read in string as datetime object with 3 digits for millisecond
I am reading in a string that is in a datetime format. However, instead of having 6 digits for the millisecond, it has only 3 with a letter Z at the end. How do I read in this string and make it a datetime object, and add 1 day, and write out this as a string in the above format i.e. 3 digits for the millisecond and a letter Z at the end. I tried the following code but not successful:
old_date= "2018-06-06T23:59:59.999Z"
new_date = datetime.datetime.strptime(old_date, '%Y-%m-%d %H:%M:%S.%f%Z') + datetime.timedelta(days=1)
print(new_date)
python python-3.x datetime
asked Nov 21 at 3:02
duckman
15713
add a comment |
I am reading in a string that is in a datetime format. However, instead of having 6 digits for the millisecond, it has only 3 with a letter Z at the end. How do I read in this string and make it a datetime object, and add 1 day, and write out this as a string in the above format i.e. 3 digits for the millisecond and a letter Z at the end. I tried the following code but not successful:
old_date= "2018-06-06T23:59:59.999Z"
new_date = datetime.datetime.strptime(old_date, '%Y-%m-%d %H:%M:%S.%f%Z') + datetime.timedelta(days=1)
print(new_date)
python python-3.x datetime
asked Nov 21 at 3:02
duckman
15713
add a comment |
I am reading in a string that is in a datetime format. However, instead of having 6 digits for the millisecond, it has only 3 with a letter Z at the end. How do I read in this string and make it a datetime object, and add 1 day, and write out this as a string in the above format i.e. 3 digits for the millisecond and a letter Z at the end. I tried the following code but not successful:
old_date= "2018-06-06T23:59:59.999Z"
new_date = datetime.datetime.strptime(old_date, '%Y-%m-%d %H:%M:%S.%f%Z') + datetime.timedelta(days=1)
print(new_date)
python python-3.x datetime
asked Nov 21 at 3:02
duckman
15713
I am reading in a string that is in a datetime format. However, instead of having 6 digits for the millisecond, it has only 3 with a letter Z at the end. How do I read in this string and make it a datetime object, and add 1 day, and write out this as a string in the above format i.e. 3 digits for the millisecond and a letter Z at the end. I tried the following code but not successful:
old_date= "2018-06-06T23:59:59.999Z"
new_date = datetime.datetime.strptime(old_date, '%Y-%m-%d %H:%M:%S.%f%Z') + datetime.timedelta(days=1)
print(new_date)
python python-3.x datetime
python python-3.x datetime
asked Nov 21 at 3:02
duckman
15713
asked Nov 21 at 3:02
duckman
15713
asked Nov 21 at 3:02
duckman
15713
asked Nov 21 at 3:02
duckman
15713
asked Nov 21 at 3:02
duckman
15713
15713
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
You should using this format
datetime.datetime.strptime(old_date, '%Y-%m-%dT%H:%M:%S.%fZ')
Out[180]: datetime.datetime(2018, 6, 6, 23, 59, 59, 999000)
Update
dt1=datetime.datetime.strptime(old_date, '%Y-%m-%dT%H:%M:%S.%fZ')+datetime.timedelta(days=1)
dt1.strftime('%Y-%m-%d %H:%M:%S.%f')[:-3]+'Z'
Out[196]: '2018-06-07 23:59:59.999Z'
answered Nov 21 at 3:05
W-B
99.9k73163
Thanks. how about writing this as a string with 3 digits for the milisecondpart and Z at the end?
– duckman
Nov 21 at 3:15
@duckman check the update
– W-B
Nov 21 at 3:22
you are the champ!
– duckman
Nov 21 at 3:23
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You should using this format
datetime.datetime.strptime(old_date, '%Y-%m-%dT%H:%M:%S.%fZ')
Out[180]: datetime.datetime(2018, 6, 6, 23, 59, 59, 999000)
Update
dt1=datetime.datetime.strptime(old_date, '%Y-%m-%dT%H:%M:%S.%fZ')+datetime.timedelta(days=1)
dt1.strftime('%Y-%m-%d %H:%M:%S.%f')[:-3]+'Z'
Out[196]: '2018-06-07 23:59:59.999Z'
answered Nov 21 at 3:05
W-B
99.9k73163
Thanks. how about writing this as a string with 3 digits for the milisecondpart and Z at the end?
– duckman
Nov 21 at 3:15
@duckman check the update
– W-B
Nov 21 at 3:22
you are the champ!
– duckman
Nov 21 at 3:23
add a comment |
You should using this format
datetime.datetime.strptime(old_date, '%Y-%m-%dT%H:%M:%S.%fZ')
Out[180]: datetime.datetime(2018, 6, 6, 23, 59, 59, 999000)
Update
dt1=datetime.datetime.strptime(old_date, '%Y-%m-%dT%H:%M:%S.%fZ')+datetime.timedelta(days=1)
dt1.strftime('%Y-%m-%d %H:%M:%S.%f')[:-3]+'Z'
Out[196]: '2018-06-07 23:59:59.999Z'
answered Nov 21 at 3:05
W-B
99.9k73163
Thanks. how about writing this as a string with 3 digits for the milisecondpart and Z at the end?
– duckman
Nov 21 at 3:15
@duckman check the update
– W-B
Nov 21 at 3:22
you are the champ!
– duckman
Nov 21 at 3:23
add a comment |
You should using this format
datetime.datetime.strptime(old_date, '%Y-%m-%dT%H:%M:%S.%fZ')
Out[180]: datetime.datetime(2018, 6, 6, 23, 59, 59, 999000)
Update
dt1=datetime.datetime.strptime(old_date, '%Y-%m-%dT%H:%M:%S.%fZ')+datetime.timedelta(days=1)
dt1.strftime('%Y-%m-%d %H:%M:%S.%f')[:-3]+'Z'
Out[196]: '2018-06-07 23:59:59.999Z'
answered Nov 21 at 3:05
W-B
99.9k73163
You should using this format
datetime.datetime.strptime(old_date, '%Y-%m-%dT%H:%M:%S.%fZ')
Out[180]: datetime.datetime(2018, 6, 6, 23, 59, 59, 999000)
Update
dt1=datetime.datetime.strptime(old_date, '%Y-%m-%dT%H:%M:%S.%fZ')+datetime.timedelta(days=1)
dt1.strftime('%Y-%m-%d %H:%M:%S.%f')[:-3]+'Z'
Out[196]: '2018-06-07 23:59:59.999Z'
answered Nov 21 at 3:05
W-B
99.9k73163
edited Nov 21 at 3:22
answered Nov 21 at 3:05
W-B
99.9k73163
answered Nov 21 at 3:05
W-B
99.9k73163
answered Nov 21 at 3:05
W-B
99.9k73163
99.9k73163
Thanks. how about writing this as a string with 3 digits for the milisecondpart and Z at the end?
– duckman
Nov 21 at 3:15
@duckman check the update
– W-B
Nov 21 at 3:22
you are the champ!
– duckman
Nov 21 at 3:23
add a comment |
Thanks. how about writing this as a string with 3 digits for the milisecondpart and Z at the end?
– duckman
Nov 21 at 3:15
@duckman check the update
– W-B
Nov 21 at 3:22
you are the champ!
– duckman
Nov 21 at 3:23
Thanks. how about writing this as a string with 3 digits for the milisecondpart and Z at the end?
– duckman
Nov 21 at 3:15
Thanks. how about writing this as a string with 3 digits for the milisecondpart and Z at the end?
– duckman
Nov 21 at 3:15
@duckman check the update
– W-B
Nov 21 at 3:22
@duckman check the update
– W-B
Nov 21 at 3:22
you are the champ!
– duckman
Nov 21 at 3:23
you are the champ!
– duckman
Nov 21 at 3:23
add a comment |
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