factorial code giving alternate +ve and -ve output for number > 19, tried long long, didn't work
0
$begingroup$
`#include
int main(void) {
int fact = 1;
int num;
printf("Enter a numbern");
scanf("%d", &num);
while ( num > 0 ) {
fact=fact*num;
num=num-1;
}
printf("%dn", fact );
return 0;
}`
I tried using long long data type but it did not work and I was getting alternate +ve and -ve numbers as output
c
asked 10 mins ago
adarsh narayanadarsh narayan
1
New contributor
adarsh narayan is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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$endgroup$
add a comment |
0
$begingroup$
`#include
int main(void) {
int fact = 1;
int num;
printf("Enter a numbern");
scanf("%d", &num);
while ( num > 0 ) {
fact=fact*num;
num=num-1;
}
printf("%dn", fact );
return 0;
}`
I tried using long long data type but it did not work and I was getting alternate +ve and -ve numbers as output
c
asked 10 mins ago
adarsh narayanadarsh narayan
1
New contributor
adarsh narayan is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
0
0
0
$begingroup$
`#include
int main(void) {
int fact = 1;
int num;
printf("Enter a numbern");
scanf("%d", &num);
while ( num > 0 ) {
fact=fact*num;
num=num-1;
}
printf("%dn", fact );
return 0;
}`
I tried using long long data type but it did not work and I was getting alternate +ve and -ve numbers as output
c
asked 10 mins ago
adarsh narayanadarsh narayan
1
New contributor
adarsh narayan is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
`#include
int main(void) {
int fact = 1;
int num;
printf("Enter a numbern");
scanf("%d", &num);
while ( num > 0 ) {
fact=fact*num;
num=num-1;
}
printf("%dn", fact );
return 0;
}`
I tried using long long data type but it did not work and I was getting alternate +ve and -ve numbers as output
c
c
asked 10 mins ago
adarsh narayanadarsh narayan
1
New contributor
adarsh narayan is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 10 mins ago
adarsh narayanadarsh narayan
1
New contributor
adarsh narayan is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 10 mins ago
adarsh narayanadarsh narayan
1
New contributor
adarsh narayan is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 10 mins ago
adarsh narayanadarsh narayan
1
asked 10 mins ago
adarsh narayanadarsh narayan
1
1
New contributor
adarsh narayan is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
adarsh narayan is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
adarsh narayan is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
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