eyzuky - You can use sample in ghci: sample arbitraryLetter.

          – Lee
          Nov 24 '18 at 14:20




















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