Extracting Cakephp Multidimensional arrays
up vote
0
down vote
favorite
I need to find all the records from an array of id ( $user_id = array(); ) to be saved into a table of notifications, to tell these users that their accounts are activated.
After executed these,
$x = $this->User->find('all',array('conditions'=>array('User.id'=>$user_id)));
$find = Set::extract('/User', $x);
I get this result:
Array(
[0] => Array
(
[User] => Array
(
[id] => 2
[name] => joe
[age] => 13
[class] => D
)
)
[1] => Array
(
[User] => Array
(
[id] => 3
[name] => lambert
[age] => 14
[class] => E
)
)
)
I need to achive the array below by extracting the one above
Array
{
[id] => 2
[name] => joe
[age] => 13
[class] => D
}
Array
{
[id] => 3
[name] => lambert
[age] => 14
[class] => E
}
How to make this happen using CakePHP?
Then, inside my view, how to send multiple records based on the extracted array above?
Is it possible to make a foreach loop inside view?
echo $html->link(__('Send',true),array('controller'=>'users','action'=>'notifications',$user_id),array('class'=>'button'));
Obviously, putting the link inside the loop will result in two links with different ids ($user_id = 2 and $user_id = 3). I don't want that to happen. I want a single link that will submit these ids in one go.
cakephp
edited Nov 20 at 2:23
Cœur
17.2k9102141
asked May 12 '12 at 13:59
foxns7
3832617
add a comment |
up vote
0
down vote
favorite
I need to find all the records from an array of id ( $user_id = array(); ) to be saved into a table of notifications, to tell these users that their accounts are activated.
After executed these,
$x = $this->User->find('all',array('conditions'=>array('User.id'=>$user_id)));
$find = Set::extract('/User', $x);
I get this result:
Array(
[0] => Array
(
[User] => Array
(
[id] => 2
[name] => joe
[age] => 13
[class] => D
)
)
[1] => Array
(
[User] => Array
(
[id] => 3
[name] => lambert
[age] => 14
[class] => E
)
)
)
I need to achive the array below by extracting the one above
Array
{
[id] => 2
[name] => joe
[age] => 13
[class] => D
}
Array
{
[id] => 3
[name] => lambert
[age] => 14
[class] => E
}
How to make this happen using CakePHP?
Then, inside my view, how to send multiple records based on the extracted array above?
Is it possible to make a foreach loop inside view?
echo $html->link(__('Send',true),array('controller'=>'users','action'=>'notifications',$user_id),array('class'=>'button'));
Obviously, putting the link inside the loop will result in two links with different ids ($user_id = 2 and $user_id = 3). I don't want that to happen. I want a single link that will submit these ids in one go.
cakephp
edited Nov 20 at 2:23
Cœur
17.2k9102141
asked May 12 '12 at 13:59
foxns7
3832617
1) Yes you could loop in view. 2) Doesn't a form make more sense, then you could use a button to POST all the ids. Although, extracting all the ids like{n}.User.idand passing that tolink()method should work. Creating a url that looks likecontroller/action/id=1&id=2afaik. Still a POST makes more sense.
– tigrang
May 12 '12 at 17:13
To be more clear about the latter part of my comment,'id' => $arrOfExtractedIdsin the link array (2nd param oflink()method. Or $ids = array('id' => $arrOfExtractedIds'); and'?' => $idsto pass as GET params
– tigrang
May 12 '12 at 17:22
In the view, I didn't create forms. Form is created inside the controller (including saveAll). I do$this->set('users_details',$users_details)to display all the users information inside the .ctp file.(Just for display - name,class etc.). The Submit button is the only thing that will run the submission. Can this be achived without$this->User->createinside the view? Simply said, the users info is already saved inside the controller, I just need to notify them that their accounts are ready by clicking the Submit button that will send out the information to them.
– foxns7
May 12 '12 at 22:23
I suggest you use bin.cakephp.org and paste your controller, model, and form as I can't understand what you are trying to do.
– tigrang
May 12 '12 at 22:54
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I need to find all the records from an array of id ( $user_id = array(); ) to be saved into a table of notifications, to tell these users that their accounts are activated.
After executed these,
$x = $this->User->find('all',array('conditions'=>array('User.id'=>$user_id)));
$find = Set::extract('/User', $x);
I get this result:
Array(
[0] => Array
(
[User] => Array
(
[id] => 2
[name] => joe
[age] => 13
[class] => D
)
)
[1] => Array
(
[User] => Array
(
[id] => 3
[name] => lambert
[age] => 14
[class] => E
)
)
)
I need to achive the array below by extracting the one above
Array
{
[id] => 2
[name] => joe
[age] => 13
[class] => D
}
Array
{
[id] => 3
[name] => lambert
[age] => 14
[class] => E
}
How to make this happen using CakePHP?
Then, inside my view, how to send multiple records based on the extracted array above?
Is it possible to make a foreach loop inside view?
echo $html->link(__('Send',true),array('controller'=>'users','action'=>'notifications',$user_id),array('class'=>'button'));
Obviously, putting the link inside the loop will result in two links with different ids ($user_id = 2 and $user_id = 3). I don't want that to happen. I want a single link that will submit these ids in one go.
cakephp
edited Nov 20 at 2:23
Cœur
17.2k9102141
asked May 12 '12 at 13:59
foxns7
3832617
I need to find all the records from an array of id ( $user_id = array(); ) to be saved into a table of notifications, to tell these users that their accounts are activated.
After executed these,
$x = $this->User->find('all',array('conditions'=>array('User.id'=>$user_id)));
$find = Set::extract('/User', $x);
I get this result:
Array(
[0] => Array
(
[User] => Array
(
[id] => 2
[name] => joe
[age] => 13
[class] => D
)
)
[1] => Array
(
[User] => Array
(
[id] => 3
[name] => lambert
[age] => 14
[class] => E
)
)
)
I need to achive the array below by extracting the one above
Array
{
[id] => 2
[name] => joe
[age] => 13
[class] => D
}
Array
{
[id] => 3
[name] => lambert
[age] => 14
[class] => E
}
How to make this happen using CakePHP?
Then, inside my view, how to send multiple records based on the extracted array above?
Is it possible to make a foreach loop inside view?
echo $html->link(__('Send',true),array('controller'=>'users','action'=>'notifications',$user_id),array('class'=>'button'));
Obviously, putting the link inside the loop will result in two links with different ids ($user_id = 2 and $user_id = 3). I don't want that to happen. I want a single link that will submit these ids in one go.
cakephp
cakephp
edited Nov 20 at 2:23
Cœur
17.2k9102141
asked May 12 '12 at 13:59
foxns7
3832617
edited Nov 20 at 2:23
Cœur
17.2k9102141
asked May 12 '12 at 13:59
foxns7
3832617
edited Nov 20 at 2:23
Cœur
17.2k9102141
edited Nov 20 at 2:23
Cœur
17.2k9102141
edited Nov 20 at 2:23
Cœur
17.2k9102141
17.2k9102141
asked May 12 '12 at 13:59
foxns7
3832617
asked May 12 '12 at 13:59
foxns7
3832617
asked May 12 '12 at 13:59
foxns7
3832617
3832617
1) Yes you could loop in view. 2) Doesn't a form make more sense, then you could use a button to POST all the ids. Although, extracting all the ids like{n}.User.idand passing that tolink()method should work. Creating a url that looks likecontroller/action/id=1&id=2afaik. Still a POST makes more sense.
– tigrang
May 12 '12 at 17:13
To be more clear about the latter part of my comment,'id' => $arrOfExtractedIdsin the link array (2nd param oflink()method. Or $ids = array('id' => $arrOfExtractedIds'); and'?' => $idsto pass as GET params
– tigrang
May 12 '12 at 17:22
In the view, I didn't create forms. Form is created inside the controller (including saveAll). I do$this->set('users_details',$users_details)to display all the users information inside the .ctp file.(Just for display - name,class etc.). The Submit button is the only thing that will run the submission. Can this be achived without$this->User->createinside the view? Simply said, the users info is already saved inside the controller, I just need to notify them that their accounts are ready by clicking the Submit button that will send out the information to them.
– foxns7
May 12 '12 at 22:23
I suggest you use bin.cakephp.org and paste your controller, model, and form as I can't understand what you are trying to do.
– tigrang
May 12 '12 at 22:54
add a comment |
1) Yes you could loop in view. 2) Doesn't a form make more sense, then you could use a button to POST all the ids. Although, extracting all the ids like{n}.User.idand passing that tolink()method should work. Creating a url that looks likecontroller/action/id=1&id=2afaik. Still a POST makes more sense.
– tigrang
May 12 '12 at 17:13
To be more clear about the latter part of my comment,'id' => $arrOfExtractedIdsin the link array (2nd param oflink()method. Or $ids = array('id' => $arrOfExtractedIds'); and'?' => $idsto pass as GET params
– tigrang
May 12 '12 at 17:22
In the view, I didn't create forms. Form is created inside the controller (including saveAll). I do$this->set('users_details',$users_details)to display all the users information inside the .ctp file.(Just for display - name,class etc.). The Submit button is the only thing that will run the submission. Can this be achived without$this->User->createinside the view? Simply said, the users info is already saved inside the controller, I just need to notify them that their accounts are ready by clicking the Submit button that will send out the information to them.
– foxns7
May 12 '12 at 22:23
I suggest you use bin.cakephp.org and paste your controller, model, and form as I can't understand what you are trying to do.
– tigrang
May 12 '12 at 22:54
1) Yes you could loop in view. 2) Doesn't a form make more sense, then you could use a button to POST all the ids. Although, extracting all the ids like
{n}.User.id and passing that to link() method should work. Creating a url that looks like controller/action/id=1&id=2 afaik. Still a POST makes more sense.– tigrang
May 12 '12 at 17:13
1) Yes you could loop in view. 2) Doesn't a form make more sense, then you could use a button to POST all the ids. Although, extracting all the ids like
{n}.User.id and passing that to link() method should work. Creating a url that looks like controller/action/id=1&id=2 afaik. Still a POST makes more sense.– tigrang
May 12 '12 at 17:13
To be more clear about the latter part of my comment,
'id' => $arrOfExtractedIds in the link array (2nd param of link() method. Or $ids = array('id' => $arrOfExtractedIds'); and '?' => $ids to pass as GET params– tigrang
May 12 '12 at 17:22
To be more clear about the latter part of my comment,
'id' => $arrOfExtractedIds in the link array (2nd param of link() method. Or $ids = array('id' => $arrOfExtractedIds'); and '?' => $ids to pass as GET params– tigrang
May 12 '12 at 17:22
In the view, I didn't create forms. Form is created inside the controller (including saveAll). I do
$this->set('users_details',$users_details) to display all the users information inside the .ctp file.(Just for display - name,class etc.). The Submit button is the only thing that will run the submission. Can this be achived without $this->User->create inside the view? Simply said, the users info is already saved inside the controller, I just need to notify them that their accounts are ready by clicking the Submit button that will send out the information to them.– foxns7
May 12 '12 at 22:23
In the view, I didn't create forms. Form is created inside the controller (including saveAll). I do
$this->set('users_details',$users_details) to display all the users information inside the .ctp file.(Just for display - name,class etc.). The Submit button is the only thing that will run the submission. Can this be achived without $this->User->create inside the view? Simply said, the users info is already saved inside the controller, I just need to notify them that their accounts are ready by clicking the Submit button that will send out the information to them.– foxns7
May 12 '12 at 22:23
I suggest you use bin.cakephp.org and paste your controller, model, and form as I can't understand what you are trying to do.
– tigrang
May 12 '12 at 22:54
I suggest you use bin.cakephp.org and paste your controller, model, and form as I can't understand what you are trying to do.
– tigrang
May 12 '12 at 22:54
add a comment |
1 Answer
1
active
oldest
votes
up vote
1
down vote
accepted
The answer for your first question
$data_final =array();
foreach($findas $d)
{
$data_final =$d['User'];
}
then you wil achive
Array
(
[0] => Array
(
[id] => 2
[name] => joe
[age] => 13
[class] => D
)
[1] => Array
(
[id] => 4
[name] => lamber
[age] => 23
[class] => E
)
)
The answer to second question
the way you are doing with url is not a good practice. you should post the records
answered May 12 '12 at 17:23
Moyed Ansari
7,50222548
There are two typos in the foreach loop.
– tigrang
May 12 '12 at 17:28
what do u mean by two typos ?
– Moyed Ansari
May 12 '12 at 17:30
foreach($$findas $d)Should beforeach($find as $d)
– tigrang
May 12 '12 at 17:38
thanks for helping :)
– Moyed Ansari
May 12 '12 at 17:39
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
accepted
The answer for your first question
$data_final =array();
foreach($findas $d)
{
$data_final =$d['User'];
}
then you wil achive
Array
(
[0] => Array
(
[id] => 2
[name] => joe
[age] => 13
[class] => D
)
[1] => Array
(
[id] => 4
[name] => lamber
[age] => 23
[class] => E
)
)
The answer to second question
the way you are doing with url is not a good practice. you should post the records
answered May 12 '12 at 17:23
Moyed Ansari
7,50222548
There are two typos in the foreach loop.
– tigrang
May 12 '12 at 17:28
what do u mean by two typos ?
– Moyed Ansari
May 12 '12 at 17:30
foreach($$findas $d)Should beforeach($find as $d)
– tigrang
May 12 '12 at 17:38
thanks for helping :)
– Moyed Ansari
May 12 '12 at 17:39
add a comment |
up vote
1
down vote
accepted
The answer for your first question
$data_final =array();
foreach($findas $d)
{
$data_final =$d['User'];
}
then you wil achive
Array
(
[0] => Array
(
[id] => 2
[name] => joe
[age] => 13
[class] => D
)
[1] => Array
(
[id] => 4
[name] => lamber
[age] => 23
[class] => E
)
)
The answer to second question
the way you are doing with url is not a good practice. you should post the records
answered May 12 '12 at 17:23
Moyed Ansari
7,50222548
There are two typos in the foreach loop.
– tigrang
May 12 '12 at 17:28
what do u mean by two typos ?
– Moyed Ansari
May 12 '12 at 17:30
foreach($$findas $d)Should beforeach($find as $d)
– tigrang
May 12 '12 at 17:38
thanks for helping :)
– Moyed Ansari
May 12 '12 at 17:39
add a comment |
up vote
1
down vote
accepted
up vote
1
down vote
accepted
The answer for your first question
$data_final =array();
foreach($findas $d)
{
$data_final =$d['User'];
}
then you wil achive
Array
(
[0] => Array
(
[id] => 2
[name] => joe
[age] => 13
[class] => D
)
[1] => Array
(
[id] => 4
[name] => lamber
[age] => 23
[class] => E
)
)
The answer to second question
the way you are doing with url is not a good practice. you should post the records
answered May 12 '12 at 17:23
Moyed Ansari
7,50222548
The answer for your first question
$data_final =array();
foreach($findas $d)
{
$data_final =$d['User'];
}
then you wil achive
Array
(
[0] => Array
(
[id] => 2
[name] => joe
[age] => 13
[class] => D
)
[1] => Array
(
[id] => 4
[name] => lamber
[age] => 23
[class] => E
)
)
The answer to second question
the way you are doing with url is not a good practice. you should post the records
answered May 12 '12 at 17:23
Moyed Ansari
7,50222548
edited May 12 '12 at 17:39
answered May 12 '12 at 17:23
Moyed Ansari
7,50222548
answered May 12 '12 at 17:23
Moyed Ansari
7,50222548
answered May 12 '12 at 17:23
Moyed Ansari
7,50222548
7,50222548
There are two typos in the foreach loop.
– tigrang
May 12 '12 at 17:28
what do u mean by two typos ?
– Moyed Ansari
May 12 '12 at 17:30
foreach($$findas $d)Should beforeach($find as $d)
– tigrang
May 12 '12 at 17:38
thanks for helping :)
– Moyed Ansari
May 12 '12 at 17:39
add a comment |
There are two typos in the foreach loop.
– tigrang
May 12 '12 at 17:28
what do u mean by two typos ?
– Moyed Ansari
May 12 '12 at 17:30
foreach($$findas $d)Should beforeach($find as $d)
– tigrang
May 12 '12 at 17:38
thanks for helping :)
– Moyed Ansari
May 12 '12 at 17:39
There are two typos in the foreach loop.
– tigrang
May 12 '12 at 17:28
There are two typos in the foreach loop.
– tigrang
May 12 '12 at 17:28
what do u mean by two typos ?
– Moyed Ansari
May 12 '12 at 17:30
what do u mean by two typos ?
– Moyed Ansari
May 12 '12 at 17:30
foreach($$findas $d) Should be foreach($find as $d)– tigrang
May 12 '12 at 17:38
foreach($$findas $d) Should be foreach($find as $d)– tigrang
May 12 '12 at 17:38
thanks for helping :)
– Moyed Ansari
May 12 '12 at 17:39
thanks for helping :)
– Moyed Ansari
May 12 '12 at 17:39
add a comment |
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1) Yes you could loop in view. 2) Doesn't a form make more sense, then you could use a button to POST all the ids. Although, extracting all the ids like
{n}.User.idand passing that tolink()method should work. Creating a url that looks likecontroller/action/id=1&id=2afaik. Still a POST makes more sense.– tigrang
May 12 '12 at 17:13
To be more clear about the latter part of my comment,
'id' => $arrOfExtractedIdsin the link array (2nd param oflink()method. Or $ids = array('id' => $arrOfExtractedIds'); and'?' => $idsto pass as GET params– tigrang
May 12 '12 at 17:22
In the view, I didn't create forms. Form is created inside the controller (including saveAll). I do
$this->set('users_details',$users_details)to display all the users information inside the .ctp file.(Just for display - name,class etc.). The Submit button is the only thing that will run the submission. Can this be achived without$this->User->createinside the view? Simply said, the users info is already saved inside the controller, I just need to notify them that their accounts are ready by clicking the Submit button that will send out the information to them.– foxns7
May 12 '12 at 22:23
I suggest you use bin.cakephp.org and paste your controller, model, and form as I can't understand what you are trying to do.
– tigrang
May 12 '12 at 22:54