Scoreboard sorting (Secondary sort, skip duplicate ranking)











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I have two different scoreboard sorting function but one of them is not working in some test cases (which I don't know).



Example input/output



Input: 4 Contestants and then the list of the score.



4
AAA 3 2 1
CCC 2 3 1
BBB 2 3 1
DDD 1 1 0


Output: BBB, CCC is using the same ranking so there is no 3rd place then DDD is using 4th place instead



1 AAA 3 2 1 6
2 BBB 2 3 1 6
2 CCC 2 3 1 6
4 DDD 1 1 0 2


Sorting Order (Primary, Secondary, Tertiary, Quaternary)




  • Gold Medal (Descending - Most on top)

  • Silver Medal (Descending)

  • Bronze Medal (Descending)

  • Contestant's name (Alphabetical Order)


Here's the first one (Working Correctly)



This one uses dictionary characteristic which key cannot be duplicated.



ranking = dict()
for _ in range(int(input())):
lst = input().split()
contestant, score = lst[0], tuple(map(int, lst[1:]))
if ranking.get(score): #If same score exist append it
ranking.get(score).append(contestant)
else: ranking[score] = [contestant] #If not create new key

ranking = list(map(lambda i: (i[0], sorted(i[1])), sorted(ranking.items(), reverse=True)))
rank = 1

for i, j in ranking: #Print out the result
for k in j:
print(rank, k, " ".join(map(str, i)), sum(i))
rank += len(j) #Skip the duplicate rank


Here's what ranking will look like:



[((3, 2, 1), ['AAA']), ((2, 3, 1), ['BBB', 'CCC']), ((1, 1, 0), ['DDD'])]


Second One (Working Correctly but not on some cases)



This one just appends to the list and check for a duplicate when printing.



ranking = [input().split() for _ in range(int(input()))]
#Convert each items into format like (Contestant, Gold, Silver, Bronze, Total)
ranking = map(lambda i: [i[0]] + list(map(int, i[1:])) + [sum(map(int, i[1:]))], ranking)
#Sort by descending on medals but ascending on contestant's name
ranking = sorted(ranking, key=lambda i: (-i[1], -i[2], -i[3], i[0]))

rank = 0 #Current Ranking
same = 0 #1 if last item's have the same score else 0
last = #Store last printed score
for i in ranking:
if i[1:] != last:
rank += 1
else: same = 1
if same and i[1:] != last:
same = 0
rank += 1
print(rank, *i)
last = i[1:]


ranking for this one



[['AAA', 3, 2, 1, 6], ['BBB', 2, 3, 1, 6], ['CCC', 2, 3, 1, 6], ['DDD', 1, 1, 0, 2]]


I have no idea what causes these two to output different results.









share


























    up vote
    0
    down vote

    favorite












    I have two different scoreboard sorting function but one of them is not working in some test cases (which I don't know).



    Example input/output



    Input: 4 Contestants and then the list of the score.



    4
    AAA 3 2 1
    CCC 2 3 1
    BBB 2 3 1
    DDD 1 1 0


    Output: BBB, CCC is using the same ranking so there is no 3rd place then DDD is using 4th place instead



    1 AAA 3 2 1 6
    2 BBB 2 3 1 6
    2 CCC 2 3 1 6
    4 DDD 1 1 0 2


    Sorting Order (Primary, Secondary, Tertiary, Quaternary)




    • Gold Medal (Descending - Most on top)

    • Silver Medal (Descending)

    • Bronze Medal (Descending)

    • Contestant's name (Alphabetical Order)


    Here's the first one (Working Correctly)



    This one uses dictionary characteristic which key cannot be duplicated.



    ranking = dict()
    for _ in range(int(input())):
    lst = input().split()
    contestant, score = lst[0], tuple(map(int, lst[1:]))
    if ranking.get(score): #If same score exist append it
    ranking.get(score).append(contestant)
    else: ranking[score] = [contestant] #If not create new key

    ranking = list(map(lambda i: (i[0], sorted(i[1])), sorted(ranking.items(), reverse=True)))
    rank = 1

    for i, j in ranking: #Print out the result
    for k in j:
    print(rank, k, " ".join(map(str, i)), sum(i))
    rank += len(j) #Skip the duplicate rank


    Here's what ranking will look like:



    [((3, 2, 1), ['AAA']), ((2, 3, 1), ['BBB', 'CCC']), ((1, 1, 0), ['DDD'])]


    Second One (Working Correctly but not on some cases)



    This one just appends to the list and check for a duplicate when printing.



    ranking = [input().split() for _ in range(int(input()))]
    #Convert each items into format like (Contestant, Gold, Silver, Bronze, Total)
    ranking = map(lambda i: [i[0]] + list(map(int, i[1:])) + [sum(map(int, i[1:]))], ranking)
    #Sort by descending on medals but ascending on contestant's name
    ranking = sorted(ranking, key=lambda i: (-i[1], -i[2], -i[3], i[0]))

    rank = 0 #Current Ranking
    same = 0 #1 if last item's have the same score else 0
    last = #Store last printed score
    for i in ranking:
    if i[1:] != last:
    rank += 1
    else: same = 1
    if same and i[1:] != last:
    same = 0
    rank += 1
    print(rank, *i)
    last = i[1:]


    ranking for this one



    [['AAA', 3, 2, 1, 6], ['BBB', 2, 3, 1, 6], ['CCC', 2, 3, 1, 6], ['DDD', 1, 1, 0, 2]]


    I have no idea what causes these two to output different results.









    share
























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      I have two different scoreboard sorting function but one of them is not working in some test cases (which I don't know).



      Example input/output



      Input: 4 Contestants and then the list of the score.



      4
      AAA 3 2 1
      CCC 2 3 1
      BBB 2 3 1
      DDD 1 1 0


      Output: BBB, CCC is using the same ranking so there is no 3rd place then DDD is using 4th place instead



      1 AAA 3 2 1 6
      2 BBB 2 3 1 6
      2 CCC 2 3 1 6
      4 DDD 1 1 0 2


      Sorting Order (Primary, Secondary, Tertiary, Quaternary)




      • Gold Medal (Descending - Most on top)

      • Silver Medal (Descending)

      • Bronze Medal (Descending)

      • Contestant's name (Alphabetical Order)


      Here's the first one (Working Correctly)



      This one uses dictionary characteristic which key cannot be duplicated.



      ranking = dict()
      for _ in range(int(input())):
      lst = input().split()
      contestant, score = lst[0], tuple(map(int, lst[1:]))
      if ranking.get(score): #If same score exist append it
      ranking.get(score).append(contestant)
      else: ranking[score] = [contestant] #If not create new key

      ranking = list(map(lambda i: (i[0], sorted(i[1])), sorted(ranking.items(), reverse=True)))
      rank = 1

      for i, j in ranking: #Print out the result
      for k in j:
      print(rank, k, " ".join(map(str, i)), sum(i))
      rank += len(j) #Skip the duplicate rank


      Here's what ranking will look like:



      [((3, 2, 1), ['AAA']), ((2, 3, 1), ['BBB', 'CCC']), ((1, 1, 0), ['DDD'])]


      Second One (Working Correctly but not on some cases)



      This one just appends to the list and check for a duplicate when printing.



      ranking = [input().split() for _ in range(int(input()))]
      #Convert each items into format like (Contestant, Gold, Silver, Bronze, Total)
      ranking = map(lambda i: [i[0]] + list(map(int, i[1:])) + [sum(map(int, i[1:]))], ranking)
      #Sort by descending on medals but ascending on contestant's name
      ranking = sorted(ranking, key=lambda i: (-i[1], -i[2], -i[3], i[0]))

      rank = 0 #Current Ranking
      same = 0 #1 if last item's have the same score else 0
      last = #Store last printed score
      for i in ranking:
      if i[1:] != last:
      rank += 1
      else: same = 1
      if same and i[1:] != last:
      same = 0
      rank += 1
      print(rank, *i)
      last = i[1:]


      ranking for this one



      [['AAA', 3, 2, 1, 6], ['BBB', 2, 3, 1, 6], ['CCC', 2, 3, 1, 6], ['DDD', 1, 1, 0, 2]]


      I have no idea what causes these two to output different results.









      share













      I have two different scoreboard sorting function but one of them is not working in some test cases (which I don't know).



      Example input/output



      Input: 4 Contestants and then the list of the score.



      4
      AAA 3 2 1
      CCC 2 3 1
      BBB 2 3 1
      DDD 1 1 0


      Output: BBB, CCC is using the same ranking so there is no 3rd place then DDD is using 4th place instead



      1 AAA 3 2 1 6
      2 BBB 2 3 1 6
      2 CCC 2 3 1 6
      4 DDD 1 1 0 2


      Sorting Order (Primary, Secondary, Tertiary, Quaternary)




      • Gold Medal (Descending - Most on top)

      • Silver Medal (Descending)

      • Bronze Medal (Descending)

      • Contestant's name (Alphabetical Order)


      Here's the first one (Working Correctly)



      This one uses dictionary characteristic which key cannot be duplicated.



      ranking = dict()
      for _ in range(int(input())):
      lst = input().split()
      contestant, score = lst[0], tuple(map(int, lst[1:]))
      if ranking.get(score): #If same score exist append it
      ranking.get(score).append(contestant)
      else: ranking[score] = [contestant] #If not create new key

      ranking = list(map(lambda i: (i[0], sorted(i[1])), sorted(ranking.items(), reverse=True)))
      rank = 1

      for i, j in ranking: #Print out the result
      for k in j:
      print(rank, k, " ".join(map(str, i)), sum(i))
      rank += len(j) #Skip the duplicate rank


      Here's what ranking will look like:



      [((3, 2, 1), ['AAA']), ((2, 3, 1), ['BBB', 'CCC']), ((1, 1, 0), ['DDD'])]


      Second One (Working Correctly but not on some cases)



      This one just appends to the list and check for a duplicate when printing.



      ranking = [input().split() for _ in range(int(input()))]
      #Convert each items into format like (Contestant, Gold, Silver, Bronze, Total)
      ranking = map(lambda i: [i[0]] + list(map(int, i[1:])) + [sum(map(int, i[1:]))], ranking)
      #Sort by descending on medals but ascending on contestant's name
      ranking = sorted(ranking, key=lambda i: (-i[1], -i[2], -i[3], i[0]))

      rank = 0 #Current Ranking
      same = 0 #1 if last item's have the same score else 0
      last = #Store last printed score
      for i in ranking:
      if i[1:] != last:
      rank += 1
      else: same = 1
      if same and i[1:] != last:
      same = 0
      rank += 1
      print(rank, *i)
      last = i[1:]


      ranking for this one



      [['AAA', 3, 2, 1, 6], ['BBB', 2, 3, 1, 6], ['CCC', 2, 3, 1, 6], ['DDD', 1, 1, 0, 2]]


      I have no idea what causes these two to output different results.







      python sorting unit-testing





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