Type of included data is null with JsonApiSerializer in Fractal
This is what I get at the moment with Fractal's JsonApiSerializer of Fractal in Laravel:
{
"type": "projects",
"id": "18",
"attributes": {
"name": "pariatur",
"parent_id": 1
},
"relationships": {
"tasks": {
"data": [
{
"type": null,
"id": "245"
}
]
}
}
}
],
"included": [
{
"type": null,
"id": "435",
"attributes": {
"name": "incidunt",
"content": "Laboriosam occaecati qui voluptas suscipit. Magni numquam incidunt pariatur et at. Alias molestias perspiciatis quae sit.",
"project_id": 12,
"due_at": "1971-05-19"
}
},
I know you can set the type for the requested resource like so:
// Important, notice the Resource Key in the third parameter:
$resource = new Item($book, new JsonApiBookTransformer(), 'books');
$resource = new Collection($books, new JsonApiBookTransformer(), 'books');
How can I do this for included data?
laravel thephpleague-fractal
add a comment |
This is what I get at the moment with Fractal's JsonApiSerializer of Fractal in Laravel:
{
"type": "projects",
"id": "18",
"attributes": {
"name": "pariatur",
"parent_id": 1
},
"relationships": {
"tasks": {
"data": [
{
"type": null,
"id": "245"
}
]
}
}
}
],
"included": [
{
"type": null,
"id": "435",
"attributes": {
"name": "incidunt",
"content": "Laboriosam occaecati qui voluptas suscipit. Magni numquam incidunt pariatur et at. Alias molestias perspiciatis quae sit.",
"project_id": 12,
"due_at": "1971-05-19"
}
},
I know you can set the type for the requested resource like so:
// Important, notice the Resource Key in the third parameter:
$resource = new Item($book, new JsonApiBookTransformer(), 'books');
$resource = new Collection($books, new JsonApiBookTransformer(), 'books');
How can I do this for included data?
laravel thephpleague-fractal
add a comment |
This is what I get at the moment with Fractal's JsonApiSerializer of Fractal in Laravel:
{
"type": "projects",
"id": "18",
"attributes": {
"name": "pariatur",
"parent_id": 1
},
"relationships": {
"tasks": {
"data": [
{
"type": null,
"id": "245"
}
]
}
}
}
],
"included": [
{
"type": null,
"id": "435",
"attributes": {
"name": "incidunt",
"content": "Laboriosam occaecati qui voluptas suscipit. Magni numquam incidunt pariatur et at. Alias molestias perspiciatis quae sit.",
"project_id": 12,
"due_at": "1971-05-19"
}
},
I know you can set the type for the requested resource like so:
// Important, notice the Resource Key in the third parameter:
$resource = new Item($book, new JsonApiBookTransformer(), 'books');
$resource = new Collection($books, new JsonApiBookTransformer(), 'books');
How can I do this for included data?
laravel thephpleague-fractal
This is what I get at the moment with Fractal's JsonApiSerializer of Fractal in Laravel:
{
"type": "projects",
"id": "18",
"attributes": {
"name": "pariatur",
"parent_id": 1
},
"relationships": {
"tasks": {
"data": [
{
"type": null,
"id": "245"
}
]
}
}
}
],
"included": [
{
"type": null,
"id": "435",
"attributes": {
"name": "incidunt",
"content": "Laboriosam occaecati qui voluptas suscipit. Magni numquam incidunt pariatur et at. Alias molestias perspiciatis quae sit.",
"project_id": 12,
"due_at": "1971-05-19"
}
},
I know you can set the type for the requested resource like so:
// Important, notice the Resource Key in the third parameter:
$resource = new Item($book, new JsonApiBookTransformer(), 'books');
$resource = new Collection($books, new JsonApiBookTransformer(), 'books');
How can I do this for included data?
laravel thephpleague-fractal
laravel thephpleague-fractal
asked Nov 21 '18 at 16:26
Artjom Heinz
11
11
add a comment |
add a comment |
1 Answer
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For people who may stumble upon this. I was missing that you need to set the ressourceKey in the corresponding transformer where you call collection() to include the data. Makes sense of course. In my case:
public function includeTasks(Project $project, ParamBag $paramBag)
{
list($orderCol, $orderBy) = $paramBag->get('order') ?: ['created_at', 'desc'];
$tasks = $project->tasks()->orderBy($orderCol, $orderBy)->get();
return $this->collection($tasks, App::make(TaskTransformer::class), 'tasks');
}
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
For people who may stumble upon this. I was missing that you need to set the ressourceKey in the corresponding transformer where you call collection() to include the data. Makes sense of course. In my case:
public function includeTasks(Project $project, ParamBag $paramBag)
{
list($orderCol, $orderBy) = $paramBag->get('order') ?: ['created_at', 'desc'];
$tasks = $project->tasks()->orderBy($orderCol, $orderBy)->get();
return $this->collection($tasks, App::make(TaskTransformer::class), 'tasks');
}
add a comment |
For people who may stumble upon this. I was missing that you need to set the ressourceKey in the corresponding transformer where you call collection() to include the data. Makes sense of course. In my case:
public function includeTasks(Project $project, ParamBag $paramBag)
{
list($orderCol, $orderBy) = $paramBag->get('order') ?: ['created_at', 'desc'];
$tasks = $project->tasks()->orderBy($orderCol, $orderBy)->get();
return $this->collection($tasks, App::make(TaskTransformer::class), 'tasks');
}
add a comment |
For people who may stumble upon this. I was missing that you need to set the ressourceKey in the corresponding transformer where you call collection() to include the data. Makes sense of course. In my case:
public function includeTasks(Project $project, ParamBag $paramBag)
{
list($orderCol, $orderBy) = $paramBag->get('order') ?: ['created_at', 'desc'];
$tasks = $project->tasks()->orderBy($orderCol, $orderBy)->get();
return $this->collection($tasks, App::make(TaskTransformer::class), 'tasks');
}
For people who may stumble upon this. I was missing that you need to set the ressourceKey in the corresponding transformer where you call collection() to include the data. Makes sense of course. In my case:
public function includeTasks(Project $project, ParamBag $paramBag)
{
list($orderCol, $orderBy) = $paramBag->get('order') ?: ['created_at', 'desc'];
$tasks = $project->tasks()->orderBy($orderCol, $orderBy)->get();
return $this->collection($tasks, App::make(TaskTransformer::class), 'tasks');
}
answered Nov 22 '18 at 8:16
Artjom Heinz
11
11
add a comment |
add a comment |
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