memory address gets cut off after 8 digits
memory address gets cuts off after 8 digits help
DWORD* memoryAddress = (DWORD*)0x155221000;
turns from 0x155221000 into 0x55221000 after conversion.
c++
asked Nov 23 '18 at 20:08
42342342343244234234234324
63
add a comment |
memory address gets cuts off after 8 digits help
DWORD* memoryAddress = (DWORD*)0x155221000;
turns from 0x155221000 into 0x55221000 after conversion.
c++
asked Nov 23 '18 at 20:08
42342342343244234234234324
63
How do you know what's stored in your pointer value?
– Andrew Henle
Nov 23 '18 at 20:10
2
DWORDis 4 bytes so it should be able to store... a maximum of0xFFFFFFFF. Exactly what you're seeing.
– wizzwizz4
Nov 23 '18 at 20:12
you are supposed to store memory addresses as pointers and i forgot it was in hex and so it was a 64 bit hex memadress i was trying to access using so small things like DWORD when i needed to use DWORD64* for the 64 bit programs memory addresses thanks all answers.
– 4234234234324
Nov 23 '18 at 20:23
Is this on Windows? If so, the datatype you are looking for isDWORD_PTR, or maybeuintptr_t.
– Paul Sanders
Nov 23 '18 at 20:47
add a comment |
memory address gets cuts off after 8 digits help
DWORD* memoryAddress = (DWORD*)0x155221000;
turns from 0x155221000 into 0x55221000 after conversion.
c++
asked Nov 23 '18 at 20:08
42342342343244234234234324
63
memory address gets cuts off after 8 digits help
DWORD* memoryAddress = (DWORD*)0x155221000;
turns from 0x155221000 into 0x55221000 after conversion.
c++
c++
asked Nov 23 '18 at 20:08
42342342343244234234234324
63
asked Nov 23 '18 at 20:08
42342342343244234234234324
63
edited Nov 23 '18 at 20:26
4234234234324
asked Nov 23 '18 at 20:08
42342342343244234234234324
63
asked Nov 23 '18 at 20:08
42342342343244234234234324
63
asked Nov 23 '18 at 20:08
42342342343244234234234324
63
63
How do you know what's stored in your pointer value?
– Andrew Henle
Nov 23 '18 at 20:10
2
DWORDis 4 bytes so it should be able to store... a maximum of0xFFFFFFFF. Exactly what you're seeing.
– wizzwizz4
Nov 23 '18 at 20:12
you are supposed to store memory addresses as pointers and i forgot it was in hex and so it was a 64 bit hex memadress i was trying to access using so small things like DWORD when i needed to use DWORD64* for the 64 bit programs memory addresses thanks all answers.
– 4234234234324
Nov 23 '18 at 20:23
Is this on Windows? If so, the datatype you are looking for isDWORD_PTR, or maybeuintptr_t.
– Paul Sanders
Nov 23 '18 at 20:47
add a comment |
How do you know what's stored in your pointer value?
– Andrew Henle
Nov 23 '18 at 20:10
2
DWORDis 4 bytes so it should be able to store... a maximum of0xFFFFFFFF. Exactly what you're seeing.
– wizzwizz4
Nov 23 '18 at 20:12
you are supposed to store memory addresses as pointers and i forgot it was in hex and so it was a 64 bit hex memadress i was trying to access using so small things like DWORD when i needed to use DWORD64* for the 64 bit programs memory addresses thanks all answers.
– 4234234234324
Nov 23 '18 at 20:23
Is this on Windows? If so, the datatype you are looking for isDWORD_PTR, or maybeuintptr_t.
– Paul Sanders
Nov 23 '18 at 20:47
How do you know what's stored in your pointer value?
– Andrew Henle
Nov 23 '18 at 20:10
How do you know what's stored in your pointer value?
– Andrew Henle
Nov 23 '18 at 20:10
2
2
DWORD is 4 bytes so it should be able to store... a maximum of 0xFFFFFFFF. Exactly what you're seeing.– wizzwizz4
Nov 23 '18 at 20:12
DWORD is 4 bytes so it should be able to store... a maximum of 0xFFFFFFFF. Exactly what you're seeing.– wizzwizz4
Nov 23 '18 at 20:12
you are supposed to store memory addresses as pointers and i forgot it was in hex and so it was a 64 bit hex memadress i was trying to access using so small things like DWORD when i needed to use DWORD64* for the 64 bit programs memory addresses thanks all answers.
– 4234234234324
Nov 23 '18 at 20:23
you are supposed to store memory addresses as pointers and i forgot it was in hex and so it was a 64 bit hex memadress i was trying to access using so small things like DWORD when i needed to use DWORD64* for the 64 bit programs memory addresses thanks all answers.
– 4234234234324
Nov 23 '18 at 20:23
Is this on Windows? If so, the datatype you are looking for is
DWORD_PTR, or maybe uintptr_t.– Paul Sanders
Nov 23 '18 at 20:47
Is this on Windows? If so, the datatype you are looking for is
DWORD_PTR, or maybe uintptr_t.– Paul Sanders
Nov 23 '18 at 20:47
add a comment |
1 Answer
1
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On a 32bits system, an address is 4 bytes long. So DWORD* memoryAddress = (DWORD*)0x155221000; would be truncated by definition (also bad to use C-style casts). The compiler should give you a truncation warning by the way.
1428295680 is the base-10 representation of the same value (addresses are usually represented in hexadecimal, still the same value).
As the comments from different people said, DWORD is 4 bytes (just a coincidence that addresses are also 4 bytes), it would also truncate your number for the same reason.
answered Nov 23 '18 at 20:11
Matthieu BrucherMatthieu Brucher
15.6k32140
add a comment |
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1 Answer
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1 Answer
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active
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votes
On a 32bits system, an address is 4 bytes long. So DWORD* memoryAddress = (DWORD*)0x155221000; would be truncated by definition (also bad to use C-style casts). The compiler should give you a truncation warning by the way.
1428295680 is the base-10 representation of the same value (addresses are usually represented in hexadecimal, still the same value).
As the comments from different people said, DWORD is 4 bytes (just a coincidence that addresses are also 4 bytes), it would also truncate your number for the same reason.
answered Nov 23 '18 at 20:11
Matthieu BrucherMatthieu Brucher
15.6k32140
add a comment |
On a 32bits system, an address is 4 bytes long. So DWORD* memoryAddress = (DWORD*)0x155221000; would be truncated by definition (also bad to use C-style casts). The compiler should give you a truncation warning by the way.
1428295680 is the base-10 representation of the same value (addresses are usually represented in hexadecimal, still the same value).
As the comments from different people said, DWORD is 4 bytes (just a coincidence that addresses are also 4 bytes), it would also truncate your number for the same reason.
answered Nov 23 '18 at 20:11
Matthieu BrucherMatthieu Brucher
15.6k32140
add a comment |
On a 32bits system, an address is 4 bytes long. So DWORD* memoryAddress = (DWORD*)0x155221000; would be truncated by definition (also bad to use C-style casts). The compiler should give you a truncation warning by the way.
1428295680 is the base-10 representation of the same value (addresses are usually represented in hexadecimal, still the same value).
As the comments from different people said, DWORD is 4 bytes (just a coincidence that addresses are also 4 bytes), it would also truncate your number for the same reason.
answered Nov 23 '18 at 20:11
Matthieu BrucherMatthieu Brucher
15.6k32140
On a 32bits system, an address is 4 bytes long. So DWORD* memoryAddress = (DWORD*)0x155221000; would be truncated by definition (also bad to use C-style casts). The compiler should give you a truncation warning by the way.
1428295680 is the base-10 representation of the same value (addresses are usually represented in hexadecimal, still the same value).
As the comments from different people said, DWORD is 4 bytes (just a coincidence that addresses are also 4 bytes), it would also truncate your number for the same reason.
answered Nov 23 '18 at 20:11
Matthieu BrucherMatthieu Brucher
15.6k32140
edited Nov 23 '18 at 23:09
answered Nov 23 '18 at 20:11
Matthieu BrucherMatthieu Brucher
15.6k32140
answered Nov 23 '18 at 20:11
Matthieu BrucherMatthieu Brucher
15.6k32140
answered Nov 23 '18 at 20:11
Matthieu BrucherMatthieu Brucher
15.6k32140
15.6k32140
add a comment |
add a comment |
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How do you know what's stored in your pointer value?
– Andrew Henle
Nov 23 '18 at 20:10
2
DWORDis 4 bytes so it should be able to store... a maximum of0xFFFFFFFF. Exactly what you're seeing.– wizzwizz4
Nov 23 '18 at 20:12
you are supposed to store memory addresses as pointers and i forgot it was in hex and so it was a 64 bit hex memadress i was trying to access using so small things like DWORD when i needed to use DWORD64* for the 64 bit programs memory addresses thanks all answers.
– 4234234234324
Nov 23 '18 at 20:23
Is this on Windows? If so, the datatype you are looking for is
DWORD_PTR, or maybeuintptr_t.– Paul Sanders
Nov 23 '18 at 20:47