3d matrix inline initialization
0
Is there any way to inline initialize a 3D matrix in MATLAB in a single line? Thus, without use of for-loops and pre-initialization, e.g. via zero(a,b,c). As far as I know we can only do 2D as in:
matr=[1,2;3,4]
where , and ; indicate the two dimensions. Is there any deliminator for the third dimension that I do not know about? I know that the a multi-line initilization is possible via
matr(:,:,1) = [1 2 3; 9 8 7; 4 6 5];
matr(:,:,2) = [0 3 2; 8 8 4; 5 3 5];
matr(:,:,3) = [6 4 7; 6 8 5; 5 4 3];
matlab multidimensional-array initialization
edited Nov 21 at 3:06
Cœur
17.4k9102143
asked Jan 11 '16 at 9:47
Sebastian
8981119
add a comment |
0
Is there any way to inline initialize a 3D matrix in MATLAB in a single line? Thus, without use of for-loops and pre-initialization, e.g. via zero(a,b,c). As far as I know we can only do 2D as in:
matr=[1,2;3,4]
where , and ; indicate the two dimensions. Is there any deliminator for the third dimension that I do not know about? I know that the a multi-line initilization is possible via
matr(:,:,1) = [1 2 3; 9 8 7; 4 6 5];
matr(:,:,2) = [0 3 2; 8 8 4; 5 3 5];
matr(:,:,3) = [6 4 7; 6 8 5; 5 4 3];
matlab multidimensional-array initialization
edited Nov 21 at 3:06
Cœur
17.4k9102143
asked Jan 11 '16 at 9:47
Sebastian
8981119
Here is the official doc concerning the creation/manipulation of multi-dimensional arrays uk.mathworks.com/help/matlab/math/multidimensional-arrays.html
– marsei
Jan 11 '16 at 14:17
This is weird bahaviour?!?matr(:,:,1) = [1 2 3; 9 8 7; 4 6 5];initialises a3x3 double, and not a3x3x1 double; then the second line suddenly is able to add a dimension to an existing array. I always thought that'd give you a "dimension mismatch" error. Seems like you learn something every day
– Adriaan
Jan 11 '16 at 14:41
add a comment |
0
0
0
Is there any way to inline initialize a 3D matrix in MATLAB in a single line? Thus, without use of for-loops and pre-initialization, e.g. via zero(a,b,c). As far as I know we can only do 2D as in:
matr=[1,2;3,4]
where , and ; indicate the two dimensions. Is there any deliminator for the third dimension that I do not know about? I know that the a multi-line initilization is possible via
matr(:,:,1) = [1 2 3; 9 8 7; 4 6 5];
matr(:,:,2) = [0 3 2; 8 8 4; 5 3 5];
matr(:,:,3) = [6 4 7; 6 8 5; 5 4 3];
matlab multidimensional-array initialization
edited Nov 21 at 3:06
Cœur
17.4k9102143
asked Jan 11 '16 at 9:47
Sebastian
8981119
Is there any way to inline initialize a 3D matrix in MATLAB in a single line? Thus, without use of for-loops and pre-initialization, e.g. via zero(a,b,c). As far as I know we can only do 2D as in:
matr=[1,2;3,4]
where , and ; indicate the two dimensions. Is there any deliminator for the third dimension that I do not know about? I know that the a multi-line initilization is possible via
matr(:,:,1) = [1 2 3; 9 8 7; 4 6 5];
matr(:,:,2) = [0 3 2; 8 8 4; 5 3 5];
matr(:,:,3) = [6 4 7; 6 8 5; 5 4 3];
matlab multidimensional-array initialization
matlab multidimensional-array initialization
edited Nov 21 at 3:06
Cœur
17.4k9102143
asked Jan 11 '16 at 9:47
Sebastian
8981119
edited Nov 21 at 3:06
Cœur
17.4k9102143
asked Jan 11 '16 at 9:47
Sebastian
8981119
edited Nov 21 at 3:06
Cœur
17.4k9102143
edited Nov 21 at 3:06
Cœur
17.4k9102143
edited Nov 21 at 3:06
Cœur
17.4k9102143
17.4k9102143
asked Jan 11 '16 at 9:47
Sebastian
8981119
asked Jan 11 '16 at 9:47
Sebastian
8981119
asked Jan 11 '16 at 9:47
Sebastian
8981119
8981119
Here is the official doc concerning the creation/manipulation of multi-dimensional arrays uk.mathworks.com/help/matlab/math/multidimensional-arrays.html
– marsei
Jan 11 '16 at 14:17
This is weird bahaviour?!?matr(:,:,1) = [1 2 3; 9 8 7; 4 6 5];initialises a3x3 double, and not a3x3x1 double; then the second line suddenly is able to add a dimension to an existing array. I always thought that'd give you a "dimension mismatch" error. Seems like you learn something every day
– Adriaan
Jan 11 '16 at 14:41
add a comment |
Here is the official doc concerning the creation/manipulation of multi-dimensional arrays uk.mathworks.com/help/matlab/math/multidimensional-arrays.html
– marsei
Jan 11 '16 at 14:17
This is weird bahaviour?!?matr(:,:,1) = [1 2 3; 9 8 7; 4 6 5];initialises a3x3 double, and not a3x3x1 double; then the second line suddenly is able to add a dimension to an existing array. I always thought that'd give you a "dimension mismatch" error. Seems like you learn something every day
– Adriaan
Jan 11 '16 at 14:41
Here is the official doc concerning the creation/manipulation of multi-dimensional arrays uk.mathworks.com/help/matlab/math/multidimensional-arrays.html
– marsei
Jan 11 '16 at 14:17
Here is the official doc concerning the creation/manipulation of multi-dimensional arrays uk.mathworks.com/help/matlab/math/multidimensional-arrays.html
– marsei
Jan 11 '16 at 14:17
This is weird bahaviour?!?
matr(:,:,1) = [1 2 3; 9 8 7; 4 6 5]; initialises a 3x3 double, and not a 3x3x1 double; then the second line suddenly is able to add a dimension to an existing array. I always thought that'd give you a "dimension mismatch" error. Seems like you learn something every day– Adriaan
Jan 11 '16 at 14:41
This is weird bahaviour?!?
matr(:,:,1) = [1 2 3; 9 8 7; 4 6 5]; initialises a 3x3 double, and not a 3x3x1 double; then the second line suddenly is able to add a dimension to an existing array. I always thought that'd give you a "dimension mismatch" error. Seems like you learn something every day– Adriaan
Jan 11 '16 at 14:41
add a comment |
1 Answer
1
active
oldest
votes
2
Use cat to concatenate along the third dimension:
cat(3, [1 2 3; 9 8 7; 4 6 5], [0 3 2; 8 8 4; 5 3 5], [6 4 7; 6 8 5; 5 4 3])
You can also achieve this using reshape:
reshape([[1 2 3; 9 8 7; 4 6 5], [0 3 2; 8 8 4; 5 3 5], [6 4 7; 6 8 5; 5 4 3]], [3,3,3])
answered Jan 11 '16 at 10:03
Dan
36.8k95299
not pretty but works, thanks!
– Sebastian
Jan 11 '16 at 10:06
1
The second one does not give the correct results (actually, this was what I was trying first, too). Here,permute(reshape([1 2 3; 9 8 7; 4 6 5;0 3 2; 8 8 4; 5 3 5; 6 4 7; 6 8 5; 5 4 3].',[3,3,3]),[2,1,3])gives the correct matrix.
– Nemesis
Jan 11 '16 at 12:02
@Nemesis see edit
– Dan
Jan 11 '16 at 12:06
Looks good (and better than mytransposeandpermute).
– Nemesis
Jan 11 '16 at 12:40
@Nemesis still a poor choice compared tocatthough
– Dan
Jan 11 '16 at 12:44
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
2
Use cat to concatenate along the third dimension:
cat(3, [1 2 3; 9 8 7; 4 6 5], [0 3 2; 8 8 4; 5 3 5], [6 4 7; 6 8 5; 5 4 3])
You can also achieve this using reshape:
reshape([[1 2 3; 9 8 7; 4 6 5], [0 3 2; 8 8 4; 5 3 5], [6 4 7; 6 8 5; 5 4 3]], [3,3,3])
answered Jan 11 '16 at 10:03
Dan
36.8k95299
not pretty but works, thanks!
– Sebastian
Jan 11 '16 at 10:06
1
The second one does not give the correct results (actually, this was what I was trying first, too). Here,permute(reshape([1 2 3; 9 8 7; 4 6 5;0 3 2; 8 8 4; 5 3 5; 6 4 7; 6 8 5; 5 4 3].',[3,3,3]),[2,1,3])gives the correct matrix.
– Nemesis
Jan 11 '16 at 12:02
@Nemesis see edit
– Dan
Jan 11 '16 at 12:06
Looks good (and better than mytransposeandpermute).
– Nemesis
Jan 11 '16 at 12:40
@Nemesis still a poor choice compared tocatthough
– Dan
Jan 11 '16 at 12:44
add a comment |
2
Use cat to concatenate along the third dimension:
cat(3, [1 2 3; 9 8 7; 4 6 5], [0 3 2; 8 8 4; 5 3 5], [6 4 7; 6 8 5; 5 4 3])
You can also achieve this using reshape:
reshape([[1 2 3; 9 8 7; 4 6 5], [0 3 2; 8 8 4; 5 3 5], [6 4 7; 6 8 5; 5 4 3]], [3,3,3])
answered Jan 11 '16 at 10:03
Dan
36.8k95299
not pretty but works, thanks!
– Sebastian
Jan 11 '16 at 10:06
1
The second one does not give the correct results (actually, this was what I was trying first, too). Here,permute(reshape([1 2 3; 9 8 7; 4 6 5;0 3 2; 8 8 4; 5 3 5; 6 4 7; 6 8 5; 5 4 3].',[3,3,3]),[2,1,3])gives the correct matrix.
– Nemesis
Jan 11 '16 at 12:02
@Nemesis see edit
– Dan
Jan 11 '16 at 12:06
Looks good (and better than mytransposeandpermute).
– Nemesis
Jan 11 '16 at 12:40
@Nemesis still a poor choice compared tocatthough
– Dan
Jan 11 '16 at 12:44
add a comment |
2
2
2
Use cat to concatenate along the third dimension:
cat(3, [1 2 3; 9 8 7; 4 6 5], [0 3 2; 8 8 4; 5 3 5], [6 4 7; 6 8 5; 5 4 3])
You can also achieve this using reshape:
reshape([[1 2 3; 9 8 7; 4 6 5], [0 3 2; 8 8 4; 5 3 5], [6 4 7; 6 8 5; 5 4 3]], [3,3,3])
answered Jan 11 '16 at 10:03
Dan
36.8k95299
Use cat to concatenate along the third dimension:
cat(3, [1 2 3; 9 8 7; 4 6 5], [0 3 2; 8 8 4; 5 3 5], [6 4 7; 6 8 5; 5 4 3])
You can also achieve this using reshape:
reshape([[1 2 3; 9 8 7; 4 6 5], [0 3 2; 8 8 4; 5 3 5], [6 4 7; 6 8 5; 5 4 3]], [3,3,3])
answered Jan 11 '16 at 10:03
Dan
36.8k95299
edited Jan 11 '16 at 12:06
answered Jan 11 '16 at 10:03
Dan
36.8k95299
answered Jan 11 '16 at 10:03
Dan
36.8k95299
answered Jan 11 '16 at 10:03
Dan
36.8k95299
36.8k95299
not pretty but works, thanks!
– Sebastian
Jan 11 '16 at 10:06
1
The second one does not give the correct results (actually, this was what I was trying first, too). Here,permute(reshape([1 2 3; 9 8 7; 4 6 5;0 3 2; 8 8 4; 5 3 5; 6 4 7; 6 8 5; 5 4 3].',[3,3,3]),[2,1,3])gives the correct matrix.
– Nemesis
Jan 11 '16 at 12:02
@Nemesis see edit
– Dan
Jan 11 '16 at 12:06
Looks good (and better than mytransposeandpermute).
– Nemesis
Jan 11 '16 at 12:40
@Nemesis still a poor choice compared tocatthough
– Dan
Jan 11 '16 at 12:44
add a comment |
not pretty but works, thanks!
– Sebastian
Jan 11 '16 at 10:06
1
The second one does not give the correct results (actually, this was what I was trying first, too). Here,permute(reshape([1 2 3; 9 8 7; 4 6 5;0 3 2; 8 8 4; 5 3 5; 6 4 7; 6 8 5; 5 4 3].',[3,3,3]),[2,1,3])gives the correct matrix.
– Nemesis
Jan 11 '16 at 12:02
@Nemesis see edit
– Dan
Jan 11 '16 at 12:06
Looks good (and better than mytransposeandpermute).
– Nemesis
Jan 11 '16 at 12:40
@Nemesis still a poor choice compared tocatthough
– Dan
Jan 11 '16 at 12:44
not pretty but works, thanks!
– Sebastian
Jan 11 '16 at 10:06
not pretty but works, thanks!
– Sebastian
Jan 11 '16 at 10:06
1
1
The second one does not give the correct results (actually, this was what I was trying first, too). Here,
permute(reshape([1 2 3; 9 8 7; 4 6 5;0 3 2; 8 8 4; 5 3 5; 6 4 7; 6 8 5; 5 4 3].',[3,3,3]),[2,1,3]) gives the correct matrix.– Nemesis
Jan 11 '16 at 12:02
The second one does not give the correct results (actually, this was what I was trying first, too). Here,
permute(reshape([1 2 3; 9 8 7; 4 6 5;0 3 2; 8 8 4; 5 3 5; 6 4 7; 6 8 5; 5 4 3].',[3,3,3]),[2,1,3]) gives the correct matrix.– Nemesis
Jan 11 '16 at 12:02
@Nemesis see edit
– Dan
Jan 11 '16 at 12:06
@Nemesis see edit
– Dan
Jan 11 '16 at 12:06
Looks good (and better than my
transpose and permute).– Nemesis
Jan 11 '16 at 12:40
Looks good (and better than my
transpose and permute).– Nemesis
Jan 11 '16 at 12:40
@Nemesis still a poor choice compared to
cat though– Dan
Jan 11 '16 at 12:44
@Nemesis still a poor choice compared to
cat though– Dan
Jan 11 '16 at 12:44
add a comment |
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Here is the official doc concerning the creation/manipulation of multi-dimensional arrays uk.mathworks.com/help/matlab/math/multidimensional-arrays.html
– marsei
Jan 11 '16 at 14:17
This is weird bahaviour?!?
matr(:,:,1) = [1 2 3; 9 8 7; 4 6 5];initialises a3x3 double, and not a3x3x1 double; then the second line suddenly is able to add a dimension to an existing array. I always thought that'd give you a "dimension mismatch" error. Seems like you learn something every day– Adriaan
Jan 11 '16 at 14:41