ValueTuples lose their property names when serialized
While trying to serialize a named value tuple to JSON string, it loses the names assigned to items
(string type, string text) myTypes = ("A", "I am an animal");
var cnvValue = JsonConvert.SerializeObject(myTypes);
I am expecting the serialized value as
{"type":"A","text":"I am an animal"}
but the actual results are
{"Item1":"A","Item2":"I am an animal"}
There are two things that i am interested to know
- Why does it behave like that
- How to get the expected output
c# json.net tuples valuetuple
add a comment |
While trying to serialize a named value tuple to JSON string, it loses the names assigned to items
(string type, string text) myTypes = ("A", "I am an animal");
var cnvValue = JsonConvert.SerializeObject(myTypes);
I am expecting the serialized value as
{"type":"A","text":"I am an animal"}
but the actual results are
{"Item1":"A","Item2":"I am an animal"}
There are two things that i am interested to know
- Why does it behave like that
- How to get the expected output
c# json.net tuples valuetuple
FYI github.com/JamesNK/Newtonsoft.Json/issues/1505
– John
3 hours ago
add a comment |
While trying to serialize a named value tuple to JSON string, it loses the names assigned to items
(string type, string text) myTypes = ("A", "I am an animal");
var cnvValue = JsonConvert.SerializeObject(myTypes);
I am expecting the serialized value as
{"type":"A","text":"I am an animal"}
but the actual results are
{"Item1":"A","Item2":"I am an animal"}
There are two things that i am interested to know
- Why does it behave like that
- How to get the expected output
c# json.net tuples valuetuple
While trying to serialize a named value tuple to JSON string, it loses the names assigned to items
(string type, string text) myTypes = ("A", "I am an animal");
var cnvValue = JsonConvert.SerializeObject(myTypes);
I am expecting the serialized value as
{"type":"A","text":"I am an animal"}
but the actual results are
{"Item1":"A","Item2":"I am an animal"}
There are two things that i am interested to know
- Why does it behave like that
- How to get the expected output
c# json.net tuples valuetuple
c# json.net tuples valuetuple
edited 3 hours ago
Caius Jard
11.2k21138
11.2k21138
asked 3 hours ago
mdowesmdowes
597
597
FYI github.com/JamesNK/Newtonsoft.Json/issues/1505
– John
3 hours ago
add a comment |
FYI github.com/JamesNK/Newtonsoft.Json/issues/1505
– John
3 hours ago
FYI github.com/JamesNK/Newtonsoft.Json/issues/1505
– John
3 hours ago
FYI github.com/JamesNK/Newtonsoft.Json/issues/1505
– John
3 hours ago
add a comment |
2 Answers
2
active
oldest
votes
How to get the expected output
Something like this:
var myTypes = new{ type = "A", text = "I am an animal"};
var cnvValue = JsonConvert.SerializeObject(myTypes);
should work if you’re looking for a similarly terse approach. Doesn’t use ValueTuple
s (but anonymous types) under the hood though; this is my interpreting your question as “how can I produce this expected JSON without going to the full extent of declaring a class etc”
You interpreted it in the correct sense. I used ValueTuples to do exactly that.
– mdowes
2 hours ago
add a comment |
The names are a compiler trick. If you look at the definition for ValueTuple
you'll see that its field names are just Item1
, Item2
, etc.
Since JsonConvert.SerializeObject
was compiled well before you assigned names that you could use during your compilation, it cannot recover the names.
Method parameters/return types are decorated with attributes that indicate the names to be used when a method's signature includes ValueTuple
s. This allows code authored later to "see" the names by the compiler playing tricks again, but that's the "wrong way around" to be of much use here.
How to get the expected output
Introduce an explicit type, if the names of the fields/properties are so important.
Important to note that the explicit type could be an anonymous type.
– Avner Shahar-Kashtan
3 hours ago
2
@AvnerShahar-Kashtan Anonymous type are not explicit anyway
– Rahul
3 hours ago
I do not want to create an explicit type to use it only once. But still I want the names of items to appear in JSON string.
– mdowes
2 hours ago
If you want the better names, you need to at least use an anonymous type, or a named type.ValueTuple
will not help you, as you've seen.
– Lasse Vågsæther Karlsen
2 hours ago
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
How to get the expected output
Something like this:
var myTypes = new{ type = "A", text = "I am an animal"};
var cnvValue = JsonConvert.SerializeObject(myTypes);
should work if you’re looking for a similarly terse approach. Doesn’t use ValueTuple
s (but anonymous types) under the hood though; this is my interpreting your question as “how can I produce this expected JSON without going to the full extent of declaring a class etc”
You interpreted it in the correct sense. I used ValueTuples to do exactly that.
– mdowes
2 hours ago
add a comment |
How to get the expected output
Something like this:
var myTypes = new{ type = "A", text = "I am an animal"};
var cnvValue = JsonConvert.SerializeObject(myTypes);
should work if you’re looking for a similarly terse approach. Doesn’t use ValueTuple
s (but anonymous types) under the hood though; this is my interpreting your question as “how can I produce this expected JSON without going to the full extent of declaring a class etc”
You interpreted it in the correct sense. I used ValueTuples to do exactly that.
– mdowes
2 hours ago
add a comment |
How to get the expected output
Something like this:
var myTypes = new{ type = "A", text = "I am an animal"};
var cnvValue = JsonConvert.SerializeObject(myTypes);
should work if you’re looking for a similarly terse approach. Doesn’t use ValueTuple
s (but anonymous types) under the hood though; this is my interpreting your question as “how can I produce this expected JSON without going to the full extent of declaring a class etc”
How to get the expected output
Something like this:
var myTypes = new{ type = "A", text = "I am an animal"};
var cnvValue = JsonConvert.SerializeObject(myTypes);
should work if you’re looking for a similarly terse approach. Doesn’t use ValueTuple
s (but anonymous types) under the hood though; this is my interpreting your question as “how can I produce this expected JSON without going to the full extent of declaring a class etc”
edited 5 mins ago
Mafii
5,11212244
5,11212244
answered 3 hours ago
Caius JardCaius Jard
11.2k21138
11.2k21138
You interpreted it in the correct sense. I used ValueTuples to do exactly that.
– mdowes
2 hours ago
add a comment |
You interpreted it in the correct sense. I used ValueTuples to do exactly that.
– mdowes
2 hours ago
You interpreted it in the correct sense. I used ValueTuples to do exactly that.
– mdowes
2 hours ago
You interpreted it in the correct sense. I used ValueTuples to do exactly that.
– mdowes
2 hours ago
add a comment |
The names are a compiler trick. If you look at the definition for ValueTuple
you'll see that its field names are just Item1
, Item2
, etc.
Since JsonConvert.SerializeObject
was compiled well before you assigned names that you could use during your compilation, it cannot recover the names.
Method parameters/return types are decorated with attributes that indicate the names to be used when a method's signature includes ValueTuple
s. This allows code authored later to "see" the names by the compiler playing tricks again, but that's the "wrong way around" to be of much use here.
How to get the expected output
Introduce an explicit type, if the names of the fields/properties are so important.
Important to note that the explicit type could be an anonymous type.
– Avner Shahar-Kashtan
3 hours ago
2
@AvnerShahar-Kashtan Anonymous type are not explicit anyway
– Rahul
3 hours ago
I do not want to create an explicit type to use it only once. But still I want the names of items to appear in JSON string.
– mdowes
2 hours ago
If you want the better names, you need to at least use an anonymous type, or a named type.ValueTuple
will not help you, as you've seen.
– Lasse Vågsæther Karlsen
2 hours ago
add a comment |
The names are a compiler trick. If you look at the definition for ValueTuple
you'll see that its field names are just Item1
, Item2
, etc.
Since JsonConvert.SerializeObject
was compiled well before you assigned names that you could use during your compilation, it cannot recover the names.
Method parameters/return types are decorated with attributes that indicate the names to be used when a method's signature includes ValueTuple
s. This allows code authored later to "see" the names by the compiler playing tricks again, but that's the "wrong way around" to be of much use here.
How to get the expected output
Introduce an explicit type, if the names of the fields/properties are so important.
Important to note that the explicit type could be an anonymous type.
– Avner Shahar-Kashtan
3 hours ago
2
@AvnerShahar-Kashtan Anonymous type are not explicit anyway
– Rahul
3 hours ago
I do not want to create an explicit type to use it only once. But still I want the names of items to appear in JSON string.
– mdowes
2 hours ago
If you want the better names, you need to at least use an anonymous type, or a named type.ValueTuple
will not help you, as you've seen.
– Lasse Vågsæther Karlsen
2 hours ago
add a comment |
The names are a compiler trick. If you look at the definition for ValueTuple
you'll see that its field names are just Item1
, Item2
, etc.
Since JsonConvert.SerializeObject
was compiled well before you assigned names that you could use during your compilation, it cannot recover the names.
Method parameters/return types are decorated with attributes that indicate the names to be used when a method's signature includes ValueTuple
s. This allows code authored later to "see" the names by the compiler playing tricks again, but that's the "wrong way around" to be of much use here.
How to get the expected output
Introduce an explicit type, if the names of the fields/properties are so important.
The names are a compiler trick. If you look at the definition for ValueTuple
you'll see that its field names are just Item1
, Item2
, etc.
Since JsonConvert.SerializeObject
was compiled well before you assigned names that you could use during your compilation, it cannot recover the names.
Method parameters/return types are decorated with attributes that indicate the names to be used when a method's signature includes ValueTuple
s. This allows code authored later to "see" the names by the compiler playing tricks again, but that's the "wrong way around" to be of much use here.
How to get the expected output
Introduce an explicit type, if the names of the fields/properties are so important.
edited 3 hours ago
answered 3 hours ago
Damien_The_UnbelieverDamien_The_Unbeliever
194k17246334
194k17246334
Important to note that the explicit type could be an anonymous type.
– Avner Shahar-Kashtan
3 hours ago
2
@AvnerShahar-Kashtan Anonymous type are not explicit anyway
– Rahul
3 hours ago
I do not want to create an explicit type to use it only once. But still I want the names of items to appear in JSON string.
– mdowes
2 hours ago
If you want the better names, you need to at least use an anonymous type, or a named type.ValueTuple
will not help you, as you've seen.
– Lasse Vågsæther Karlsen
2 hours ago
add a comment |
Important to note that the explicit type could be an anonymous type.
– Avner Shahar-Kashtan
3 hours ago
2
@AvnerShahar-Kashtan Anonymous type are not explicit anyway
– Rahul
3 hours ago
I do not want to create an explicit type to use it only once. But still I want the names of items to appear in JSON string.
– mdowes
2 hours ago
If you want the better names, you need to at least use an anonymous type, or a named type.ValueTuple
will not help you, as you've seen.
– Lasse Vågsæther Karlsen
2 hours ago
Important to note that the explicit type could be an anonymous type.
– Avner Shahar-Kashtan
3 hours ago
Important to note that the explicit type could be an anonymous type.
– Avner Shahar-Kashtan
3 hours ago
2
2
@AvnerShahar-Kashtan Anonymous type are not explicit anyway
– Rahul
3 hours ago
@AvnerShahar-Kashtan Anonymous type are not explicit anyway
– Rahul
3 hours ago
I do not want to create an explicit type to use it only once. But still I want the names of items to appear in JSON string.
– mdowes
2 hours ago
I do not want to create an explicit type to use it only once. But still I want the names of items to appear in JSON string.
– mdowes
2 hours ago
If you want the better names, you need to at least use an anonymous type, or a named type.
ValueTuple
will not help you, as you've seen.– Lasse Vågsæther Karlsen
2 hours ago
If you want the better names, you need to at least use an anonymous type, or a named type.
ValueTuple
will not help you, as you've seen.– Lasse Vågsæther Karlsen
2 hours ago
add a comment |
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FYI github.com/JamesNK/Newtonsoft.Json/issues/1505
– John
3 hours ago