Aggregate multiple collections based on student Id
I am trying to aggregate 2 collections in MongoDB based on a student's ID. One collection consists of student personal information, another one consists of the students logs. The issue is that the data is in array which is why I think my aggregation is not working. Any help will be appreciated.
student collection
{
"_id" : ObjectId("(Object ID here"),
"data" : [
{
"name" : "John",
"id" : 1
},
{
"name" : "Sandy",
"id" : 2
}
]
}
logs collection
{
"_id" : ObjectId("(Object ID here"),
"logs" : [
{
"studentId" : 1,
"activity" : "11112,334,123"
},
{
"studentId" : 2,
"activity" : "11112,334,123"
}
]
}
Here is what I have tried:
dbo.collection("student").aggregate([
{ "$lookup": {
"localField": "data.id",
"from": "logs",
"foreignField": "logs.studentId",
"as": "studentInfo"
}
}]).toArray(function(err, results) {
console.log(results);
});
Expected result:
studentinfo: {
id: 1,
name: "John",
activity" : "11112,334,123"
}
arrays mongodb mongoose mongodb-query aggregation-framework
|
show 1 more comment
I am trying to aggregate 2 collections in MongoDB based on a student's ID. One collection consists of student personal information, another one consists of the students logs. The issue is that the data is in array which is why I think my aggregation is not working. Any help will be appreciated.
student collection
{
"_id" : ObjectId("(Object ID here"),
"data" : [
{
"name" : "John",
"id" : 1
},
{
"name" : "Sandy",
"id" : 2
}
]
}
logs collection
{
"_id" : ObjectId("(Object ID here"),
"logs" : [
{
"studentId" : 1,
"activity" : "11112,334,123"
},
{
"studentId" : 2,
"activity" : "11112,334,123"
}
]
}
Here is what I have tried:
dbo.collection("student").aggregate([
{ "$lookup": {
"localField": "data.id",
"from": "logs",
"foreignField": "logs.studentId",
"as": "studentInfo"
}
}]).toArray(function(err, results) {
console.log(results);
});
Expected result:
studentinfo: {
id: 1,
name: "John",
activity" : "11112,334,123"
}
arrays mongodb mongoose mongodb-query aggregation-framework
What version of mongodb you are using? And what output do you want?
– Anthony Winzlet
Nov 21 '18 at 16:32
Any reason to store data like this? Usually each student would be it's own document
– Bajal
Nov 21 '18 at 16:55
@AnthonyWinzlet I want to have a joined result with students logs along with personal information
– HeelMega
Nov 21 '18 at 17:06
@Bajal true but this is part of a bigger application where student does not have that much info currently
– HeelMega
Nov 21 '18 at 17:07
@HeelMega could you just paste expected output for given input ?
– mickl
Nov 21 '18 at 17:08
|
show 1 more comment
I am trying to aggregate 2 collections in MongoDB based on a student's ID. One collection consists of student personal information, another one consists of the students logs. The issue is that the data is in array which is why I think my aggregation is not working. Any help will be appreciated.
student collection
{
"_id" : ObjectId("(Object ID here"),
"data" : [
{
"name" : "John",
"id" : 1
},
{
"name" : "Sandy",
"id" : 2
}
]
}
logs collection
{
"_id" : ObjectId("(Object ID here"),
"logs" : [
{
"studentId" : 1,
"activity" : "11112,334,123"
},
{
"studentId" : 2,
"activity" : "11112,334,123"
}
]
}
Here is what I have tried:
dbo.collection("student").aggregate([
{ "$lookup": {
"localField": "data.id",
"from": "logs",
"foreignField": "logs.studentId",
"as": "studentInfo"
}
}]).toArray(function(err, results) {
console.log(results);
});
Expected result:
studentinfo: {
id: 1,
name: "John",
activity" : "11112,334,123"
}
arrays mongodb mongoose mongodb-query aggregation-framework
I am trying to aggregate 2 collections in MongoDB based on a student's ID. One collection consists of student personal information, another one consists of the students logs. The issue is that the data is in array which is why I think my aggregation is not working. Any help will be appreciated.
student collection
{
"_id" : ObjectId("(Object ID here"),
"data" : [
{
"name" : "John",
"id" : 1
},
{
"name" : "Sandy",
"id" : 2
}
]
}
logs collection
{
"_id" : ObjectId("(Object ID here"),
"logs" : [
{
"studentId" : 1,
"activity" : "11112,334,123"
},
{
"studentId" : 2,
"activity" : "11112,334,123"
}
]
}
Here is what I have tried:
dbo.collection("student").aggregate([
{ "$lookup": {
"localField": "data.id",
"from": "logs",
"foreignField": "logs.studentId",
"as": "studentInfo"
}
}]).toArray(function(err, results) {
console.log(results);
});
Expected result:
studentinfo: {
id: 1,
name: "John",
activity" : "11112,334,123"
}
arrays mongodb mongoose mongodb-query aggregation-framework
arrays mongodb mongoose mongodb-query aggregation-framework
edited Nov 21 '18 at 17:18
asked Nov 21 '18 at 16:28
HeelMega
677
677
What version of mongodb you are using? And what output do you want?
– Anthony Winzlet
Nov 21 '18 at 16:32
Any reason to store data like this? Usually each student would be it's own document
– Bajal
Nov 21 '18 at 16:55
@AnthonyWinzlet I want to have a joined result with students logs along with personal information
– HeelMega
Nov 21 '18 at 17:06
@Bajal true but this is part of a bigger application where student does not have that much info currently
– HeelMega
Nov 21 '18 at 17:07
@HeelMega could you just paste expected output for given input ?
– mickl
Nov 21 '18 at 17:08
|
show 1 more comment
What version of mongodb you are using? And what output do you want?
– Anthony Winzlet
Nov 21 '18 at 16:32
Any reason to store data like this? Usually each student would be it's own document
– Bajal
Nov 21 '18 at 16:55
@AnthonyWinzlet I want to have a joined result with students logs along with personal information
– HeelMega
Nov 21 '18 at 17:06
@Bajal true but this is part of a bigger application where student does not have that much info currently
– HeelMega
Nov 21 '18 at 17:07
@HeelMega could you just paste expected output for given input ?
– mickl
Nov 21 '18 at 17:08
What version of mongodb you are using? And what output do you want?
– Anthony Winzlet
Nov 21 '18 at 16:32
What version of mongodb you are using? And what output do you want?
– Anthony Winzlet
Nov 21 '18 at 16:32
Any reason to store data like this? Usually each student would be it's own document
– Bajal
Nov 21 '18 at 16:55
Any reason to store data like this? Usually each student would be it's own document
– Bajal
Nov 21 '18 at 16:55
@AnthonyWinzlet I want to have a joined result with students logs along with personal information
– HeelMega
Nov 21 '18 at 17:06
@AnthonyWinzlet I want to have a joined result with students logs along with personal information
– HeelMega
Nov 21 '18 at 17:06
@Bajal true but this is part of a bigger application where student does not have that much info currently
– HeelMega
Nov 21 '18 at 17:07
@Bajal true but this is part of a bigger application where student does not have that much info currently
– HeelMega
Nov 21 '18 at 17:07
@HeelMega could you just paste expected output for given input ?
– mickl
Nov 21 '18 at 17:08
@HeelMega could you just paste expected output for given input ?
– mickl
Nov 21 '18 at 17:08
|
show 1 more comment
1 Answer
1
active
oldest
votes
You can use below aggregation with mongodb 3.6
So basically your foreign field is an array you need to use $lookup
with the pipeline to $unwind
the foreign array inside the $lookup
pipeline and to match the corresponding ids
.
db.students.aggregate([
{ "$lookup": {
"from": "logs",
"let": { "dataId": "$data.id" },
"pipeline": [
{ "$unwind": "$logs" },
{ "$match": { "$expr": { "$in": ["$logs.studentId", "$$dataId"] }}},
{ "$replaceRoot": { "newRoot": "$logs" }}
],
"as": "students"
}}
])
or use this to merge both the arrays
db.students.aggregate([
{ "$lookup": {
"from": "logs",
"let": { "dataId": "$data.id" },
"pipeline": [
{ "$unwind": "$logs" },
{ "$match": { "$expr": { "$in": ["$logs.studentId", "$$dataId"] }}},
{ "$replaceRoot": { "newRoot": "$logs" }}
],
"as": "students"
}},
{ "$project": {
"students": {
"$map": {
"input": "$students",
"in": {
"studentId": "$$this.studentId",
"activity": "$$this.activity",
"name": { "$arrayElemAt": ["$data.name", { "$indexOfArray": ["$data.id", "$$this.studentId"] }]}
}
}
}
}}
])
Output
[
{
"students": [
{
"activity": "11112,334,123",
"name": "John",
"studentId": 1
},
{
"activity": "11112,334,123",
"name": "Sandy",
"studentId": 2
}
]
}
]
Where is dataId in the first query coming from?
– HeelMega
Nov 21 '18 at 17:47
dataId
is the variable we have taken inlet
expression. Which is yourlocalField
.
– Anthony Winzlet
Nov 21 '18 at 17:49
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53416506%2faggregate-multiple-collections-based-on-student-id%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You can use below aggregation with mongodb 3.6
So basically your foreign field is an array you need to use $lookup
with the pipeline to $unwind
the foreign array inside the $lookup
pipeline and to match the corresponding ids
.
db.students.aggregate([
{ "$lookup": {
"from": "logs",
"let": { "dataId": "$data.id" },
"pipeline": [
{ "$unwind": "$logs" },
{ "$match": { "$expr": { "$in": ["$logs.studentId", "$$dataId"] }}},
{ "$replaceRoot": { "newRoot": "$logs" }}
],
"as": "students"
}}
])
or use this to merge both the arrays
db.students.aggregate([
{ "$lookup": {
"from": "logs",
"let": { "dataId": "$data.id" },
"pipeline": [
{ "$unwind": "$logs" },
{ "$match": { "$expr": { "$in": ["$logs.studentId", "$$dataId"] }}},
{ "$replaceRoot": { "newRoot": "$logs" }}
],
"as": "students"
}},
{ "$project": {
"students": {
"$map": {
"input": "$students",
"in": {
"studentId": "$$this.studentId",
"activity": "$$this.activity",
"name": { "$arrayElemAt": ["$data.name", { "$indexOfArray": ["$data.id", "$$this.studentId"] }]}
}
}
}
}}
])
Output
[
{
"students": [
{
"activity": "11112,334,123",
"name": "John",
"studentId": 1
},
{
"activity": "11112,334,123",
"name": "Sandy",
"studentId": 2
}
]
}
]
Where is dataId in the first query coming from?
– HeelMega
Nov 21 '18 at 17:47
dataId
is the variable we have taken inlet
expression. Which is yourlocalField
.
– Anthony Winzlet
Nov 21 '18 at 17:49
add a comment |
You can use below aggregation with mongodb 3.6
So basically your foreign field is an array you need to use $lookup
with the pipeline to $unwind
the foreign array inside the $lookup
pipeline and to match the corresponding ids
.
db.students.aggregate([
{ "$lookup": {
"from": "logs",
"let": { "dataId": "$data.id" },
"pipeline": [
{ "$unwind": "$logs" },
{ "$match": { "$expr": { "$in": ["$logs.studentId", "$$dataId"] }}},
{ "$replaceRoot": { "newRoot": "$logs" }}
],
"as": "students"
}}
])
or use this to merge both the arrays
db.students.aggregate([
{ "$lookup": {
"from": "logs",
"let": { "dataId": "$data.id" },
"pipeline": [
{ "$unwind": "$logs" },
{ "$match": { "$expr": { "$in": ["$logs.studentId", "$$dataId"] }}},
{ "$replaceRoot": { "newRoot": "$logs" }}
],
"as": "students"
}},
{ "$project": {
"students": {
"$map": {
"input": "$students",
"in": {
"studentId": "$$this.studentId",
"activity": "$$this.activity",
"name": { "$arrayElemAt": ["$data.name", { "$indexOfArray": ["$data.id", "$$this.studentId"] }]}
}
}
}
}}
])
Output
[
{
"students": [
{
"activity": "11112,334,123",
"name": "John",
"studentId": 1
},
{
"activity": "11112,334,123",
"name": "Sandy",
"studentId": 2
}
]
}
]
Where is dataId in the first query coming from?
– HeelMega
Nov 21 '18 at 17:47
dataId
is the variable we have taken inlet
expression. Which is yourlocalField
.
– Anthony Winzlet
Nov 21 '18 at 17:49
add a comment |
You can use below aggregation with mongodb 3.6
So basically your foreign field is an array you need to use $lookup
with the pipeline to $unwind
the foreign array inside the $lookup
pipeline and to match the corresponding ids
.
db.students.aggregate([
{ "$lookup": {
"from": "logs",
"let": { "dataId": "$data.id" },
"pipeline": [
{ "$unwind": "$logs" },
{ "$match": { "$expr": { "$in": ["$logs.studentId", "$$dataId"] }}},
{ "$replaceRoot": { "newRoot": "$logs" }}
],
"as": "students"
}}
])
or use this to merge both the arrays
db.students.aggregate([
{ "$lookup": {
"from": "logs",
"let": { "dataId": "$data.id" },
"pipeline": [
{ "$unwind": "$logs" },
{ "$match": { "$expr": { "$in": ["$logs.studentId", "$$dataId"] }}},
{ "$replaceRoot": { "newRoot": "$logs" }}
],
"as": "students"
}},
{ "$project": {
"students": {
"$map": {
"input": "$students",
"in": {
"studentId": "$$this.studentId",
"activity": "$$this.activity",
"name": { "$arrayElemAt": ["$data.name", { "$indexOfArray": ["$data.id", "$$this.studentId"] }]}
}
}
}
}}
])
Output
[
{
"students": [
{
"activity": "11112,334,123",
"name": "John",
"studentId": 1
},
{
"activity": "11112,334,123",
"name": "Sandy",
"studentId": 2
}
]
}
]
You can use below aggregation with mongodb 3.6
So basically your foreign field is an array you need to use $lookup
with the pipeline to $unwind
the foreign array inside the $lookup
pipeline and to match the corresponding ids
.
db.students.aggregate([
{ "$lookup": {
"from": "logs",
"let": { "dataId": "$data.id" },
"pipeline": [
{ "$unwind": "$logs" },
{ "$match": { "$expr": { "$in": ["$logs.studentId", "$$dataId"] }}},
{ "$replaceRoot": { "newRoot": "$logs" }}
],
"as": "students"
}}
])
or use this to merge both the arrays
db.students.aggregate([
{ "$lookup": {
"from": "logs",
"let": { "dataId": "$data.id" },
"pipeline": [
{ "$unwind": "$logs" },
{ "$match": { "$expr": { "$in": ["$logs.studentId", "$$dataId"] }}},
{ "$replaceRoot": { "newRoot": "$logs" }}
],
"as": "students"
}},
{ "$project": {
"students": {
"$map": {
"input": "$students",
"in": {
"studentId": "$$this.studentId",
"activity": "$$this.activity",
"name": { "$arrayElemAt": ["$data.name", { "$indexOfArray": ["$data.id", "$$this.studentId"] }]}
}
}
}
}}
])
Output
[
{
"students": [
{
"activity": "11112,334,123",
"name": "John",
"studentId": 1
},
{
"activity": "11112,334,123",
"name": "Sandy",
"studentId": 2
}
]
}
]
edited Nov 21 '18 at 17:52
answered Nov 21 '18 at 17:27
Anthony Winzlet
14.1k41239
14.1k41239
Where is dataId in the first query coming from?
– HeelMega
Nov 21 '18 at 17:47
dataId
is the variable we have taken inlet
expression. Which is yourlocalField
.
– Anthony Winzlet
Nov 21 '18 at 17:49
add a comment |
Where is dataId in the first query coming from?
– HeelMega
Nov 21 '18 at 17:47
dataId
is the variable we have taken inlet
expression. Which is yourlocalField
.
– Anthony Winzlet
Nov 21 '18 at 17:49
Where is dataId in the first query coming from?
– HeelMega
Nov 21 '18 at 17:47
Where is dataId in the first query coming from?
– HeelMega
Nov 21 '18 at 17:47
dataId
is the variable we have taken in let
expression. Which is your localField
.– Anthony Winzlet
Nov 21 '18 at 17:49
dataId
is the variable we have taken in let
expression. Which is your localField
.– Anthony Winzlet
Nov 21 '18 at 17:49
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Some of your past answers have not been well-received, and you're in danger of being blocked from answering.
Please pay close attention to the following guidance:
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53416506%2faggregate-multiple-collections-based-on-student-id%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
What version of mongodb you are using? And what output do you want?
– Anthony Winzlet
Nov 21 '18 at 16:32
Any reason to store data like this? Usually each student would be it's own document
– Bajal
Nov 21 '18 at 16:55
@AnthonyWinzlet I want to have a joined result with students logs along with personal information
– HeelMega
Nov 21 '18 at 17:06
@Bajal true but this is part of a bigger application where student does not have that much info currently
– HeelMega
Nov 21 '18 at 17:07
@HeelMega could you just paste expected output for given input ?
– mickl
Nov 21 '18 at 17:08