Line passing through a point and parallel to another: Where am I wrong?
documentclass{standalone}
usepackage{tikz}
usetikzlibrary{intersections}
usetikzlibrary{calc}
begin{document}
begin{tikzpicture}
coordinate (A) at (0,0);
coordinate (B) at (2,4);
coordinate (C) at (8,0);
coordinate (M) at (4,0);
path[name path=Circle] (B) circle [radius=3cm];
path[name path=AB] (A)--(B);
path[name path=BC] (B)--(C);
path [name intersections={of=Circle and BC}];
coordinate (E) at (intersection-1);
path [name intersections={of=Circle and AB}];
coordinate (D) at (intersection-1);
draw[thick](A)--(B)--(C)--cycle;
draw[thick](B) circle [radius=3cm];
draw[thick](D)--(E) (M)--(B);
% From a point draw a parallel line by calculating the vector
coordinate (P) at (intersection cs:first line={(B)--(C)}, second line={(A) -- +($(E)-(D)$)});
% Here is my problem:
coordinate (N) at (intersection cs:first line={(B)--(M)}, second line={(C) -- +($(D)-(E)$)});
draw[thick, red] (A)--(P) (C)--(N);
end{tikzpicture}
end{document}
Question: The second drawn line, which is supposed to also be a parallel, is not. What am I doing wrong?
tikz-pgf
add a comment |
documentclass{standalone}
usepackage{tikz}
usetikzlibrary{intersections}
usetikzlibrary{calc}
begin{document}
begin{tikzpicture}
coordinate (A) at (0,0);
coordinate (B) at (2,4);
coordinate (C) at (8,0);
coordinate (M) at (4,0);
path[name path=Circle] (B) circle [radius=3cm];
path[name path=AB] (A)--(B);
path[name path=BC] (B)--(C);
path [name intersections={of=Circle and BC}];
coordinate (E) at (intersection-1);
path [name intersections={of=Circle and AB}];
coordinate (D) at (intersection-1);
draw[thick](A)--(B)--(C)--cycle;
draw[thick](B) circle [radius=3cm];
draw[thick](D)--(E) (M)--(B);
% From a point draw a parallel line by calculating the vector
coordinate (P) at (intersection cs:first line={(B)--(C)}, second line={(A) -- +($(E)-(D)$)});
% Here is my problem:
coordinate (N) at (intersection cs:first line={(B)--(M)}, second line={(C) -- +($(D)-(E)$)});
draw[thick, red] (A)--(P) (C)--(N);
end{tikzpicture}
end{document}
Question: The second drawn line, which is supposed to also be a parallel, is not. What am I doing wrong?
tikz-pgf
add a comment |
documentclass{standalone}
usepackage{tikz}
usetikzlibrary{intersections}
usetikzlibrary{calc}
begin{document}
begin{tikzpicture}
coordinate (A) at (0,0);
coordinate (B) at (2,4);
coordinate (C) at (8,0);
coordinate (M) at (4,0);
path[name path=Circle] (B) circle [radius=3cm];
path[name path=AB] (A)--(B);
path[name path=BC] (B)--(C);
path [name intersections={of=Circle and BC}];
coordinate (E) at (intersection-1);
path [name intersections={of=Circle and AB}];
coordinate (D) at (intersection-1);
draw[thick](A)--(B)--(C)--cycle;
draw[thick](B) circle [radius=3cm];
draw[thick](D)--(E) (M)--(B);
% From a point draw a parallel line by calculating the vector
coordinate (P) at (intersection cs:first line={(B)--(C)}, second line={(A) -- +($(E)-(D)$)});
% Here is my problem:
coordinate (N) at (intersection cs:first line={(B)--(M)}, second line={(C) -- +($(D)-(E)$)});
draw[thick, red] (A)--(P) (C)--(N);
end{tikzpicture}
end{document}
Question: The second drawn line, which is supposed to also be a parallel, is not. What am I doing wrong?
tikz-pgf
documentclass{standalone}
usepackage{tikz}
usetikzlibrary{intersections}
usetikzlibrary{calc}
begin{document}
begin{tikzpicture}
coordinate (A) at (0,0);
coordinate (B) at (2,4);
coordinate (C) at (8,0);
coordinate (M) at (4,0);
path[name path=Circle] (B) circle [radius=3cm];
path[name path=AB] (A)--(B);
path[name path=BC] (B)--(C);
path [name intersections={of=Circle and BC}];
coordinate (E) at (intersection-1);
path [name intersections={of=Circle and AB}];
coordinate (D) at (intersection-1);
draw[thick](A)--(B)--(C)--cycle;
draw[thick](B) circle [radius=3cm];
draw[thick](D)--(E) (M)--(B);
% From a point draw a parallel line by calculating the vector
coordinate (P) at (intersection cs:first line={(B)--(C)}, second line={(A) -- +($(E)-(D)$)});
% Here is my problem:
coordinate (N) at (intersection cs:first line={(B)--(M)}, second line={(C) -- +($(D)-(E)$)});
draw[thick, red] (A)--(P) (C)--(N);
end{tikzpicture}
end{document}
Question: The second drawn line, which is supposed to also be a parallel, is not. What am I doing wrong?
tikz-pgf
tikz-pgf
asked 1 hour ago
blackened
1,388713
1,388713
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
If you use the +
syntax in this context, it seems not to always give you what one may expect. In general, +
means "relative to the first coordinate of this path". But who knows what the first coordinate is in the context of intersection cs:
? It is, however, not too difficult to produce the parallel lines just by computing the slope and using it. For the sake of clarity, I labeled all coordinates.
documentclass{standalone}
usepackage{tikz}
usetikzlibrary{intersections}
usetikzlibrary{calc}
begin{document}
begin{tikzpicture}
coordinate[label=left:$A$] (A) at (0,0);
coordinate[label=above:$B$] (B) at (2,4);
coordinate[label=right:$C$] (C) at (8,0);
coordinate[label=45:$M$] (M) at (4,0);
draw[name path=Circle] (B) circle [radius=3cm];
path[name path=AB] (A)--(B);
path[name path=BC] (B)--(C);
path [name intersections={of=Circle and BC}];
coordinate[label=right:$E$] (E) at (intersection-1);
path [name intersections={of=Circle and AB}];
coordinate[label=left:$D$] (D) at (intersection-1);
draw[thick](A)--(B)--(C)--cycle;
%draw[thick](B) circle [radius=3cm];
draw[thick](D)--(E) (M)--(B);
% From a point draw a parallel line by calculating the vector
path let p1=($(E)-(D)$),n1={atan2(y1,x1)} in
($(A)+(n1:1)$) coordinate (auxA)
($(C)+(n1:1)$) coordinate (auxC);
coordinate[label=right:$P$] (P) at (intersection cs:first line={(B)--(C)},
second line={(A) -- (auxA)});
% Here is my problem:
coordinate[label=below:$N$]
(N) at (intersection cs:first line={(B)--(M)},
second line={(C) -- (auxC)});
draw[thick, red] (A)--(P) (C)--(N) ;
end{tikzpicture}
end{document}
As you see, the red lines are parallel.
One may want cast this into a style:
documentclass{standalone}
usepackage{tikz}
usetikzlibrary{intersections}
usetikzlibrary{calc}
begin{document}
tikzset{line through/.style args={#1 parallel to line through #2 and #3 and
length #4}{insert path={%
let p1=($(#3)-(#2)$),n1={atan2(y1,x1)} in (#1) -- ++ (n1:#4)}}}
begin{tikzpicture}
coordinate[label=left:$A$] (A) at (0,0);
coordinate[label=above:$B$] (B) at (2,4);
coordinate[label=right:$C$] (C) at (8,0);
coordinate[label=45:$M$] (M) at (4,0);
draw[name path=Circle] (B) circle [radius=3cm];
path[name path=AB] (A)--(B);
path[name path=BC] (B)--(C);
path [name intersections={of=Circle and BC}];
coordinate[label=right:$E$] (E) at (intersection-1);
path [name intersections={of=Circle and AB}];
coordinate[label=left:$D$] (D) at (intersection-1);
draw[thick](A)--(B)--(C)--cycle;
%draw[thick](B) circle [radius=3cm];
draw[thick](D)--(E) (M)--(B);
% From a point draw a parallel line by calculating the vector
path[line through=A parallel to line through E and D and length 1]
coordinate (auxA)
[line through=C parallel to line through E and D and length 1]
coordinate (auxC);
coordinate[label=right:$P$] (P) at (intersection cs:first line={(B)--(C)},
second line={(A) -- (auxA)});
% Here is my problem:
coordinate[label=below:$N$]
(N) at (intersection cs:first line={(B)--(M)},
second line={(C) -- (auxC)});
draw[thick, red] (A)--(P) (C)--(N) ;
end{tikzpicture}
end{document}
Thank you. I was following this answer.
– blackened
39 mins ago
@blackened Yes, there it is very clear what the first point of the path is. Therefore, it is clear what+
does. However, in the context ofintersection cs:
it is not clear to me where single paths start and end, and hence-- +(coordinate)
may not be what one may thing it is. I am sorry if you feel that my wording is offensive, would like to apologize, and change it right away.
– marmot
37 mins ago
No worries at all. I just assumed that that answer encompassed all cases. How can I turn your approach to atikz
style definition?
– blackened
35 mins ago
@blackened What precisely do you want the style to accomplish? A line through a given point with the slope coinciding with the one of another line. (And rereading my original post I think my wording did indeed not reflect what I wanted to say.)
– marmot
33 mins ago
What precisely do you want the style to accomplish? A line through a given point with the slope coinciding with the one of another line. Yes. (From your question, I understand that one may want to accomplish other options. What are they?)
– blackened
31 mins ago
|
show 1 more comment
Use second line={(C)--($(C)+(D)-(E)$)})
. The first one works as expected because (A)=(0,0)
documentclass{article}
usepackage{tikz}
usetikzlibrary{intersections}
usetikzlibrary{calc}
begin{document}
begin{tikzpicture}
coordinate[label=A] (A) at (0,0);
coordinate[label=B](B) at (2,4);
coordinate[label=C] (C) at (8,0);
coordinate[label=M] (M) at (4,0);
path[name path=Circle] (B) circle [radius=3cm];
path[name path=AB] (A)--(B);
path[name path=BC] (B)--(C);
path [name intersections={of=Circle and BC}];
coordinate[label=E] (E) at (intersection-1);
path [name intersections={of=Circle and AB}];
coordinate[label=D] (D) at (intersection-1);
draw[thick](A)--(B)--(C)--cycle;
draw[thick](B) circle [radius=3cm];
draw[thick](D)--(E) (M)--(B);
% From a point draw a parallel line by calculating the vector
coordinate[label=P] (P) at (intersection cs:first line={(B)--(C)}, second line={(A) -- +($(E)-(D)$)});
% Here is my problem:
coordinate[label=N] (N) at (intersection cs:first line={(B)--(M)}, second line={(C)--($(C)+(D)-(E)$)}); % <------
draw[thick, red] (A)--(P) (C)--(N);
end{tikzpicture}
end{document}
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
If you use the +
syntax in this context, it seems not to always give you what one may expect. In general, +
means "relative to the first coordinate of this path". But who knows what the first coordinate is in the context of intersection cs:
? It is, however, not too difficult to produce the parallel lines just by computing the slope and using it. For the sake of clarity, I labeled all coordinates.
documentclass{standalone}
usepackage{tikz}
usetikzlibrary{intersections}
usetikzlibrary{calc}
begin{document}
begin{tikzpicture}
coordinate[label=left:$A$] (A) at (0,0);
coordinate[label=above:$B$] (B) at (2,4);
coordinate[label=right:$C$] (C) at (8,0);
coordinate[label=45:$M$] (M) at (4,0);
draw[name path=Circle] (B) circle [radius=3cm];
path[name path=AB] (A)--(B);
path[name path=BC] (B)--(C);
path [name intersections={of=Circle and BC}];
coordinate[label=right:$E$] (E) at (intersection-1);
path [name intersections={of=Circle and AB}];
coordinate[label=left:$D$] (D) at (intersection-1);
draw[thick](A)--(B)--(C)--cycle;
%draw[thick](B) circle [radius=3cm];
draw[thick](D)--(E) (M)--(B);
% From a point draw a parallel line by calculating the vector
path let p1=($(E)-(D)$),n1={atan2(y1,x1)} in
($(A)+(n1:1)$) coordinate (auxA)
($(C)+(n1:1)$) coordinate (auxC);
coordinate[label=right:$P$] (P) at (intersection cs:first line={(B)--(C)},
second line={(A) -- (auxA)});
% Here is my problem:
coordinate[label=below:$N$]
(N) at (intersection cs:first line={(B)--(M)},
second line={(C) -- (auxC)});
draw[thick, red] (A)--(P) (C)--(N) ;
end{tikzpicture}
end{document}
As you see, the red lines are parallel.
One may want cast this into a style:
documentclass{standalone}
usepackage{tikz}
usetikzlibrary{intersections}
usetikzlibrary{calc}
begin{document}
tikzset{line through/.style args={#1 parallel to line through #2 and #3 and
length #4}{insert path={%
let p1=($(#3)-(#2)$),n1={atan2(y1,x1)} in (#1) -- ++ (n1:#4)}}}
begin{tikzpicture}
coordinate[label=left:$A$] (A) at (0,0);
coordinate[label=above:$B$] (B) at (2,4);
coordinate[label=right:$C$] (C) at (8,0);
coordinate[label=45:$M$] (M) at (4,0);
draw[name path=Circle] (B) circle [radius=3cm];
path[name path=AB] (A)--(B);
path[name path=BC] (B)--(C);
path [name intersections={of=Circle and BC}];
coordinate[label=right:$E$] (E) at (intersection-1);
path [name intersections={of=Circle and AB}];
coordinate[label=left:$D$] (D) at (intersection-1);
draw[thick](A)--(B)--(C)--cycle;
%draw[thick](B) circle [radius=3cm];
draw[thick](D)--(E) (M)--(B);
% From a point draw a parallel line by calculating the vector
path[line through=A parallel to line through E and D and length 1]
coordinate (auxA)
[line through=C parallel to line through E and D and length 1]
coordinate (auxC);
coordinate[label=right:$P$] (P) at (intersection cs:first line={(B)--(C)},
second line={(A) -- (auxA)});
% Here is my problem:
coordinate[label=below:$N$]
(N) at (intersection cs:first line={(B)--(M)},
second line={(C) -- (auxC)});
draw[thick, red] (A)--(P) (C)--(N) ;
end{tikzpicture}
end{document}
Thank you. I was following this answer.
– blackened
39 mins ago
@blackened Yes, there it is very clear what the first point of the path is. Therefore, it is clear what+
does. However, in the context ofintersection cs:
it is not clear to me where single paths start and end, and hence-- +(coordinate)
may not be what one may thing it is. I am sorry if you feel that my wording is offensive, would like to apologize, and change it right away.
– marmot
37 mins ago
No worries at all. I just assumed that that answer encompassed all cases. How can I turn your approach to atikz
style definition?
– blackened
35 mins ago
@blackened What precisely do you want the style to accomplish? A line through a given point with the slope coinciding with the one of another line. (And rereading my original post I think my wording did indeed not reflect what I wanted to say.)
– marmot
33 mins ago
What precisely do you want the style to accomplish? A line through a given point with the slope coinciding with the one of another line. Yes. (From your question, I understand that one may want to accomplish other options. What are they?)
– blackened
31 mins ago
|
show 1 more comment
If you use the +
syntax in this context, it seems not to always give you what one may expect. In general, +
means "relative to the first coordinate of this path". But who knows what the first coordinate is in the context of intersection cs:
? It is, however, not too difficult to produce the parallel lines just by computing the slope and using it. For the sake of clarity, I labeled all coordinates.
documentclass{standalone}
usepackage{tikz}
usetikzlibrary{intersections}
usetikzlibrary{calc}
begin{document}
begin{tikzpicture}
coordinate[label=left:$A$] (A) at (0,0);
coordinate[label=above:$B$] (B) at (2,4);
coordinate[label=right:$C$] (C) at (8,0);
coordinate[label=45:$M$] (M) at (4,0);
draw[name path=Circle] (B) circle [radius=3cm];
path[name path=AB] (A)--(B);
path[name path=BC] (B)--(C);
path [name intersections={of=Circle and BC}];
coordinate[label=right:$E$] (E) at (intersection-1);
path [name intersections={of=Circle and AB}];
coordinate[label=left:$D$] (D) at (intersection-1);
draw[thick](A)--(B)--(C)--cycle;
%draw[thick](B) circle [radius=3cm];
draw[thick](D)--(E) (M)--(B);
% From a point draw a parallel line by calculating the vector
path let p1=($(E)-(D)$),n1={atan2(y1,x1)} in
($(A)+(n1:1)$) coordinate (auxA)
($(C)+(n1:1)$) coordinate (auxC);
coordinate[label=right:$P$] (P) at (intersection cs:first line={(B)--(C)},
second line={(A) -- (auxA)});
% Here is my problem:
coordinate[label=below:$N$]
(N) at (intersection cs:first line={(B)--(M)},
second line={(C) -- (auxC)});
draw[thick, red] (A)--(P) (C)--(N) ;
end{tikzpicture}
end{document}
As you see, the red lines are parallel.
One may want cast this into a style:
documentclass{standalone}
usepackage{tikz}
usetikzlibrary{intersections}
usetikzlibrary{calc}
begin{document}
tikzset{line through/.style args={#1 parallel to line through #2 and #3 and
length #4}{insert path={%
let p1=($(#3)-(#2)$),n1={atan2(y1,x1)} in (#1) -- ++ (n1:#4)}}}
begin{tikzpicture}
coordinate[label=left:$A$] (A) at (0,0);
coordinate[label=above:$B$] (B) at (2,4);
coordinate[label=right:$C$] (C) at (8,0);
coordinate[label=45:$M$] (M) at (4,0);
draw[name path=Circle] (B) circle [radius=3cm];
path[name path=AB] (A)--(B);
path[name path=BC] (B)--(C);
path [name intersections={of=Circle and BC}];
coordinate[label=right:$E$] (E) at (intersection-1);
path [name intersections={of=Circle and AB}];
coordinate[label=left:$D$] (D) at (intersection-1);
draw[thick](A)--(B)--(C)--cycle;
%draw[thick](B) circle [radius=3cm];
draw[thick](D)--(E) (M)--(B);
% From a point draw a parallel line by calculating the vector
path[line through=A parallel to line through E and D and length 1]
coordinate (auxA)
[line through=C parallel to line through E and D and length 1]
coordinate (auxC);
coordinate[label=right:$P$] (P) at (intersection cs:first line={(B)--(C)},
second line={(A) -- (auxA)});
% Here is my problem:
coordinate[label=below:$N$]
(N) at (intersection cs:first line={(B)--(M)},
second line={(C) -- (auxC)});
draw[thick, red] (A)--(P) (C)--(N) ;
end{tikzpicture}
end{document}
Thank you. I was following this answer.
– blackened
39 mins ago
@blackened Yes, there it is very clear what the first point of the path is. Therefore, it is clear what+
does. However, in the context ofintersection cs:
it is not clear to me where single paths start and end, and hence-- +(coordinate)
may not be what one may thing it is. I am sorry if you feel that my wording is offensive, would like to apologize, and change it right away.
– marmot
37 mins ago
No worries at all. I just assumed that that answer encompassed all cases. How can I turn your approach to atikz
style definition?
– blackened
35 mins ago
@blackened What precisely do you want the style to accomplish? A line through a given point with the slope coinciding with the one of another line. (And rereading my original post I think my wording did indeed not reflect what I wanted to say.)
– marmot
33 mins ago
What precisely do you want the style to accomplish? A line through a given point with the slope coinciding with the one of another line. Yes. (From your question, I understand that one may want to accomplish other options. What are they?)
– blackened
31 mins ago
|
show 1 more comment
If you use the +
syntax in this context, it seems not to always give you what one may expect. In general, +
means "relative to the first coordinate of this path". But who knows what the first coordinate is in the context of intersection cs:
? It is, however, not too difficult to produce the parallel lines just by computing the slope and using it. For the sake of clarity, I labeled all coordinates.
documentclass{standalone}
usepackage{tikz}
usetikzlibrary{intersections}
usetikzlibrary{calc}
begin{document}
begin{tikzpicture}
coordinate[label=left:$A$] (A) at (0,0);
coordinate[label=above:$B$] (B) at (2,4);
coordinate[label=right:$C$] (C) at (8,0);
coordinate[label=45:$M$] (M) at (4,0);
draw[name path=Circle] (B) circle [radius=3cm];
path[name path=AB] (A)--(B);
path[name path=BC] (B)--(C);
path [name intersections={of=Circle and BC}];
coordinate[label=right:$E$] (E) at (intersection-1);
path [name intersections={of=Circle and AB}];
coordinate[label=left:$D$] (D) at (intersection-1);
draw[thick](A)--(B)--(C)--cycle;
%draw[thick](B) circle [radius=3cm];
draw[thick](D)--(E) (M)--(B);
% From a point draw a parallel line by calculating the vector
path let p1=($(E)-(D)$),n1={atan2(y1,x1)} in
($(A)+(n1:1)$) coordinate (auxA)
($(C)+(n1:1)$) coordinate (auxC);
coordinate[label=right:$P$] (P) at (intersection cs:first line={(B)--(C)},
second line={(A) -- (auxA)});
% Here is my problem:
coordinate[label=below:$N$]
(N) at (intersection cs:first line={(B)--(M)},
second line={(C) -- (auxC)});
draw[thick, red] (A)--(P) (C)--(N) ;
end{tikzpicture}
end{document}
As you see, the red lines are parallel.
One may want cast this into a style:
documentclass{standalone}
usepackage{tikz}
usetikzlibrary{intersections}
usetikzlibrary{calc}
begin{document}
tikzset{line through/.style args={#1 parallel to line through #2 and #3 and
length #4}{insert path={%
let p1=($(#3)-(#2)$),n1={atan2(y1,x1)} in (#1) -- ++ (n1:#4)}}}
begin{tikzpicture}
coordinate[label=left:$A$] (A) at (0,0);
coordinate[label=above:$B$] (B) at (2,4);
coordinate[label=right:$C$] (C) at (8,0);
coordinate[label=45:$M$] (M) at (4,0);
draw[name path=Circle] (B) circle [radius=3cm];
path[name path=AB] (A)--(B);
path[name path=BC] (B)--(C);
path [name intersections={of=Circle and BC}];
coordinate[label=right:$E$] (E) at (intersection-1);
path [name intersections={of=Circle and AB}];
coordinate[label=left:$D$] (D) at (intersection-1);
draw[thick](A)--(B)--(C)--cycle;
%draw[thick](B) circle [radius=3cm];
draw[thick](D)--(E) (M)--(B);
% From a point draw a parallel line by calculating the vector
path[line through=A parallel to line through E and D and length 1]
coordinate (auxA)
[line through=C parallel to line through E and D and length 1]
coordinate (auxC);
coordinate[label=right:$P$] (P) at (intersection cs:first line={(B)--(C)},
second line={(A) -- (auxA)});
% Here is my problem:
coordinate[label=below:$N$]
(N) at (intersection cs:first line={(B)--(M)},
second line={(C) -- (auxC)});
draw[thick, red] (A)--(P) (C)--(N) ;
end{tikzpicture}
end{document}
If you use the +
syntax in this context, it seems not to always give you what one may expect. In general, +
means "relative to the first coordinate of this path". But who knows what the first coordinate is in the context of intersection cs:
? It is, however, not too difficult to produce the parallel lines just by computing the slope and using it. For the sake of clarity, I labeled all coordinates.
documentclass{standalone}
usepackage{tikz}
usetikzlibrary{intersections}
usetikzlibrary{calc}
begin{document}
begin{tikzpicture}
coordinate[label=left:$A$] (A) at (0,0);
coordinate[label=above:$B$] (B) at (2,4);
coordinate[label=right:$C$] (C) at (8,0);
coordinate[label=45:$M$] (M) at (4,0);
draw[name path=Circle] (B) circle [radius=3cm];
path[name path=AB] (A)--(B);
path[name path=BC] (B)--(C);
path [name intersections={of=Circle and BC}];
coordinate[label=right:$E$] (E) at (intersection-1);
path [name intersections={of=Circle and AB}];
coordinate[label=left:$D$] (D) at (intersection-1);
draw[thick](A)--(B)--(C)--cycle;
%draw[thick](B) circle [radius=3cm];
draw[thick](D)--(E) (M)--(B);
% From a point draw a parallel line by calculating the vector
path let p1=($(E)-(D)$),n1={atan2(y1,x1)} in
($(A)+(n1:1)$) coordinate (auxA)
($(C)+(n1:1)$) coordinate (auxC);
coordinate[label=right:$P$] (P) at (intersection cs:first line={(B)--(C)},
second line={(A) -- (auxA)});
% Here is my problem:
coordinate[label=below:$N$]
(N) at (intersection cs:first line={(B)--(M)},
second line={(C) -- (auxC)});
draw[thick, red] (A)--(P) (C)--(N) ;
end{tikzpicture}
end{document}
As you see, the red lines are parallel.
One may want cast this into a style:
documentclass{standalone}
usepackage{tikz}
usetikzlibrary{intersections}
usetikzlibrary{calc}
begin{document}
tikzset{line through/.style args={#1 parallel to line through #2 and #3 and
length #4}{insert path={%
let p1=($(#3)-(#2)$),n1={atan2(y1,x1)} in (#1) -- ++ (n1:#4)}}}
begin{tikzpicture}
coordinate[label=left:$A$] (A) at (0,0);
coordinate[label=above:$B$] (B) at (2,4);
coordinate[label=right:$C$] (C) at (8,0);
coordinate[label=45:$M$] (M) at (4,0);
draw[name path=Circle] (B) circle [radius=3cm];
path[name path=AB] (A)--(B);
path[name path=BC] (B)--(C);
path [name intersections={of=Circle and BC}];
coordinate[label=right:$E$] (E) at (intersection-1);
path [name intersections={of=Circle and AB}];
coordinate[label=left:$D$] (D) at (intersection-1);
draw[thick](A)--(B)--(C)--cycle;
%draw[thick](B) circle [radius=3cm];
draw[thick](D)--(E) (M)--(B);
% From a point draw a parallel line by calculating the vector
path[line through=A parallel to line through E and D and length 1]
coordinate (auxA)
[line through=C parallel to line through E and D and length 1]
coordinate (auxC);
coordinate[label=right:$P$] (P) at (intersection cs:first line={(B)--(C)},
second line={(A) -- (auxA)});
% Here is my problem:
coordinate[label=below:$N$]
(N) at (intersection cs:first line={(B)--(M)},
second line={(C) -- (auxC)});
draw[thick, red] (A)--(P) (C)--(N) ;
end{tikzpicture}
end{document}
edited 25 mins ago
answered 44 mins ago
marmot
85.6k497182
85.6k497182
Thank you. I was following this answer.
– blackened
39 mins ago
@blackened Yes, there it is very clear what the first point of the path is. Therefore, it is clear what+
does. However, in the context ofintersection cs:
it is not clear to me where single paths start and end, and hence-- +(coordinate)
may not be what one may thing it is. I am sorry if you feel that my wording is offensive, would like to apologize, and change it right away.
– marmot
37 mins ago
No worries at all. I just assumed that that answer encompassed all cases. How can I turn your approach to atikz
style definition?
– blackened
35 mins ago
@blackened What precisely do you want the style to accomplish? A line through a given point with the slope coinciding with the one of another line. (And rereading my original post I think my wording did indeed not reflect what I wanted to say.)
– marmot
33 mins ago
What precisely do you want the style to accomplish? A line through a given point with the slope coinciding with the one of another line. Yes. (From your question, I understand that one may want to accomplish other options. What are they?)
– blackened
31 mins ago
|
show 1 more comment
Thank you. I was following this answer.
– blackened
39 mins ago
@blackened Yes, there it is very clear what the first point of the path is. Therefore, it is clear what+
does. However, in the context ofintersection cs:
it is not clear to me where single paths start and end, and hence-- +(coordinate)
may not be what one may thing it is. I am sorry if you feel that my wording is offensive, would like to apologize, and change it right away.
– marmot
37 mins ago
No worries at all. I just assumed that that answer encompassed all cases. How can I turn your approach to atikz
style definition?
– blackened
35 mins ago
@blackened What precisely do you want the style to accomplish? A line through a given point with the slope coinciding with the one of another line. (And rereading my original post I think my wording did indeed not reflect what I wanted to say.)
– marmot
33 mins ago
What precisely do you want the style to accomplish? A line through a given point with the slope coinciding with the one of another line. Yes. (From your question, I understand that one may want to accomplish other options. What are they?)
– blackened
31 mins ago
Thank you. I was following this answer.
– blackened
39 mins ago
Thank you. I was following this answer.
– blackened
39 mins ago
@blackened Yes, there it is very clear what the first point of the path is. Therefore, it is clear what
+
does. However, in the context of intersection cs:
it is not clear to me where single paths start and end, and hence -- +(coordinate)
may not be what one may thing it is. I am sorry if you feel that my wording is offensive, would like to apologize, and change it right away.– marmot
37 mins ago
@blackened Yes, there it is very clear what the first point of the path is. Therefore, it is clear what
+
does. However, in the context of intersection cs:
it is not clear to me where single paths start and end, and hence -- +(coordinate)
may not be what one may thing it is. I am sorry if you feel that my wording is offensive, would like to apologize, and change it right away.– marmot
37 mins ago
No worries at all. I just assumed that that answer encompassed all cases. How can I turn your approach to a
tikz
style definition?– blackened
35 mins ago
No worries at all. I just assumed that that answer encompassed all cases. How can I turn your approach to a
tikz
style definition?– blackened
35 mins ago
@blackened What precisely do you want the style to accomplish? A line through a given point with the slope coinciding with the one of another line. (And rereading my original post I think my wording did indeed not reflect what I wanted to say.)
– marmot
33 mins ago
@blackened What precisely do you want the style to accomplish? A line through a given point with the slope coinciding with the one of another line. (And rereading my original post I think my wording did indeed not reflect what I wanted to say.)
– marmot
33 mins ago
What precisely do you want the style to accomplish? A line through a given point with the slope coinciding with the one of another line. Yes. (From your question, I understand that one may want to accomplish other options. What are they?)
– blackened
31 mins ago
What precisely do you want the style to accomplish? A line through a given point with the slope coinciding with the one of another line. Yes. (From your question, I understand that one may want to accomplish other options. What are they?)
– blackened
31 mins ago
|
show 1 more comment
Use second line={(C)--($(C)+(D)-(E)$)})
. The first one works as expected because (A)=(0,0)
documentclass{article}
usepackage{tikz}
usetikzlibrary{intersections}
usetikzlibrary{calc}
begin{document}
begin{tikzpicture}
coordinate[label=A] (A) at (0,0);
coordinate[label=B](B) at (2,4);
coordinate[label=C] (C) at (8,0);
coordinate[label=M] (M) at (4,0);
path[name path=Circle] (B) circle [radius=3cm];
path[name path=AB] (A)--(B);
path[name path=BC] (B)--(C);
path [name intersections={of=Circle and BC}];
coordinate[label=E] (E) at (intersection-1);
path [name intersections={of=Circle and AB}];
coordinate[label=D] (D) at (intersection-1);
draw[thick](A)--(B)--(C)--cycle;
draw[thick](B) circle [radius=3cm];
draw[thick](D)--(E) (M)--(B);
% From a point draw a parallel line by calculating the vector
coordinate[label=P] (P) at (intersection cs:first line={(B)--(C)}, second line={(A) -- +($(E)-(D)$)});
% Here is my problem:
coordinate[label=N] (N) at (intersection cs:first line={(B)--(M)}, second line={(C)--($(C)+(D)-(E)$)}); % <------
draw[thick, red] (A)--(P) (C)--(N);
end{tikzpicture}
end{document}
add a comment |
Use second line={(C)--($(C)+(D)-(E)$)})
. The first one works as expected because (A)=(0,0)
documentclass{article}
usepackage{tikz}
usetikzlibrary{intersections}
usetikzlibrary{calc}
begin{document}
begin{tikzpicture}
coordinate[label=A] (A) at (0,0);
coordinate[label=B](B) at (2,4);
coordinate[label=C] (C) at (8,0);
coordinate[label=M] (M) at (4,0);
path[name path=Circle] (B) circle [radius=3cm];
path[name path=AB] (A)--(B);
path[name path=BC] (B)--(C);
path [name intersections={of=Circle and BC}];
coordinate[label=E] (E) at (intersection-1);
path [name intersections={of=Circle and AB}];
coordinate[label=D] (D) at (intersection-1);
draw[thick](A)--(B)--(C)--cycle;
draw[thick](B) circle [radius=3cm];
draw[thick](D)--(E) (M)--(B);
% From a point draw a parallel line by calculating the vector
coordinate[label=P] (P) at (intersection cs:first line={(B)--(C)}, second line={(A) -- +($(E)-(D)$)});
% Here is my problem:
coordinate[label=N] (N) at (intersection cs:first line={(B)--(M)}, second line={(C)--($(C)+(D)-(E)$)}); % <------
draw[thick, red] (A)--(P) (C)--(N);
end{tikzpicture}
end{document}
add a comment |
Use second line={(C)--($(C)+(D)-(E)$)})
. The first one works as expected because (A)=(0,0)
documentclass{article}
usepackage{tikz}
usetikzlibrary{intersections}
usetikzlibrary{calc}
begin{document}
begin{tikzpicture}
coordinate[label=A] (A) at (0,0);
coordinate[label=B](B) at (2,4);
coordinate[label=C] (C) at (8,0);
coordinate[label=M] (M) at (4,0);
path[name path=Circle] (B) circle [radius=3cm];
path[name path=AB] (A)--(B);
path[name path=BC] (B)--(C);
path [name intersections={of=Circle and BC}];
coordinate[label=E] (E) at (intersection-1);
path [name intersections={of=Circle and AB}];
coordinate[label=D] (D) at (intersection-1);
draw[thick](A)--(B)--(C)--cycle;
draw[thick](B) circle [radius=3cm];
draw[thick](D)--(E) (M)--(B);
% From a point draw a parallel line by calculating the vector
coordinate[label=P] (P) at (intersection cs:first line={(B)--(C)}, second line={(A) -- +($(E)-(D)$)});
% Here is my problem:
coordinate[label=N] (N) at (intersection cs:first line={(B)--(M)}, second line={(C)--($(C)+(D)-(E)$)}); % <------
draw[thick, red] (A)--(P) (C)--(N);
end{tikzpicture}
end{document}
Use second line={(C)--($(C)+(D)-(E)$)})
. The first one works as expected because (A)=(0,0)
documentclass{article}
usepackage{tikz}
usetikzlibrary{intersections}
usetikzlibrary{calc}
begin{document}
begin{tikzpicture}
coordinate[label=A] (A) at (0,0);
coordinate[label=B](B) at (2,4);
coordinate[label=C] (C) at (8,0);
coordinate[label=M] (M) at (4,0);
path[name path=Circle] (B) circle [radius=3cm];
path[name path=AB] (A)--(B);
path[name path=BC] (B)--(C);
path [name intersections={of=Circle and BC}];
coordinate[label=E] (E) at (intersection-1);
path [name intersections={of=Circle and AB}];
coordinate[label=D] (D) at (intersection-1);
draw[thick](A)--(B)--(C)--cycle;
draw[thick](B) circle [radius=3cm];
draw[thick](D)--(E) (M)--(B);
% From a point draw a parallel line by calculating the vector
coordinate[label=P] (P) at (intersection cs:first line={(B)--(C)}, second line={(A) -- +($(E)-(D)$)});
% Here is my problem:
coordinate[label=N] (N) at (intersection cs:first line={(B)--(M)}, second line={(C)--($(C)+(D)-(E)$)}); % <------
draw[thick, red] (A)--(P) (C)--(N);
end{tikzpicture}
end{document}
edited 19 mins ago
answered 37 mins ago
Hafid Boukhoulda
1,3641515
1,3641515
add a comment |
add a comment |
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