Append Shapley reason codes on all observations to the entire data
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Here is my code to get the top 5 Shaply reason codes on mtcars dataset.
#install.packages("randomForest"); install.packages("tidyverse"); install.packages(""iml)
library(tidyverse); library(iml); library(randomForest)
set.seed(42)
mtcars1 <- mtcars %>% mutate(vs = as.factor(vs),
id = row_number())
x <- "vs"
y <- paste0(setdiff(setdiff(names(mtcars1), "vs"), "id"), collapse = "+")
rf = randomForest(as.formula(paste0(x, "~ ", y)), data = mtcars1, ntree = 50)
predictor = Predictor$new(rf, data = mtcars1, y = mtcars1$vs)
shapley = Shapley$new(predictor, x.interest = mtcars1[1,])
shapleyresults <- as_tibble(shapley$results) %>% arrange(desc(phi)) %>% slice(1:5) %>% select(feature.value, phi)
- How can I get the reason codes for all the observations (instead of one at a time in the 2nd last line in the above code: mtcars[1,])?
And, append/left_join the shapleyresults using id on to the entire dataset?
The dataset would be 5-times longer. Should we use purrr here to do that?
r tidyverse purrr
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up vote
0
down vote
favorite
Here is my code to get the top 5 Shaply reason codes on mtcars dataset.
#install.packages("randomForest"); install.packages("tidyverse"); install.packages(""iml)
library(tidyverse); library(iml); library(randomForest)
set.seed(42)
mtcars1 <- mtcars %>% mutate(vs = as.factor(vs),
id = row_number())
x <- "vs"
y <- paste0(setdiff(setdiff(names(mtcars1), "vs"), "id"), collapse = "+")
rf = randomForest(as.formula(paste0(x, "~ ", y)), data = mtcars1, ntree = 50)
predictor = Predictor$new(rf, data = mtcars1, y = mtcars1$vs)
shapley = Shapley$new(predictor, x.interest = mtcars1[1,])
shapleyresults <- as_tibble(shapley$results) %>% arrange(desc(phi)) %>% slice(1:5) %>% select(feature.value, phi)
- How can I get the reason codes for all the observations (instead of one at a time in the 2nd last line in the above code: mtcars[1,])?
And, append/left_join the shapleyresults using id on to the entire dataset?
The dataset would be 5-times longer. Should we use purrr here to do that?
r tidyverse purrr
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
Here is my code to get the top 5 Shaply reason codes on mtcars dataset.
#install.packages("randomForest"); install.packages("tidyverse"); install.packages(""iml)
library(tidyverse); library(iml); library(randomForest)
set.seed(42)
mtcars1 <- mtcars %>% mutate(vs = as.factor(vs),
id = row_number())
x <- "vs"
y <- paste0(setdiff(setdiff(names(mtcars1), "vs"), "id"), collapse = "+")
rf = randomForest(as.formula(paste0(x, "~ ", y)), data = mtcars1, ntree = 50)
predictor = Predictor$new(rf, data = mtcars1, y = mtcars1$vs)
shapley = Shapley$new(predictor, x.interest = mtcars1[1,])
shapleyresults <- as_tibble(shapley$results) %>% arrange(desc(phi)) %>% slice(1:5) %>% select(feature.value, phi)
- How can I get the reason codes for all the observations (instead of one at a time in the 2nd last line in the above code: mtcars[1,])?
And, append/left_join the shapleyresults using id on to the entire dataset?
The dataset would be 5-times longer. Should we use purrr here to do that?
r tidyverse purrr
Here is my code to get the top 5 Shaply reason codes on mtcars dataset.
#install.packages("randomForest"); install.packages("tidyverse"); install.packages(""iml)
library(tidyverse); library(iml); library(randomForest)
set.seed(42)
mtcars1 <- mtcars %>% mutate(vs = as.factor(vs),
id = row_number())
x <- "vs"
y <- paste0(setdiff(setdiff(names(mtcars1), "vs"), "id"), collapse = "+")
rf = randomForest(as.formula(paste0(x, "~ ", y)), data = mtcars1, ntree = 50)
predictor = Predictor$new(rf, data = mtcars1, y = mtcars1$vs)
shapley = Shapley$new(predictor, x.interest = mtcars1[1,])
shapleyresults <- as_tibble(shapley$results) %>% arrange(desc(phi)) %>% slice(1:5) %>% select(feature.value, phi)
- How can I get the reason codes for all the observations (instead of one at a time in the 2nd last line in the above code: mtcars[1,])?
And, append/left_join the shapleyresults using id on to the entire dataset?
The dataset would be 5-times longer. Should we use purrr here to do that?
r tidyverse purrr
r tidyverse purrr
edited Nov 20 at 2:24
asked Nov 20 at 2:16
Geet
528615
528615
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
up vote
0
down vote
accepted
I found the solution.
#install.packages("randomForest"); install.packages("tidyverse"); install.packages("iml")
library(tidyverse); library(iml); library(randomForest)
set.seed(42)
mtcars1 <- mtcars %>% mutate(vs = as.factor(vs),
id = row_number())
x <- "vs"
y <- paste0(setdiff(setdiff(names(mtcars1), "vs"), "id"), collapse = "+")
rf = randomForest(as.formula(paste0(x, "~ ", y)), data = mtcars1, ntree = 50)
predictor <- Predictor$new(rf, data = mtcars1, y = mtcars1$vs)
shapelyresults <- map_dfr(1:nrow(mtcars), ~(Shapley$new(predictor, x.interest = mtcars1[.x,]) %>%
.$results %>%
as_tibble() %>%
arrange(desc(phi)) %>%
slice(1:5) %>%
select(feature.value, phi) %>%
mutate(id = .x)))
final_data <- mtcars1 %>% left_join(shapelyresults, by = "id")
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
accepted
I found the solution.
#install.packages("randomForest"); install.packages("tidyverse"); install.packages("iml")
library(tidyverse); library(iml); library(randomForest)
set.seed(42)
mtcars1 <- mtcars %>% mutate(vs = as.factor(vs),
id = row_number())
x <- "vs"
y <- paste0(setdiff(setdiff(names(mtcars1), "vs"), "id"), collapse = "+")
rf = randomForest(as.formula(paste0(x, "~ ", y)), data = mtcars1, ntree = 50)
predictor <- Predictor$new(rf, data = mtcars1, y = mtcars1$vs)
shapelyresults <- map_dfr(1:nrow(mtcars), ~(Shapley$new(predictor, x.interest = mtcars1[.x,]) %>%
.$results %>%
as_tibble() %>%
arrange(desc(phi)) %>%
slice(1:5) %>%
select(feature.value, phi) %>%
mutate(id = .x)))
final_data <- mtcars1 %>% left_join(shapelyresults, by = "id")
add a comment |
up vote
0
down vote
accepted
I found the solution.
#install.packages("randomForest"); install.packages("tidyverse"); install.packages("iml")
library(tidyverse); library(iml); library(randomForest)
set.seed(42)
mtcars1 <- mtcars %>% mutate(vs = as.factor(vs),
id = row_number())
x <- "vs"
y <- paste0(setdiff(setdiff(names(mtcars1), "vs"), "id"), collapse = "+")
rf = randomForest(as.formula(paste0(x, "~ ", y)), data = mtcars1, ntree = 50)
predictor <- Predictor$new(rf, data = mtcars1, y = mtcars1$vs)
shapelyresults <- map_dfr(1:nrow(mtcars), ~(Shapley$new(predictor, x.interest = mtcars1[.x,]) %>%
.$results %>%
as_tibble() %>%
arrange(desc(phi)) %>%
slice(1:5) %>%
select(feature.value, phi) %>%
mutate(id = .x)))
final_data <- mtcars1 %>% left_join(shapelyresults, by = "id")
add a comment |
up vote
0
down vote
accepted
up vote
0
down vote
accepted
I found the solution.
#install.packages("randomForest"); install.packages("tidyverse"); install.packages("iml")
library(tidyverse); library(iml); library(randomForest)
set.seed(42)
mtcars1 <- mtcars %>% mutate(vs = as.factor(vs),
id = row_number())
x <- "vs"
y <- paste0(setdiff(setdiff(names(mtcars1), "vs"), "id"), collapse = "+")
rf = randomForest(as.formula(paste0(x, "~ ", y)), data = mtcars1, ntree = 50)
predictor <- Predictor$new(rf, data = mtcars1, y = mtcars1$vs)
shapelyresults <- map_dfr(1:nrow(mtcars), ~(Shapley$new(predictor, x.interest = mtcars1[.x,]) %>%
.$results %>%
as_tibble() %>%
arrange(desc(phi)) %>%
slice(1:5) %>%
select(feature.value, phi) %>%
mutate(id = .x)))
final_data <- mtcars1 %>% left_join(shapelyresults, by = "id")
I found the solution.
#install.packages("randomForest"); install.packages("tidyverse"); install.packages("iml")
library(tidyverse); library(iml); library(randomForest)
set.seed(42)
mtcars1 <- mtcars %>% mutate(vs = as.factor(vs),
id = row_number())
x <- "vs"
y <- paste0(setdiff(setdiff(names(mtcars1), "vs"), "id"), collapse = "+")
rf = randomForest(as.formula(paste0(x, "~ ", y)), data = mtcars1, ntree = 50)
predictor <- Predictor$new(rf, data = mtcars1, y = mtcars1$vs)
shapelyresults <- map_dfr(1:nrow(mtcars), ~(Shapley$new(predictor, x.interest = mtcars1[.x,]) %>%
.$results %>%
as_tibble() %>%
arrange(desc(phi)) %>%
slice(1:5) %>%
select(feature.value, phi) %>%
mutate(id = .x)))
final_data <- mtcars1 %>% left_join(shapelyresults, by = "id")
answered Nov 20 at 17:52
Geet
528615
528615
add a comment |
add a comment |
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