How to add total number of items using list/conditional statments
trying to write a code where when a certain key is pressed, the word pops up on the canvas (in this case they are all drinks). When the user keeps pressing the certain keys to add a drink, the total cost adds up.
However, the only thing in my code the works is the word "water" and the total cost keeps overlaying.
How do I fix my code so that each menu item appears on the canvas and how to fix the total cost?
(I attempted to move the background colour around however it still did not work. Also this coding is from processing, and it is not java script)
def setup():
size (500, 500)
background (255)
menu = ["Mocha","Coffee","Juice","water"]
prices = [5,2,3,1]
order =
total = ''
cost = 0
Mocha = 5
Coffee = 2
Juice = 3
Water = 1
undo = -1
space = 0
i = 0
str1= 1
def draw():
global total
space = 100
fill (0)
line(250,0,250,500)
textSize (30)
text("Menu", 60, 50)
textSize (15)
for i in range(len(menu)):
str1 = menu[i] + " : $" + str(prices[i])
text(str1, 70, space)
space = space+20
textSize (30)
text( "Your Order:", 260,50)
textSize (15)
#total = text("Cost : $0", 300,450)
total= text(str1, 350, 450)
def keyPressed():
global space
global cost, total, menu, str1, i
if key == 'm' :
i=0
elif key == 'c' :
i=1
elif key == 'j' :
i=2
elif key == 'w' :
i=3
elif undo == 'u' :
i=-1
space = space+20
if i == -1 :
if len(order) > 0:
menu = order.pop(0)
menu.pop(item)
for i in range(len(menu)):
if menu[i] == str1 :
cost = cost - prices[i]
menu.pop(total)
str1 = "Cost : $" + str(cost)
total= text(str1, 350, 450)
else :
order.append(text( menu[i], 300, space+90))
cost = cost+prices[i]
str1 = "Cost : $" + str(cost)
total = text( str1, 360, 450)
python processing
add a comment |
trying to write a code where when a certain key is pressed, the word pops up on the canvas (in this case they are all drinks). When the user keeps pressing the certain keys to add a drink, the total cost adds up.
However, the only thing in my code the works is the word "water" and the total cost keeps overlaying.
How do I fix my code so that each menu item appears on the canvas and how to fix the total cost?
(I attempted to move the background colour around however it still did not work. Also this coding is from processing, and it is not java script)
def setup():
size (500, 500)
background (255)
menu = ["Mocha","Coffee","Juice","water"]
prices = [5,2,3,1]
order =
total = ''
cost = 0
Mocha = 5
Coffee = 2
Juice = 3
Water = 1
undo = -1
space = 0
i = 0
str1= 1
def draw():
global total
space = 100
fill (0)
line(250,0,250,500)
textSize (30)
text("Menu", 60, 50)
textSize (15)
for i in range(len(menu)):
str1 = menu[i] + " : $" + str(prices[i])
text(str1, 70, space)
space = space+20
textSize (30)
text( "Your Order:", 260,50)
textSize (15)
#total = text("Cost : $0", 300,450)
total= text(str1, 350, 450)
def keyPressed():
global space
global cost, total, menu, str1, i
if key == 'm' :
i=0
elif key == 'c' :
i=1
elif key == 'j' :
i=2
elif key == 'w' :
i=3
elif undo == 'u' :
i=-1
space = space+20
if i == -1 :
if len(order) > 0:
menu = order.pop(0)
menu.pop(item)
for i in range(len(menu)):
if menu[i] == str1 :
cost = cost - prices[i]
menu.pop(total)
str1 = "Cost : $" + str(cost)
total= text(str1, 350, 450)
else :
order.append(text( menu[i], 300, space+90))
cost = cost+prices[i]
str1 = "Cost : $" + str(cost)
total = text( str1, 360, 450)
python processing
The key which was pressed, when thekeyPressed
function is called, is contained in the system variablekey
. You have to compare the variablekey
to the character'm'
,'c'
,'j'
,'w'
and'u'
.
– Rabbid76
Nov 22 '18 at 20:03
okay so I just changed it to be if key =="j" but it still does not work
– Vex143
Nov 22 '18 at 20:59
add a comment |
trying to write a code where when a certain key is pressed, the word pops up on the canvas (in this case they are all drinks). When the user keeps pressing the certain keys to add a drink, the total cost adds up.
However, the only thing in my code the works is the word "water" and the total cost keeps overlaying.
How do I fix my code so that each menu item appears on the canvas and how to fix the total cost?
(I attempted to move the background colour around however it still did not work. Also this coding is from processing, and it is not java script)
def setup():
size (500, 500)
background (255)
menu = ["Mocha","Coffee","Juice","water"]
prices = [5,2,3,1]
order =
total = ''
cost = 0
Mocha = 5
Coffee = 2
Juice = 3
Water = 1
undo = -1
space = 0
i = 0
str1= 1
def draw():
global total
space = 100
fill (0)
line(250,0,250,500)
textSize (30)
text("Menu", 60, 50)
textSize (15)
for i in range(len(menu)):
str1 = menu[i] + " : $" + str(prices[i])
text(str1, 70, space)
space = space+20
textSize (30)
text( "Your Order:", 260,50)
textSize (15)
#total = text("Cost : $0", 300,450)
total= text(str1, 350, 450)
def keyPressed():
global space
global cost, total, menu, str1, i
if key == 'm' :
i=0
elif key == 'c' :
i=1
elif key == 'j' :
i=2
elif key == 'w' :
i=3
elif undo == 'u' :
i=-1
space = space+20
if i == -1 :
if len(order) > 0:
menu = order.pop(0)
menu.pop(item)
for i in range(len(menu)):
if menu[i] == str1 :
cost = cost - prices[i]
menu.pop(total)
str1 = "Cost : $" + str(cost)
total= text(str1, 350, 450)
else :
order.append(text( menu[i], 300, space+90))
cost = cost+prices[i]
str1 = "Cost : $" + str(cost)
total = text( str1, 360, 450)
python processing
trying to write a code where when a certain key is pressed, the word pops up on the canvas (in this case they are all drinks). When the user keeps pressing the certain keys to add a drink, the total cost adds up.
However, the only thing in my code the works is the word "water" and the total cost keeps overlaying.
How do I fix my code so that each menu item appears on the canvas and how to fix the total cost?
(I attempted to move the background colour around however it still did not work. Also this coding is from processing, and it is not java script)
def setup():
size (500, 500)
background (255)
menu = ["Mocha","Coffee","Juice","water"]
prices = [5,2,3,1]
order =
total = ''
cost = 0
Mocha = 5
Coffee = 2
Juice = 3
Water = 1
undo = -1
space = 0
i = 0
str1= 1
def draw():
global total
space = 100
fill (0)
line(250,0,250,500)
textSize (30)
text("Menu", 60, 50)
textSize (15)
for i in range(len(menu)):
str1 = menu[i] + " : $" + str(prices[i])
text(str1, 70, space)
space = space+20
textSize (30)
text( "Your Order:", 260,50)
textSize (15)
#total = text("Cost : $0", 300,450)
total= text(str1, 350, 450)
def keyPressed():
global space
global cost, total, menu, str1, i
if key == 'm' :
i=0
elif key == 'c' :
i=1
elif key == 'j' :
i=2
elif key == 'w' :
i=3
elif undo == 'u' :
i=-1
space = space+20
if i == -1 :
if len(order) > 0:
menu = order.pop(0)
menu.pop(item)
for i in range(len(menu)):
if menu[i] == str1 :
cost = cost - prices[i]
menu.pop(total)
str1 = "Cost : $" + str(cost)
total= text(str1, 350, 450)
else :
order.append(text( menu[i], 300, space+90))
cost = cost+prices[i]
str1 = "Cost : $" + str(cost)
total = text( str1, 360, 450)
python processing
python processing
edited Nov 22 '18 at 21:00
Vex143
asked Nov 22 '18 at 19:38
Vex143Vex143
62
62
The key which was pressed, when thekeyPressed
function is called, is contained in the system variablekey
. You have to compare the variablekey
to the character'm'
,'c'
,'j'
,'w'
and'u'
.
– Rabbid76
Nov 22 '18 at 20:03
okay so I just changed it to be if key =="j" but it still does not work
– Vex143
Nov 22 '18 at 20:59
add a comment |
The key which was pressed, when thekeyPressed
function is called, is contained in the system variablekey
. You have to compare the variablekey
to the character'm'
,'c'
,'j'
,'w'
and'u'
.
– Rabbid76
Nov 22 '18 at 20:03
okay so I just changed it to be if key =="j" but it still does not work
– Vex143
Nov 22 '18 at 20:59
The key which was pressed, when the
keyPressed
function is called, is contained in the system variable key
. You have to compare the variable key
to the character 'm'
, 'c'
, 'j'
, 'w'
and 'u'
.– Rabbid76
Nov 22 '18 at 20:03
The key which was pressed, when the
keyPressed
function is called, is contained in the system variable key
. You have to compare the variable key
to the character 'm'
, 'c'
, 'j'
, 'w'
and 'u'
.– Rabbid76
Nov 22 '18 at 20:03
okay so I just changed it to be if key =="j" but it still does not work
– Vex143
Nov 22 '18 at 20:59
okay so I just changed it to be if key =="j" but it still does not work
– Vex143
Nov 22 '18 at 20:59
add a comment |
1 Answer
1
active
oldest
votes
The total cost keeps overlaying itself because the stage is not being cleared between draw() loops. Add background(255)
at the top of the draw loop so that the stage is refreshed. Doing this however will introduce the need to loop through the order and draw its contents in the "Your Order:" section each loop.
You're getting name clashes with the variable i
, which is making your code perform oddly. Remove the i = 0
declaration near the top of your program. This fixes the "water"-only issue.
This needs to be changed: order.append(text( menu[i], 300, space+90))
. You can't add Processing draw (text()
) methods to an array like this.
Putting this all together (and a few more things) gives us this:
def setup():
size (500, 500)
background (255)
menu = ["Mocha","Coffee","Juice","Water"]
prices = [5,2,3,1]
order =
cost = 0
def draw():
background(255)
fill(0)
line(250,0,250,500)
textSize (30)
text("Menu", 60, 50)
space = 100
textSize (15)
for i in range(len(menu)):
str1 = menu[i] + " : $" + str(prices[i])
text(str1, 70, space)
space = space+20
textSize (30)
text( "Your Order:", 260,50)
textSize (15)
text("Cost : $" + str(cost), 350, 450)
for ypos, item in enumerate(order):
text(menu[item] + ".... $" + str(prices[item]), 270, ypos*20 + 80)
def keyPressed():
global cost, menu
if key == 'm' :
i=0
elif key == 'c' :
i=1
elif key == 'j' :
i=2
elif key == 'w' :
i=3
elif key == 'u' :
i=-1
else: # do nothing if the key is undefined
return
if i == -1 :
if len(order) > 0:
cost -= prices[order[-1]] # subtract cost
order.pop() # pop the order, not the menu!
else :
cost += prices[i]
order.append(i)
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
The total cost keeps overlaying itself because the stage is not being cleared between draw() loops. Add background(255)
at the top of the draw loop so that the stage is refreshed. Doing this however will introduce the need to loop through the order and draw its contents in the "Your Order:" section each loop.
You're getting name clashes with the variable i
, which is making your code perform oddly. Remove the i = 0
declaration near the top of your program. This fixes the "water"-only issue.
This needs to be changed: order.append(text( menu[i], 300, space+90))
. You can't add Processing draw (text()
) methods to an array like this.
Putting this all together (and a few more things) gives us this:
def setup():
size (500, 500)
background (255)
menu = ["Mocha","Coffee","Juice","Water"]
prices = [5,2,3,1]
order =
cost = 0
def draw():
background(255)
fill(0)
line(250,0,250,500)
textSize (30)
text("Menu", 60, 50)
space = 100
textSize (15)
for i in range(len(menu)):
str1 = menu[i] + " : $" + str(prices[i])
text(str1, 70, space)
space = space+20
textSize (30)
text( "Your Order:", 260,50)
textSize (15)
text("Cost : $" + str(cost), 350, 450)
for ypos, item in enumerate(order):
text(menu[item] + ".... $" + str(prices[item]), 270, ypos*20 + 80)
def keyPressed():
global cost, menu
if key == 'm' :
i=0
elif key == 'c' :
i=1
elif key == 'j' :
i=2
elif key == 'w' :
i=3
elif key == 'u' :
i=-1
else: # do nothing if the key is undefined
return
if i == -1 :
if len(order) > 0:
cost -= prices[order[-1]] # subtract cost
order.pop() # pop the order, not the menu!
else :
cost += prices[i]
order.append(i)
add a comment |
The total cost keeps overlaying itself because the stage is not being cleared between draw() loops. Add background(255)
at the top of the draw loop so that the stage is refreshed. Doing this however will introduce the need to loop through the order and draw its contents in the "Your Order:" section each loop.
You're getting name clashes with the variable i
, which is making your code perform oddly. Remove the i = 0
declaration near the top of your program. This fixes the "water"-only issue.
This needs to be changed: order.append(text( menu[i], 300, space+90))
. You can't add Processing draw (text()
) methods to an array like this.
Putting this all together (and a few more things) gives us this:
def setup():
size (500, 500)
background (255)
menu = ["Mocha","Coffee","Juice","Water"]
prices = [5,2,3,1]
order =
cost = 0
def draw():
background(255)
fill(0)
line(250,0,250,500)
textSize (30)
text("Menu", 60, 50)
space = 100
textSize (15)
for i in range(len(menu)):
str1 = menu[i] + " : $" + str(prices[i])
text(str1, 70, space)
space = space+20
textSize (30)
text( "Your Order:", 260,50)
textSize (15)
text("Cost : $" + str(cost), 350, 450)
for ypos, item in enumerate(order):
text(menu[item] + ".... $" + str(prices[item]), 270, ypos*20 + 80)
def keyPressed():
global cost, menu
if key == 'm' :
i=0
elif key == 'c' :
i=1
elif key == 'j' :
i=2
elif key == 'w' :
i=3
elif key == 'u' :
i=-1
else: # do nothing if the key is undefined
return
if i == -1 :
if len(order) > 0:
cost -= prices[order[-1]] # subtract cost
order.pop() # pop the order, not the menu!
else :
cost += prices[i]
order.append(i)
add a comment |
The total cost keeps overlaying itself because the stage is not being cleared between draw() loops. Add background(255)
at the top of the draw loop so that the stage is refreshed. Doing this however will introduce the need to loop through the order and draw its contents in the "Your Order:" section each loop.
You're getting name clashes with the variable i
, which is making your code perform oddly. Remove the i = 0
declaration near the top of your program. This fixes the "water"-only issue.
This needs to be changed: order.append(text( menu[i], 300, space+90))
. You can't add Processing draw (text()
) methods to an array like this.
Putting this all together (and a few more things) gives us this:
def setup():
size (500, 500)
background (255)
menu = ["Mocha","Coffee","Juice","Water"]
prices = [5,2,3,1]
order =
cost = 0
def draw():
background(255)
fill(0)
line(250,0,250,500)
textSize (30)
text("Menu", 60, 50)
space = 100
textSize (15)
for i in range(len(menu)):
str1 = menu[i] + " : $" + str(prices[i])
text(str1, 70, space)
space = space+20
textSize (30)
text( "Your Order:", 260,50)
textSize (15)
text("Cost : $" + str(cost), 350, 450)
for ypos, item in enumerate(order):
text(menu[item] + ".... $" + str(prices[item]), 270, ypos*20 + 80)
def keyPressed():
global cost, menu
if key == 'm' :
i=0
elif key == 'c' :
i=1
elif key == 'j' :
i=2
elif key == 'w' :
i=3
elif key == 'u' :
i=-1
else: # do nothing if the key is undefined
return
if i == -1 :
if len(order) > 0:
cost -= prices[order[-1]] # subtract cost
order.pop() # pop the order, not the menu!
else :
cost += prices[i]
order.append(i)
The total cost keeps overlaying itself because the stage is not being cleared between draw() loops. Add background(255)
at the top of the draw loop so that the stage is refreshed. Doing this however will introduce the need to loop through the order and draw its contents in the "Your Order:" section each loop.
You're getting name clashes with the variable i
, which is making your code perform oddly. Remove the i = 0
declaration near the top of your program. This fixes the "water"-only issue.
This needs to be changed: order.append(text( menu[i], 300, space+90))
. You can't add Processing draw (text()
) methods to an array like this.
Putting this all together (and a few more things) gives us this:
def setup():
size (500, 500)
background (255)
menu = ["Mocha","Coffee","Juice","Water"]
prices = [5,2,3,1]
order =
cost = 0
def draw():
background(255)
fill(0)
line(250,0,250,500)
textSize (30)
text("Menu", 60, 50)
space = 100
textSize (15)
for i in range(len(menu)):
str1 = menu[i] + " : $" + str(prices[i])
text(str1, 70, space)
space = space+20
textSize (30)
text( "Your Order:", 260,50)
textSize (15)
text("Cost : $" + str(cost), 350, 450)
for ypos, item in enumerate(order):
text(menu[item] + ".... $" + str(prices[item]), 270, ypos*20 + 80)
def keyPressed():
global cost, menu
if key == 'm' :
i=0
elif key == 'c' :
i=1
elif key == 'j' :
i=2
elif key == 'w' :
i=3
elif key == 'u' :
i=-1
else: # do nothing if the key is undefined
return
if i == -1 :
if len(order) > 0:
cost -= prices[order[-1]] # subtract cost
order.pop() # pop the order, not the menu!
else :
cost += prices[i]
order.append(i)
answered Nov 23 '18 at 15:25
![](https://i.stack.imgur.com/RsllH.jpg?s=32&g=1)
![](https://i.stack.imgur.com/RsllH.jpg?s=32&g=1)
micyclemicycle
649115
649115
add a comment |
add a comment |
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The key which was pressed, when the
keyPressed
function is called, is contained in the system variablekey
. You have to compare the variablekey
to the character'm'
,'c'
,'j'
,'w'
and'u'
.– Rabbid76
Nov 22 '18 at 20:03
okay so I just changed it to be if key =="j" but it still does not work
– Vex143
Nov 22 '18 at 20:59