How to compare value with column value and get second highest value if it is greater than passing value












0















I have table 'my_table' with price column and product column



If I pass value 1800 then it should get second highest record like



 SELECT *, ABS(price-1800) x FROM my_table WHERE product = 1 ORDER BY x LIMIT 1;

Expected output:
id product price
1 p1 2000


If I pass value 2200 or 5000 it should get record like



SELECT *, ABS(price-2200) x FROM my_table WHERE product = 1 ORDER BY x LIMIT 1;
Expected output:
id product price
1 p1 2500


but The query is not working as per my expectation if I pass value 2200 it is selecting record 2000 but i want record 2500



how to write query to acheive this?










share|improve this question























  • Duplicate from: stackoverflow.com/q/53467145/2469308

    – Madhur Bhaiya
    Nov 25 '18 at 13:38
















0















I have table 'my_table' with price column and product column



If I pass value 1800 then it should get second highest record like



 SELECT *, ABS(price-1800) x FROM my_table WHERE product = 1 ORDER BY x LIMIT 1;

Expected output:
id product price
1 p1 2000


If I pass value 2200 or 5000 it should get record like



SELECT *, ABS(price-2200) x FROM my_table WHERE product = 1 ORDER BY x LIMIT 1;
Expected output:
id product price
1 p1 2500


but The query is not working as per my expectation if I pass value 2200 it is selecting record 2000 but i want record 2500



how to write query to acheive this?










share|improve this question























  • Duplicate from: stackoverflow.com/q/53467145/2469308

    – Madhur Bhaiya
    Nov 25 '18 at 13:38














0












0








0








I have table 'my_table' with price column and product column



If I pass value 1800 then it should get second highest record like



 SELECT *, ABS(price-1800) x FROM my_table WHERE product = 1 ORDER BY x LIMIT 1;

Expected output:
id product price
1 p1 2000


If I pass value 2200 or 5000 it should get record like



SELECT *, ABS(price-2200) x FROM my_table WHERE product = 1 ORDER BY x LIMIT 1;
Expected output:
id product price
1 p1 2500


but The query is not working as per my expectation if I pass value 2200 it is selecting record 2000 but i want record 2500



how to write query to acheive this?










share|improve this question














I have table 'my_table' with price column and product column



If I pass value 1800 then it should get second highest record like



 SELECT *, ABS(price-1800) x FROM my_table WHERE product = 1 ORDER BY x LIMIT 1;

Expected output:
id product price
1 p1 2000


If I pass value 2200 or 5000 it should get record like



SELECT *, ABS(price-2200) x FROM my_table WHERE product = 1 ORDER BY x LIMIT 1;
Expected output:
id product price
1 p1 2500


but The query is not working as per my expectation if I pass value 2200 it is selecting record 2000 but i want record 2500



how to write query to acheive this?







mysql






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 25 '18 at 13:37









parvezparvez

336




336













  • Duplicate from: stackoverflow.com/q/53467145/2469308

    – Madhur Bhaiya
    Nov 25 '18 at 13:38



















  • Duplicate from: stackoverflow.com/q/53467145/2469308

    – Madhur Bhaiya
    Nov 25 '18 at 13:38

















Duplicate from: stackoverflow.com/q/53467145/2469308

– Madhur Bhaiya
Nov 25 '18 at 13:38





Duplicate from: stackoverflow.com/q/53467145/2469308

– Madhur Bhaiya
Nov 25 '18 at 13:38












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