locate column location from variable and pass to .range“” code
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I am using the partial code below to locate a borrower's name in a horizontal list. Once I find the name I need to pass the column and be able to reference that column in range("").value. So for example it finds the name in column G I can then use the range.value code and some how pair it up with different rows to do copy or do other things with.
Sub Copy_From_Borrower_DBase()
Dim myVal As String
Dim sourceRng As Range
myVal = Sheets("Main").Range("F2").Value ' dropdown list
Set sourceRng = Worksheets("Borrower Database").Range("5:5").Find( _
What:=myVal, LookAt:=xlWhole) 'locate column where to copy from
Sheets("Main").Range("F5").Value = Worksheets("Borrower Database"). _
Range("??????????").Value 'Borrower Name
End Sub
excel vba excel-vba
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up vote
1
down vote
favorite
I am using the partial code below to locate a borrower's name in a horizontal list. Once I find the name I need to pass the column and be able to reference that column in range("").value. So for example it finds the name in column G I can then use the range.value code and some how pair it up with different rows to do copy or do other things with.
Sub Copy_From_Borrower_DBase()
Dim myVal As String
Dim sourceRng As Range
myVal = Sheets("Main").Range("F2").Value ' dropdown list
Set sourceRng = Worksheets("Borrower Database").Range("5:5").Find( _
What:=myVal, LookAt:=xlWhole) 'locate column where to copy from
Sheets("Main").Range("F5").Value = Worksheets("Borrower Database"). _
Range("??????????").Value 'Borrower Name
End Sub
excel vba excel-vba
add a comment |
up vote
1
down vote
favorite
up vote
1
down vote
favorite
I am using the partial code below to locate a borrower's name in a horizontal list. Once I find the name I need to pass the column and be able to reference that column in range("").value. So for example it finds the name in column G I can then use the range.value code and some how pair it up with different rows to do copy or do other things with.
Sub Copy_From_Borrower_DBase()
Dim myVal As String
Dim sourceRng As Range
myVal = Sheets("Main").Range("F2").Value ' dropdown list
Set sourceRng = Worksheets("Borrower Database").Range("5:5").Find( _
What:=myVal, LookAt:=xlWhole) 'locate column where to copy from
Sheets("Main").Range("F5").Value = Worksheets("Borrower Database"). _
Range("??????????").Value 'Borrower Name
End Sub
excel vba excel-vba
I am using the partial code below to locate a borrower's name in a horizontal list. Once I find the name I need to pass the column and be able to reference that column in range("").value. So for example it finds the name in column G I can then use the range.value code and some how pair it up with different rows to do copy or do other things with.
Sub Copy_From_Borrower_DBase()
Dim myVal As String
Dim sourceRng As Range
myVal = Sheets("Main").Range("F2").Value ' dropdown list
Set sourceRng = Worksheets("Borrower Database").Range("5:5").Find( _
What:=myVal, LookAt:=xlWhole) 'locate column where to copy from
Sheets("Main").Range("F5").Value = Worksheets("Borrower Database"). _
Range("??????????").Value 'Borrower Name
End Sub
excel vba excel-vba
excel vba excel-vba
edited Nov 20 at 7:11
Pᴇʜ
19.9k42650
19.9k42650
asked Nov 20 at 3:52
MEC
586
586
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1 Answer
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0
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To grab the column from your sourceRng, you can simply use the .Column property. I personally would use Cells() instead of Range() since you're dealing with column numbers.
So, in your use case:
Worksheets("Main").Range("F5").Value = Worksheets("Borrower Database"). _
Cells(Row, sourceRng.Column).Value 'Borrower Name
Where you would replace Row with your corresponding row number.
Glad to assist!
– K.Dᴀᴠɪs
Nov 20 at 4:46
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
accepted
To grab the column from your sourceRng, you can simply use the .Column property. I personally would use Cells() instead of Range() since you're dealing with column numbers.
So, in your use case:
Worksheets("Main").Range("F5").Value = Worksheets("Borrower Database"). _
Cells(Row, sourceRng.Column).Value 'Borrower Name
Where you would replace Row with your corresponding row number.
Glad to assist!
– K.Dᴀᴠɪs
Nov 20 at 4:46
add a comment |
up vote
0
down vote
accepted
To grab the column from your sourceRng, you can simply use the .Column property. I personally would use Cells() instead of Range() since you're dealing with column numbers.
So, in your use case:
Worksheets("Main").Range("F5").Value = Worksheets("Borrower Database"). _
Cells(Row, sourceRng.Column).Value 'Borrower Name
Where you would replace Row with your corresponding row number.
Glad to assist!
– K.Dᴀᴠɪs
Nov 20 at 4:46
add a comment |
up vote
0
down vote
accepted
up vote
0
down vote
accepted
To grab the column from your sourceRng, you can simply use the .Column property. I personally would use Cells() instead of Range() since you're dealing with column numbers.
So, in your use case:
Worksheets("Main").Range("F5").Value = Worksheets("Borrower Database"). _
Cells(Row, sourceRng.Column).Value 'Borrower Name
Where you would replace Row with your corresponding row number.
To grab the column from your sourceRng, you can simply use the .Column property. I personally would use Cells() instead of Range() since you're dealing with column numbers.
So, in your use case:
Worksheets("Main").Range("F5").Value = Worksheets("Borrower Database"). _
Cells(Row, sourceRng.Column).Value 'Borrower Name
Where you would replace Row with your corresponding row number.
answered Nov 20 at 4:14
K.Dᴀᴠɪs
6,474112140
6,474112140
Glad to assist!
– K.Dᴀᴠɪs
Nov 20 at 4:46
add a comment |
Glad to assist!
– K.Dᴀᴠɪs
Nov 20 at 4:46
Glad to assist!
– K.Dᴀᴠɪs
Nov 20 at 4:46
Glad to assist!
– K.Dᴀᴠɪs
Nov 20 at 4:46
add a comment |
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