Writing a conditional statement for this tables

I have a requirement where I need to write a few lines of case statement to generate a new column, counting the first and the second column to return the result.

In this example I want to check if the second column has more null, then return 'semi valid'

ref no       first column      second column      result (new column) 

1234         yes               yes 

1234         null              null

1234         yes               null

In this example I want to check if there's no null in both, then return 'valid'

ref no       first column      second column      result (new column) 

1234         yes               yes 

1234         yes               yes

1234         yes               yes

In this example I want to check if the second column has more null, then return 'higher valid'

ref no       first column      second column      result (new column) 

1234         yes               yes 

1234         yes               yes

1234         yes               null

In this example I want to check if the first column has more null, then return 'not valid'

ref no       first column      second column      result (new column) 

1234         null              yes 

1234         null              yes

1234         null              yes

edited Nov 23 '18 at 13:41

asked Nov 21 '18 at 16:06

H.Atrin

Improved formatting & title. You didn't specify what language you're using.
– Federico Grandi
Nov 21 '18 at 20:30

Thanks Federico Grandi, I am using T-sql , the question I have asked need to be implemented to existing view
– H.Atrin
Nov 22 '18 at 9:29

I've added TSQL to the tags
– Federico Grandi
Nov 22 '18 at 16:26

Any advice/answer?
– H.Atrin
Nov 23 '18 at 9:53

add a comment |

ref no       first column      second column      result (new column) 

1234         yes               yes 

1234         null              null

1234         yes               null

In this example I want to check if there's no null in both, then return 'valid'

ref no       first column      second column      result (new column) 

1234         yes               yes 

1234         yes               yes

1234         yes               yes

In this example I want to check if the second column has more null, then return 'higher valid'

ref no       first column      second column      result (new column) 

1234         yes               yes 

1234         yes               yes

1234         yes               null

In this example I want to check if the first column has more null, then return 'not valid'

ref no       first column      second column      result (new column) 

1234         null              yes 

1234         null              yes

1234         null              yes

edited Nov 23 '18 at 13:41

asked Nov 21 '18 at 16:06

H.Atrin

Improved formatting & title. You didn't specify what language you're using.
– Federico Grandi
Nov 21 '18 at 20:30

Thanks Federico Grandi, I am using T-sql , the question I have asked need to be implemented to existing view
– H.Atrin
Nov 22 '18 at 9:29

I've added TSQL to the tags
– Federico Grandi
Nov 22 '18 at 16:26

Any advice/answer?
– H.Atrin
Nov 23 '18 at 9:53

add a comment |

ref no       first column      second column      result (new column) 

1234         yes               yes 

1234         null              null

1234         yes               null

In this example I want to check if there's no null in both, then return 'valid'

ref no       first column      second column      result (new column) 

1234         yes               yes 

1234         yes               yes

1234         yes               yes

In this example I want to check if the second column has more null, then return 'higher valid'

ref no       first column      second column      result (new column) 

1234         yes               yes 

1234         yes               yes

1234         yes               null

In this example I want to check if the first column has more null, then return 'not valid'

ref no       first column      second column      result (new column) 

1234         null              yes 

1234         null              yes

1234         null              yes

edited Nov 23 '18 at 13:41

asked Nov 21 '18 at 16:06

H.Atrin

ref no       first column      second column      result (new column) 

1234         yes               yes 

1234         null              null

1234         yes               null

In this example I want to check if there's no null in both, then return 'valid'

ref no       first column      second column      result (new column) 

1234         yes               yes 

1234         yes               yes

1234         yes               yes

In this example I want to check if the second column has more null, then return 'higher valid'

ref no       first column      second column      result (new column) 

1234         yes               yes 

1234         yes               yes

1234         yes               null

In this example I want to check if the first column has more null, then return 'not valid'

ref no       first column      second column      result (new column) 

1234         null              yes 

1234         null              yes

1234         null              yes

tsql syntax case condition

edited Nov 23 '18 at 13:41

asked Nov 21 '18 at 16:06

H.Atrin

edited Nov 23 '18 at 13:41

asked Nov 21 '18 at 16:06

H.Atrin

edited Nov 23 '18 at 13:41

asked Nov 21 '18 at 16:06

H.Atrin

asked Nov 21 '18 at 16:06

H.Atrin

asked Nov 21 '18 at 16:06

H.Atrin

Improved formatting & title. You didn't specify what language you're using.
– Federico Grandi
Nov 21 '18 at 20:30

Thanks Federico Grandi, I am using T-sql , the question I have asked need to be implemented to existing view
– H.Atrin
Nov 22 '18 at 9:29

I've added TSQL to the tags
– Federico Grandi
Nov 22 '18 at 16:26

Any advice/answer?
– H.Atrin
Nov 23 '18 at 9:53

add a comment |

Improved formatting & title. You didn't specify what language you're using.
– Federico Grandi
Nov 21 '18 at 20:30

Thanks Federico Grandi, I am using T-sql , the question I have asked need to be implemented to existing view
– H.Atrin
Nov 22 '18 at 9:29

I've added TSQL to the tags
– Federico Grandi
Nov 22 '18 at 16:26

Any advice/answer?
– H.Atrin
Nov 23 '18 at 9:53

Improved formatting & title. You didn't specify what language you're using.
– Federico Grandi
Nov 21 '18 at 20:30

Thanks Federico Grandi, I am using T-sql , the question I have asked need to be implemented to existing view
– H.Atrin
Nov 22 '18 at 9:29

I've added TSQL to the tags
– Federico Grandi
Nov 22 '18 at 16:26

Any advice/answer?
– H.Atrin
Nov 23 '18 at 9:53

add a comment |

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