Deleting Rows in Google Sheets when data only repeats in Column A
Using Google Sheets I have almost finished a macro to create heatsheets for swim meets, but I am having trouble getting rid of the duplicate names. The data only repeats in Column A, but I want to delete the entire row when Column A does have a repeat. So in the example below I need to delete Row 3, Row 7, and Row 8.
Name IM
James Smith 47.7
James Smith 48.27
Sally Baker 53.76
Katie Jones 57.63
Advay Shah 58.15
Sally Baker 58.65
Katie Jones 59.52
I am using the following lines of code (the spacing is wrong because I struggled with pasting into the post), but it's not doing anything when I run the macro. Obviously I have something incorrect.
function removeDuplicates() {
var sheet = SpreadsheetApp.getActiveSheet();
var data = sheet.getDataRange().getValues();
var newData = ;
for (i in data) {
var row = data[i];
var duplicate = false;
for (j in newData) {
if (row.join() == newData[j].join()) {
duplicate = true;
}
}
if (!duplicate) {
newData.push(row);
}
}
sheet.clearContents();
sheet.getRange(1, 1, newData.length, newData[0].length).setValues(newData);
}
google-apps-script google-sheets
add a comment |
Using Google Sheets I have almost finished a macro to create heatsheets for swim meets, but I am having trouble getting rid of the duplicate names. The data only repeats in Column A, but I want to delete the entire row when Column A does have a repeat. So in the example below I need to delete Row 3, Row 7, and Row 8.
Name IM
James Smith 47.7
James Smith 48.27
Sally Baker 53.76
Katie Jones 57.63
Advay Shah 58.15
Sally Baker 58.65
Katie Jones 59.52
I am using the following lines of code (the spacing is wrong because I struggled with pasting into the post), but it's not doing anything when I run the macro. Obviously I have something incorrect.
function removeDuplicates() {
var sheet = SpreadsheetApp.getActiveSheet();
var data = sheet.getDataRange().getValues();
var newData = ;
for (i in data) {
var row = data[i];
var duplicate = false;
for (j in newData) {
if (row.join() == newData[j].join()) {
duplicate = true;
}
}
if (!duplicate) {
newData.push(row);
}
}
sheet.clearContents();
sheet.getRange(1, 1, newData.length, newData[0].length).setValues(newData);
}
google-apps-script google-sheets
You want to remove the duplicated name. When there are the duplicated names, you want to leave the 1st one. If my understanding is correct, how about modifying fromif (row.join() == newData[j].join()) {
toif (row[0] == newData[j][0]) {
?0
ofrow[0]
andnewData[j][0]
means the column "A".
– Tanaike
Nov 20 at 22:31
For the heats to generate correctly, the entire row which contains the duplicated names has to be deleted, but yes it has to leave the first occurrence of the name. I will give that a shot!
– reylequan
Nov 21 at 19:28
Thank you for replying. I'm glad your issue was solved.
– Tanaike
Nov 21 at 23:31
add a comment |
Using Google Sheets I have almost finished a macro to create heatsheets for swim meets, but I am having trouble getting rid of the duplicate names. The data only repeats in Column A, but I want to delete the entire row when Column A does have a repeat. So in the example below I need to delete Row 3, Row 7, and Row 8.
Name IM
James Smith 47.7
James Smith 48.27
Sally Baker 53.76
Katie Jones 57.63
Advay Shah 58.15
Sally Baker 58.65
Katie Jones 59.52
I am using the following lines of code (the spacing is wrong because I struggled with pasting into the post), but it's not doing anything when I run the macro. Obviously I have something incorrect.
function removeDuplicates() {
var sheet = SpreadsheetApp.getActiveSheet();
var data = sheet.getDataRange().getValues();
var newData = ;
for (i in data) {
var row = data[i];
var duplicate = false;
for (j in newData) {
if (row.join() == newData[j].join()) {
duplicate = true;
}
}
if (!duplicate) {
newData.push(row);
}
}
sheet.clearContents();
sheet.getRange(1, 1, newData.length, newData[0].length).setValues(newData);
}
google-apps-script google-sheets
Using Google Sheets I have almost finished a macro to create heatsheets for swim meets, but I am having trouble getting rid of the duplicate names. The data only repeats in Column A, but I want to delete the entire row when Column A does have a repeat. So in the example below I need to delete Row 3, Row 7, and Row 8.
Name IM
James Smith 47.7
James Smith 48.27
Sally Baker 53.76
Katie Jones 57.63
Advay Shah 58.15
Sally Baker 58.65
Katie Jones 59.52
I am using the following lines of code (the spacing is wrong because I struggled with pasting into the post), but it's not doing anything when I run the macro. Obviously I have something incorrect.
function removeDuplicates() {
var sheet = SpreadsheetApp.getActiveSheet();
var data = sheet.getDataRange().getValues();
var newData = ;
for (i in data) {
var row = data[i];
var duplicate = false;
for (j in newData) {
if (row.join() == newData[j].join()) {
duplicate = true;
}
}
if (!duplicate) {
newData.push(row);
}
}
sheet.clearContents();
sheet.getRange(1, 1, newData.length, newData[0].length).setValues(newData);
}
google-apps-script google-sheets
google-apps-script google-sheets
asked Nov 20 at 22:16
reylequan
11
11
You want to remove the duplicated name. When there are the duplicated names, you want to leave the 1st one. If my understanding is correct, how about modifying fromif (row.join() == newData[j].join()) {
toif (row[0] == newData[j][0]) {
?0
ofrow[0]
andnewData[j][0]
means the column "A".
– Tanaike
Nov 20 at 22:31
For the heats to generate correctly, the entire row which contains the duplicated names has to be deleted, but yes it has to leave the first occurrence of the name. I will give that a shot!
– reylequan
Nov 21 at 19:28
Thank you for replying. I'm glad your issue was solved.
– Tanaike
Nov 21 at 23:31
add a comment |
You want to remove the duplicated name. When there are the duplicated names, you want to leave the 1st one. If my understanding is correct, how about modifying fromif (row.join() == newData[j].join()) {
toif (row[0] == newData[j][0]) {
?0
ofrow[0]
andnewData[j][0]
means the column "A".
– Tanaike
Nov 20 at 22:31
For the heats to generate correctly, the entire row which contains the duplicated names has to be deleted, but yes it has to leave the first occurrence of the name. I will give that a shot!
– reylequan
Nov 21 at 19:28
Thank you for replying. I'm glad your issue was solved.
– Tanaike
Nov 21 at 23:31
You want to remove the duplicated name. When there are the duplicated names, you want to leave the 1st one. If my understanding is correct, how about modifying from
if (row.join() == newData[j].join()) {
to if (row[0] == newData[j][0]) {
? 0
of row[0]
and newData[j][0]
means the column "A".– Tanaike
Nov 20 at 22:31
You want to remove the duplicated name. When there are the duplicated names, you want to leave the 1st one. If my understanding is correct, how about modifying from
if (row.join() == newData[j].join()) {
to if (row[0] == newData[j][0]) {
? 0
of row[0]
and newData[j][0]
means the column "A".– Tanaike
Nov 20 at 22:31
For the heats to generate correctly, the entire row which contains the duplicated names has to be deleted, but yes it has to leave the first occurrence of the name. I will give that a shot!
– reylequan
Nov 21 at 19:28
For the heats to generate correctly, the entire row which contains the duplicated names has to be deleted, but yes it has to leave the first occurrence of the name. I will give that a shot!
– reylequan
Nov 21 at 19:28
Thank you for replying. I'm glad your issue was solved.
– Tanaike
Nov 21 at 23:31
Thank you for replying. I'm glad your issue was solved.
– Tanaike
Nov 21 at 23:31
add a comment |
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You want to remove the duplicated name. When there are the duplicated names, you want to leave the 1st one. If my understanding is correct, how about modifying from
if (row.join() == newData[j].join()) {
toif (row[0] == newData[j][0]) {
?0
ofrow[0]
andnewData[j][0]
means the column "A".– Tanaike
Nov 20 at 22:31
For the heats to generate correctly, the entire row which contains the duplicated names has to be deleted, but yes it has to leave the first occurrence of the name. I will give that a shot!
– reylequan
Nov 21 at 19:28
Thank you for replying. I'm glad your issue was solved.
– Tanaike
Nov 21 at 23:31