Simple Android Volley login request
Multi tool use
0
$begingroup$
I've made a simple login API request which gets a token as a response. I had to use Toast a few times. Is is possible to make it with only two Toasts Successful/Failed?
public void login(View view){
RequestQueue queue = Volley.newRequestQueue(this);
String URL = "http://10.0.2.2:8000/api/login";
StringRequest request = new StringRequest(Request.Method.POST, URL,
new Response.Listener<String>()
{
@Override
public void onResponse(String response) {
try {
JSONObject jsonObj = new JSONObject(response);
myToken =jsonObj.getString("token");
if (myToken != ""){
Toast.makeText(getApplicationContext(), "Login successfull !", Toast.LENGTH_LONG).show();
} else {
Toast.makeText(getApplicationContext(), "Ooops something is not correct !", Toast.LENGTH_LONG).show();
}
} catch (JSONException e) {
myToken = "";
Toast.makeText(getApplicationContext(), "Ooops something is not correct !", Toast.LENGTH_LONG).show();
e.printStackTrace();
}
}
},
new Response.ErrorListener()
{
@Override
public void onErrorResponse(VolleyError error) {
myToken = "";
Toast.makeText(getApplicationContext(), "Ooops something is not correct !", Toast.LENGTH_LONG).show();
NetworkResponse response = error.networkResponse;
String errorMsg = "";
if(response != null && response.data != null){
String errorString = new String(response.data);
}
}
}
) {
@Override
protected Map<String, String> getParams()
{
Map<String, String> params = new HashMap<String, String>();
TextInputEditText mail = findViewById(R.id.textInputEditTextEmail);
TextInputEditText pw = findViewById(R.id.textInputEditTextPassword);
params.put("email", mail.getText().toString());
params.put("password", pw.getText().toString());
return params;
}
};
queue.add(request);
}
java android authentication
edited 19 mins ago
Jamal♦
30.3k11117227
asked 9 hours ago
Programer AnelProgramer Anel
1
New contributor
Programer Anel is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
0
$begingroup$
I've made a simple login API request which gets a token as a response. I had to use Toast a few times. Is is possible to make it with only two Toasts Successful/Failed?
public void login(View view){
RequestQueue queue = Volley.newRequestQueue(this);
String URL = "http://10.0.2.2:8000/api/login";
StringRequest request = new StringRequest(Request.Method.POST, URL,
new Response.Listener<String>()
{
@Override
public void onResponse(String response) {
try {
JSONObject jsonObj = new JSONObject(response);
myToken =jsonObj.getString("token");
if (myToken != ""){
Toast.makeText(getApplicationContext(), "Login successfull !", Toast.LENGTH_LONG).show();
} else {
Toast.makeText(getApplicationContext(), "Ooops something is not correct !", Toast.LENGTH_LONG).show();
}
} catch (JSONException e) {
myToken = "";
Toast.makeText(getApplicationContext(), "Ooops something is not correct !", Toast.LENGTH_LONG).show();
e.printStackTrace();
}
}
},
new Response.ErrorListener()
{
@Override
public void onErrorResponse(VolleyError error) {
myToken = "";
Toast.makeText(getApplicationContext(), "Ooops something is not correct !", Toast.LENGTH_LONG).show();
NetworkResponse response = error.networkResponse;
String errorMsg = "";
if(response != null && response.data != null){
String errorString = new String(response.data);
}
}
}
) {
@Override
protected Map<String, String> getParams()
{
Map<String, String> params = new HashMap<String, String>();
TextInputEditText mail = findViewById(R.id.textInputEditTextEmail);
TextInputEditText pw = findViewById(R.id.textInputEditTextPassword);
params.put("email", mail.getText().toString());
params.put("password", pw.getText().toString());
return params;
}
};
queue.add(request);
}
java android authentication
edited 19 mins ago
Jamal♦
30.3k11117227
asked 9 hours ago
Programer AnelProgramer Anel
1
New contributor
Programer Anel is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
0
0
0
$begingroup$
I've made a simple login API request which gets a token as a response. I had to use Toast a few times. Is is possible to make it with only two Toasts Successful/Failed?
public void login(View view){
RequestQueue queue = Volley.newRequestQueue(this);
String URL = "http://10.0.2.2:8000/api/login";
StringRequest request = new StringRequest(Request.Method.POST, URL,
new Response.Listener<String>()
{
@Override
public void onResponse(String response) {
try {
JSONObject jsonObj = new JSONObject(response);
myToken =jsonObj.getString("token");
if (myToken != ""){
Toast.makeText(getApplicationContext(), "Login successfull !", Toast.LENGTH_LONG).show();
} else {
Toast.makeText(getApplicationContext(), "Ooops something is not correct !", Toast.LENGTH_LONG).show();
}
} catch (JSONException e) {
myToken = "";
Toast.makeText(getApplicationContext(), "Ooops something is not correct !", Toast.LENGTH_LONG).show();
e.printStackTrace();
}
}
},
new Response.ErrorListener()
{
@Override
public void onErrorResponse(VolleyError error) {
myToken = "";
Toast.makeText(getApplicationContext(), "Ooops something is not correct !", Toast.LENGTH_LONG).show();
NetworkResponse response = error.networkResponse;
String errorMsg = "";
if(response != null && response.data != null){
String errorString = new String(response.data);
}
}
}
) {
@Override
protected Map<String, String> getParams()
{
Map<String, String> params = new HashMap<String, String>();
TextInputEditText mail = findViewById(R.id.textInputEditTextEmail);
TextInputEditText pw = findViewById(R.id.textInputEditTextPassword);
params.put("email", mail.getText().toString());
params.put("password", pw.getText().toString());
return params;
}
};
queue.add(request);
}
java android authentication
edited 19 mins ago
Jamal♦
30.3k11117227
asked 9 hours ago
Programer AnelProgramer Anel
1
New contributor
Programer Anel is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
I've made a simple login API request which gets a token as a response. I had to use Toast a few times. Is is possible to make it with only two Toasts Successful/Failed?
public void login(View view){
RequestQueue queue = Volley.newRequestQueue(this);
String URL = "http://10.0.2.2:8000/api/login";
StringRequest request = new StringRequest(Request.Method.POST, URL,
new Response.Listener<String>()
{
@Override
public void onResponse(String response) {
try {
JSONObject jsonObj = new JSONObject(response);
myToken =jsonObj.getString("token");
if (myToken != ""){
Toast.makeText(getApplicationContext(), "Login successfull !", Toast.LENGTH_LONG).show();
} else {
Toast.makeText(getApplicationContext(), "Ooops something is not correct !", Toast.LENGTH_LONG).show();
}
} catch (JSONException e) {
myToken = "";
Toast.makeText(getApplicationContext(), "Ooops something is not correct !", Toast.LENGTH_LONG).show();
e.printStackTrace();
}
}
},
new Response.ErrorListener()
{
@Override
public void onErrorResponse(VolleyError error) {
myToken = "";
Toast.makeText(getApplicationContext(), "Ooops something is not correct !", Toast.LENGTH_LONG).show();
NetworkResponse response = error.networkResponse;
String errorMsg = "";
if(response != null && response.data != null){
String errorString = new String(response.data);
}
}
}
) {
@Override
protected Map<String, String> getParams()
{
Map<String, String> params = new HashMap<String, String>();
TextInputEditText mail = findViewById(R.id.textInputEditTextEmail);
TextInputEditText pw = findViewById(R.id.textInputEditTextPassword);
params.put("email", mail.getText().toString());
params.put("password", pw.getText().toString());
return params;
}
};
queue.add(request);
}
java android authentication
java android authentication
edited 19 mins ago
Jamal♦
30.3k11117227
asked 9 hours ago
Programer AnelProgramer Anel
1
New contributor
Programer Anel is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 19 mins ago
Jamal♦
30.3k11117227
asked 9 hours ago
Programer AnelProgramer Anel
1
New contributor
Programer Anel is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 19 mins ago
Jamal♦
30.3k11117227
edited 19 mins ago
Jamal♦
30.3k11117227
edited 19 mins ago
Jamal♦
30.3k11117227
30.3k11117227
asked 9 hours ago
Programer AnelProgramer Anel
1
New contributor
Programer Anel is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 9 hours ago
Programer AnelProgramer Anel
1
asked 9 hours ago
Programer AnelProgramer Anel
1
1
New contributor
Programer Anel is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Programer Anel is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Programer Anel is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
1
$begingroup$
You can use a variable and assume that it will fail, if you do not print the new message
public void login(View view){
RequestQueue queue = Volley.newRequestQueue(this);
String URL = "http://10.0.2.2:8000/api/login";
StringRequest request = new StringRequest(Request.Method.POST, URL,
new Response.Listener<String>()
{
@Override
public void onResponse(String response) {
String loginMsg = "Ooops something is not correct !";
try {
JSONObject jsonObj = new JSONObject(response);
myToken =jsonObj.getString("token");
if (myToken != ""){
loginMsg = "Login successfull !"
}
} catch (JSONException e) {
myToken = "";
e.printStackTrace();
}
Toast.makeText(getApplicationContext(), loginMsg, Toast.LENGTH_LONG).show();
}
},
new Response.ErrorListener()
{
@Override
public void onErrorResponse(VolleyError error) {
myToken = "";
Toast.makeText(getApplicationContext(), "Ooops something is not correct !", Toast.LENGTH_LONG).show();
NetworkResponse response = error.networkResponse;
String errorMsg = "";
if(response != null && response.data != null){
String errorString = new String(response.data);
}
}
}
) {
@Override
protected Map<String, String> getParams()
{
Map<String, String> params = new HashMap<String, String>();
TextInputEditText mail = findViewById(R.id.textInputEditTextEmail);
TextInputEditText pw = findViewById(R.id.textInputEditTextPassword);
params.put("email", mail.getText().toString());
params.put("password", pw.getText().toString());
return params;
}
};
queue.add(request);
}
answered 6 hours ago
Tlaloc-ESTlaloc-ES
111
New contributor
Tlaloc-ES is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["\$", "\$"]]);
});
});
}, "mathjax-editing");
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "196"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Programer Anel is a new contributor. Be nice, and check out our Code of Conduct.
draft saved
draft discarded
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fcodereview.stackexchange.com%2fquestions%2f212771%2fsimple-android-volley-login-request%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
$begingroup$
You can use a variable and assume that it will fail, if you do not print the new message
public void login(View view){
RequestQueue queue = Volley.newRequestQueue(this);
String URL = "http://10.0.2.2:8000/api/login";
StringRequest request = new StringRequest(Request.Method.POST, URL,
new Response.Listener<String>()
{
@Override
public void onResponse(String response) {
String loginMsg = "Ooops something is not correct !";
try {
JSONObject jsonObj = new JSONObject(response);
myToken =jsonObj.getString("token");
if (myToken != ""){
loginMsg = "Login successfull !"
}
} catch (JSONException e) {
myToken = "";
e.printStackTrace();
}
Toast.makeText(getApplicationContext(), loginMsg, Toast.LENGTH_LONG).show();
}
},
new Response.ErrorListener()
{
@Override
public void onErrorResponse(VolleyError error) {
myToken = "";
Toast.makeText(getApplicationContext(), "Ooops something is not correct !", Toast.LENGTH_LONG).show();
NetworkResponse response = error.networkResponse;
String errorMsg = "";
if(response != null && response.data != null){
String errorString = new String(response.data);
}
}
}
) {
@Override
protected Map<String, String> getParams()
{
Map<String, String> params = new HashMap<String, String>();
TextInputEditText mail = findViewById(R.id.textInputEditTextEmail);
TextInputEditText pw = findViewById(R.id.textInputEditTextPassword);
params.put("email", mail.getText().toString());
params.put("password", pw.getText().toString());
return params;
}
};
queue.add(request);
}
answered 6 hours ago
Tlaloc-ESTlaloc-ES
111
New contributor
Tlaloc-ES is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
1
$begingroup$
You can use a variable and assume that it will fail, if you do not print the new message
public void login(View view){
RequestQueue queue = Volley.newRequestQueue(this);
String URL = "http://10.0.2.2:8000/api/login";
StringRequest request = new StringRequest(Request.Method.POST, URL,
new Response.Listener<String>()
{
@Override
public void onResponse(String response) {
String loginMsg = "Ooops something is not correct !";
try {
JSONObject jsonObj = new JSONObject(response);
myToken =jsonObj.getString("token");
if (myToken != ""){
loginMsg = "Login successfull !"
}
} catch (JSONException e) {
myToken = "";
e.printStackTrace();
}
Toast.makeText(getApplicationContext(), loginMsg, Toast.LENGTH_LONG).show();
}
},
new Response.ErrorListener()
{
@Override
public void onErrorResponse(VolleyError error) {
myToken = "";
Toast.makeText(getApplicationContext(), "Ooops something is not correct !", Toast.LENGTH_LONG).show();
NetworkResponse response = error.networkResponse;
String errorMsg = "";
if(response != null && response.data != null){
String errorString = new String(response.data);
}
}
}
) {
@Override
protected Map<String, String> getParams()
{
Map<String, String> params = new HashMap<String, String>();
TextInputEditText mail = findViewById(R.id.textInputEditTextEmail);
TextInputEditText pw = findViewById(R.id.textInputEditTextPassword);
params.put("email", mail.getText().toString());
params.put("password", pw.getText().toString());
return params;
}
};
queue.add(request);
}
answered 6 hours ago
Tlaloc-ESTlaloc-ES
111
New contributor
Tlaloc-ES is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
1
1
1
$begingroup$
You can use a variable and assume that it will fail, if you do not print the new message
public void login(View view){
RequestQueue queue = Volley.newRequestQueue(this);
String URL = "http://10.0.2.2:8000/api/login";
StringRequest request = new StringRequest(Request.Method.POST, URL,
new Response.Listener<String>()
{
@Override
public void onResponse(String response) {
String loginMsg = "Ooops something is not correct !";
try {
JSONObject jsonObj = new JSONObject(response);
myToken =jsonObj.getString("token");
if (myToken != ""){
loginMsg = "Login successfull !"
}
} catch (JSONException e) {
myToken = "";
e.printStackTrace();
}
Toast.makeText(getApplicationContext(), loginMsg, Toast.LENGTH_LONG).show();
}
},
new Response.ErrorListener()
{
@Override
public void onErrorResponse(VolleyError error) {
myToken = "";
Toast.makeText(getApplicationContext(), "Ooops something is not correct !", Toast.LENGTH_LONG).show();
NetworkResponse response = error.networkResponse;
String errorMsg = "";
if(response != null && response.data != null){
String errorString = new String(response.data);
}
}
}
) {
@Override
protected Map<String, String> getParams()
{
Map<String, String> params = new HashMap<String, String>();
TextInputEditText mail = findViewById(R.id.textInputEditTextEmail);
TextInputEditText pw = findViewById(R.id.textInputEditTextPassword);
params.put("email", mail.getText().toString());
params.put("password", pw.getText().toString());
return params;
}
};
queue.add(request);
}
answered 6 hours ago
Tlaloc-ESTlaloc-ES
111
New contributor
Tlaloc-ES is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
You can use a variable and assume that it will fail, if you do not print the new message
public void login(View view){
RequestQueue queue = Volley.newRequestQueue(this);
String URL = "http://10.0.2.2:8000/api/login";
StringRequest request = new StringRequest(Request.Method.POST, URL,
new Response.Listener<String>()
{
@Override
public void onResponse(String response) {
String loginMsg = "Ooops something is not correct !";
try {
JSONObject jsonObj = new JSONObject(response);
myToken =jsonObj.getString("token");
if (myToken != ""){
loginMsg = "Login successfull !"
}
} catch (JSONException e) {
myToken = "";
e.printStackTrace();
}
Toast.makeText(getApplicationContext(), loginMsg, Toast.LENGTH_LONG).show();
}
},
new Response.ErrorListener()
{
@Override
public void onErrorResponse(VolleyError error) {
myToken = "";
Toast.makeText(getApplicationContext(), "Ooops something is not correct !", Toast.LENGTH_LONG).show();
NetworkResponse response = error.networkResponse;
String errorMsg = "";
if(response != null && response.data != null){
String errorString = new String(response.data);
}
}
}
) {
@Override
protected Map<String, String> getParams()
{
Map<String, String> params = new HashMap<String, String>();
TextInputEditText mail = findViewById(R.id.textInputEditTextEmail);
TextInputEditText pw = findViewById(R.id.textInputEditTextPassword);
params.put("email", mail.getText().toString());
params.put("password", pw.getText().toString());
return params;
}
};
queue.add(request);
}
answered 6 hours ago
Tlaloc-ESTlaloc-ES
111
New contributor
Tlaloc-ES is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered 6 hours ago
Tlaloc-ESTlaloc-ES
111
New contributor
Tlaloc-ES is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered 6 hours ago
Tlaloc-ESTlaloc-ES
111
answered 6 hours ago
Tlaloc-ESTlaloc-ES
111
111
New contributor
Tlaloc-ES is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Tlaloc-ES is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Tlaloc-ES is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
Programer Anel is a new contributor. Be nice, and check out our Code of Conduct.
draft saved
draft discarded
Programer Anel is a new contributor. Be nice, and check out our Code of Conduct.
Programer Anel is a new contributor. Be nice, and check out our Code of Conduct.
Programer Anel is a new contributor. Be nice, and check out our Code of Conduct.
Thanks for contributing an answer to Code Review Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
draft saved
draft discarded
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fcodereview.stackexchange.com%2fquestions%2f212771%2fsimple-android-volley-login-request%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
h acXvMD4XG4ibYE hysTQMX 7U,M DVdq7x b75d1DcFd,q2w2zJ2cHa7u2 GOmQxJT
