Finding the maximum property under a value












0















I have a list of objects, each with its properties.
I am trying to find a specific object in this list with this .find although I can't figure out how to find the maximum value of one of it's properties under a certain value.



let x = this.state.pricing_adjustments_view.filter((e) => {
return e.location_id === this.state.selectedLocation,
e.car_model_id === this.state.selectedCar,
moment(e.calendar_day).isSame(this.state.from, "day"),
_.max(e.minimum_duration) <= duration
})


Here it's the e.minimum_duration. I want to find the biggest value, but that is under "duration"
I am trying it with "lodash", here represented by the "_".
I am open to other possibilities.



this.state.pricing_adjustments_view is an array of objects, and you could say that for each object, the "UNIQUE" key is its "location_id", "car_model_id", "calendar_day" and "minimum_duration".



So there are several objects that are the same if we only consider "location_id", "car_model_id", "calendar_day", and then they have different "minimum_duration". I need to get the one that has the highest "minimum_duration".










share|improve this question




















  • 1





    Pls provide some example of input and expected output.

    – Nitish Narang
    Nov 23 '18 at 20:07











  • return with a check and comma operator? either some code is missing or it makes no sense.

    – Nina Scholz
    Nov 23 '18 at 20:07











  • @NinaScholz it's how i usually do it, .filter((e) => {return e.thing = thing, e.thing = thing}) and it works

    – Valenti
    Nov 23 '18 at 20:09






  • 1





    I'm not certain there is enough detail here for us to help you, consider reading up on Minimal, Complete, Verifieable Example

    – D Lowther
    Nov 23 '18 at 20:10











  • for example e.location_id === this.state.selectedLocation has nothing to do with the rest. it is not use in an if clause, nor as expression as return value or as part of a ternary.

    – Nina Scholz
    Nov 23 '18 at 20:11
















0















I have a list of objects, each with its properties.
I am trying to find a specific object in this list with this .find although I can't figure out how to find the maximum value of one of it's properties under a certain value.



let x = this.state.pricing_adjustments_view.filter((e) => {
return e.location_id === this.state.selectedLocation,
e.car_model_id === this.state.selectedCar,
moment(e.calendar_day).isSame(this.state.from, "day"),
_.max(e.minimum_duration) <= duration
})


Here it's the e.minimum_duration. I want to find the biggest value, but that is under "duration"
I am trying it with "lodash", here represented by the "_".
I am open to other possibilities.



this.state.pricing_adjustments_view is an array of objects, and you could say that for each object, the "UNIQUE" key is its "location_id", "car_model_id", "calendar_day" and "minimum_duration".



So there are several objects that are the same if we only consider "location_id", "car_model_id", "calendar_day", and then they have different "minimum_duration". I need to get the one that has the highest "minimum_duration".










share|improve this question




















  • 1





    Pls provide some example of input and expected output.

    – Nitish Narang
    Nov 23 '18 at 20:07











  • return with a check and comma operator? either some code is missing or it makes no sense.

    – Nina Scholz
    Nov 23 '18 at 20:07











  • @NinaScholz it's how i usually do it, .filter((e) => {return e.thing = thing, e.thing = thing}) and it works

    – Valenti
    Nov 23 '18 at 20:09






  • 1





    I'm not certain there is enough detail here for us to help you, consider reading up on Minimal, Complete, Verifieable Example

    – D Lowther
    Nov 23 '18 at 20:10











  • for example e.location_id === this.state.selectedLocation has nothing to do with the rest. it is not use in an if clause, nor as expression as return value or as part of a ternary.

    – Nina Scholz
    Nov 23 '18 at 20:11














0












0








0








I have a list of objects, each with its properties.
I am trying to find a specific object in this list with this .find although I can't figure out how to find the maximum value of one of it's properties under a certain value.



let x = this.state.pricing_adjustments_view.filter((e) => {
return e.location_id === this.state.selectedLocation,
e.car_model_id === this.state.selectedCar,
moment(e.calendar_day).isSame(this.state.from, "day"),
_.max(e.minimum_duration) <= duration
})


Here it's the e.minimum_duration. I want to find the biggest value, but that is under "duration"
I am trying it with "lodash", here represented by the "_".
I am open to other possibilities.



this.state.pricing_adjustments_view is an array of objects, and you could say that for each object, the "UNIQUE" key is its "location_id", "car_model_id", "calendar_day" and "minimum_duration".



So there are several objects that are the same if we only consider "location_id", "car_model_id", "calendar_day", and then they have different "minimum_duration". I need to get the one that has the highest "minimum_duration".










share|improve this question
















I have a list of objects, each with its properties.
I am trying to find a specific object in this list with this .find although I can't figure out how to find the maximum value of one of it's properties under a certain value.



let x = this.state.pricing_adjustments_view.filter((e) => {
return e.location_id === this.state.selectedLocation,
e.car_model_id === this.state.selectedCar,
moment(e.calendar_day).isSame(this.state.from, "day"),
_.max(e.minimum_duration) <= duration
})


Here it's the e.minimum_duration. I want to find the biggest value, but that is under "duration"
I am trying it with "lodash", here represented by the "_".
I am open to other possibilities.



this.state.pricing_adjustments_view is an array of objects, and you could say that for each object, the "UNIQUE" key is its "location_id", "car_model_id", "calendar_day" and "minimum_duration".



So there are several objects that are the same if we only consider "location_id", "car_model_id", "calendar_day", and then they have different "minimum_duration". I need to get the one that has the highest "minimum_duration".







javascript lodash






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 23 '18 at 20:16







Valenti

















asked Nov 23 '18 at 20:06









ValentiValenti

32




32








  • 1





    Pls provide some example of input and expected output.

    – Nitish Narang
    Nov 23 '18 at 20:07











  • return with a check and comma operator? either some code is missing or it makes no sense.

    – Nina Scholz
    Nov 23 '18 at 20:07











  • @NinaScholz it's how i usually do it, .filter((e) => {return e.thing = thing, e.thing = thing}) and it works

    – Valenti
    Nov 23 '18 at 20:09






  • 1





    I'm not certain there is enough detail here for us to help you, consider reading up on Minimal, Complete, Verifieable Example

    – D Lowther
    Nov 23 '18 at 20:10











  • for example e.location_id === this.state.selectedLocation has nothing to do with the rest. it is not use in an if clause, nor as expression as return value or as part of a ternary.

    – Nina Scholz
    Nov 23 '18 at 20:11














  • 1





    Pls provide some example of input and expected output.

    – Nitish Narang
    Nov 23 '18 at 20:07











  • return with a check and comma operator? either some code is missing or it makes no sense.

    – Nina Scholz
    Nov 23 '18 at 20:07











  • @NinaScholz it's how i usually do it, .filter((e) => {return e.thing = thing, e.thing = thing}) and it works

    – Valenti
    Nov 23 '18 at 20:09






  • 1





    I'm not certain there is enough detail here for us to help you, consider reading up on Minimal, Complete, Verifieable Example

    – D Lowther
    Nov 23 '18 at 20:10











  • for example e.location_id === this.state.selectedLocation has nothing to do with the rest. it is not use in an if clause, nor as expression as return value or as part of a ternary.

    – Nina Scholz
    Nov 23 '18 at 20:11








1




1





Pls provide some example of input and expected output.

– Nitish Narang
Nov 23 '18 at 20:07





Pls provide some example of input and expected output.

– Nitish Narang
Nov 23 '18 at 20:07













return with a check and comma operator? either some code is missing or it makes no sense.

– Nina Scholz
Nov 23 '18 at 20:07





return with a check and comma operator? either some code is missing or it makes no sense.

– Nina Scholz
Nov 23 '18 at 20:07













@NinaScholz it's how i usually do it, .filter((e) => {return e.thing = thing, e.thing = thing}) and it works

– Valenti
Nov 23 '18 at 20:09





@NinaScholz it's how i usually do it, .filter((e) => {return e.thing = thing, e.thing = thing}) and it works

– Valenti
Nov 23 '18 at 20:09




1




1





I'm not certain there is enough detail here for us to help you, consider reading up on Minimal, Complete, Verifieable Example

– D Lowther
Nov 23 '18 at 20:10





I'm not certain there is enough detail here for us to help you, consider reading up on Minimal, Complete, Verifieable Example

– D Lowther
Nov 23 '18 at 20:10













for example e.location_id === this.state.selectedLocation has nothing to do with the rest. it is not use in an if clause, nor as expression as return value or as part of a ternary.

– Nina Scholz
Nov 23 '18 at 20:11





for example e.location_id === this.state.selectedLocation has nothing to do with the rest. it is not use in an if clause, nor as expression as return value or as part of a ternary.

– Nina Scholz
Nov 23 '18 at 20:11












1 Answer
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Ok,



You say it's the minimum_duration that interests you. In order to find the biggest (or smallest..) It's simple to just order pricing_adjustments_view by minimum_duration and take it's highest value.



So you can basically do following using lodash lib.



// sort dataa..
let sorted = _.sortBy(this.state.pricing_adjustments_view, 'minimum_duration');

// take last in list!
let has_highest_minimum_duration = sorted[sorted.length-1];





share|improve this answer























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    Ok,



    You say it's the minimum_duration that interests you. In order to find the biggest (or smallest..) It's simple to just order pricing_adjustments_view by minimum_duration and take it's highest value.



    So you can basically do following using lodash lib.



    // sort dataa..
    let sorted = _.sortBy(this.state.pricing_adjustments_view, 'minimum_duration');

    // take last in list!
    let has_highest_minimum_duration = sorted[sorted.length-1];





    share|improve this answer




























      0














      Ok,



      You say it's the minimum_duration that interests you. In order to find the biggest (or smallest..) It's simple to just order pricing_adjustments_view by minimum_duration and take it's highest value.



      So you can basically do following using lodash lib.



      // sort dataa..
      let sorted = _.sortBy(this.state.pricing_adjustments_view, 'minimum_duration');

      // take last in list!
      let has_highest_minimum_duration = sorted[sorted.length-1];





      share|improve this answer


























        0












        0








        0







        Ok,



        You say it's the minimum_duration that interests you. In order to find the biggest (or smallest..) It's simple to just order pricing_adjustments_view by minimum_duration and take it's highest value.



        So you can basically do following using lodash lib.



        // sort dataa..
        let sorted = _.sortBy(this.state.pricing_adjustments_view, 'minimum_duration');

        // take last in list!
        let has_highest_minimum_duration = sorted[sorted.length-1];





        share|improve this answer













        Ok,



        You say it's the minimum_duration that interests you. In order to find the biggest (or smallest..) It's simple to just order pricing_adjustments_view by minimum_duration and take it's highest value.



        So you can basically do following using lodash lib.



        // sort dataa..
        let sorted = _.sortBy(this.state.pricing_adjustments_view, 'minimum_duration');

        // take last in list!
        let has_highest_minimum_duration = sorted[sorted.length-1];






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Jan 18 at 22:37









        Silvan BregySilvan Bregy

        60829




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