How does the Pauli exclusion work on fermions but not on bosons?
$begingroup$
How does fractional spin effect the symmetry of combined wavefunctions?
Why is Planck constant the universal anchor for determining if a particle is a Boson or a Fermion?
quantum-mechanics quantum-spin pauli-exclusion-principle
edited Nov 24 '18 at 8:41
Blazar
12811
asked Nov 24 '18 at 8:27
Naama-selaNaama-sela
195
$endgroup$
add a comment |
$begingroup$
How does fractional spin effect the symmetry of combined wavefunctions?
Why is Planck constant the universal anchor for determining if a particle is a Boson or a Fermion?
quantum-mechanics quantum-spin pauli-exclusion-principle
edited Nov 24 '18 at 8:41
Blazar
12811
asked Nov 24 '18 at 8:27
Naama-selaNaama-sela
195
$endgroup$
add a comment |
$begingroup$
How does fractional spin effect the symmetry of combined wavefunctions?
Why is Planck constant the universal anchor for determining if a particle is a Boson or a Fermion?
quantum-mechanics quantum-spin pauli-exclusion-principle
edited Nov 24 '18 at 8:41
Blazar
12811
asked Nov 24 '18 at 8:27
Naama-selaNaama-sela
195
$endgroup$
How does fractional spin effect the symmetry of combined wavefunctions?
Why is Planck constant the universal anchor for determining if a particle is a Boson or a Fermion?
quantum-mechanics quantum-spin pauli-exclusion-principle
quantum-mechanics quantum-spin pauli-exclusion-principle
edited Nov 24 '18 at 8:41
Blazar
12811
asked Nov 24 '18 at 8:27
Naama-selaNaama-sela
195
edited Nov 24 '18 at 8:41
Blazar
12811
asked Nov 24 '18 at 8:27
Naama-selaNaama-sela
195
edited Nov 24 '18 at 8:41
Blazar
12811
edited Nov 24 '18 at 8:41
Blazar
12811
edited Nov 24 '18 at 8:41
Blazar
12811
12811
asked Nov 24 '18 at 8:27
Naama-selaNaama-sela
195
asked Nov 24 '18 at 8:27
Naama-selaNaama-sela
195
asked Nov 24 '18 at 8:27
Naama-selaNaama-sela
195
195
add a comment |
add a comment |
1 Answer
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The relation between spin and the exclusion principle is called the spin statistics theorem, but I don't think there is an elementary explanation for it (other than doing the math).
Plancks constant does not determine if a particle is a boson or a fermion
answered Nov 24 '18 at 9:03
yankylyankyl
836
$endgroup$
1
$begingroup$
There is the elementary handwaving that exchanging two particles is half a rotation. At least in 3D, a full rotation gives the state that one started with, but in 2D one can have anyons (fractional quantum Hall effect).
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– Pieter
Nov 24 '18 at 12:14
add a comment |
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1 Answer
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active
oldest
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1 Answer
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active
oldest
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active
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votes
$begingroup$
The relation between spin and the exclusion principle is called the spin statistics theorem, but I don't think there is an elementary explanation for it (other than doing the math).
Plancks constant does not determine if a particle is a boson or a fermion
answered Nov 24 '18 at 9:03
yankylyankyl
836
$endgroup$
1
$begingroup$
There is the elementary handwaving that exchanging two particles is half a rotation. At least in 3D, a full rotation gives the state that one started with, but in 2D one can have anyons (fractional quantum Hall effect).
$endgroup$
– Pieter
Nov 24 '18 at 12:14
add a comment |
$begingroup$
The relation between spin and the exclusion principle is called the spin statistics theorem, but I don't think there is an elementary explanation for it (other than doing the math).
Plancks constant does not determine if a particle is a boson or a fermion
answered Nov 24 '18 at 9:03
yankylyankyl
836
$endgroup$
1
$begingroup$
There is the elementary handwaving that exchanging two particles is half a rotation. At least in 3D, a full rotation gives the state that one started with, but in 2D one can have anyons (fractional quantum Hall effect).
$endgroup$
– Pieter
Nov 24 '18 at 12:14
add a comment |
$begingroup$
The relation between spin and the exclusion principle is called the spin statistics theorem, but I don't think there is an elementary explanation for it (other than doing the math).
Plancks constant does not determine if a particle is a boson or a fermion
answered Nov 24 '18 at 9:03
yankylyankyl
836
$endgroup$
The relation between spin and the exclusion principle is called the spin statistics theorem, but I don't think there is an elementary explanation for it (other than doing the math).
Plancks constant does not determine if a particle is a boson or a fermion
answered Nov 24 '18 at 9:03
yankylyankyl
836
answered Nov 24 '18 at 9:03
yankylyankyl
836
answered Nov 24 '18 at 9:03
yankylyankyl
836
answered Nov 24 '18 at 9:03
yankylyankyl
836
836
1
$begingroup$
There is the elementary handwaving that exchanging two particles is half a rotation. At least in 3D, a full rotation gives the state that one started with, but in 2D one can have anyons (fractional quantum Hall effect).
$endgroup$
– Pieter
Nov 24 '18 at 12:14
add a comment |
1
$begingroup$
There is the elementary handwaving that exchanging two particles is half a rotation. At least in 3D, a full rotation gives the state that one started with, but in 2D one can have anyons (fractional quantum Hall effect).
$endgroup$
– Pieter
Nov 24 '18 at 12:14
1
1
$begingroup$
There is the elementary handwaving that exchanging two particles is half a rotation. At least in 3D, a full rotation gives the state that one started with, but in 2D one can have anyons (fractional quantum Hall effect).
$endgroup$
– Pieter
Nov 24 '18 at 12:14
$begingroup$
There is the elementary handwaving that exchanging two particles is half a rotation. At least in 3D, a full rotation gives the state that one started with, but in 2D one can have anyons (fractional quantum Hall effect).
$endgroup$
– Pieter
Nov 24 '18 at 12:14
add a comment |
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