Calculate last month, last 3 months, and last 6 months from today
I am looking for some ideas on how this could be improved:
switch ($periodValue) {
case "lastmonth":
$until = mktime(0, 0, 0, date('n'), 1, date('Y'));
$from = mktime(0, 0, 0, date('n', $until) - 1, 1, date('Y', $until));
break;
case "last3month":
$until = mktime(0, 0, 0, date('n'), 1, date('Y'));
$from = mktime(0, 0, 0, date('n', $until)-3, 1, date('Y', $until));
break;
case "last6month":
$until = mktime(0, 0, 0, date('n'), 1, date('Y'));
$from = mktime(0, 0, 0, date('n', $until)-6, 1, date('Y', $until));
break;
How could I make this "smarter", so that it works out if we are near the end of the month it will show the last 30 days instead of the previous month?
php datetime
edited Sep 10 '14 at 14:12
Jamal♦
30.2k11116226
asked Sep 25 '12 at 18:50
John Magnolia
158116
add a comment |
I am looking for some ideas on how this could be improved:
switch ($periodValue) {
case "lastmonth":
$until = mktime(0, 0, 0, date('n'), 1, date('Y'));
$from = mktime(0, 0, 0, date('n', $until) - 1, 1, date('Y', $until));
break;
case "last3month":
$until = mktime(0, 0, 0, date('n'), 1, date('Y'));
$from = mktime(0, 0, 0, date('n', $until)-3, 1, date('Y', $until));
break;
case "last6month":
$until = mktime(0, 0, 0, date('n'), 1, date('Y'));
$from = mktime(0, 0, 0, date('n', $until)-6, 1, date('Y', $until));
break;
How could I make this "smarter", so that it works out if we are near the end of the month it will show the last 30 days instead of the previous month?
php datetime
edited Sep 10 '14 at 14:12
Jamal♦
30.2k11116226
asked Sep 25 '12 at 18:50
John Magnolia
158116
add a comment |
I am looking for some ideas on how this could be improved:
switch ($periodValue) {
case "lastmonth":
$until = mktime(0, 0, 0, date('n'), 1, date('Y'));
$from = mktime(0, 0, 0, date('n', $until) - 1, 1, date('Y', $until));
break;
case "last3month":
$until = mktime(0, 0, 0, date('n'), 1, date('Y'));
$from = mktime(0, 0, 0, date('n', $until)-3, 1, date('Y', $until));
break;
case "last6month":
$until = mktime(0, 0, 0, date('n'), 1, date('Y'));
$from = mktime(0, 0, 0, date('n', $until)-6, 1, date('Y', $until));
break;
How could I make this "smarter", so that it works out if we are near the end of the month it will show the last 30 days instead of the previous month?
php datetime
edited Sep 10 '14 at 14:12
Jamal♦
30.2k11116226
asked Sep 25 '12 at 18:50
John Magnolia
158116
I am looking for some ideas on how this could be improved:
switch ($periodValue) {
case "lastmonth":
$until = mktime(0, 0, 0, date('n'), 1, date('Y'));
$from = mktime(0, 0, 0, date('n', $until) - 1, 1, date('Y', $until));
break;
case "last3month":
$until = mktime(0, 0, 0, date('n'), 1, date('Y'));
$from = mktime(0, 0, 0, date('n', $until)-3, 1, date('Y', $until));
break;
case "last6month":
$until = mktime(0, 0, 0, date('n'), 1, date('Y'));
$from = mktime(0, 0, 0, date('n', $until)-6, 1, date('Y', $until));
break;
How could I make this "smarter", so that it works out if we are near the end of the month it will show the last 30 days instead of the previous month?
php datetime
php datetime
edited Sep 10 '14 at 14:12
Jamal♦
30.2k11116226
asked Sep 25 '12 at 18:50
John Magnolia
158116
edited Sep 10 '14 at 14:12
Jamal♦
30.2k11116226
asked Sep 25 '12 at 18:50
John Magnolia
158116
edited Sep 10 '14 at 14:12
Jamal♦
30.2k11116226
edited Sep 10 '14 at 14:12
Jamal♦
30.2k11116226
edited Sep 10 '14 at 14:12
Jamal♦
30.2k11116226
30.2k11116226
asked Sep 25 '12 at 18:50
John Magnolia
158116
asked Sep 25 '12 at 18:50
John Magnolia
158116
asked Sep 25 '12 at 18:50
John Magnolia
158116
158116
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
Try the DateTime class. In combination with the DateInterval class you can do something like this:
$until = new DateTime();
$interval = new DateInterval('P2M');//2 months
$from = $until->sub($interval);
echo 'from' . $from->format('Y-m-d') . 'until' . $until->format('Y-m-d');
Also, you have to set the $until variable only once, before the switch statement.
edited Sep 10 '14 at 9:17
Anil Jaiswal
33
answered Sep 25 '12 at 20:59
Dirk McQuickly
20114
add a comment |
The date/time functions in PHP are a tricky thing. Last I looked into this there were known bugs with many of the date/time functions, especially around leap years, but no solutions. I don't know if that has changed, haven't had the need to look, so this answer might not be the best one, but have you tried strtotime()?
$period = 30;//90 for 3 months, 180 for 6 months
$until = strtotime( 'now' );
$from = strtotime( "-$period days" );
//or
$period = 'last month';//'last 3 months', or 'last 6 months'
$from = strtotime( $period );
I've not tried any of the above, but I'm fairly confident the first half should work, but I'm not sure about the last half. However, strtotime() is a pretty smart function, so who knows. Hope it helps.
answered Sep 25 '12 at 20:19
mseancole
5,8731926
90 days ago isn't actually 3 months ago. for example if now is 31/5/2018 which is the time of this comment.
– deathemperor
May 31 at 9:55
add a comment |
$year = $data['year'];
$month = $data['month'];
$last_three_month_total_day = 0;
for ( $i=0; $i <= 2 ; $i++ ){
$last_three_month_total_day += cal_days_in_month(CAL_GREGORIAN,$month,$year);
$month = $month -1 ;
if($month == 0){ $month = 12; $year = $year-1 ;}
}
$result['last_three_month_total_day'] = $last_three_month_total_day;
answered 8 mins ago
pradip kor
101
New contributor
pradip kor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
Try the DateTime class. In combination with the DateInterval class you can do something like this:
$until = new DateTime();
$interval = new DateInterval('P2M');//2 months
$from = $until->sub($interval);
echo 'from' . $from->format('Y-m-d') . 'until' . $until->format('Y-m-d');
Also, you have to set the $until variable only once, before the switch statement.
edited Sep 10 '14 at 9:17
Anil Jaiswal
33
answered Sep 25 '12 at 20:59
Dirk McQuickly
20114
add a comment |
Try the DateTime class. In combination with the DateInterval class you can do something like this:
$until = new DateTime();
$interval = new DateInterval('P2M');//2 months
$from = $until->sub($interval);
echo 'from' . $from->format('Y-m-d') . 'until' . $until->format('Y-m-d');
Also, you have to set the $until variable only once, before the switch statement.
edited Sep 10 '14 at 9:17
Anil Jaiswal
33
answered Sep 25 '12 at 20:59
Dirk McQuickly
20114
add a comment |
Try the DateTime class. In combination with the DateInterval class you can do something like this:
$until = new DateTime();
$interval = new DateInterval('P2M');//2 months
$from = $until->sub($interval);
echo 'from' . $from->format('Y-m-d') . 'until' . $until->format('Y-m-d');
Also, you have to set the $until variable only once, before the switch statement.
edited Sep 10 '14 at 9:17
Anil Jaiswal
33
answered Sep 25 '12 at 20:59
Dirk McQuickly
20114
Try the DateTime class. In combination with the DateInterval class you can do something like this:
$until = new DateTime();
$interval = new DateInterval('P2M');//2 months
$from = $until->sub($interval);
echo 'from' . $from->format('Y-m-d') . 'until' . $until->format('Y-m-d');
Also, you have to set the $until variable only once, before the switch statement.
edited Sep 10 '14 at 9:17
Anil Jaiswal
33
answered Sep 25 '12 at 20:59
Dirk McQuickly
20114
edited Sep 10 '14 at 9:17
Anil Jaiswal
33
edited Sep 10 '14 at 9:17
Anil Jaiswal
33
edited Sep 10 '14 at 9:17
Anil Jaiswal
33
33
answered Sep 25 '12 at 20:59
Dirk McQuickly
20114
answered Sep 25 '12 at 20:59
Dirk McQuickly
20114
answered Sep 25 '12 at 20:59
Dirk McQuickly
20114
20114
add a comment |
add a comment |
The date/time functions in PHP are a tricky thing. Last I looked into this there were known bugs with many of the date/time functions, especially around leap years, but no solutions. I don't know if that has changed, haven't had the need to look, so this answer might not be the best one, but have you tried strtotime()?
$period = 30;//90 for 3 months, 180 for 6 months
$until = strtotime( 'now' );
$from = strtotime( "-$period days" );
//or
$period = 'last month';//'last 3 months', or 'last 6 months'
$from = strtotime( $period );
I've not tried any of the above, but I'm fairly confident the first half should work, but I'm not sure about the last half. However, strtotime() is a pretty smart function, so who knows. Hope it helps.
answered Sep 25 '12 at 20:19
mseancole
5,8731926
90 days ago isn't actually 3 months ago. for example if now is 31/5/2018 which is the time of this comment.
– deathemperor
May 31 at 9:55
add a comment |
The date/time functions in PHP are a tricky thing. Last I looked into this there were known bugs with many of the date/time functions, especially around leap years, but no solutions. I don't know if that has changed, haven't had the need to look, so this answer might not be the best one, but have you tried strtotime()?
$period = 30;//90 for 3 months, 180 for 6 months
$until = strtotime( 'now' );
$from = strtotime( "-$period days" );
//or
$period = 'last month';//'last 3 months', or 'last 6 months'
$from = strtotime( $period );
I've not tried any of the above, but I'm fairly confident the first half should work, but I'm not sure about the last half. However, strtotime() is a pretty smart function, so who knows. Hope it helps.
answered Sep 25 '12 at 20:19
mseancole
5,8731926
90 days ago isn't actually 3 months ago. for example if now is 31/5/2018 which is the time of this comment.
– deathemperor
May 31 at 9:55
add a comment |
The date/time functions in PHP are a tricky thing. Last I looked into this there were known bugs with many of the date/time functions, especially around leap years, but no solutions. I don't know if that has changed, haven't had the need to look, so this answer might not be the best one, but have you tried strtotime()?
$period = 30;//90 for 3 months, 180 for 6 months
$until = strtotime( 'now' );
$from = strtotime( "-$period days" );
//or
$period = 'last month';//'last 3 months', or 'last 6 months'
$from = strtotime( $period );
I've not tried any of the above, but I'm fairly confident the first half should work, but I'm not sure about the last half. However, strtotime() is a pretty smart function, so who knows. Hope it helps.
answered Sep 25 '12 at 20:19
mseancole
5,8731926
The date/time functions in PHP are a tricky thing. Last I looked into this there were known bugs with many of the date/time functions, especially around leap years, but no solutions. I don't know if that has changed, haven't had the need to look, so this answer might not be the best one, but have you tried strtotime()?
$period = 30;//90 for 3 months, 180 for 6 months
$until = strtotime( 'now' );
$from = strtotime( "-$period days" );
//or
$period = 'last month';//'last 3 months', or 'last 6 months'
$from = strtotime( $period );
I've not tried any of the above, but I'm fairly confident the first half should work, but I'm not sure about the last half. However, strtotime() is a pretty smart function, so who knows. Hope it helps.
answered Sep 25 '12 at 20:19
mseancole
5,8731926
answered Sep 25 '12 at 20:19
mseancole
5,8731926
answered Sep 25 '12 at 20:19
mseancole
5,8731926
answered Sep 25 '12 at 20:19
mseancole
5,8731926
5,8731926
90 days ago isn't actually 3 months ago. for example if now is 31/5/2018 which is the time of this comment.
– deathemperor
May 31 at 9:55
add a comment |
90 days ago isn't actually 3 months ago. for example if now is 31/5/2018 which is the time of this comment.
– deathemperor
May 31 at 9:55
90 days ago isn't actually 3 months ago. for example if now is 31/5/2018 which is the time of this comment.
– deathemperor
May 31 at 9:55
90 days ago isn't actually 3 months ago. for example if now is 31/5/2018 which is the time of this comment.
– deathemperor
May 31 at 9:55
add a comment |
$year = $data['year'];
$month = $data['month'];
$last_three_month_total_day = 0;
for ( $i=0; $i <= 2 ; $i++ ){
$last_three_month_total_day += cal_days_in_month(CAL_GREGORIAN,$month,$year);
$month = $month -1 ;
if($month == 0){ $month = 12; $year = $year-1 ;}
}
$result['last_three_month_total_day'] = $last_three_month_total_day;
answered 8 mins ago
pradip kor
101
New contributor
pradip kor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
$year = $data['year'];
$month = $data['month'];
$last_three_month_total_day = 0;
for ( $i=0; $i <= 2 ; $i++ ){
$last_three_month_total_day += cal_days_in_month(CAL_GREGORIAN,$month,$year);
$month = $month -1 ;
if($month == 0){ $month = 12; $year = $year-1 ;}
}
$result['last_three_month_total_day'] = $last_three_month_total_day;
answered 8 mins ago
pradip kor
101
New contributor
pradip kor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
$year = $data['year'];
$month = $data['month'];
$last_three_month_total_day = 0;
for ( $i=0; $i <= 2 ; $i++ ){
$last_three_month_total_day += cal_days_in_month(CAL_GREGORIAN,$month,$year);
$month = $month -1 ;
if($month == 0){ $month = 12; $year = $year-1 ;}
}
$result['last_three_month_total_day'] = $last_three_month_total_day;
answered 8 mins ago
pradip kor
101
New contributor
pradip kor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$year = $data['year'];
$month = $data['month'];
$last_three_month_total_day = 0;
for ( $i=0; $i <= 2 ; $i++ ){
$last_three_month_total_day += cal_days_in_month(CAL_GREGORIAN,$month,$year);
$month = $month -1 ;
if($month == 0){ $month = 12; $year = $year-1 ;}
}
$result['last_three_month_total_day'] = $last_three_month_total_day;
answered 8 mins ago
pradip kor
101
New contributor
pradip kor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered 8 mins ago
pradip kor
101
New contributor
pradip kor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered 8 mins ago
pradip kor
101
answered 8 mins ago
pradip kor
101
101
New contributor
pradip kor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
pradip kor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
pradip kor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
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