Show variable as a text in php
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i'm having trouble showing the text ip4=$(/sbin/ip -o -4 addr list eth0 | awk '{print $4}' | cut -d/ -f1)
in PHP
$shpmtaserver .= "ip4=$(/sbin/ip -o -4 addr list eth0 | awk '{print $4}' | cut -d/ -f1)" . "n";
Any ideas to do this ?
php shell
add a comment |
up vote
-2
down vote
favorite
i'm having trouble showing the text ip4=$(/sbin/ip -o -4 addr list eth0 | awk '{print $4}' | cut -d/ -f1)
in PHP
$shpmtaserver .= "ip4=$(/sbin/ip -o -4 addr list eth0 | awk '{print $4}' | cut -d/ -f1)" . "n";
Any ideas to do this ?
php shell
1
The code you've posted doesn't do anything except append to a string, but it should at least do that correctly. What exactly are you expecting to happen?
– iainn
Nov 20 at 13:50
add a comment |
up vote
-2
down vote
favorite
up vote
-2
down vote
favorite
i'm having trouble showing the text ip4=$(/sbin/ip -o -4 addr list eth0 | awk '{print $4}' | cut -d/ -f1)
in PHP
$shpmtaserver .= "ip4=$(/sbin/ip -o -4 addr list eth0 | awk '{print $4}' | cut -d/ -f1)" . "n";
Any ideas to do this ?
php shell
i'm having trouble showing the text ip4=$(/sbin/ip -o -4 addr list eth0 | awk '{print $4}' | cut -d/ -f1)
in PHP
$shpmtaserver .= "ip4=$(/sbin/ip -o -4 addr list eth0 | awk '{print $4}' | cut -d/ -f1)" . "n";
Any ideas to do this ?
php shell
php shell
edited Nov 20 at 13:44
Funk Forty Niner
80.5k1247100
80.5k1247100
asked Nov 20 at 13:38
Ali EL KANDOUSSI
41
41
1
The code you've posted doesn't do anything except append to a string, but it should at least do that correctly. What exactly are you expecting to happen?
– iainn
Nov 20 at 13:50
add a comment |
1
The code you've posted doesn't do anything except append to a string, but it should at least do that correctly. What exactly are you expecting to happen?
– iainn
Nov 20 at 13:50
1
1
The code you've posted doesn't do anything except append to a string, but it should at least do that correctly. What exactly are you expecting to happen?
– iainn
Nov 20 at 13:50
The code you've posted doesn't do anything except append to a string, but it should at least do that correctly. What exactly are you expecting to happen?
– iainn
Nov 20 at 13:50
add a comment |
1 Answer
1
active
oldest
votes
up vote
0
down vote
Try removing the .
in front of .=
. You would use that to append to an existing variable.
The follow code should work just fine.
$shpmtaserver = "ip4=$(/sbin/ip -o -4 addr list eth0 | awk '{print $4}' | cut -d/ -f1)" . "n";
echo $shpmtaserver;
add a comment |
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1 Answer
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
Try removing the .
in front of .=
. You would use that to append to an existing variable.
The follow code should work just fine.
$shpmtaserver = "ip4=$(/sbin/ip -o -4 addr list eth0 | awk '{print $4}' | cut -d/ -f1)" . "n";
echo $shpmtaserver;
add a comment |
up vote
0
down vote
Try removing the .
in front of .=
. You would use that to append to an existing variable.
The follow code should work just fine.
$shpmtaserver = "ip4=$(/sbin/ip -o -4 addr list eth0 | awk '{print $4}' | cut -d/ -f1)" . "n";
echo $shpmtaserver;
add a comment |
up vote
0
down vote
up vote
0
down vote
Try removing the .
in front of .=
. You would use that to append to an existing variable.
The follow code should work just fine.
$shpmtaserver = "ip4=$(/sbin/ip -o -4 addr list eth0 | awk '{print $4}' | cut -d/ -f1)" . "n";
echo $shpmtaserver;
Try removing the .
in front of .=
. You would use that to append to an existing variable.
The follow code should work just fine.
$shpmtaserver = "ip4=$(/sbin/ip -o -4 addr list eth0 | awk '{print $4}' | cut -d/ -f1)" . "n";
echo $shpmtaserver;
answered Nov 20 at 13:41
Dirk Scholten
574217
574217
add a comment |
add a comment |
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1
The code you've posted doesn't do anything except append to a string, but it should at least do that correctly. What exactly are you expecting to happen?
– iainn
Nov 20 at 13:50