What's wrong with my code?












-1












$begingroup$


I've written a simple code in c to convert Celsius to Fahrenheit:



#include<stdio.h>
int main(){

float cel, fah;

printf("Enter tempreture in celsius.n");
scanf("%f", &cel);


Please let me know if this question is off-topic here, because I' new to this community.
fah=cel*(9/5)+32;



printf("Tempreture in fahrenheit is:%.2fn", fah);

return 0;
}


The problem is in this part:



fah=cel*(9/5)+32;


When I run it, with 100 as input, I get 132 as result.The section(9/5) is not calculated. How can I fix it?



Please let me know if this question is off-topic here, because I am new to this community.










share|improve this question









New contributor




Codito ergo sum is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$

















    -1












    $begingroup$


    I've written a simple code in c to convert Celsius to Fahrenheit:



    #include<stdio.h>
    int main(){

    float cel, fah;

    printf("Enter tempreture in celsius.n");
    scanf("%f", &cel);


    Please let me know if this question is off-topic here, because I' new to this community.
    fah=cel*(9/5)+32;



    printf("Tempreture in fahrenheit is:%.2fn", fah);

    return 0;
    }


    The problem is in this part:



    fah=cel*(9/5)+32;


    When I run it, with 100 as input, I get 132 as result.The section(9/5) is not calculated. How can I fix it?



    Please let me know if this question is off-topic here, because I am new to this community.










    share|improve this question









    New contributor




    Codito ergo sum is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.







    $endgroup$















      -1












      -1








      -1





      $begingroup$


      I've written a simple code in c to convert Celsius to Fahrenheit:



      #include<stdio.h>
      int main(){

      float cel, fah;

      printf("Enter tempreture in celsius.n");
      scanf("%f", &cel);


      Please let me know if this question is off-topic here, because I' new to this community.
      fah=cel*(9/5)+32;



      printf("Tempreture in fahrenheit is:%.2fn", fah);

      return 0;
      }


      The problem is in this part:



      fah=cel*(9/5)+32;


      When I run it, with 100 as input, I get 132 as result.The section(9/5) is not calculated. How can I fix it?



      Please let me know if this question is off-topic here, because I am new to this community.










      share|improve this question









      New contributor




      Codito ergo sum is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.







      $endgroup$




      I've written a simple code in c to convert Celsius to Fahrenheit:



      #include<stdio.h>
      int main(){

      float cel, fah;

      printf("Enter tempreture in celsius.n");
      scanf("%f", &cel);


      Please let me know if this question is off-topic here, because I' new to this community.
      fah=cel*(9/5)+32;



      printf("Tempreture in fahrenheit is:%.2fn", fah);

      return 0;
      }


      The problem is in this part:



      fah=cel*(9/5)+32;


      When I run it, with 100 as input, I get 132 as result.The section(9/5) is not calculated. How can I fix it?



      Please let me know if this question is off-topic here, because I am new to this community.







      c






      share|improve this question









      New contributor




      Codito ergo sum is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      share|improve this question









      New contributor




      Codito ergo sum is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      share|improve this question




      share|improve this question








      edited 2 mins ago







      Codito ergo sum













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      Codito ergo sum is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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      asked 10 mins ago









      Codito ergo sumCodito ergo sum

      991




      991




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      New contributor





      Codito ergo sum is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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      Check out our Code of Conduct.






















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