Form a string consisting of the common letters that appear in two input strings












0














The idea is to write a function that takes two strings and returns a new string that repeats in the previous two: examples:



'ABBA' & 'AOHB' => 'AB'
'cohs' & 'ohba' => 'oh'


A brute force solution would be nested for loops like so:






const x = 'ABCD'
const y = 'AHOB'

function subStr(str1, str2) {
let final = ''

for (let i = 0; i < str1.length; i++) {
for (let j = 0; j < str2.length; j++) {
if (str1[i] === str2[j]) {
final += str1[i]
}
}
}

return final
}



console.log(subStr(x, y)) // => AB












share|improve this question
























  • Could you clarify, with additional examples, what should happen when letters appear in different orders within the two input strings?
    – 200_success
    3 mins ago
















0














The idea is to write a function that takes two strings and returns a new string that repeats in the previous two: examples:



'ABBA' & 'AOHB' => 'AB'
'cohs' & 'ohba' => 'oh'


A brute force solution would be nested for loops like so:






const x = 'ABCD'
const y = 'AHOB'

function subStr(str1, str2) {
let final = ''

for (let i = 0; i < str1.length; i++) {
for (let j = 0; j < str2.length; j++) {
if (str1[i] === str2[j]) {
final += str1[i]
}
}
}

return final
}



console.log(subStr(x, y)) // => AB












share|improve this question
























  • Could you clarify, with additional examples, what should happen when letters appear in different orders within the two input strings?
    – 200_success
    3 mins ago














0












0








0







The idea is to write a function that takes two strings and returns a new string that repeats in the previous two: examples:



'ABBA' & 'AOHB' => 'AB'
'cohs' & 'ohba' => 'oh'


A brute force solution would be nested for loops like so:






const x = 'ABCD'
const y = 'AHOB'

function subStr(str1, str2) {
let final = ''

for (let i = 0; i < str1.length; i++) {
for (let j = 0; j < str2.length; j++) {
if (str1[i] === str2[j]) {
final += str1[i]
}
}
}

return final
}



console.log(subStr(x, y)) // => AB












share|improve this question















The idea is to write a function that takes two strings and returns a new string that repeats in the previous two: examples:



'ABBA' & 'AOHB' => 'AB'
'cohs' & 'ohba' => 'oh'


A brute force solution would be nested for loops like so:






const x = 'ABCD'
const y = 'AHOB'

function subStr(str1, str2) {
let final = ''

for (let i = 0; i < str1.length; i++) {
for (let j = 0; j < str2.length; j++) {
if (str1[i] === str2[j]) {
final += str1[i]
}
}
}

return final
}



console.log(subStr(x, y)) // => AB








const x = 'ABCD'
const y = 'AHOB'

function subStr(str1, str2) {
let final = ''

for (let i = 0; i < str1.length; i++) {
for (let j = 0; j < str2.length; j++) {
if (str1[i] === str2[j]) {
final += str1[i]
}
}
}

return final
}



console.log(subStr(x, y)) // => AB





const x = 'ABCD'
const y = 'AHOB'

function subStr(str1, str2) {
let final = ''

for (let i = 0; i < str1.length; i++) {
for (let j = 0; j < str2.length; j++) {
if (str1[i] === str2[j]) {
final += str1[i]
}
}
}

return final
}



console.log(subStr(x, y)) // => AB






javascript algorithm strings






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edited 5 mins ago









200_success

128k15150412




128k15150412










asked 47 mins ago









SakoBu

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  • Could you clarify, with additional examples, what should happen when letters appear in different orders within the two input strings?
    – 200_success
    3 mins ago


















  • Could you clarify, with additional examples, what should happen when letters appear in different orders within the two input strings?
    – 200_success
    3 mins ago
















Could you clarify, with additional examples, what should happen when letters appear in different orders within the two input strings?
– 200_success
3 mins ago




Could you clarify, with additional examples, what should happen when letters appear in different orders within the two input strings?
– 200_success
3 mins ago















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