ngOnChanges for multiple values in different child components in angular 6
I have a parent component which makes 2 async api calls and gets data from the backend. I am watching these variables from 2 child components. I am using angular 6
Parent Component.html:
<child-comp1 [data1]="data1"></child-comp1>
<child-comp2 [data2]="data2"></child-comp2>
Parent-component.ts :
getData(){
this.getData1();
this.getData2();
}
getData1(){
//Make api call to get data.
this.data1 = response;
}
getData2(){
//Make api call to get data2
this.data2 = response;
}
Child-component1.ts:
@Input data1 : Array[Data1Model1];
ngOnChanges(changes: SimpleChanges) {
if (changes['data1']) {
}
}
Child-component2.ts:
@Input data2 : Array[Data1Model2];
ngOnChanges(changes: SimpleChanges) {
if (changes['data2']) {
}
}
Changes are not detected for child-component2. When i remove the child-component1, the changes are detected in component2. How can both components detect changes at the same time?
typescript angular6 ngonchanges
add a comment |
I have a parent component which makes 2 async api calls and gets data from the backend. I am watching these variables from 2 child components. I am using angular 6
Parent Component.html:
<child-comp1 [data1]="data1"></child-comp1>
<child-comp2 [data2]="data2"></child-comp2>
Parent-component.ts :
getData(){
this.getData1();
this.getData2();
}
getData1(){
//Make api call to get data.
this.data1 = response;
}
getData2(){
//Make api call to get data2
this.data2 = response;
}
Child-component1.ts:
@Input data1 : Array[Data1Model1];
ngOnChanges(changes: SimpleChanges) {
if (changes['data1']) {
}
}
Child-component2.ts:
@Input data2 : Array[Data1Model2];
ngOnChanges(changes: SimpleChanges) {
if (changes['data2']) {
}
}
Changes are not detected for child-component2. When i remove the child-component1, the changes are detected in component2. How can both components detect changes at the same time?
typescript angular6 ngonchanges
Post a complete minimal example reproducing the problem. We can't tell anything with the pseudo-code you posted.
– JB Nizet
Nov 21 at 7:00
add a comment |
I have a parent component which makes 2 async api calls and gets data from the backend. I am watching these variables from 2 child components. I am using angular 6
Parent Component.html:
<child-comp1 [data1]="data1"></child-comp1>
<child-comp2 [data2]="data2"></child-comp2>
Parent-component.ts :
getData(){
this.getData1();
this.getData2();
}
getData1(){
//Make api call to get data.
this.data1 = response;
}
getData2(){
//Make api call to get data2
this.data2 = response;
}
Child-component1.ts:
@Input data1 : Array[Data1Model1];
ngOnChanges(changes: SimpleChanges) {
if (changes['data1']) {
}
}
Child-component2.ts:
@Input data2 : Array[Data1Model2];
ngOnChanges(changes: SimpleChanges) {
if (changes['data2']) {
}
}
Changes are not detected for child-component2. When i remove the child-component1, the changes are detected in component2. How can both components detect changes at the same time?
typescript angular6 ngonchanges
I have a parent component which makes 2 async api calls and gets data from the backend. I am watching these variables from 2 child components. I am using angular 6
Parent Component.html:
<child-comp1 [data1]="data1"></child-comp1>
<child-comp2 [data2]="data2"></child-comp2>
Parent-component.ts :
getData(){
this.getData1();
this.getData2();
}
getData1(){
//Make api call to get data.
this.data1 = response;
}
getData2(){
//Make api call to get data2
this.data2 = response;
}
Child-component1.ts:
@Input data1 : Array[Data1Model1];
ngOnChanges(changes: SimpleChanges) {
if (changes['data1']) {
}
}
Child-component2.ts:
@Input data2 : Array[Data1Model2];
ngOnChanges(changes: SimpleChanges) {
if (changes['data2']) {
}
}
Changes are not detected for child-component2. When i remove the child-component1, the changes are detected in component2. How can both components detect changes at the same time?
typescript angular6 ngonchanges
typescript angular6 ngonchanges
asked Nov 21 at 6:25
UI Dev
276
276
Post a complete minimal example reproducing the problem. We can't tell anything with the pseudo-code you posted.
– JB Nizet
Nov 21 at 7:00
add a comment |
Post a complete minimal example reproducing the problem. We can't tell anything with the pseudo-code you posted.
– JB Nizet
Nov 21 at 7:00
Post a complete minimal example reproducing the problem. We can't tell anything with the pseudo-code you posted.
– JB Nizet
Nov 21 at 7:00
Post a complete minimal example reproducing the problem. We can't tell anything with the pseudo-code you posted.
– JB Nizet
Nov 21 at 7:00
add a comment |
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Post a complete minimal example reproducing the problem. We can't tell anything with the pseudo-code you posted.
– JB Nizet
Nov 21 at 7:00