Type of included data is null with JsonApiSerializer in Fractal












0














This is what I get at the moment with Fractal's JsonApiSerializer of Fractal in Laravel:



{
"type": "projects",
"id": "18",
"attributes": {
"name": "pariatur",
"parent_id": 1
},
"relationships": {
"tasks": {
"data": [
{
"type": null,
"id": "245"
}
]
}
}
}
],
"included": [
{
"type": null,
"id": "435",
"attributes": {
"name": "incidunt",
"content": "Laboriosam occaecati qui voluptas suscipit. Magni numquam incidunt pariatur et at. Alias molestias perspiciatis quae sit.",
"project_id": 12,
"due_at": "1971-05-19"
}
},


I know you can set the type for the requested resource like so:



// Important, notice the Resource Key in the third parameter:
$resource = new Item($book, new JsonApiBookTransformer(), 'books');
$resource = new Collection($books, new JsonApiBookTransformer(), 'books');


How can I do this for included data?










share|improve this question



























    0














    This is what I get at the moment with Fractal's JsonApiSerializer of Fractal in Laravel:



    {
    "type": "projects",
    "id": "18",
    "attributes": {
    "name": "pariatur",
    "parent_id": 1
    },
    "relationships": {
    "tasks": {
    "data": [
    {
    "type": null,
    "id": "245"
    }
    ]
    }
    }
    }
    ],
    "included": [
    {
    "type": null,
    "id": "435",
    "attributes": {
    "name": "incidunt",
    "content": "Laboriosam occaecati qui voluptas suscipit. Magni numquam incidunt pariatur et at. Alias molestias perspiciatis quae sit.",
    "project_id": 12,
    "due_at": "1971-05-19"
    }
    },


    I know you can set the type for the requested resource like so:



    // Important, notice the Resource Key in the third parameter:
    $resource = new Item($book, new JsonApiBookTransformer(), 'books');
    $resource = new Collection($books, new JsonApiBookTransformer(), 'books');


    How can I do this for included data?










    share|improve this question

























      0












      0








      0







      This is what I get at the moment with Fractal's JsonApiSerializer of Fractal in Laravel:



      {
      "type": "projects",
      "id": "18",
      "attributes": {
      "name": "pariatur",
      "parent_id": 1
      },
      "relationships": {
      "tasks": {
      "data": [
      {
      "type": null,
      "id": "245"
      }
      ]
      }
      }
      }
      ],
      "included": [
      {
      "type": null,
      "id": "435",
      "attributes": {
      "name": "incidunt",
      "content": "Laboriosam occaecati qui voluptas suscipit. Magni numquam incidunt pariatur et at. Alias molestias perspiciatis quae sit.",
      "project_id": 12,
      "due_at": "1971-05-19"
      }
      },


      I know you can set the type for the requested resource like so:



      // Important, notice the Resource Key in the third parameter:
      $resource = new Item($book, new JsonApiBookTransformer(), 'books');
      $resource = new Collection($books, new JsonApiBookTransformer(), 'books');


      How can I do this for included data?










      share|improve this question













      This is what I get at the moment with Fractal's JsonApiSerializer of Fractal in Laravel:



      {
      "type": "projects",
      "id": "18",
      "attributes": {
      "name": "pariatur",
      "parent_id": 1
      },
      "relationships": {
      "tasks": {
      "data": [
      {
      "type": null,
      "id": "245"
      }
      ]
      }
      }
      }
      ],
      "included": [
      {
      "type": null,
      "id": "435",
      "attributes": {
      "name": "incidunt",
      "content": "Laboriosam occaecati qui voluptas suscipit. Magni numquam incidunt pariatur et at. Alias molestias perspiciatis quae sit.",
      "project_id": 12,
      "due_at": "1971-05-19"
      }
      },


      I know you can set the type for the requested resource like so:



      // Important, notice the Resource Key in the third parameter:
      $resource = new Item($book, new JsonApiBookTransformer(), 'books');
      $resource = new Collection($books, new JsonApiBookTransformer(), 'books');


      How can I do this for included data?







      laravel thephpleague-fractal






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 21 '18 at 16:26









      Artjom Heinz

      11




      11
























          1 Answer
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          0














          For people who may stumble upon this. I was missing that you need to set the ressourceKey in the corresponding transformer where you call collection() to include the data. Makes sense of course. In my case:



          public function includeTasks(Project $project, ParamBag $paramBag)
          {
          list($orderCol, $orderBy) = $paramBag->get('order') ?: ['created_at', 'desc'];

          $tasks = $project->tasks()->orderBy($orderCol, $orderBy)->get();

          return $this->collection($tasks, App::make(TaskTransformer::class), 'tasks');
          }





          share|improve this answer





















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            0














            For people who may stumble upon this. I was missing that you need to set the ressourceKey in the corresponding transformer where you call collection() to include the data. Makes sense of course. In my case:



            public function includeTasks(Project $project, ParamBag $paramBag)
            {
            list($orderCol, $orderBy) = $paramBag->get('order') ?: ['created_at', 'desc'];

            $tasks = $project->tasks()->orderBy($orderCol, $orderBy)->get();

            return $this->collection($tasks, App::make(TaskTransformer::class), 'tasks');
            }





            share|improve this answer


























              0














              For people who may stumble upon this. I was missing that you need to set the ressourceKey in the corresponding transformer where you call collection() to include the data. Makes sense of course. In my case:



              public function includeTasks(Project $project, ParamBag $paramBag)
              {
              list($orderCol, $orderBy) = $paramBag->get('order') ?: ['created_at', 'desc'];

              $tasks = $project->tasks()->orderBy($orderCol, $orderBy)->get();

              return $this->collection($tasks, App::make(TaskTransformer::class), 'tasks');
              }





              share|improve this answer
























                0












                0








                0






                For people who may stumble upon this. I was missing that you need to set the ressourceKey in the corresponding transformer where you call collection() to include the data. Makes sense of course. In my case:



                public function includeTasks(Project $project, ParamBag $paramBag)
                {
                list($orderCol, $orderBy) = $paramBag->get('order') ?: ['created_at', 'desc'];

                $tasks = $project->tasks()->orderBy($orderCol, $orderBy)->get();

                return $this->collection($tasks, App::make(TaskTransformer::class), 'tasks');
                }





                share|improve this answer












                For people who may stumble upon this. I was missing that you need to set the ressourceKey in the corresponding transformer where you call collection() to include the data. Makes sense of course. In my case:



                public function includeTasks(Project $project, ParamBag $paramBag)
                {
                list($orderCol, $orderBy) = $paramBag->get('order') ?: ['created_at', 'desc'];

                $tasks = $project->tasks()->orderBy($orderCol, $orderBy)->get();

                return $this->collection($tasks, App::make(TaskTransformer::class), 'tasks');
                }






                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Nov 22 '18 at 8:16









                Artjom Heinz

                11




                11






























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